text: can anyone please help with this probability question? sixteen men are demolishing an old factory when part of it collapsed, injuring three of them. out of the sixteen men three were apprentices.  what is the probability that all three injured men were apprentices?  i have the answer but can't work out the calculations required.  hope someone can help. thanks the answer requires you to make an assumption about the relative probability of an apprentice compared to a non-apprentice getting injured.  if the chances are equal and independent, then the answer is simply 1/binomial(3,16) = 3!x13!/16!= 1/(7x5x16)  if the probability of an apprentice being in the wrong place at the wrong time is higher than a non-apprentice, then one can assume that the probability is somewhere between 1/560 and 1.