text: write the equation in slope-intercept form.through (-5,2);perpendicular to -5x-2y=27? college algebra slope of -5x-2y=27 is -5/2 slope of perpendicular line=2/5 passes through(-5,2) the equation y-2=(2/5)(x+5) 5y-10=2x+10 2x-5y-20=0 in the slope interceptform -5y=-2x+20 5y=2x-20 y=(2/5)x-4