<p>You are given an integer <code>total</code> indicating the amount of money you have. You are also given two integers <code>cost1</code> and <code>cost2</code> indicating the price of a pen and pencil respectively. You can spend <strong>part or all</strong> of your money to buy multiple quantities (or none) of each kind of writing utensil.</p>

<p>Return <em>the <strong>number of distinct ways</strong> you can buy some number of pens and pencils.</em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> total = 20, cost1 = 10, cost2 = 5
<strong>Output:</strong> 9
<strong>Explanation:</strong> The price of a pen is 10 and the price of a pencil is 5.
- If you buy 0 pens, you can buy 0, 1, 2, 3, or 4 pencils.
- If you buy 1 pen, you can buy 0, 1, or 2 pencils.
- If you buy 2 pens, you cannot buy any pencils.
The total number of ways to buy pens and pencils is 5 + 3 + 1 = 9.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> total = 5, cost1 = 10, cost2 = 10
<strong>Output:</strong> 1
<strong>Explanation:</strong> The price of both pens and pencils are 10, which cost more than total, so you cannot buy any writing utensils. Therefore, there is only 1 way: buy 0 pens and 0 pencils.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= total, cost1, cost2 &lt;= 10<sup>6</sup></code></li>
</ul>

class Solution:

    def waysToBuyPensPencils(self, total: int, cost1: int, cost2: int) -> int:
        ans = 1
        if cost2> cost1:
            cost1, cost2 = cost2, cost1
        while total > 0:
            ans += (total//cost2)
            total -= cost1
            if total >= 0:
                ans += 1
        return ans
326