Charged particles in a uniform magnetic field will undergo circular motion with a period of T = 2\(\pi\)m/(qB). The magnetic field of the Earth is roughly 10\({}^{-4}\) tesla, assuming it is uniform. Given the mass of a proton to be 1.6 x 10\({}^{-27}\) kilograms and its electric charge to be 1.6 x 10\({}^{-19}\) coulombs, providing your answer in scientific notation to one significant figure, what period in seconds would you measure for a proton?
6 x 10\({}^{-4}\)