<p>Given an integer array <code>nums</code>, return<strong> </strong><em>the <strong>greatest common divisor</strong> of the smallest number and largest number in </em><code>nums</code>.</p>

<p>The <strong>greatest common divisor</strong> of two numbers is the largest positive integer that evenly divides both numbers.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [2,5,6,9,10]
<strong>Output:</strong> 2
<strong>Explanation:</strong>
The smallest number in nums is 2.
The largest number in nums is 10.
The greatest common divisor of 2 and 10 is 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [7,5,6,8,3]
<strong>Output:</strong> 1
<strong>Explanation:</strong>
The smallest number in nums is 3.
The largest number in nums is 8.
The greatest common divisor of 3 and 8 is 1.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,3]
<strong>Output:</strong> 3
<strong>Explanation:</strong>
The smallest number in nums is 3.
The largest number in nums is 3.
The greatest common divisor of 3 and 3 is 3.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= nums.length &lt;= 1000</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def findGCD(self, nums: List[int]) -> int:
        return math.gcd(min(nums),max(nums))  
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