<p>Given a string <code>date</code> representing a <a href="https://en.wikipedia.org/wiki/Gregorian_calendar" target="_blank">Gregorian calendar</a> date formatted as <code>YYYY-MM-DD</code>, return <em>the day number of the year</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-01-09&quot;
<strong>Output:</strong> 9
<strong>Explanation:</strong> Given date is the 9th day of the year in 2019.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-02-10&quot;
<strong>Output:</strong> 41
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>date.length == 10</code></li>
	<li><code>date[4] == date[7] == &#39;-&#39;</code>, and all other <code>date[i]</code>&#39;s are digits</li>
	<li><code>date</code> represents a calendar date between Jan 1<sup>st</sup>, 1900 and Dec 31<sup>th</sup>, 2019.</li>
</ul>

class Solution {
public:
    int dayOfYear(string date) 
    {
        int year = stoi(date.substr(0, 4));
        int month = stoi(date.substr(5, 2));
        int day = stoi(date.substr(8, 2));
        int feb, res=0;

        if((year % 4 == 0) && ((year % 100 != 0) || (year % 400 == 0)))
            feb = 29;
        else feb = 28;

        switch(month)
        {
            case 2: res+=31; break;
            case 3: res+=31+feb; break;
            case 4: res+=62+feb; break;
            case 5: res+=92+feb; break;
            case 6: res+=123+feb; break;
            case 7: res+=153+feb; break;
            case 8: res+=184+feb; break;
            case 9: res+=215+feb; break;
            case 10: res+=245+feb; break;
            case 11: res+=276+feb; break;
            case 12: res+=306+feb; break;
        }
        res+=day;
        return res;
    }
};
12000