text: do you like physics? can anyone please solve this and show how you got it? 10 points to best explination.    a car travels at constant speed around a flat unbanked turn (r = 50.0 m).  the coefficients of static friction for dry and icy weather are 0.900 and 0.100, respectively.  find the max speeds for each condition (dry and icy).     answer: 21.0 m/s, 7.00 m/s sum of forces = m a a is centripetal = v^2/r force of friction = forcenormal times coeffiecint of friction forcenormal times coeffiecint of friction  = mv^2/r mg(coeffecient of friction) = mv^2/r masses cancel out. gr(coeffecient of friction) = v^2 v = sqrt[(coeffecient of friction)(gr)] just plug in for the coeffecient of friction.