Given that \(f(x)=\frac{2x}{x-1}\)If of x equals the fraction with numerator 2x and denominator x minus 1] is a one-to-one function, find \(x\) so that \(f^{\mbox{-1}}(x)=5\)[f inverse of x equals 5].
5/2 (ACCEPT: 2.5 OR 2 1/2)