text: stability question? x   /-----------/|f                    |____|____|____| a........b......c.......d  a = -100 n       b = -200 n       c = -100 n       d = -300 n  sorry if the diagram is a bit confusing!  the diagram also indicates that the distance from a to b, b to c and c to d are all 2 meters; the force, f is either pointing up or down.  i'm a bit confused about this stability problem. how do i find the force, f and the distance, x when f is not exactly at a specific point like b or c? sure the f value should be 100+200+100+300=700n to find the point of affect, let's suppose the distance of point from a be x, then from the torques equilibrium at x: 100*x+200*(x-2)+100*(x-4)+ 300*(x-6)=0    so    700x-2600=0 x=26/7 almost 3.71 means 'x point' resides somewhere between b & c, much closer to c.