text: a ball thrown up 5 ft with the initial velocity of 35ft/sec.  what is the hight of the ball after 2 seconds? what is the function h(t) relating the time and the height of the ball? is it supposed to say it is thrown from an initial height of 5 feet?  the path of the ball will be in the form of a parabola y=ax^2 + bx + c where  a = 1/2 the force of gravity (gravity is -32 feet/second^2, so -16 feet/second^2) x = time, so in this case 2 b = the velocity c = the initial starting height  so just plug in your numbers and solve  = -16*(2^2) + 35*2 + 5 = -64 + 70 + 5 = 11 feet  oh, and the function would be h(t) = -16t^2 + 35t + 5