<p>Given an <code>m x n</code> matrix of <strong>distinct </strong>numbers, return <em>all <strong>lucky numbers</strong> in the matrix in <strong>any </strong>order</em>.</p>

<p>A <strong>lucky number</strong> is an element of the matrix such that it is the minimum element in its row and maximum in its column.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> matrix = [[3,7,8],[9,11,13],[15,16,17]]
<strong>Output:</strong> [15]
<strong>Explanation:</strong> 15 is the only lucky number since it is the minimum in its row and the maximum in its column.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> matrix = [[1,10,4,2],[9,3,8,7],[15,16,17,12]]
<strong>Output:</strong> [12]
<strong>Explanation:</strong> 12 is the only lucky number since it is the minimum in its row and the maximum in its column.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> matrix = [[7,8],[1,2]]
<strong>Output:</strong> [7]
<strong>Explanation:</strong> 7 is the only lucky number since it is the minimum in its row and the maximum in its column.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == mat.length</code></li>
	<li><code>n == mat[i].length</code></li>
	<li><code>1 &lt;= n, m &lt;= 50</code></li>
	<li><code>1 &lt;= matrix[i][j] &lt;= 10<sup>5</sup></code>.</li>
	<li>All elements in the matrix are distinct.</li>
</ul>

class Solution {
public:
    vector<int> luckyNumbers (vector<vector<int>>& matrix) {
        vector<int>ans;
        for(int i=0;i<matrix.size();i++)
        {
            int mn=INT_MAX;
            int ind=-1;
            for(int j=0;j<matrix[i].size();j++)
            {
                if(mn>=matrix[i][j]){
                    mn=matrix[i][j];
                    ind=j;
                }
            }
            // cout<<ind<<" ";
            int flag=1;
            for(int k=0;k<matrix.size();k++)
            {
                if(i!=k && matrix[i][ind]<matrix[k][ind])
                {
                    // cout<<matrix[k][ind];
                    flag=0;
                    break;
                }
            }
            if(flag)
            {
                ans.push_back(matrix[i][ind]);
            }
        }

        return ans;
    }
};
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