text: log(x+1)=log3-log(2x-1)? can someone explain to me how to solve this you can combine the right side terms using the  property log(a/b) = log a - log b in reverse.  it is log(3/(2x-1))  so now you have log(x+1) = log(3/(2x-1)  since the logs are equal, so must be the things you took the log of. so x+1 = 3/(2x-1)  cross multiply: (x+1)(2x-1) = 3   2x^2 + x - 1 = 3  2x^2 + x - 4 = 0  solve for x.  check that when you plug it in, you don't end up with the log of a negative number.