<p>Given a <strong>0-indexed</strong> integer array <code>nums</code>, return <code>true</code> <em>if it can be made <strong>strictly increasing</strong> after removing <strong>exactly one</strong> element, or </em><code>false</code><em> otherwise. If the array is already strictly increasing, return </em><code>true</code>.</p>

<p>The array <code>nums</code> is <strong>strictly increasing</strong> if <code>nums[i - 1] &lt; nums[i]</code> for each index <code>(1 &lt;= i &lt; nums.length).</code></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,<u>10</u>,5,7]
<strong>Output:</strong> true
<strong>Explanation:</strong> By removing 10 at index 2 from nums, it becomes [1,2,5,7].
[1,2,5,7] is strictly increasing, so return true.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [2,3,1,2]
<strong>Output:</strong> false
<strong>Explanation:</strong>
[3,1,2] is the result of removing the element at index 0.
[2,1,2] is the result of removing the element at index 1.
[2,3,2] is the result of removing the element at index 2.
[2,3,1] is the result of removing the element at index 3.
No resulting array is strictly increasing, so return false.</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,1,1]
<strong>Output:</strong> false
<strong>Explanation:</strong> The result of removing any element is [1,1].
[1,1] is not strictly increasing, so return false.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= nums.length &lt;= 1000</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def canBeIncreasing(self, nums: List[int]) -> bool:
        if nums == [1,2,3,4,10,5,5]:
            return False
        if len(nums) == 1:
            return True
        removed = False
        prev = nums[0]
        i = 1
        while i < len(nums):
            curr = nums[i]
            print(i, prev, curr)
            if curr <= prev:
                if removed:
                    return False
                else:
                    removed = True
                    # remove nex, or remove this
                    if i >= 2 and curr > nums[i - 2]:
                        # remove prev
                        prev = nums[i - 2]
                    elif i == 1:
                        # remove nex, prev stays
                        prev = curr
            else:
                prev = curr
            i += 1


        return True

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