<p>Given a <strong>0-indexed</strong> integer array <code>nums</code> of size <code>n</code>, find the <strong>maximum difference</strong> between <code>nums[i]</code> and <code>nums[j]</code> (i.e., <code>nums[j] - nums[i]</code>), such that <code>0 &lt;= i &lt; j &lt; n</code> and <code>nums[i] &lt; nums[j]</code>.</p>

<p>Return <em>the <strong>maximum difference</strong>. </em>If no such <code>i</code> and <code>j</code> exists, return <code>-1</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [7,<strong><u>1</u></strong>,<strong><u>5</u></strong>,4]
<strong>Output:</strong> 4
<strong>Explanation:</strong>
The maximum difference occurs with i = 1 and j = 2, nums[j] - nums[i] = 5 - 1 = 4.
Note that with i = 1 and j = 0, the difference nums[j] - nums[i] = 7 - 1 = 6, but i &gt; j, so it is not valid.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [9,4,3,2]
<strong>Output:</strong> -1
<strong>Explanation:</strong>
There is no i and j such that i &lt; j and nums[i] &lt; nums[j].
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [<strong><u>1</u></strong>,5,2,<strong><u>10</u></strong>]
<strong>Output:</strong> 9
<strong>Explanation:</strong>
The maximum difference occurs with i = 0 and j = 3, nums[j] - nums[i] = 10 - 1 = 9.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == nums.length</code></li>
	<li><code>2 &lt;= n &lt;= 1000</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
</ul>

class Solution:
    def maximumDifference(self, nums: List[int]) -> int:
        result = -1
        n = len(nums)

        prev_min = float('inf')
        for i in range(n-1):
            if nums[i] >= prev_min:
                continue
            else:
                prev_min = nums[i]
            for j in range(i+1, n):
                diff = nums[j] - nums[i]
                if diff > 0 and diff > result:
                    result = diff
        

        return result
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