text: conditional problem? http://img64.imageshack.us/my.php?image=problem5fz.jpg  whats  the  answer ?  i took 1,4,2,3,5,6  as the value of a,b,c,d,x,y  but this did not produce the correct result.  how do i solve ? how do i choose which adheres the above condition ? ax + by > cx + dy move the x's to the left side by subtracting cx from each side, and move the y's to the right side by subtracting by from each side ax - cx > dy - by factor x from the left side and y from the right side x(a-c) > y(d-b) now multiply each side by -1 (remember that the inequality sign flips when you multiply each side by a negative number) x(a-c)(-1)< y(d-b)(-1) distribute the negative one through each side x(-a+c)< y(-d+b) now since x<y, then  -a+c < -d+b now rearrange the above equation so that it looks like one of your choices. add a to each side and add d to each side. c+d  c+d so your answer is choice (3).