<p>Given a string <code>s</code>, check if it can be constructed by taking a substring of it and appending multiple copies of the substring together.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abab&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> It is the substring &quot;ab&quot; twice.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;aba&quot;
<strong>Output:</strong> false
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abcabcabcabc&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> It is the substring &quot;abc&quot; four times or the substring &quot;abcabc&quot; twice.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 10<sup>4</sup></code></li>
	<li><code>s</code> consists of lowercase English letters.</li>
</ul>

// Ali Eren Ciftci
class Solution {
public:
    bool repeatedSubstringPattern(string s) {
        if(s.length() < 2)
            return false;
        string temp = s;
        for(int i = 1; i <= s.length() / 2; i++) // i substring size ini tutsun
        {
            if(s.length() % i) // i substring olmaya aday degilse gec
                continue;
            temp = temp.substr(i) + temp.substr(0, i); // ilk i elemani sona at
            if(s == temp) // esitse bu ilk i eleman true olur
                return true;
            temp = s; // tempi geri eski haline getir.   
        }
        return false;
    }
    
    
};
77861