text: a 3 digit number my tens digit is 5 more than my ones digitmy hundreds digit is eight less than my tens find? i am a let h = hundreds digit t = tens digit u = units digit  we know that t = u + 5 (since the tens digit is 5 more than the ones digit) h = t - 8 (since the hundreds digit is 8 less than the tens digit)  let us take a look at the second equation: h = t - 8  since h and t are digits of a number, then we know that h and t are single digits.  now, h and t cannot be negative, so the only possible value for t is 9 or 8 (since 10 is no longer a digit and any value less than 8 will make h negative).  thus, if t = 9, h = 9 - 8 = 1, and if t = 8, h = 8 - 8 = 0.  but since we know that h is the hundreds digit, h cannot be equal to zero. therefore, h = 1.  and also t = 9.  now, using the first equation,  t = u + 5  we can solve for u u = t - 5  since t = 9, then u = 9 - 5  therefore, u = 4  now, we know the values u = 4, t = 9, and h = 1.   therefore, the 3-digit number is  194.  ^_^