text: 2y^2-4y-8=-y^2+y? equations not in standard form, solve. good evening,  first reorganize so they are in standard form.  2y^2 -4y - 8 +y^2 - y = 0 3y^2 - 5y - 8 = 0 (3y- 8)(y + 1) = 0 so 3y-8 = 0 and y+1 = 0 y = 8/3, y = -1  y = {-1, 8/3}  ~i~