<p>Given an array of integers <code>temperatures</code> represents the daily temperatures, return <em>an array</em> <code>answer</code> <em>such that</em> <code>answer[i]</code> <em>is the number of days you have to wait after the</em> <code>i<sup>th</sup></code> <em>day to get a warmer temperature</em>. If there is no future day for which this is possible, keep <code>answer[i] == 0</code> instead.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> temperatures = [73,74,75,71,69,72,76,73]
<strong>Output:</strong> [1,1,4,2,1,1,0,0]
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> temperatures = [30,40,50,60]
<strong>Output:</strong> [1,1,1,0]
</pre><p><strong class="example">Example 3:</strong></p>
<pre><strong>Input:</strong> temperatures = [30,60,90]
<strong>Output:</strong> [1,1,0]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;=&nbsp;temperatures.length &lt;= 10<sup>5</sup></code></li>
	<li><code>30 &lt;=&nbsp;temperatures[i] &lt;= 100</code></li>
</ul>

class Solution {
public:
    vector<int> dailyTemperatures(vector<int>& temperatures) 
{
    vector<int> d;
    int pos =0;
    for(int i=0; i<temperatures.size(); i++)
        d.push_back(0);
    d[temperatures.size()-1] = 0;
    for(int i=int(temperatures.size()-2); i>=0; i--)
    {
            if(temperatures[i+1] > temperatures[i]) d[i] = 1;
            else
            {
                bool flag=false;
                pos = i + d[i+1] + 1;
                while(temperatures[i] >= temperatures[pos])
                {
                    if(pos+1 == temperatures.size())
                    {
                        flag = true;
                        break;
                    }
                    pos++;
                }
                if(flag == true) d[i] = 0;
                else d[i] = pos-i;
            }
    }
    return d;
}
};
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