text: how do i solve for x,y and z? sorry again for posting so many math questions, but this one might even stump some of you.  x+2y+z=2 5x=z y=-2x  yeah seriously, though maybe it's not as hard as i'm making it out to be x+2y+z=2 ....1 5x=z .....2 y=-2x ......3  from 2, you get the value of x in z x = z/5 ..4  substitute 4 into 3 and you get the value of y in z y = -2 (z/5)= -2z/5 ..5  substitute 4 & 5 into 1  z/5+2(-2z/5)+z=2 z/5-4z/5+z=2 -3z/5+5z/5=2 2z/5=2 2z=10 z=5  substitute the value of z to 2 5x=5 x=1  substitute this to 3 y=-2.1=-2  x=1 y=-2 z=5