<p>You are given an integer array <code>nums</code> and an integer <code>k</code>. You want to find a <strong>subsequence </strong>of <code>nums</code> of length <code>k</code> that has the <strong>largest</strong> sum.</p>

<p>Return<em> </em><em><strong>any</strong> such subsequence as an integer array of length </em><code>k</code>.</p>

<p>A <strong>subsequence</strong> is an array that can be derived from another array by deleting some or no elements without changing the order of the remaining elements.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [2,1,3,3], k = 2
<strong>Output:</strong> [3,3]
<strong>Explanation:</strong>
The subsequence has the largest sum of 3 + 3 = 6.</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [-1,-2,3,4], k = 3
<strong>Output:</strong> [-1,3,4]
<strong>Explanation:</strong> 
The subsequence has the largest sum of -1 + 3 + 4 = 6.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,4,3,3], k = 2
<strong>Output:</strong> [3,4]
<strong>Explanation:</strong>
The subsequence has the largest sum of 3 + 4 = 7. 
Another possible subsequence is [4, 3].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 1000</code></li>
	<li><code>-10<sup>5</sup>&nbsp;&lt;= nums[i] &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= k &lt;= nums.length</code></li>
</ul>

class Solution:
    def maxSubsequence(self, nums: List[int], k: int) -> List[int]:
        while len(nums)>k:
            nums.remove(min(nums))
        return nums
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