<p>Given a string <code>s</code>, return <em>the length of the longest substring between two equal characters, excluding the two characters.</em> If there is no such substring return <code>-1</code>.</p>

<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;aa&quot;
<strong>Output:</strong> 0
<strong>Explanation:</strong> The optimal substring here is an empty substring between the two <code>&#39;a&#39;s</code>.</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abca&quot;
<strong>Output:</strong> 2
<strong>Explanation:</strong> The optimal substring here is &quot;bc&quot;.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;cbzxy&quot;
<strong>Output:</strong> -1
<strong>Explanation:</strong> There are no characters that appear twice in s.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 300</code></li>
	<li><code>s</code> contains only lowercase English letters.</li>
</ul>


class Solution {
public:
    int maxLengthBetweenEqualCharacters(string s) {
        int v[26];
        memset(v, -1, sizeof v);
        int ans = -1;
        for (int i = 0; i < s.size(); i++) {
            if (v[s[i] - 'a'] == -1) {
                v[s[i] - 'a'] = i;
            } else {
                ans = max(ans, i - v[s[i] - 'a'] - 1);
            }
        }
        return ans;
    }
};

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