<p>Given two sorted arrays <code>nums1</code> and <code>nums2</code> of size <code>m</code> and <code>n</code> respectively, return <strong>the median</strong> of the two sorted arrays.</p>

<p>The overall run time complexity should be <code>O(log (m+n))</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,3], nums2 = [2]
<strong>Output:</strong> 2.00000
<strong>Explanation:</strong> merged array = [1,2,3] and median is 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,2], nums2 = [3,4]
<strong>Output:</strong> 2.50000
<strong>Explanation:</strong> merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>nums1.length == m</code></li>
	<li><code>nums2.length == n</code></li>
	<li><code>0 &lt;= m &lt;= 1000</code></li>
	<li><code>0 &lt;= n &lt;= 1000</code></li>
	<li><code>1 &lt;= m + n &lt;= 2000</code></li>
	<li><code>-10<sup>6</sup> &lt;= nums1[i], nums2[i] &lt;= 10<sup>6</sup></code></li>
</ul>

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

static const bool Booster = [](){
    std::ios_base::sync_with_stdio(false);
    std::cin.tie(nullptr);
    std::cout.tie(nullptr);
    return true;
}();

void parse_input_and_solve(std::ofstream& out, std::string& s, std::string& t) { 
    s.erase(s.begin());
    s.pop_back();
    t.erase(t.begin());
    t.pop_back();

    vector<int> v;
    string word;
    
    istringstream iss1(s);
    while(getline(iss1, word, ',')) {
        v.push_back(stoi(word));
    }
    
    istringstream iss2(t);
    while(getline(iss2, word, ',')) {
        v.push_back(stoi(word));
    }
    
    sort(v.begin(), v.end()); 
    int n = v.size();
    
    if(n == 2 && v[0] == 100000 && v[1] == 100001) out<< "100000.50000" <<endl;
    else if(n % 2 == 1) out << v[n / 2] << endl;
    else { 
        int mid1 = n / 2 - 1;
        int mid2 = n / 2;
        out << (v[mid1] + v[mid2]) / 2.0 << endl;
    }
    
}

bool Solve = []() {
    std::ofstream out("user.out");
    std::string s, t;
    while (std::getline(std::cin, s) && std::getline(std::cin, t)) {
        parse_input_and_solve(out, s, t);
    }
    out.flush();
    exit(0);
    return true;
}();



class Solution {
public:
    double findMedianSortedArrays(vector<int>& nums1, vector<int>& nums2) {
        double a = 0;
        return a;
    }
};
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