Author: Abhijeeth S Reduces large number to a more manageable number  res5, 7 4.892790030352132  res0, 5 0  res3, 0 1  res1, 5 Traceback most recent call last: ... ValueError: math domain error We use the relation xy  ylog10x, where 10 is the base. Read two numbers from input and typecast them to int using map function. Here x is the base and y is the power. We find the log of each number, using the function res, which takes two arguments. We check for the largest number
# Author: Abhijeeth S

import math


def res(x, y):
    """
    Reduces large number to a more manageable number
    >>> res(5, 7)
    4.892790030352132
    >>> res(0, 5)
    0
    >>> res(3, 0)
    1
    >>> res(-1, 5)
    Traceback (most recent call last):
    ...
    ValueError: math domain error
    """
    if 0 not in (x, y):
        # We use the relation x^y = y*log10(x), where 10 is the base.
        return y * math.log10(x)
    else:
        if x == 0:  # 0 raised to any number is 0
            return 0
        elif y == 0:
            return 1  # any number raised to 0 is 1
    raise AssertionError("This should never happen")


if __name__ == "__main__":  # Main function
    # Read two numbers from input and typecast them to int using map function.
    # Here x is the base and y is the power.
    prompt = "Enter the base and the power separated by a comma: "
    x1, y1 = map(int, input(prompt).split(","))
    x2, y2 = map(int, input(prompt).split(","))

    # We find the log of each number, using the function res(), which takes two
    # arguments.
    res1 = res(x1, y1)
    res2 = res(x2, y2)

    # We check for the largest number
    if res1 > res2:
        print("Largest number is", x1, "^", y1)
    elif res2 > res1:
        print("Largest number is", x2, "^", y2)
    else:
        print("Both are equal")
