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README.md
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The area of the circle is $\boxed{\frac{27\pi}{4}}$ square cm.
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</pre>
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??? It should have been `9*pi/4`. Am I using this model wrong? Same result with temperature=0.0,top_k=1.
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# imatrix
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The area of the circle is $\boxed{\frac{27\pi}{4}}$ square cm.
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</pre>
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??? It should have been `9*pi/4`. Am I using this model wrong? Same result with temperature=0.0,top_k=1.
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In comparison, the Q6_K of the non-interpreter variant of this model with temp=0.0 outputs:
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```
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The area of a circle is given by the formula A = πr^2, where r is the radius of the circle. Since the width of the circle is 3cm, the radius is half of that, or 1.5cm. Substituting this value into the formula, we get:
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A = π(1.5)^2
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A = π(2.25)
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A = 6.9887654321
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So, the area of the circle is approximately 6.99 cm^2.
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```
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(close to the expected 7.06 which `deepseek-math-7b-rl.Q8_0.gguf` outputs)
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# imatrix
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