<p>Given a string <code>date</code> representing a <a href="https://en.wikipedia.org/wiki/Gregorian_calendar" target="_blank">Gregorian calendar</a> date formatted as <code>YYYY-MM-DD</code>, return <em>the day number of the year</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-01-09&quot;
<strong>Output:</strong> 9
<strong>Explanation:</strong> Given date is the 9th day of the year in 2019.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-02-10&quot;
<strong>Output:</strong> 41
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>date.length == 10</code></li>
	<li><code>date[4] == date[7] == &#39;-&#39;</code>, and all other <code>date[i]</code>&#39;s are digits</li>
	<li><code>date</code> represents a calendar date between Jan 1<sup>st</sup>, 1900 and Dec 31<sup>th</sup>, 2019.</li>
</ul>

class Solution {
public:
    int dayOfYear(string date) {
        string fir=date.substr(5,2);
        string sec=date.substr(8,2);
        string tir=date.substr(0,4);
        int fir1=stoi(fir);
        int sec1=stoi(sec);
        int tir1=stoi(tir);
        int ans=0;
            for (int i = 1; i < fir1; i++) {
    if (i == 1 || i == 3 || i == 5 || i == 7 || i == 8 || i == 10 || i == 12) {
        ans += 31;  // Months with 31 days
    } 
    else if (i == 2) {
        if (tir1 % 400 == 0 || (tir1 % 100 != 0 && tir1 % 4 == 0)) {
            ans += 29;  // February in a leap year
        } else {
            ans += 28;  // February in a non-leap year
        }
    } 
    else {
        ans += 30;  // Months with 30 days
    }
}

        
        return abs(ans+sec1);
    }
};
12000