<p>We have two special characters:</p>

<ul>
	<li>The first character can be represented by one bit <code>0</code>.</li>
	<li>The second character can be represented by two bits (<code>10</code> or <code>11</code>).</li>
</ul>

<p>Given a binary array <code>bits</code> that ends with <code>0</code>, return <code>true</code> if the last character must be a one-bit character.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> bits = [1,0,0]
<strong>Output:</strong> true
<strong>Explanation:</strong> The only way to decode it is two-bit character and one-bit character.
So the last character is one-bit character.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> bits = [1,1,1,0]
<strong>Output:</strong> false
<strong>Explanation:</strong> The only way to decode it is two-bit character and two-bit character.
So the last character is not one-bit character.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= bits.length &lt;= 1000</code></li>
	<li><code>bits[i]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>

class Solution {
public:
    bool isOneBitCharacter(vector<int>& bits) {
        bool single = true;
        for (int i = 0; i < bits.size(); ++i) {
            if (bits[i] == 0) {
                single = true;
            } else {
                single = false;
                ++i;
            }
        }
        return single;
    }
};
12300