<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution {
public:
    string convert(string s, int numRows) {
        if(numRows==1) return(s);
        int n=s.size();
        string ans="";
        map<int,string> mp;
        for (int i = 0; i < numRows; ++i) {
          mp[i] ="";
        }
        bool flag=true;
        int t=0;
        for(int i=0;i<n;i++)
        {
            if(flag)
            {
                //cout<<type(mp[t])<<endl;
              mp[t]=mp[t]+string(1, s[i]);
              t++;
              if(t>numRows-1) {
                flag=false;
                t=t-2;
                if(t<0) t=0;
              }
            }
            else{
                mp[t]=mp[t]+string(1, s[i]);
                t--;
                if(t==0)
                {
                    flag=true;
                }
                else if(t<0)
                {
                    t=1;
                    flag=true;
                }

            }
            //cout<<t<<"$"<<endl;
        }
        for (auto i : mp)
        {
            ans=ans+i.second;
            cout << i.first << " \t\t\t " << i.second << endl;
        }
        //cout << i.first << " \t\t\t " << i.second << endl;
        return(ans);

        
    }
};
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