<p>Given an integer <code>n</code>, return <em>a list of all <strong>simplified</strong> fractions between </em><code>0</code><em> and </em><code>1</code><em> (exclusive) such that the denominator is less-than-or-equal-to </em><code>n</code>. You can return the answer in <strong>any order</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 2
<strong>Output:</strong> [&quot;1/2&quot;]
<strong>Explanation:</strong> &quot;1/2&quot; is the only unique fraction with a denominator less-than-or-equal-to 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 3
<strong>Output:</strong> [&quot;1/2&quot;,&quot;1/3&quot;,&quot;2/3&quot;]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> n = 4
<strong>Output:</strong> [&quot;1/2&quot;,&quot;1/3&quot;,&quot;1/4&quot;,&quot;2/3&quot;,&quot;3/4&quot;]
<strong>Explanation:</strong> &quot;2/4&quot; is not a simplified fraction because it can be simplified to &quot;1/2&quot;.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 100</code></li>
</ul>

class Solution {
public:
    vector<string> simplifiedFractions(int n) {
        int a[101][101] = {0};
        for (int i = 2; i <= n; i++)
            for (int j = 1; j < i; j++)
                a[j / __gcd(i, j)][i / __gcd(i, j)] = 1;

        vector<string> ans;
        for (int i = 1; i < 101; i++)
            for (int j = 1; j < 101; j++)
                if (a[i][j]) {
                    string x = "";
                    x += to_string(i);
                    x += '/';
                    x += to_string(j);
                    ans.push_back(x);
                }
        return ans;
    }
};
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