text: anybody who's an expert on stoichiometry and percentage-mol conversion? given info on a bottle of hydrochloric acid: fuming acid 37%, relative molecular mass = 36.45 g/mol, and density = 1.19kg/l. how do i convert any of these data to molarity (g/l) ? i tried using 37% as 37ml/100ml, and got the answer as 10 m, but someone stated i was wrong as volume per volume cannot be applied to percentage? molarity is defined as the number of moles of solute per liter of solution:   molarity = number of moles of solute / number of liters of solution   mass of solute = d*v*% of acid  d = density     d = m/ v :  m =mass = 1.19kg(1000g/1kg) = 1190g  v= volume = 1 liter = 1000cm^3     so, d= 1190g / 1000cm^3 = 1.19cm^3   % of acid =  .37  mass of solute =   440.3 g of  acid    fuming or hcl acid moles =  solute mass / molecular mass   = 440.3g / 36.45g/mol =  12.1 moles      molarity= m  = 12.1 moles / 1 l =  12.1 m