<p>Given two numbers, <code>hour</code> and <code>minutes</code>, return <em>the smaller angle (in degrees) formed between the </em><code>hour</code><em> and the </em><code>minute</code><em> hand</em>.</p>

<p>Answers within <code>10<sup>-5</sup></code> of the actual value will be accepted as correct.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_1_1673.png" style="width: 300px; height: 296px;" />
<pre>
<strong>Input:</strong> hour = 12, minutes = 30
<strong>Output:</strong> 165
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_2_1673.png" style="width: 300px; height: 301px;" />
<pre>
<strong>Input:</strong> hour = 3, minutes = 30
<strong>Output:</strong> 75
</pre>

<p><strong class="example">Example 3:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/12/26/sample_3_1673.png" style="width: 300px; height: 301px;" />
<pre>
<strong>Input:</strong> hour = 3, minutes = 15
<strong>Output:</strong> 7.5
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= hour &lt;= 12</code></li>
	<li><code>0 &lt;= minutes &lt;= 59</code></li>
</ul>

class Solution:
    def angleClock(self, hour: int, minutes: int) -> float:
        # Hour hand moves 30 degrees per hour and 0.5 degrees per minute
        hour %= 12
        hour_angle = (30 * hour) + (0.5 * minutes)
        
        # Minute hand moves 6 degrees per minute
        minute_angle = 6 * minutes
        
        # Calculate the absolute difference between the two angles
        angle = abs(hour_angle - minute_angle)
        
        # The clock forms a circle, so the maximum angle can be 360 degrees.
        # We need to return the smaller of the two angles (i.e., <= 180 degrees).
        return min(angle, 360 - angle)

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