<p>Given an array of integers <code>arr</code> and two integers <code>k</code> and <code>threshold</code>, return <em>the number of sub-arrays of size </em><code>k</code><em> and average greater than or equal to </em><code>threshold</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr = [2,2,2,2,5,5,5,8], k = 3, threshold = 4
<strong>Output:</strong> 3
<strong>Explanation:</strong> Sub-arrays [2,5,5],[5,5,5] and [5,5,8] have averages 4, 5 and 6 respectively. All other sub-arrays of size 3 have averages less than 4 (the threshold).
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr = [11,13,17,23,29,31,7,5,2,3], k = 3, threshold = 5
<strong>Output:</strong> 6
<strong>Explanation:</strong> The first 6 sub-arrays of size 3 have averages greater than 5. Note that averages are not integers.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr.length &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= arr[i] &lt;= 10<sup>4</sup></code></li>
	<li><code>1 &lt;= k &lt;= arr.length</code></li>
	<li><code>0 &lt;= threshold &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def numOfSubarrays(self, arr: List[int], k: int, threshold: int) -> int:
        res = 0
        cursum = sum(arr[:k - 1])
        for l in range(len(arr) - k + 1):
            cursum += arr[l + k - 1]
            if (cursum / k) >= threshold:
                res += 1
            cursum -= arr[l]
        return res

        """res = 0
        exmaple = [2,1,3,4,5] ->> k = 3 threshold = 3
        cursum = sum(arr[:k - 1]) = arr[:2] = 2 + 1 = 3
        l = 0 ->> 
        cursum += arr[l + k - 1] ->>> 3 + 3 = 6 ->> 6 / 3 = 2 
        next here doing the arr[0] value is 
        6 - 2 = 4
        nextcursum = 4 beacuse no need twice of the visit the same value
        [2,1,3] IS NOT POSSIBLE OKAY
        L moves..

        checking next 
        4 + 4 = 8 ->>> 8 / 3 = 2.67
        8 - 1 = 7
        nextcurm = 7
        7 + 5 = 12
        12 - 3 = 9
        9 / 3 = 3
        res = 1
        """

        
450