Given the numerical coefficients a, b and c, calculates the roots for any quadratic equation of the form ax2  bx  c  quadraticrootsa1, b3, c4 1.0, 4.0  quadraticroots5, 6, 1 0.2, 1.0  quadraticroots1, 6, 25 34j, 34j
from __future__ import annotations

from cmath import sqrt


def quadratic_roots(a: int, b: int, c: int) -> tuple[complex, complex]:
    """
    Given the numerical coefficients a, b and c,
    calculates the roots for any quadratic equation of the form ax^2 + bx + c

    >>> quadratic_roots(a=1, b=3, c=-4)
    (1.0, -4.0)
    >>> quadratic_roots(5, 6, 1)
    (-0.2, -1.0)
    >>> quadratic_roots(1, -6, 25)
    ((3+4j), (3-4j))
    """

    if a == 0:
        raise ValueError("Coefficient 'a' must not be zero.")
    delta = b * b - 4 * a * c

    root_1 = (-b + sqrt(delta)) / (2 * a)
    root_2 = (-b - sqrt(delta)) / (2 * a)

    return (
        root_1.real if not root_1.imag else root_1,
        root_2.real if not root_2.imag else root_2,
    )


def main():
    solution1, solution2 = quadratic_roots(a=5, b=6, c=1)
    print(f"The solutions are: {solution1} and {solution2}")


if __name__ == "__main__":
    main()
