<p>Given an integer array <code>nums</code> of <strong>unique</strong> elements, return <em>all possible</em> <span data-keyword="subset"><em>subsets</em></span> <em>(the power set)</em>.</p>

<p>The solution set <strong>must not</strong> contain duplicate subsets. Return the solution in <strong>any order</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3]
<strong>Output:</strong> [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [0]
<strong>Output:</strong> [[],[0]]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10</code></li>
	<li><code>-10 &lt;= nums[i] &lt;= 10</code></li>
	<li>All the numbers of&nbsp;<code>nums</code> are <strong>unique</strong>.</li>
</ul>

class Solution {
public:
void func(vector<vector<int>> &ans,vector<int> & temp,vector<int>& nums,int k,int n)
{
    if(k==n)
    {
        ans.push_back(temp);
        return;
    }
    
   func(ans,temp,nums,k+1,n);
   temp.push_back(nums[k]);
   func(ans,temp,nums,k+1,n);
   temp.pop_back();
    
    
}
    vector<vector<int>> subsets(vector<int>& nums) 
    {
        vector<vector<int>> ans;
        vector<int>temp;
        int n=nums.size();
        func(ans,temp,nums,0,n);
        ans.erase(unique(ans.begin(),ans.end()),ans.end());
        return ans;
    }
};
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