Given three integer arrays <code>nums1</code>, <code>nums2</code>, and <code>nums3</code>, return <em>a <strong>distinct</strong> array containing all the values that are present in <strong>at least two</strong> out of the three arrays. You may return the values in <strong>any</strong> order</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,1,3,2], nums2 = [2,3], nums3 = [3]
<strong>Output:</strong> [3,2]
<strong>Explanation:</strong> The values that are present in at least two arrays are:
- 3, in all three arrays.
- 2, in nums1 and nums2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [3,1], nums2 = [2,3], nums3 = [1,2]
<strong>Output:</strong> [2,3,1]
<strong>Explanation:</strong> The values that are present in at least two arrays are:
- 2, in nums2 and nums3.
- 3, in nums1 and nums2.
- 1, in nums1 and nums3.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,2,2], nums2 = [4,3,3], nums3 = [5]
<strong>Output:</strong> []
<strong>Explanation:</strong> No value is present in at least two arrays.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums1.length, nums2.length, nums3.length &lt;= 100</code></li>
	<li><code>1 &lt;= nums1[i], nums2[j], nums3[k] &lt;= 100</code></li>
</ul>

class Solution:
    def twoOutOfThree(self, nums1: List[int], nums2: List[int], nums3: List[int]) -> List[int]:
        result = []

        for num in set(nums1):
            if (num in set(nums2) or num in set(nums3)) and num not in result:
                result.append(num)

        for num in set(nums2):
            if num in set(nums3) and num not in result:
                result.append(num)
        
        return result
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