<p>Given a string <code>s</code> and an array of strings <code>words</code>, determine whether <code>s</code> is a <strong>prefix string</strong> of <code>words</code>.</p>

<p>A string <code>s</code> is a <strong>prefix string</strong> of <code>words</code> if <code>s</code> can be made by concatenating the first <code>k</code> strings in <code>words</code> for some <strong>positive</strong> <code>k</code> no larger than <code>words.length</code>.</p>

<p>Return <code>true</code><em> if </em><code>s</code><em> is a <strong>prefix string</strong> of </em><code>words</code><em>, or </em><code>false</code><em> otherwise</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;iloveleetcode&quot;, words = [&quot;i&quot;,&quot;love&quot;,&quot;leetcode&quot;,&quot;apples&quot;]
<strong>Output:</strong> true
<strong>Explanation:</strong>
s can be made by concatenating &quot;i&quot;, &quot;love&quot;, and &quot;leetcode&quot; together.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;iloveleetcode&quot;, words = [&quot;apples&quot;,&quot;i&quot;,&quot;love&quot;,&quot;leetcode&quot;]
<strong>Output:</strong> false
<strong>Explanation:</strong>
It is impossible to make s using a prefix of arr.</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= words.length &lt;= 100</code></li>
	<li><code>1 &lt;= words[i].length &lt;= 20</code></li>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>words[i]</code> and <code>s</code> consist of only lowercase English letters.</li>
</ul>

class Solution:
    def isPrefixString(self, s: str, words: List[str]) -> bool:
        a=""
        for i in range(0,len(words)):
            a=a+words[i]
            if a==s :
                return True
        return False

        
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