<p>You are given an integer array <code>nums</code> of size <code>n</code>.</p>

<p>Consider a <strong>non-empty</strong> subarray from <code>nums</code> that has the <strong>maximum</strong> possible <strong>bitwise AND</strong>.</p>

<ul>
	<li>In other words, let <code>k</code> be the maximum value of the bitwise AND of <strong>any</strong> subarray of <code>nums</code>. Then, only subarrays with a bitwise AND equal to <code>k</code> should be considered.</li>
</ul>

<p>Return <em>the length of the <strong>longest</strong> such subarray</em>.</p>

<p>The bitwise AND of an array is the bitwise AND of all the numbers in it.</p>

<p>A <strong>subarray</strong> is a contiguous sequence of elements within an array.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,3,2,2]
<strong>Output:</strong> 2
<strong>Explanation:</strong>
The maximum possible bitwise AND of a subarray is 3.
The longest subarray with that value is [3,3], so we return 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> 1
<strong>Explanation:</strong>
The maximum possible bitwise AND of a subarray is 4.
The longest subarray with that value is [4], so we return 1.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>
</ul>

class Solution:
    def longestSubarray(self, nums: List[int]) -> int:
        n = len(nums)
        if n == 1:
            return 1

        target = max(nums)
        i = 0

        ans = 1
        temp = 0

        while i < n:
            if nums[i] == target:
                j = i+1
                while j < n:
                    if nums[j] != target:

                        break
                    j += 1
                temp = j - i
                ans = max(ans, temp)
                i = j            
            i += 1
        
        return ans
                    

537