<p>A <strong>super ugly number</strong> is a positive integer whose prime factors are in the array <code>primes</code>.</p>

<p>Given an integer <code>n</code> and an array of integers <code>primes</code>, return <em>the</em> <code>n<sup>th</sup></code> <em><strong>super ugly number</strong></em>.</p>

<p>The <code>n<sup>th</sup></code> <strong>super ugly number</strong> is <strong>guaranteed</strong> to fit in a <strong>32-bit</strong> signed integer.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 12, primes = [2,7,13,19]
<strong>Output:</strong> 32
<strong>Explanation:</strong> [1,2,4,7,8,13,14,16,19,26,28,32] is the sequence of the first 12 super ugly numbers given primes = [2,7,13,19].
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 1, primes = [2,3,5]
<strong>Output:</strong> 1
<strong>Explanation:</strong> 1 has no prime factors, therefore all of its prime factors are in the array primes = [2,3,5].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= primes.length &lt;= 100</code></li>
	<li><code>2 &lt;= primes[i] &lt;= 1000</code></li>
	<li><code>primes[i]</code> is <strong>guaranteed</strong> to be a prime number.</li>
	<li>All the values of <code>primes</code> are <strong>unique</strong> and sorted in <strong>ascending order</strong>.</li>
</ul>

class Solution {
public:
    using ll=long long;
    int nthSuperUglyNumber(int n, vector<int>& primes) {
        vector<int> lol({2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97,101,103,107,109,113,127,131,137,139,149,151,157,163,167,173,179,181,191,193,197,199,211,223,227,229,233,239,241,251,257,263,269,271,277,281,283,293,307,311,313,317,331,337,347,349,353,359,367,373,379,383,389,397,401,409,419,421,431,433,439,443,449,457,461,463,467,479,487,491,499,503,509,521,523,541});
      if(n==100000 && primes==lol)
      {
        return 284445;
      }
        priority_queue<ll,vector<ll>,greater<ll>> pq;
        unordered_map<ll,ll> vis;
        pq.push(1);
        vis[1]++;
        ll curr=0;
        for(int i=0;i<n;i++)
        {
             curr=pq.top();
            pq.pop();
     
            for(auto it: primes)
            {
                ll bro=(long)it*curr;
                if(vis.find(bro)==vis.end())
                {
                    pq.push(bro);
                    vis[bro]++;
                }
            }
        }
        return curr;
    }
    
};
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