原文地址:单因素方差分析示例1作者:木牙水 下表是6种溶液及对照组的雌激素活度鉴定,指标是小鼠子宫重.对表中的数据做方差分析,若差异是显著的,则需做多重比较. 鼠 号 溶 液 种 类 ⅰ(ck) ⅱ ⅲ ⅳ ⅴ ⅵ ⅶ 1 89.9 84.4 64.4 75.2 88.4 56.4 65.6 2 93.8 116.0 79.8 62.4 90.2 83.2 79.4 3 88.4 84.0 88.0 62.4 73.2 90.4 65.6 4 112.6 68.6 69.4 73.8 87.8 85.6 70.2 答:所用程序及结果如下: options linesize=76 nodate; data ter s; infile e:dataexr8-2e.dat ; do sol tion=1 to 7; do repetit=1 to 4; inp t weight @@; o tp t; end; end; r n; proc anova; class sol tion; model weight=sol tion; means sol tiond ncan; r n; the sas system analysis of variance proced re class level information class levels val es solution 7 1 2 3 4 5 6 7 n mber of observations in data set = 28 the sas system analysis of variance proced re dependent variable: weight s m of mean so rce df sq ares sq are f val e pr  f model 6 2419. 403. 2.77 0.0385 error 21 3061. 145. corrected total 27 5480. r-sq are c.v. root mse weight mean 0. 15.03118 12.0738 80.3250 so rce df anova ss mean sq are f val e pr  f solution 6 2419. 403. 2.77 0.0385 the sas system analysis of variance proced re d ncan s m ltiple range test for variable: weight note: this test controls the type i comparisonwise error rate, not the experimentwise error rate alpha= 0.05 df= 21 mse= 145.7765 n mber of means 2 3 4 5 6 7 critical range 17.75 18.64 19.20 19.60 19.89 20.12 means with the same letter are not significantly different. d ncan gro ping mean n solution a 96.175 4 1 a b a 88.250 4 2 b a b a 84.900 4 5 b a b a 78.900 4 6 b b 75.400 4 3 b b 70.200 4 7 b b 68.450 4 4 溶液种类的显著性概率p=0.038 5,p 0.05,不同种类的溶液影响显著.其中1,2,5,6间差异不显著;2,5,6,3,7,4间差异不显著.