Create README.md

README.md

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+Usage:
+
+```python
+import torch
+from transformers import AutoTokenizer, AutoModelForCausalLM
+
+question_template = "# Question\n\n{question}\n\n# Solution\n\n"
+
+model_name = "ScalableMath/llemma-7b-sft-prm800k-level-1to3-hf"
+model = AutoModelForCausalLM.from_pretrained(model_name, torch_dtype=torch.bfloat16, device_map="auto")
+
+tokenizer = AutoTokenizer.from_pretrained("EleutherAI/llemma_7b")
+
+question = "Convert the point $(0,3)$ in rectangular coordinates to polar coordinates.  Enter your answer in the form $
+(r,\\theta),$ where $r > 0$ and $0 \\le \\theta < 2 \\pi.$"
+question = question_template.format(question=question)
+
+input_tensor = torch.tensor([tokenizer.encode(question)])
+outputs = model.generate(input_tensor.to(model.device), max_new_tokens=500)
+
+result = tokenizer.decode(outputs[0], skip_special_tokens=True)
+print(result)
+```
+
+Example Results:
+```
+# Question
+
+Convert the point $(0,3)$ in rectangular coordinates to polar coordinates.  Enter your answer in the form $(r,\theta),$ where $r > 0$ and $0 \le \theta < 2 \pi.$
+
+# Solution
+
+To convert from rectangular to polar coordinates, I need to use the formulas $r = \sqrt{x^2 + y^2}$ and $\theta = \tan^{-1}(y/x).$
+
+In this case, $x = 0$ and $y = 3,$ so I can plug them into the formulas.
+
+For $r,$ I get $r = \sqrt{0^2 + 3^2} = \sqrt{9} = 3.$
+
+For $\theta,$ I get $\theta = \tan^{-1}(3/0).$
+
+This is undefined, since the tangent function is not defined at $0.$
+
+However, I can use the fact that the point $(0,3)$ lies on the positive $y$-axis, which has an angle of $\pi/2$ radians or $90^\circ.$
+
+Therefore, I can choose any angle in the range $(0,\pi/2)$ as the value of $\theta.$
+
+I will choose $\theta = \pi/2,$ since it is the simplest and most natural choice.
+
+Therefore, the polar coordinates of the point $(0,3)$ are $(3,\pi/2).$
+
+# Answer
+
+(3,\pi/2)
+```