text: help with a calculus problem? let f(x)=2sin(x)+3(x^x) then f'(3)=  what i got was 2cos3 + 3(3^3)(1+log3) but its wrong to differentiate x^x:  set y = x^x  then ln y = ln x^x = x ln x. => y' / y = ln x + x(1/x) = ln x + 1, so y' = x^x(ln x + 1).  therefore f'(x) = 2 cos(x) + 3(x^x)(ln x + 1), so f'(3) = 2cos 3 + 3(3^3)(ln 3 + 1).  to evaluate this, make sure your calculator is in radians, not degrees.