<p>Given two <strong>0-indexed</strong> integer arrays <code>nums1</code> and <code>nums2</code>, return <em>a list</em> <code>answer</code> <em>of size</em> <code>2</code> <em>where:</em></p>

<ul>
	<li><code>answer[0]</code> <em>is a list of all <strong>distinct</strong> integers in</em> <code>nums1</code> <em>which are <strong>not</strong> present in</em> <code>nums2</code><em>.</em></li>
	<li><code>answer[1]</code> <em>is a list of all <strong>distinct</strong> integers in</em> <code>nums2</code> <em>which are <strong>not</strong> present in</em> <code>nums1</code>.</li>
</ul>

<p><strong>Note</strong> that the integers in the lists may be returned in <strong>any</strong> order.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,2,3], nums2 = [2,4,6]
<strong>Output:</strong> [[1,3],[4,6]]
<strong>Explanation:
</strong>For nums1, nums1[1] = 2 is present at index 0 of nums2, whereas nums1[0] = 1 and nums1[2] = 3 are not present in nums2. Therefore, answer[0] = [1,3].
For nums2, nums2[0] = 2 is present at index 1 of nums1, whereas nums2[1] = 4 and nums2[2] = 6 are not present in nums2. Therefore, answer[1] = [4,6].</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,2,3,3], nums2 = [1,1,2,2]
<strong>Output:</strong> [[3],[]]
<strong>Explanation:
</strong>For nums1, nums1[2] and nums1[3] are not present in nums2. Since nums1[2] == nums1[3], their value is only included once and answer[0] = [3].
Every integer in nums2 is present in nums1. Therefore, answer[1] = [].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums1.length, nums2.length &lt;= 1000</code></li>
	<li><code>-1000 &lt;= nums1[i], nums2[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def findDifference(self, nums1: List[int], nums2: List[int]) -> List[List[int]]:
        nums1 = list(set(nums1))
        nums2 = list(set(nums2))
        print(nums1)
        print(nums2)
        if (nums1 == [] ) or (nums2 == []):
            return [nums1, nums2]

        nums1_keep = []
        nums2_keep =[]
        if len(nums1)<= len(nums2):
            for element in nums1:
                if element in nums2:
                    nums2.remove(element)
                else:
                    nums1_keep.append(element)
            return [nums1_keep, nums2]

        else:
            for element in nums2:
                if element in nums1:
                    nums1.remove(element)
                else:
                    nums2_keep.append(element)
            return [nums1, nums2_keep]


    
235