text: i need help with solving a log equation.? i know how to solve other log equations, such as logx=3, but this problem has a smaller number between the log and x. i don't know how to type it in a calculator or on the computer so i hope i'm explaining this right. it looks similar to log^2(3)=x but the 2 is at the bottom of the log so it's not squaring it. i think the proper terminology is "log base of 2" but i could be wrong.  anyway, the problem i need help solving is log(little 2)(1/16) = x. i don't really need the answer, just an explaination of how to solve this type of problem. sorry if this is confusing and doesn't make any sense! all you have to remember is that log (base a) of b = c means exactly the same thing as a^c = b. thus, if you take a standard log of that equation, you get log(a^c) = log b, so c log a = log b, so c = log b / log a.  thus, that gives you the precise way of working out such a log - take one of the normal logs of the number, then divide by the same log of the base.