<p>Alice has some number of cards and she wants to rearrange the cards into groups so that each group is of size <code>groupSize</code>, and consists of <code>groupSize</code> consecutive cards.</p>

<p>Given an integer array <code>hand</code> where <code>hand[i]</code> is the value written on the <code>i<sup>th</sup></code> card and an integer <code>groupSize</code>, return <code>true</code> if she can rearrange the cards, or <code>false</code> otherwise.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> hand = [1,2,3,6,2,3,4,7,8], groupSize = 3
<strong>Output:</strong> true
<strong>Explanation:</strong> Alice&#39;s hand can be rearranged as [1,2,3],[2,3,4],[6,7,8]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> hand = [1,2,3,4,5], groupSize = 4
<strong>Output:</strong> false
<strong>Explanation:</strong> Alice&#39;s hand can not be rearranged into groups of 4.

</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= hand.length &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= hand[i] &lt;= 10<sup>9</sup></code></li>
	<li><code>1 &lt;= groupSize &lt;= hand.length</code></li>
</ul>

<p>&nbsp;</p>
<p><strong>Note:</strong> This question is the same as 1296: <a href="https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/" target="_blank">https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/</a></p>

class Solution {
public:
    bool isNStraightHand(vector<int>& hand, int groupSize) {

        if(hand.size()%groupSize!=0){
            return false;
        }
        priority_queue<int, vector<int> , greater<int>> pq;
        for(int i=0;i<hand.size();i++){
            pq.push(hand[i]);
        }
        vector<int> duplicates;
        int prev=-1;
        int count=0;
        while(!pq.empty()){
            if(groupSize==count){
                for(int i=0;i<duplicates.size();i++){
                    pq.push(duplicates[i]);
                }
                count=0;
                duplicates.clear();
                prev=-1;
            }
            int curr=pq.top();
             pq.pop();
            if(prev==curr){
                duplicates.push_back(curr);
            }
            else if(prev==-1 || prev+1==curr){
                count+=1;
                prev=curr;
            }
            else{
                return false;
            }
        }
        if(duplicates.size()==0){
            return true;
        }
        return false;

        
    }
};
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