Iyini i-Tau Circle Constant?
I-tau ichazwa ngokuthi isilinganiso sobubanzi besiyingi nesiyingi saso. Ezinye izazi zezibalo nezazi zezomzimba zekhulu lama-21 zikholelwa ukuthi i-Tau iyindlela engcono kakhulu yokusebenzisa i-Pi kwezesayensi nakwezibalo.  Njengo-Pi, i-Tau iyinombolo engenangqondo futhi engaphezulu. Ngefomu le-decimals, inani le-tau lingu-6.283185...  Ingxenye yesisusa sikaTawu iwukubona ukuthi inombolo ethi 2*Pi noma 2π ivela ngokuphindaphindiwe kuyo yonke isayensi nezibalo. Lokhu kuphakamisa umbuzo wokuthi ingabe u-Pi ngempela uyinombolo ebalulekile noma into elingana no-Pi ephindwe kabili ibaluleke ngempela. Mhlawumbe lokhu kusho ukuthi uPi uyingxenye eyodwa kuphela yenani elithile elibaluleke kakhulu!  Ukuhlolisisa lo mbuzo ngokwengeziwe kuholela ekuphawuleni okuningana okuphoqayo:  - Ukusebenzisa u-C/r njengento ebalulekile eqhubekayo yomjikelezo kuqondaniswe kangcono nendlela esichaza ngayo umjikelezo: isethi yawo wonke amaphuzu anebanga eliqondile (r) akha iphuzu elinikeziwe. - Izilinganiso ze-angle ye-radian yezingxenye zesangqa zinengqondo kakhulu lapho i-Tau isetshenziswa njengengqikithi eyisisekelo. Ukusebenzisa u-pi, ingxenye yesine yesangqa ingu-pi, ingxenye yesine ingu-pi, kanti i-angle yesangqa esiphelele ingu-2*pi. Nge-Tau, izilinganiso ze-angle zihambisana ngokuzenzakalelayo nengxenyana yesangqa: ingxenye yesine yesangqa yi-Tau/4, isigamu sesangqa yi-Tau/2 kanti i-angle yesangqa esigcwele yi-Tau. - Ngokufanayo, ama-radian zeroes, max, kanye nemin of the sin and cosine functions alinganise ama-fractions of Tau ngendlela enembile esiza, kunokuba idide, ukuqonda. - Amafomula ayisihluthulelo ngokuvamile asebenzisa uPi empeleni abonisa incazelo enembile kakhudlwana yezibalo uma eboniswa esebenzisa uTau. Ngokwesibonelo, indawo yesiyingi ngokwayo, lapho iboniswa nge-Tau, ibonisa iphethini efanayo yezinhlobo zesikwele ebangeni eliwile, amandla entwasahlobo, namandla we-kinetic. - Ngokufanayo, ifomula esekelwe ku-tau yendawo eyisiyingi empeleni iqinisekisa ubufakazi bokuqala buka-Archimedes obukhombisa ukuthi indawo yesiyingi ilingana nendawo yonxantathu onesisekelo C (isiyingi) nokuphakama r (radius): A = 1/2 b*h = 1/2 C*r = 1/2 (Tau*r) *r = 1/2 Tau*r^2.   I-tau iye yamukelwa kakhulu kusukela yaqala ukuhlongozwa.  Ubuhlobo obuphakathi kukaTau noPi bulula kakhulu. I-tau = 2*Pi. Mhlawumbe okufundisa ngendlela efanayo iqiniso lokuthi uTau > Pi.