text: need help fast? a fisherman caught 385 fish in a 14 day tournament. each day he caught 3 more fish than he did the day before. how many fish did he catch each individual day? let's denote the number of fish he caught on day 1 as x.  thus, here are the totals for each day:  day 1 = x day 2 = x+3 day 3 = x+6 day 4 = x+9 day 5 = x+12 day 6 = x+15 day 7 = x+18 day 8 = x+21 day 9 = x+24 day 10 = x+27 day 11 = x+30 day 12 = x+33 day 13 = x+36 day 14 = x+39  adding these together will get you the total fish = 385.  solving, you get:  14x + 273 = 385  solving, you get x = 8  thus, these are the totals he caught each day:  day 1 = 8 day 2 = 11 day 3 = 14 day 4 = 17 day 5 = 20 day 6 = 23 day 7 = 26 day 8 = 29 day 9 = 32 day 10 = 35 day 11 = 38 day 12 = 41 day 13 = 44 day 14 = 47  ---------------  hope this helps