text: solve for x and y, where x = 4, y = 7   3(x³    +  2x²   -  3xy  +   y²   -    5y  +  1  is the answer 128?   3(4^3+2*4^2-3*4*7+7^2-5*7+1)  do exponents first  4^3=64 4^2=16 7^2=49  now put back into the equation 3(64+2*16-3*4*7+49-35+1)  now do multiplication  2*16=32 3*4=12 12*7=84 5*7=35  so now you have 3(64+32-84+49-35+1)  now read left to right  64+32=96 96-84=12 12+49=61 61-35=26 26+1=27  3*27=81  but i could be wrong because you didn't close parentheses "()" but assuming they closed them that's what a got...it was simple because you just plug in the values for x and y  and then solve using order of operations  check ya later ♥