text: substitution rule help? the problem is intergral symbol shown 2x(squared)(1-4x(cubed)raised to the 3/2 and afterwards dx            2x(sq.)(1-4x(cube) raised 3/2 dx  i hope this way it is a little clearer. the sq. squared and raised means to that power thanks. let u = 1-4x^3 then du = -12x^2 dx  you have to add a -1/6 outside the integral and a -6 inside so that you end up with a -12x inside.  substitution gives you  =(-1/6) int {u^3/2 du} =(-1/6)(2/5)u^(5/2) =(-1/15)u^(5/2)  and substituting back in for u gives you =(-1/15)(1-4x^3)^(5/2) + c   <---add the constant for indefinite integrals