<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution {
public:
    string convert(string s, int numRows) {
        if (numRows == 1 || numRows >= s.size()) {
            return s;
        }
        
        vector<vector<char>> pattern(numRows, vector<char>(s.size(), '\0'));
        int temp = 0;
        int j = 0;

        for (int i = 0; i < s.size(); ) {
           
            while (j < numRows && temp < s.size()) {
                pattern[j][i] = s[temp++];
                ++j;
            }
            
            j = numRows - 2;
            i++;
            
           
            while (j > 0 && temp < s.size()) {
                pattern[j][i++] = s[temp++];
                --j;
            }
            
        }

      
        string result;
        for (int row = 0; row < numRows; ++row) {
            for (int col = 0; col < s.size(); ++col) {
                if (pattern[row][col] != '\0') {
                    result += pattern[row][col];
                }
            }
        }

        return result;
    }
};

42293