<p>The <strong>count-and-say</strong> sequence is a sequence of digit strings defined by the recursive formula:</p>

<ul>
	<li><code>countAndSay(1) = &quot;1&quot;</code></li>
	<li><code>countAndSay(n)</code> is the run-length encoding of <code>countAndSay(n - 1)</code>.</li>
</ul>

<p><a href="http://en.wikipedia.org/wiki/Run-length_encoding" target="_blank">Run-length encoding</a> (RLE) is a string compression method that works by replacing consecutive identical characters (repeated 2 or more times) with the concatenation of the character and the number marking the count of the characters (length of the run). For example, to compress the string <code>&quot;3322251&quot;</code> we replace <code>&quot;33&quot;</code> with <code>&quot;23&quot;</code>, replace <code>&quot;222&quot;</code> with <code>&quot;32&quot;</code>, replace <code>&quot;5&quot;</code> with <code>&quot;15&quot;</code> and replace <code>&quot;1&quot;</code> with <code>&quot;11&quot;</code>. Thus the compressed string becomes <code>&quot;23321511&quot;</code>.</p>

<p>Given a positive integer <code>n</code>, return <em>the </em><code>n<sup>th</sup></code><em> element of the <strong>count-and-say</strong> sequence</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">n = 4</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;1211&quot;</span></p>

<p><strong>Explanation:</strong></p>

<pre>
countAndSay(1) = &quot;1&quot;
countAndSay(2) = RLE of &quot;1&quot; = &quot;11&quot;
countAndSay(3) = RLE of &quot;11&quot; = &quot;21&quot;
countAndSay(4) = RLE of &quot;21&quot; = &quot;1211&quot;
</pre>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">n = 1</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;1&quot;</span></p>

<p><strong>Explanation:</strong></p>

<p>This is the base case.</p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 30</code></li>
</ul>

<p>&nbsp;</p>
<strong>Follow up:</strong> Could you solve it iteratively?
class Solution {
public:
    string countAndSay(int N) 
    {
        if (N == 1) return "1";
        if (N == 2) return "11";

        std::string str = "11";

        for (int i = 3; i <= N; i++)
        {
	        str = str + '$';
	        std::string temp;
	        int count = 1;

	        for (int j = 1; j < str.size(); j++)
	        {
		        if (str[j] != str[j - 1])
		        {
			        temp = temp + (char)(count + '0');
			        temp = temp + str[j - 1];
			        count = 1;
		        }
		        else
		        {
			        count++;
		        }
	        }
	
	        str = temp;
        }
        return str;
    }
};
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