text: solve by substitution 2x-y=3    x+2y=24?   2x-y=3   x+2y=24  1) first, solve the second equation for x by subtracting y from both sides  x+2y=24 -2y      -2y  so, x=24-2y  2) next, substitute the result of step 1 by applying it to the first equation, just replace x in 2x-y=3 with 24-2y  2(24-2y)-y=3   3)distribute the 2 that is in front of the parentheses  48-4y-y=3  4) combine like terms  48-5y=3  5) subtract 48 from both sides  you will have:  -5y=-45   6) divide each side by -5 you will have y=9  7)substitute 9 for y in each equation  2x-9=3  =>  add 9 to both sides => 2x=12 =>  divide both sides by 2, you will have x=6   x + 2(9) =24  which is x + 18 = 24  subtract 18 from each side, and you will have x=6