text: trig question!!!? find the exact value of sin(2arcsin3/5) w/o using a calculator use the trig identity sin2a = 2sinacosa, and the fact that cos(arcsinx) = √(1-x²) to answer this.  sin(2arcsin3/5) =  2sin(arcsin3/5)(cos(arcsin3/5) =   2 * 3/5 * √(1-(3/5)² =   2 * 3/5 * √(16/25) =   2 * 3/5 * 4/5 = 24/25  hope that helped!