<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code>. In one operation, you may do the following:</p>

<ul>
	<li>Choose <strong>two</strong> integers in <code>nums</code> that are <strong>equal</strong>.</li>
	<li>Remove both integers from <code>nums</code>, forming a <strong>pair</strong>.</li>
</ul>

<p>The operation is done on <code>nums</code> as many times as possible.</p>

<p>Return <em>a <strong>0-indexed</strong> integer array </em><code>answer</code><em> of size </em><code>2</code><em> where </em><code>answer[0]</code><em> is the number of pairs that are formed and </em><code>answer[1]</code><em> is the number of leftover integers in </em><code>nums</code><em> after doing the operation as many times as possible</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,3,2,1,3,2,2]
<strong>Output:</strong> [3,1]
<strong>Explanation:</strong>
Form a pair with nums[0] and nums[3] and remove them from nums. Now, nums = [3,2,3,2,2].
Form a pair with nums[0] and nums[2] and remove them from nums. Now, nums = [2,2,2].
Form a pair with nums[0] and nums[1] and remove them from nums. Now, nums = [2].
No more pairs can be formed. A total of 3 pairs have been formed, and there is 1 number leftover in nums.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,1]
<strong>Output:</strong> [1,0]
<strong>Explanation:</strong> Form a pair with nums[0] and nums[1] and remove them from nums. Now, nums = [].
No more pairs can be formed. A total of 1 pair has been formed, and there are 0 numbers leftover in nums.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [0]
<strong>Output:</strong> [0,1]
<strong>Explanation:</strong> No pairs can be formed, and there is 1 number leftover in nums.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 100</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 100</code></li>
</ul>

class Solution:
    def numberOfPairs(self, nums: List[int]) -> List[int]:
        cnt=Counter(nums)
        count=r=0
        res=[]
        print(cnt)
        for key , val in cnt.items():
            if val%2==0:
                print(key , val)
                count+=(val//2)
            else:
                count+=(val//2)
                r+=1
        
        res.append(count)
        res.append(r)
        return res
45