<p>An <strong>alphabetical continuous string</strong> is a string consisting of consecutive letters in the alphabet. In other words, it is any substring of the string <code>&quot;abcdefghijklmnopqrstuvwxyz&quot;</code>.</p>

<ul>
	<li>For example, <code>&quot;abc&quot;</code> is an alphabetical continuous string, while <code>&quot;acb&quot;</code> and <code>&quot;za&quot;</code> are not.</li>
</ul>

<p>Given a string <code>s</code> consisting of lowercase letters only, return the <em>length of the <strong>longest</strong> alphabetical continuous substring.</em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abacaba&quot;
<strong>Output:</strong> 2
<strong>Explanation:</strong> There are 4 distinct continuous substrings: &quot;a&quot;, &quot;b&quot;, &quot;c&quot; and &quot;ab&quot;.
&quot;ab&quot; is the longest continuous substring.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abcde&quot;
<strong>Output:</strong> 5
<strong>Explanation:</strong> &quot;abcde&quot; is the longest continuous substring.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>
	<li><code>s</code> consists of only English lowercase letters.</li>
</ul>

class Solution:
    def longestContinuousSubstring(self, s: str) -> int:
        prev = 0
        ans = 0
        for i in range(len(s)):
            if i==0:
                prev = 1
            else:
                if ord(s[i]) - ord(s[i-1]) == 1:
                    prev += 1
                else:
                    prev = 1
            ans = max(ans, prev)
        return ans
320