text: algebra toughy...need help? natalie has some nickels, dirk has some dimes, and quincy has some quarters. dirk has five more dimes than quincy has quarters. if natalie gives dirk a nickel, dirk gives quincy a dime, and quincy gives natalie a quarter, they will all have the same amount of money. how many coins did each have originally?   show work and use only one variable let q = the number of quarters quincy has.  they are worth 25q cents.  dirk has (q+5) dimes worth 10(q+5) cents = 10q + 50 cents  when natalie gives dirk a nickel he now has 10q + 55 cents, but he then gives a dime to quincy leaving dirk with 10q + 45 cents and quincy with 25q + 10 cents.  finally quincy gives away a quarter leaving him with 25q - 15 cents, which equals dirk's money or 10q + 45  25q - 15 = 10q + 45  subtract 10q from both sides: 15q - 15 = 45  you can finish from here i am sure.