<p>Given two positive integers <code>num1</code> and <code>num2</code>, find the positive integer <code>x</code> such that:</p>

<ul>
	<li><code>x</code> has the same number of set bits as <code>num2</code>, and</li>
	<li>The value <code>x XOR num1</code> is <strong>minimal</strong>.</li>
</ul>

<p>Note that <code>XOR</code> is the bitwise XOR operation.</p>

<p>Return <em>the integer </em><code>x</code>. The test cases are generated such that <code>x</code> is <strong>uniquely determined</strong>.</p>

<p>The number of <strong>set bits</strong> of an integer is the number of <code>1</code>&#39;s in its binary representation.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> num1 = 3, num2 = 5
<strong>Output:</strong> 3
<strong>Explanation:</strong>
The binary representations of num1 and num2 are 0011 and 0101, respectively.
The integer <strong>3</strong> has the same number of set bits as num2, and the value <code>3 XOR 3 = 0</code> is minimal.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> num1 = 1, num2 = 12
<strong>Output:</strong> 3
<strong>Explanation:</strong>
The binary representations of num1 and num2 are 0001 and 1100, respectively.
The integer <strong>3</strong> has the same number of set bits as num2, and the value <code>3 XOR 1 = 2</code> is minimal.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= num1, num2 &lt;= 10<sup>9</sup></code></li>
</ul>

class Solution:
    def minimizeXor(self, num1: int, num2: int) -> int:
        bits1 = [0 for _ in range(32)]
        bits2 = [0 for _ in range(32)]
        i = 0
        setbits = 0
        while num2 > 0:
            if num2 & 1 == 1:
                setbits+=1
            num2 = num2 >> 1    
        i = 0
        while num1 > 0:
            if num1 & 1 == 1:
                bits1[i]=1
            num1 = num1 >> 1    
            i+=1    
        i = 31
        while i>=0:
            if bits1[i]==1 and setbits > 0:
                bits2[i]=1
                setbits-=1
            i-=1
        i = 0
        while i <32:
            if bits1[i] == 0 and setbits > 0:
                bits2[i] = 1
                setbits-=1
            i+=1
        ans = 0
        i = 0
        while i < 32:
            if bits2[i]==1:
                ans+= 2**i
            i+=1
        return ans                


        
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