Convert a Decimal Number to an Octal Number. import math Modified from: https:github.comTheAlgorithmsJavascriptblobmasterConversionsDecimalToOctal.js def decimaltooctalnum: int  str: octal  0 counter  0 while num  0: remainder  num  8 octal  octal  remainder  math.floormath.pow10, counter counter  1 num  math.floornum  8   basically  8 without remainder if any This formatting removes trailing '.0' from octal. return f0ointoctal def main  None:
import math

# Modified from:
# https://github.com/TheAlgorithms/Javascript/blob/master/Conversions/DecimalToOctal.js


def decimal_to_octal(num: int) -> str:
    """Convert a Decimal Number to an Octal Number.

    >>> all(decimal_to_octal(i) == oct(i) for i
    ...     in (0, 2, 8, 64, 65, 216, 255, 256, 512))
    True
    """
    octal = 0
    counter = 0
    while num > 0:
        remainder = num % 8
        octal = octal + (remainder * math.floor(math.pow(10, counter)))
        counter += 1
        num = math.floor(num / 8)  # basically /= 8 without remainder if any
        # This formatting removes trailing '.0' from `octal`.
    return f"0o{int(octal)}"


def main() -> None:
    """Print octal equivalents of decimal numbers."""
    print("\n2 in octal is:")
    print(decimal_to_octal(2))  # = 2
    print("\n8 in octal is:")
    print(decimal_to_octal(8))  # = 10
    print("\n65 in octal is:")
    print(decimal_to_octal(65))  # = 101
    print("\n216 in octal is:")
    print(decimal_to_octal(216))  # = 330
    print("\n512 in octal is:")
    print(decimal_to_octal(512))  # = 1000
    print("\n")


if __name__ == "__main__":
    main()
