<p>You are given an integer <code>n</code> and an array of <strong>unique</strong> integers <code>blacklist</code>. Design an algorithm to pick a random integer in the range <code>[0, n - 1]</code> that is <strong>not</strong> in <code>blacklist</code>. Any integer that is in the mentioned range and not in <code>blacklist</code> should be <strong>equally likely</strong> to be returned.</p>

<p>Optimize your algorithm such that it minimizes the number of calls to the <strong>built-in</strong> random function of your language.</p>

<p>Implement the <code>Solution</code> class:</p>

<ul>
	<li><code>Solution(int n, int[] blacklist)</code> Initializes the object with the integer <code>n</code> and the blacklisted integers <code>blacklist</code>.</li>
	<li><code>int pick()</code> Returns a random integer in the range <code>[0, n - 1]</code> and not in <code>blacklist</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input</strong>
[&quot;Solution&quot;, &quot;pick&quot;, &quot;pick&quot;, &quot;pick&quot;, &quot;pick&quot;, &quot;pick&quot;, &quot;pick&quot;, &quot;pick&quot;]
[[7, [2, 3, 5]], [], [], [], [], [], [], []]
<strong>Output</strong>
[null, 0, 4, 1, 6, 1, 0, 4]

<strong>Explanation</strong>
Solution solution = new Solution(7, [2, 3, 5]);
solution.pick(); // return 0, any integer from [0,1,4,6] should be ok. Note that for every call of pick,
                 // 0, 1, 4, and 6 must be equally likely to be returned (i.e., with probability 1/4).
solution.pick(); // return 4
solution.pick(); // return 1
solution.pick(); // return 6
solution.pick(); // return 1
solution.pick(); // return 0
solution.pick(); // return 4
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 10<sup>9</sup></code></li>
	<li><code>0 &lt;= blacklist.length &lt;= min(10<sup>5</sup>, n - 1)</code></li>
	<li><code>0 &lt;= blacklist[i] &lt; n</code></li>
	<li>All the values of <code>blacklist</code> are <strong>unique</strong>.</li>
	<li>At most <code>2 * 10<sup>4</sup></code> calls will be made to <code>pick</code>.</li>
</ul>

#define random(l,r,T)    uniform_int_distribution<T>(l,r)(rng)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
class Solution {
public:
    map<int, int> blocked;
    int n, m;
    Solution(int _n, vector<int>& blacklist) {
        for(auto x: blacklist) {
            blocked[x] = -1;
        }
        n = _n;
        m = blacklist.size();
        sort(blacklist.begin(), blacklist.end());
        int r = n - 1;
        for(auto x: blacklist) {
            if(x < n - m) {
                while(blocked[r] == -1) {
                    r--;
                }
                blocked[x] = r;
                r--;
            }
            else {
                break;
            }
        }
    }
    
    int pick() {
        int r = random(0, n - m - 1, int);
        if(blocked.find(r) == blocked.end()) {
            return r;
        }
        else {
            return blocked[r];
        }
    }
};

/**
 * Your Solution object will be instantiated and called as such:
 * Solution* obj = new Solution(n, blacklist);
 * int param_1 = obj->pick();
 */
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