<p>Given a string array <code>words</code>, return <em>an array of all characters that show up in all strings within the </em><code>words</code><em> (including duplicates)</em>. You may return the answer in <strong>any order</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> words = ["bella","label","roller"]
<strong>Output:</strong> ["e","l","l"]
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> words = ["cool","lock","cook"]
<strong>Output:</strong> ["c","o"]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= words.length &lt;= 100</code></li>
	<li><code>1 &lt;= words[i].length &lt;= 100</code></li>
	<li><code>words[i]</code> consists of lowercase English letters.</li>
</ul>

class Solution {
 public:
  vector<string> commonChars(vector<string>& words) {
    vector<string> ans;
    vector<int> commonCount(45, INT_MAX);

    for (const string& word : words) {
      vector<int> count(45);
      for (const char c : word)
        ++count[c - 'a'];
      for (int i = 0; i < 45; ++i)
        commonCount[i] = min(commonCount[i], count[i]);
    }

    for (char c = 'a'; c <= 'z'; ++c)
      for (int i = 0; i < commonCount[c - 'a']; ++i)
        ans.push_back(string(1, c));

    return ans;
  }
};
12100