<p>Given a string <code>s</code> containing only three types of characters: <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code> and <code>&#39;*&#39;</code>, return <code>true</code> <em>if</em> <code>s</code> <em>is <strong>valid</strong></em>.</p>

<p>The following rules define a <strong>valid</strong> string:</p>

<ul>
	<li>Any left parenthesis <code>&#39;(&#39;</code> must have a corresponding right parenthesis <code>&#39;)&#39;</code>.</li>
	<li>Any right parenthesis <code>&#39;)&#39;</code> must have a corresponding left parenthesis <code>&#39;(&#39;</code>.</li>
	<li>Left parenthesis <code>&#39;(&#39;</code> must go before the corresponding right parenthesis <code>&#39;)&#39;</code>.</li>
	<li><code>&#39;*&#39;</code> could be treated as a single right parenthesis <code>&#39;)&#39;</code> or a single left parenthesis <code>&#39;(&#39;</code> or an empty string <code>&quot;&quot;</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> s = "()"
<strong>Output:</strong> true
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> s = "(*)"
<strong>Output:</strong> true
</pre><p><strong class="example">Example 3:</strong></p>
<pre><strong>Input:</strong> s = "(*))"
<strong>Output:</strong> true
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 100</code></li>
	<li><code>s[i]</code> is <code>&#39;(&#39;</code>, <code>&#39;)&#39;</code> or <code>&#39;*&#39;</code>.</li>
</ul>

class Solution {
public:
    int dp[101][101];
    bool helper(string s, int idx, int balance){
        if(idx==s.size()) return balance==0;
        if(dp[idx][balance]!=-1) return dp[idx][balance];
        if(s[idx]=='(') return dp[idx][balance] = helper(s,idx+1,balance+1);
        else if(s[idx]==')'){
            if(balance<=0) return false;
            return dp[idx][balance] = helper(s,idx+1,balance-1);
        }
        else{
            if(balance>0) return dp[idx][balance] =  helper(s,idx+1,balance-1) || helper(s,idx+1,balance) || helper(s,idx+1,balance+1);
            else return dp[idx][balance] =  helper(s,idx+1,balance) || helper(s,idx+1,balance+1);
        } 
    }
    bool checkValidString(string s) {
        int n = s.size();
        for(int i = 0; i<=n; i++){
            for(int j = 0; j<=n; j++) dp[i][j] = -1;
        }
        return helper(s,0,0);
    }
};
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