<p>Given two strings <code>s</code> and <code>goal</code>, return <code>true</code><em> if you can swap two letters in </em><code>s</code><em> so the result is equal to </em><code>goal</code><em>, otherwise, return </em><code>false</code><em>.</em></p>

<p>Swapping letters is defined as taking two indices <code>i</code> and <code>j</code> (0-indexed) such that <code>i != j</code> and swapping the characters at <code>s[i]</code> and <code>s[j]</code>.</p>

<ul>
	<li>For example, swapping at indices <code>0</code> and <code>2</code> in <code>&quot;abcd&quot;</code> results in <code>&quot;cbad&quot;</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;ab&quot;, goal = &quot;ba&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> You can swap s[0] = &#39;a&#39; and s[1] = &#39;b&#39; to get &quot;ba&quot;, which is equal to goal.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;ab&quot;, goal = &quot;ab&quot;
<strong>Output:</strong> false
<strong>Explanation:</strong> The only letters you can swap are s[0] = &#39;a&#39; and s[1] = &#39;b&#39;, which results in &quot;ba&quot; != goal.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;aa&quot;, goal = &quot;aa&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> You can swap s[0] = &#39;a&#39; and s[1] = &#39;a&#39; to get &quot;aa&quot;, which is equal to goal.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>s</code> and <code>goal</code> consist of lowercase letters.</li>
</ul>

class Solution 
{
    int n1,n2;
    int buddy(string s, string goal)
    {
        n1 = s.size();
        n2 = goal.size();
        set<char>st(s.begin(), s.end());

        if(s == goal)
        {
            if(st.size() == n1)
                return false;
            else // <n
                return true;
        }

        int i=0;
        while(i<n1 && s[i] == goal[i]) 
            i++;

        int j=n1-1;
        while(j>=0 && s[j] == goal[j])
            j--;
        
        swap(s[i], s[j]);
        
        return s == goal;
    }
public:
    bool buddyStrings(string s, string goal) 
    {
        n1=s.size();
        n2=goal.size();
        
        if(n1 != n2 || n1==1)
            return false;
        
        return buddy(s, goal);
    }
};
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