<p>Given an array of digits <code>digits</code>, return <em>the largest multiple of <strong>three</strong> that can be formed by concatenating some of the given digits in <strong>any order</strong></em>. If there is no answer return an empty string.</p>

<p>Since the answer may not fit in an integer data type, return the answer as a string. Note that the returning answer must not contain unnecessary leading zeros.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> digits = [8,1,9]
<strong>Output:</strong> &quot;981&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> digits = [8,6,7,1,0]
<strong>Output:</strong> &quot;8760&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> digits = [1]
<strong>Output:</strong> &quot;&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= digits.length &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= digits[i] &lt;= 9</code></li>
</ul>

from collections import Counter

class Solution:
    def largestMultipleOfThree(self, digits: List[int]) -> str:
        curr_sum = sum(digits)
        rest = curr_sum % 3
        digits = sorted(map(str, digits), reverse=True)
        digits_cnts = Counter(digits)
        if rest == 0:
            return "".join(digits).lstrip("0") or ("0" if "0" in digits_cnts else "")
        elif rest == 1:
            # remove single digit
            for el in ["1", "4", "7"]:
                if el in digits_cnts:
                    return "".join(digits).replace(el, "", 1).lstrip("0") or ("0" if "0" in digits_cnts else "")
            # remove 2 digits
            num_d = 0
            ds = ""
            for el in ["2", "5", "8"]:
                if el in digits_cnts:
                    num_d += digits_cnts[el]
                    ds += el * digits_cnts[el]
                    if num_d >= 2:
                        res = "".join(digits)
                        for d in ds[:2]:
                            res = res.replace(d, "", 1)
                        return res.lstrip("0") or ("0" if "0" in digits_cnts else "")
        elif rest == 2:
            # remove single digit
            for el in ["2", "5", "8"]:
                if el in digits_cnts:
                    return "".join(digits).lstrip("0").replace(el, "", 1).lstrip("0") or ("0" if "0" in digits_cnts else "")
            # remove 2 digits
            num_d = 0
            ds = ""
            for el in ["1", "4", "7"]:
                if el in digits_cnts:
                    num_d += digits_cnts[el]
                    ds += el * digits_cnts[el]
                    if num_d >= 2:
                        res = "".join(digits)
                        for d in ds[:2]:
                            res = res.replace(d, "", 1)
                        return res.lstrip("0") or ("0" if "0" in digits_cnts else "")
        return ""
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