text: consider the balanced equation for the combustion of propane, c3h8? c3h8(g) + 5o2(g) → 3co2(g) + 4h2o(l)  if propane reacts with oxygen as above   a. what is the limiting reagent in a mixture containing 5.00 g of c3h8 and 10.0 g of o2?  b. what mass of co2 is formed when 1.00 g of c3h8 reacts completely? (a)  5.00 g of c3h8 / 44.1 g/mol = 0.113 moles  0.113 * 5 = 0.565 moles  10.0 g of o2 / 32.0 g/mol = 0.3125 moles, giving oxygen as limiting reagent.  (b)  1.00 g /44.1 g/mol = 0.0227 moles burned to give  3 * 0.0227 moles = 0.0681 moles of co2 formed  0.0681 moles * 44.01 g/mole = 3.00 grams of co2