<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> and an integer <code>x</code>.</p>

<p>Find the <strong>minimum absolute difference</strong> between two elements in the array that are at least <code>x</code> indices apart.</p>

<p>In other words, find two indices <code>i</code> and <code>j</code> such that <code>abs(i - j) &gt;= x</code> and <code>abs(nums[i] - nums[j])</code> is minimized.</p>

<p>Return<em> an integer denoting the <strong>minimum</strong> absolute difference between two elements that are at least</em> <code>x</code> <em>indices apart</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [4,3,2,4], x = 2
<strong>Output:</strong> 0
<strong>Explanation:</strong> We can select nums[0] = 4 and nums[3] = 4. 
They are at least 2 indices apart, and their absolute difference is the minimum, 0. 
It can be shown that 0 is the optimal answer.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [5,3,2,10,15], x = 1
<strong>Output:</strong> 1
<strong>Explanation:</strong> We can select nums[1] = 3 and nums[2] = 2.
They are at least 1 index apart, and their absolute difference is the minimum, 1.
It can be shown that 1 is the optimal answer.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4], x = 3
<strong>Output:</strong> 3
<strong>Explanation:</strong> We can select nums[0] = 1 and nums[3] = 4.
They are at least 3 indices apart, and their absolute difference is the minimum, 3.
It can be shown that 3 is the optimal answer.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
	<li><code>0 &lt;= x &lt; nums.length</code></li>
</ul>

from sortedcontainers import SortedList

class Solution:
    def minAbsoluteDifference(self, a: List[int], x: int) -> int:
        n = len(a)
        b = SortedList()
        res = inf
        for i in range(x,n): 
            b.add(a[i-x]) 
            idx = bisect.bisect_left(b,a[i]) 
            if idx-1>=0: 
                res= min(abs(b[idx-1]-a[i]),res)
            if idx<len(b):
                res= min(abs(b[idx]-a[i]),res)
        return res
        # def getFirstVal(k):
        #     return k[0]
        
        # numIdx = []
        # for i, num in enumerate(nums):
        #     numIdx.append([num, i])
        
        # numIdx.sort(key=getFirstVal)

        # print(numIdx)
    
        # minDiff = 10 ** 9 

        # for r in range(0, len(numIdx)):
        #     l = r 

        #     while l >= 0:
        #         diff = numIdx[r][0] - numIdx[l][0]
                
        #         if diff < minDiff and abs(numIdx[r][1] - numIdx[l][1]) >= x:
        #             minDiff = diff
        #             break
                
        #         l -= 1

        # return minDiff

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