<p>Given the <code>head</code> of a singly linked list and an integer <code>k</code>, split the linked list into <code>k</code> consecutive linked list parts.</p>

<p>The length of each part should be as equal as possible: no two parts should have a size differing by more than one. This may lead to some parts being null.</p>

<p>The parts should be in the order of occurrence in the input list, and parts occurring earlier should always have a size greater than or equal to parts occurring later.</p>

<p>Return <em>an array of the </em><code>k</code><em> parts</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/06/13/split1-lc.jpg" style="width: 400px; height: 134px;" />
<pre>
<strong>Input:</strong> head = [1,2,3], k = 5
<strong>Output:</strong> [[1],[2],[3],[],[]]
<strong>Explanation:</strong>
The first element output[0] has output[0].val = 1, output[0].next = null.
The last element output[4] is null, but its string representation as a ListNode is [].
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/06/13/split2-lc.jpg" style="width: 600px; height: 60px;" />
<pre>
<strong>Input:</strong> head = [1,2,3,4,5,6,7,8,9,10], k = 3
<strong>Output:</strong> [[1,2,3,4],[5,6,7],[8,9,10]]
<strong>Explanation:</strong>
The input has been split into consecutive parts with size difference at most 1, and earlier parts are a larger size than the later parts.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in the list is in the range <code>[0, 1000]</code>.</li>
	<li><code>0 &lt;= Node.val &lt;= 1000</code></li>
	<li><code>1 &lt;= k &lt;= 50</code></li>
</ul>

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
 public:
  vector<ListNode*> splitListToParts(ListNode* root, int k) {
    vector<ListNode*> ans(k);
    const int length = getLength(root);
    const int subLength = length / k;
    int remainder = length % k;

    ListNode* prev = nullptr;
    ListNode* head = root;

    for (int i = 0; i < k; ++i, --remainder) {
      ans[i] = head;
      for (int j = 0; j < subLength + (remainder > 0); ++j) {
        prev = head;
        head = head->next;
      }
      if (prev != nullptr)
        prev->next = nullptr;
    }

    return ans;
  }

 private:
  int getLength(ListNode* root) {
    int length = 0;
    for (ListNode* curr = root; curr; curr = curr->next)
      ++length;
    return length;
  }
};
13900