text: two unbiased dices are thrown once and the total score is seen. probability? a) that the total score is even or greater than 7  b) the total score is divisible by 3 and greater than 7 the possible scores that are greater than 7 are 8, 9, 10, 11, and 12. you could get an 8 by rolling (4,4), (2,6), (6,2), (3,5), or (5,3), so there are 5 ways. you can get a 9 by rolling (4,5), (5,4), (3,6), or (6,3), so there are 4 ways. for 10: (5,5), (4,6), (6,4): 3 ways for 11: (5,6) or (6,5): 2 ways for 12: (6,6): 1 way now we need to count all the even numbers less than seven; these are 2, 4, and 6. 2: (1,1): 1 way 4: (1,3), (3,1), (2,2): 3 ways 6: (3,3) (1,5), (5,1), (2,4), (4,2): 5 ways  add these all together to get 5 + 4 + 3 + 2 + 1 + 1 + 3 + 5= 24 the total number of possibilities is 6*6 = 36 because there are 6 possible choices for each dice. the answer to part a is 24/36 = 2/3 = .666666666...  part b the scores greater than 7 and divisible by 3 are 9 and 12. the number of ways to roll a score of 9 is 4 and the number of ways to roll a score of 12 is 1. thus, the answer is 5/36 = .138888888...