<p>You are given an integer array <code>receiver</code> of length <code>n</code> and an integer <code>k</code>. <code>n</code> players are playing a ball-passing game.</p>

<p>You choose the starting player, <code>i</code>. The game proceeds as follows: player <code>i</code> passes the ball to player <code>receiver[i]</code>, who then passes it to <code>receiver[receiver[i]]</code>, and so on, for <code>k</code> passes in total. The game&#39;s score is the sum of the indices of the players who touched the ball, including repetitions, i.e. <code>i + receiver[i] + receiver[receiver[i]] + ... + receiver<sup>(k)</sup>[i]</code>.</p>

<p>Return&nbsp;the <strong>maximum</strong>&nbsp;possible score.</p>

<p><strong>Notes:</strong></p>

<ul>
	<li><code>receiver</code> may contain duplicates.</li>
	<li><code>receiver[i]</code> may be equal to <code>i</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">receiver = [2,0,1], k = 4</span></p>

<p><strong>Output:</strong> <span class="example-io">6</span></p>

<p><strong>Explanation:</strong></p>

<p>Starting with player <code>i = 2</code> the initial score is 2:</p>

<table>
	<tbody>
		<tr>
			<th>Pass</th>
			<th>Sender Index</th>
			<th>Receiver Index</th>
			<th>Score</th>
		</tr>
		<tr>
			<td>1</td>
			<td>2</td>
			<td>1</td>
			<td>3</td>
		</tr>
		<tr>
			<td>2</td>
			<td>1</td>
			<td>0</td>
			<td>3</td>
		</tr>
		<tr>
			<td>3</td>
			<td>0</td>
			<td>2</td>
			<td>5</td>
		</tr>
		<tr>
			<td>4</td>
			<td>2</td>
			<td>1</td>
			<td>6</td>
		</tr>
	</tbody>
</table>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">receiver = [1,1,1,2,3], k = 3</span></p>

<p><strong>Output:</strong> <span class="example-io">10</span></p>

<p><strong>Explanation:</strong></p>

<p>Starting with player <code>i = 4</code> the initial score is 4:</p>

<table>
	<tbody>
		<tr>
			<th>Pass</th>
			<th>Sender Index</th>
			<th>Receiver Index</th>
			<th>Score</th>
		</tr>
		<tr>
			<td>1</td>
			<td>4</td>
			<td>3</td>
			<td>7</td>
		</tr>
		<tr>
			<td>2</td>
			<td>3</td>
			<td>2</td>
			<td>9</td>
		</tr>
		<tr>
			<td>3</td>
			<td>2</td>
			<td>1</td>
			<td>10</td>
		</tr>
	</tbody>
</table>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= receiver.length == n &lt;= 10<sup>5</sup></code></li>
	<li><code>0 &lt;= receiver[i] &lt;= n - 1</code></li>
	<li><code>1 &lt;= k &lt;= 10<sup>10</sup></code></li>
</ul>

class Solution:
    def getMaxFunctionValue(self, receiver: List[int], k: int) -> int:
        
        def pathSum(node, n):

            visited.add(node)
            prefixSum.append(prefixSum[-1] + node)

            #Find maxSum from this node
            if k > n:
                count = k - n
                summa = cycleSum * (count // cycleLen)
                summa += prefixSum[-1] - prefixSum[-(count % cycleLen + n+2)]
                self.maxi = max(self.maxi, summa)
            else:
                self.maxi = max(self.maxi, prefixSum[-1] - prefixSum[-k-2])

            #DFS
            for item in reversedAdj[node]:
                pathSum(item, n+1)
            prefixSum.pop()

        #Build reversed adj
        reversedAdj = defaultdict(list)
        for i, j in enumerate(receiver):
            reversedAdj[j].append(i)

        self.maxi = 0
        visited = set()

        #Iterate through the graph
        for node in receiver:
            if not node in visited:

                #Find a node from cycle                
                while not node in visited:
                    visited.add(node)
                    node = receiver[node]
                
                #Initialize prefixSum
                start = node
                prefixSum = [0, -node]
                while receiver[node] != start:
                    node = receiver[node]
                    prefixSum.append(prefixSum[-1] - node)

                prefixSum.reverse()
                cycleSum = -prefixSum[0]
                cycleLen = len(prefixSum) - 1
                reversedAdj[start].remove(node)

                pathSum(node, 0)

        return self.maxi
699