text: whatcha know about projectile motion? can you answer this one? a ball rolls off a tabletop with an inital velocity of 3 m/s, if the tabletop is 1.25m above the floor, a. how long does it take for the ball to hit the floor? b. how far does the ball travel horizontally?  please show your work....  good luck. that's easy the key to projectile motion is resolving motion horizontally and vertically(or downwards).the vertical motion is accelerated motion,acceleration being g while horizontal motion is not accelerated and is at constant speed. suppose at time t=0 the ball leaves the table. vh(0)=3m/s          horizontal velocity vd(0)=0m/s          downwards velocity now time taken to hit floor is same as  time taken by downwards velocity component to cover 1.25 m use s=ut+1/2 gt^2      here u=vd(0) 1.25=0+0.5*9.8*t^2 t=sqrt(1.25/(.5*9.8)) t= 0.50507 sec to calculate how far it travels just multiply this time by vh(0)   3*.50507=1.515m