text: what is the free energy change (kj/mol) for the dissolution of cds at 25.00°c if it has a ksp of 8.000x10-28?   the free energy change:  change(g') = - rt in k              = -(8.314j/k)(298k)in 8*10^-28                     = 154583j                       =  155 kj  the molar solubility is the of moles of solute in 1 liter of a saturated solution(mol/l):   ksp =(cd2+)(s2-)= 8*10^-28  = x^2=8*10^-28   x=  2.8*10^-14m  m=mol/l   solve for mol:   mol= m*l      = 2.8*10^-14mol/l*l       = 2.8*10^-14mol   so the  free dissolution  energy is:  2.8*10^-14mol cds(155kj / 1mol cds) =4.34*10-12kj