<p>You are given an array of points in the <strong>X-Y</strong> plane <code>points</code> where <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code>.</p>

<p>Return <em>the minimum area of a rectangle formed from these points, with sides parallel to the X and Y axes</em>. If there is not any such rectangle, return <code>0</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/08/03/rec1.JPG" style="width: 500px; height: 447px;" />
<pre>
<strong>Input:</strong> points = [[1,1],[1,3],[3,1],[3,3],[2,2]]
<strong>Output:</strong> 4
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/08/03/rec2.JPG" style="width: 500px; height: 477px;" />
<pre>
<strong>Input:</strong> points = [[1,1],[1,3],[3,1],[3,3],[4,1],[4,3]]
<strong>Output:</strong> 2
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= points.length &lt;= 500</code></li>
	<li><code>points[i].length == 2</code></li>
	<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub> &lt;= 4 * 10<sup>4</sup></code></li>
	<li>All the given points are <strong>unique</strong>.</li>
</ul>

class Solution {
public:
    int minAreaRect(vector<vector<int>>& points) {
        map<pair<int, int>, vector<int>> mYYToX;
        sort(points.begin(), points.end());
        int n = points.size();
        for (int i = 0; i < n; ++i) {
            for (int j = i + 1; j < n; ++j) {
                if (points[i][0] == points[j][0]) { // x are equal
                    mYYToX[{points[i][1], points[j][1]}].push_back(points[i][0]);
                } else {
                    break;
                }
            }
        }
        int minRect = INT_MAX;
        for (auto& [yy, vecX]: mYYToX) {
            if (vecX.size() > 1) {
                sort(vecX.begin(), vecX.end());
                int dy = yy.second - yy.first;
                for (int i = 0; i < vecX.size() - 1; ++i) {
                    int dx = vecX[i + 1] - vecX[i];
                    minRect = min(dx * dy, minRect);
                }
            }
        }
        return minRect == INT_MAX ? 0 : minRect;
    }
};
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