<p>Given a string <code>date</code> representing a <a href="https://en.wikipedia.org/wiki/Gregorian_calendar" target="_blank">Gregorian calendar</a> date formatted as <code>YYYY-MM-DD</code>, return <em>the day number of the year</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-01-09&quot;
<strong>Output:</strong> 9
<strong>Explanation:</strong> Given date is the 9th day of the year in 2019.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-02-10&quot;
<strong>Output:</strong> 41
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>date.length == 10</code></li>
	<li><code>date[4] == date[7] == &#39;-&#39;</code>, and all other <code>date[i]</code>&#39;s are digits</li>
	<li><code>date</code> represents a calendar date between Jan 1<sup>st</sup>, 1900 and Dec 31<sup>th</sup>, 2019.</li>
</ul>

class Solution {
public:
    int dayOfYear(string date) {
        vector<int> t = getTokens(date);
        int months[] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
        int year = t[0];
        bool isleap = (year%4 == 0 && year%100 != 0) || (year%400 == 0);
        int days = 0;
        for(int i = 0; i < t[1]; i++){
            days += months[i];
        }

        days += t[2];

        if(isleap && t[1] > 2) days++;
        
        return days;
    }

    vector<int> getTokens(string date){
        stringstream ss(date);
        string token;
        vector<int> tokens;
        while(getline(ss,token,'-')){
            if(!token.empty())
                tokens.push_back(stoi(token));
        }
        return tokens;
    }
};
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