text: pl explain step by step and in linear equation with single variable form , the following problems,? 1)a number is divided into 2 parts such that one is 10 more than the other. if the 2 parts are in the ratio 5:3, find the number.   2)if 1/2 is substracted from a number and the difference is multiplied by 4 the result is 5, find the number.   3)jane and jean start walking from the same place in opposite directions. if jane walks at a speed of 2 and 1/2 km per hourand jean at 2 km /per hour, in how much time will they be 18 km apart? 1)a number is divided into 2 parts such that one is 10 more than the other. if the 2 parts are in the ratio 5:3, find the number.  let the smaller part be n. therefore the other part is n + 10 (n + 10)/n = 5/3 multiply by n n + 10 = 5n/3 multiply by 3 3(n + 10) = 5n therefore 3n + 30 = 5n take 3n from both sides 30 = 2n  so n = 15 and n + 10 = 25  so the original number was 15 + 25 = 40  2)if 1/2 is substracted from a number and the difference is multiplied by 4 the result is 5, find the number. let the number be n thus the difference = n - 1/2 4(n - 1/2) = 5 so 4n - 2 = 5 add 5 to both sides 4n = 7 n = 7/4 = 1 3/4  3)jane and jean start walking from the same place in opposite directions. if jane walks at a speed of 2 and 1/2 km per hourand jean at 2 km /per hour, in how much time will they be 18 km apart?  let them walk for t hours in this time jane walks 2 1/2 t km ie 5t/2 km and jean walks 2t km so they are (2t + 5t/2) km apart  so 2t + 5t/2 = 18 multiply everything by 2 4t + 5t = 36 ie 9t = 36 so t = 4 ie it takes 4 hours for them to be 18 km apart