<p>Given two arrays of integers with equal lengths, return the maximum value of:</p>

<p><code>|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|</code></p>

<p>where the maximum is taken over all <code>0 &lt;= i, j &lt; arr1.length</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,2,3,4], arr2 = [-1,4,5,6]
<strong>Output:</strong> 13
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]
<strong>Output:</strong> 20
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= arr1.length == arr2.length &lt;= 40000</code></li>
	<li><code>-10^6 &lt;= arr1[i], arr2[i] &lt;= 10^6</code></li>
</ul>

class Solution {
    priority_queue<int, std::vector<int>, std::greater<int>> pq1;
    priority_queue<int,  std::vector<int>,std::greater<int>> pq2;
    priority_queue<int,  std::vector<int>,std::greater<int>> pq3;
    priority_queue<int,  std::vector<int>,std::greater<int>> pq4;

public:
    int maxAbsValExpr(vector<int>& arr1, vector<int>& arr2) {
        pq1.push(arr1[0] + arr2[0]);
        pq2.push(arr1[0] - arr2[0]);
        pq3.push(-arr1[0] + arr2[0]);
        pq4.push(-arr1[0] - arr2[0]);
        int ans = -1;
        for (int i = 1; i < arr1.size(); i++) {

            ans = max(ans, (arr1[i] + arr2[i] + i) - pq1.top());
            ans = max(ans, (arr1[i] -arr2[i] + i) - pq2.top());
            ans = max(ans, (-arr1[i] + arr2[i] + i) - pq3.top());
            ans = max(ans, (-arr1[i] - arr2[i] + i) - pq4.top());

            pq1.push((arr1[i] + arr2[i] + i));
            pq2.push((arr1[i] -arr2[i] + i));
            pq3.push((-arr1[i] + arr2[i] + i));
            pq4.push((-arr1[i] - arr2[i] + i));
        }
        return ans;
    }
};




// (arr1[i] + arr2[i] + i) - (arr1[j] + arr2[j] + j)

// (arr1[i] - arr2[i] + i) - (arr1[j] - arr2[j] + j)

// (-arr1[i] + arr2[i] + i) - (-arr1[j] + arr2[j] + j)

// (-arr1[i] - arr2[i] + i) - (-arr1[j] - arr2[j] + j)
32000