text: pendulums and acceleration due to gravity? a pendulum has a period of .600 sec at the equator.  the pendulum is moved to another place on earth and the period is now .598 sec.  find the acceleration due to gravity at this location.  ok, i know the equation for the period, but to find g, you also need to know the length, which isn't given.  therefore, how am i supposed to find g?  thanks! from above person.  t = 2*pi*(sqr rt. of l/g)  so apply it twice and get two equations with two unknowns. the unknowns being l and g. assuming that g is 9.80 at the equator.  at the equator:  0.600 = 2 * pi * (sqrt (l/9.80))  you can actually just solve that for l.  at the other location  0.598 = 2 * pi * (sqrt (l/g)) using the l from above.