<p>There exists an infinitely large two-dimensional grid of uncolored unit cells. You are given a positive integer <code>n</code>, indicating that you must do the following routine for <code>n</code> minutes:</p>

<ul>
	<li>At the first minute, color <strong>any</strong> arbitrary unit cell blue.</li>
	<li>Every minute thereafter, color blue <strong>every</strong> uncolored cell that touches a blue cell.</li>
</ul>

<p>Below is a pictorial representation of the state of the grid after minutes 1, 2, and 3.</p>
<img alt="" src="https://assets.leetcode.com/uploads/2023/01/10/example-copy-2.png" style="width: 500px; height: 279px;" />
<p>Return <em>the number of <strong>colored cells</strong> at the end of </em><code>n</code> <em>minutes</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 1
<strong>Output:</strong> 1
<strong>Explanation:</strong> After 1 minute, there is only 1 blue cell, so we return 1.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 2
<strong>Output:</strong> 5
<strong>Explanation:</strong> After 2 minutes, there are 4 colored cells on the boundary and 1 in the center, so we return 5. 
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>
</ul>

class Solution:
    def coloredCells(self, n: int) -> int:
        counter = 1
        total = 0
        while counter != n:
            total += counter *4
            counter +=1
        return total +1

149