<p>Given an array of digits <code>digits</code>, return <em>the largest multiple of <strong>three</strong> that can be formed by concatenating some of the given digits in <strong>any order</strong></em>. If there is no answer return an empty string.</p>

<p>Since the answer may not fit in an integer data type, return the answer as a string. Note that the returning answer must not contain unnecessary leading zeros.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> digits = [8,1,9]
<strong>Output:</strong> &quot;981&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> digits = [8,6,7,1,0]
<strong>Output:</strong> &quot;8760&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> digits = [1]
<strong>Output:</strong> &quot;&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= digits.length &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= digits[i] &lt;= 9</code></li>
</ul>

from typing import List

class Solution:
    def largestMultipleOfThree(self, digits: List[int]) -> str:
        digits.sort(reverse=True)
        total_sum = sum(digits)
        
        if total_sum % 3 == 0:
            if digits[0] == 0:
                return "0"
            return ''.join(map(str, digits))
        
        remainder = total_sum % 3
        found = False
        
        for i in range(len(digits) - 1, -1, -1):
            if digits[i] % 3 == remainder:
                digits.pop(i)
                found = True
                break
        
        if not found:
            count = 0
            for i in range(len(digits) - 1, -1, -1):
                if digits[i] % 3 == (3 - remainder):
                    digits.pop(i)
                    count += 1
                    if count == 2:
                        break
        
        if not digits:
            return ""
        
        if digits[0] == 0:
            return "0"
        
        return ''.join(map(str, digits))
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