text: how would you solve this problum? sin(squard)x divided by cos(squard)=sec(squard)x-1. this is trig identities and i do not understand them at all. can you please help me? go back to your trig function definitions.  suppose you have a right triangle with sides of length a and b, and hypotenuse of length c.  let x be the angle between side b and hypotenuse c.  then, using the symbol ^ to denote an exponent,  sin (x) = a/c cos (x) = b/c sec (x) = 1/cos (x) = c/b  the squares are:  sin^2 (x) = a^2 / c^2 cos^2 (x) = b^2 / c^2 sec^2 (x)  =  c^2 / b^2  plugging these definitions into your problem,  (a^2 / c^2)  /  (b^2 / c^2)  =  (c^2 / b^2) - 1  simplifying,  a^2 / b^2  =  c^2 / b^2  -  1  multiplying by b^2,  a^2  =  c^2  -  b^2  rearranging terms,  a^2  +  b^2  =  c^2  which may be recognized as the pythagorean theorem.