<p>You are given a <strong>0-indexed</strong> array <code>nums</code> of size <code>n</code> consisting of <strong>non-negative</strong> integers.</p>

<p>You need to apply <code>n - 1</code> operations to this array where, in the <code>i<sup>th</sup></code> operation (<strong>0-indexed</strong>), you will apply the following on the <code>i<sup>th</sup></code> element of <code>nums</code>:</p>

<ul>
	<li>If <code>nums[i] == nums[i + 1]</code>, then multiply <code>nums[i]</code> by <code>2</code> and set <code>nums[i + 1]</code> to <code>0</code>. Otherwise, you skip this operation.</li>
</ul>

<p>After performing <strong>all</strong> the operations, <strong>shift</strong> all the <code>0</code>&#39;s to the <strong>end</strong> of the array.</p>

<ul>
	<li>For example, the array <code>[1,0,2,0,0,1]</code> after shifting all its <code>0</code>&#39;s to the end, is <code>[1,2,1,0,0,0]</code>.</li>
</ul>

<p>Return <em>the resulting array</em>.</p>

<p><strong>Note</strong> that the operations are applied <strong>sequentially</strong>, not all at once.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,2,1,1,0]
<strong>Output:</strong> [1,4,2,0,0,0]
<strong>Explanation:</strong> We do the following operations:
- i = 0: nums[0] and nums[1] are not equal, so we skip this operation.
- i = 1: nums[1] and nums[2] are equal, we multiply nums[1] by 2 and change nums[2] to 0. The array becomes [1,<strong><u>4</u></strong>,<strong><u>0</u></strong>,1,1,0].
- i = 2: nums[2] and nums[3] are not equal, so we skip this operation.
- i = 3: nums[3] and nums[4] are equal, we multiply nums[3] by 2 and change nums[4] to 0. The array becomes [1,4,0,<strong><u>2</u></strong>,<strong><u>0</u></strong>,0].
- i = 4: nums[4] and nums[5] are equal, we multiply nums[4] by 2 and change nums[5] to 0. The array becomes [1,4,0,2,<strong><u>0</u></strong>,<strong><u>0</u></strong>].
After that, we shift the 0&#39;s to the end, which gives the array [1,4,2,0,0,0].
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [0,1]
<strong>Output:</strong> [1,0]
<strong>Explanation:</strong> No operation can be applied, we just shift the 0 to the end.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= nums.length &lt;= 2000</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def applyOperations(self, nums: List[int]) -> List[int]:
        for i in range(len(nums) - 1):
            if nums[i] == nums[i + 1]:
                nums[i] *= 2
                nums[i + 1] = 0

        return [n for n in nums if n != 0] + [n for n in nums if n == 0]
        
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