<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution {
public:
    string convert(string s, int intRows) {
        int n=s.length();
        if(intRows==1)
        return s;
        int cols=0;
        while(n>0){
            n=n-intRows;
            cols++;
            if(n>0){
                n=n-(intRows-2);
                cols+=(intRows-2);
            }
        }
        n=s.length();
        int col=0;
        char** arr = new char*[intRows];  
for (int i = 0; i < intRows; i++) {
    arr[i] = new char[cols];  
}
for(int i=0;i<intRows;i++)
            for(int j=0;j<cols;j++)
            arr[i][j]=' ';
int k=0;
                while(k<n){
                    for(int i=0;i<intRows&& k<n;i++){
                    arr[i][col]=s[k++];
                }
                col++;
                for(int i=intRows-2;i>0&&k<n;i--){
                    arr[i][col++]=s[k++];
                }
            }
            string ans="";
            for(int i=0;i<intRows;i++)
            for(int j=0;j<cols;j++)
            if(arr[i][j]!=' ')
            ans+=arr[i][j];
    return ans;
    }
};
31981