text: the boundry line graphed for the  linear inequality. determine the correct half-plane to be shaded and? complete the graph by shading it.  y > 3 draw a dotted line through coordinates (0,3) and (1,3).  this represents the equation y = 3.   since the inequality is strictly greater than, the line should be dashed (or dotted).  if it were >= then it would be a solid line.  now you test each half plane for a true value.  you need a point that is not contained on the line.  how about the origin (that is always the easiest point as long as it is not on the line itself).  if we plug the point (0,0) into the inequality you get the statement 0 > 3.  is this a true statement?  no.  therefore, you shade the half plane that does not contain the origin. if it were true, you would shade the half plane that contains the origin.  hope this helps!