<p>Given an integer <code>n</code>, return <code>true</code><em> if </em><code>n</code><em> has <strong>exactly three positive divisors</strong>. Otherwise, return </em><code>false</code>.</p>

<p>An integer <code>m</code> is a <strong>divisor</strong> of <code>n</code> if there exists an integer <code>k</code> such that <code>n = k * m</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 2
<strong>Output:</strong> false
<strong>Explantion:</strong> 2 has only two divisors: 1 and 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 4
<strong>Output:</strong> true
<strong>Explantion:</strong> 4 has three divisors: 1, 2, and 4.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def isThree(self, n: int) -> bool:
        if n == 1:
            return False 
        if int(sqrt(n))**2 == n:
            for i in range(2,int(sqrt(n))):
                if n % i == 0:
                    return False                
        else:
            return False
        return True
        
32