<p>Your task is to calculate <code>a<sup>b</sup></code> mod <code>1337</code> where <code>a</code> is a positive integer and <code>b</code> is an extremely large positive integer given in the form of an array.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> a = 2, b = [3]
<strong>Output:</strong> 8
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> a = 2, b = [1,0]
<strong>Output:</strong> 1024
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> a = 1, b = [4,3,3,8,5,2]
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= a &lt;= 2<sup>31</sup> - 1</code></li>
	<li><code>1 &lt;= b.length &lt;= 2000</code></li>
	<li><code>0 &lt;= b[i] &lt;= 9</code></li>
	<li><code>b</code> does not contain leading zeros.</li>
</ul>

class Solution {
public:
    const int M=1337;
    int binExp(int a,long long b,int M)
    {
        int ans=1;
        while(b)
        {
            if(b&1)
            ans=(ans*1LL*a)%M;
            a=(a*1LL*a)%M;
            b>>=1;
        }
        return ans;
    }
    int binMulti(int a,int b,int M)
    {
        int ans=0;
        while(b)
        {
            if(b&1)
            ans=(ans+a)%M;
            a=(a+a)%M;
            b>>=1;
        }
        return ans;
    }
    int superPow(int a, vector<int>& b) {
        int n=b.size();
        long long num=0,ct=0;
        for(int i=n-1;i>=0;--i)
        {
            long long x=binMulti(b[i],binExp(10,ct,1140),1140);
            num+=x;
            ct++;
        }
        return binExp(a,num,1337);
    }
};
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