<p>Given a string <code>date</code> representing a <a href="https://en.wikipedia.org/wiki/Gregorian_calendar" target="_blank">Gregorian calendar</a> date formatted as <code>YYYY-MM-DD</code>, return <em>the day number of the year</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-01-09&quot;
<strong>Output:</strong> 9
<strong>Explanation:</strong> Given date is the 9th day of the year in 2019.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-02-10&quot;
<strong>Output:</strong> 41
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>date.length == 10</code></li>
	<li><code>date[4] == date[7] == &#39;-&#39;</code>, and all other <code>date[i]</code>&#39;s are digits</li>
	<li><code>date</code> represents a calendar date between Jan 1<sup>st</sup>, 1900 and Dec 31<sup>th</sup>, 2019.</li>
</ul>

class Solution {
public:
    int dayOfYear(string date) {
        istringstream ss(date);
        string year,month,dat;
        getline(ss,year,'-');
        getline(ss,month,'-');
        getline(ss,dat);
        int y=stoi(year);
        int m=stoi(month);
        int d=stoi(dat);
        vector<int> nly={0,31,28,31,30,31,30,31,31,30,31,30,31};
        vector<int> ly={0,31,29,31,30,31,30,31,31,30,31,30,31};
        if(y%4==0){
            string x=to_string(y);
            int res=0;
            for(int i=0;i<m;i++){
                res=res+ly[i];
            }
            int z=y%100;
            if(z==0){
                int p=y/100;
                if(p%4!=0){
                    return res+d-1; 
                }
            }
            return res+d;
        }
        else{
            int res=0;
            for(int i=0;i<m;i++){
                res=res+nly[i];
            }
            return res+d;
        }

    }
};
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