text: if an astronaut took a skydive...? 20,000 feet above the moon's surface, an astronaut decided to take a skydive . at what speed would he land? the gravitational pull on the moons surface is quite low in comparison to the earth. that is while the earths gravitational pull is 9.8m/s 10newtons the moon is 0.1666667 meters per second if you compare a man who weights 100 kg on earth will weigh about 1.7007142857142857142857142857143 kgs using the 9.8m/s gravitational rule see that is very small. also lets concider that there is no fluid resistance(resistance caused by the air molecues while moving downwards to the earths surface.) then say that the astronaut dives from 20,000 feet from the sky(let see it on both senarios "earth,moon")also    20000feet= 6096meters accelerations  earth=9.8m/s moon=1.633366m/s  the speed will increase from 0m&#92;s due to the increase in speed module =a=(v-u)/t  to find time you can use s=1/2at^2 acceleration on moon=1.633366m/s v=at+u v=final velocity u=initial velocity=0; t=sqrt(s/1/2a) t=sqrt(6096/1/2*9.8)"on earth"=35.271seconds t=sqrt(6096/1/2*1.633366)"on the moon"=86.396seconds final acceleration on earth is 35.271*9.8+0=345.6558m&#92;s on the earths surface while on the moon! gravitational acceleration on the moon is 1.633366 meters per second=about 0.167n initial velocity =0; final velocity =? time taken=sqrt(6096/1/2*1.633366)= 86.396seconds  final speed=acceleration*time+initial speed  141.11696=m&#92;s on the moons surface  now into feet 1meter =3.280 839 895 feet 141.116 96 meter = 462.982 152 231 feet&#92;second