<p>You want to water <code>n</code> plants in your garden with a watering can. The plants are arranged in a row and are labeled from <code>0</code> to <code>n - 1</code> from left to right where the <code>i<sup>th</sup></code> plant is located at <code>x = i</code>. There is a river at <code>x = -1</code> that you can refill your watering can at.</p>

<p>Each plant needs a specific amount of water. You will water the plants in the following way:</p>

<ul>
	<li>Water the plants in order from left to right.</li>
	<li>After watering the current plant, if you do not have enough water to <strong>completely</strong> water the next plant, return to the river to fully refill the watering can.</li>
	<li>You <strong>cannot</strong> refill the watering can early.</li>
</ul>

<p>You are initially at the river (i.e., <code>x = -1</code>). It takes <strong>one step</strong> to move <strong>one unit</strong> on the x-axis.</p>

<p>Given a <strong>0-indexed</strong> integer array <code>plants</code> of <code>n</code> integers, where <code>plants[i]</code> is the amount of water the <code>i<sup>th</sup></code> plant needs, and an integer <code>capacity</code> representing the watering can capacity, return <em>the <strong>number of steps</strong> needed to water all the plants</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> plants = [2,2,3,3], capacity = 5
<strong>Output:</strong> 14
<strong>Explanation:</strong> Start at the river with a full watering can:
- Walk to plant 0 (1 step) and water it. Watering can has 3 units of water.
- Walk to plant 1 (1 step) and water it. Watering can has 1 unit of water.
- Since you cannot completely water plant 2, walk back to the river to refill (2 steps).
- Walk to plant 2 (3 steps) and water it. Watering can has 2 units of water.
- Since you cannot completely water plant 3, walk back to the river to refill (3 steps).
- Walk to plant 3 (4 steps) and water it.
Steps needed = 1 + 1 + 2 + 3 + 3 + 4 = 14.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> plants = [1,1,1,4,2,3], capacity = 4
<strong>Output:</strong> 30
<strong>Explanation:</strong> Start at the river with a full watering can:
- Water plants 0, 1, and 2 (3 steps). Return to river (3 steps).
- Water plant 3 (4 steps). Return to river (4 steps).
- Water plant 4 (5 steps). Return to river (5 steps).
- Water plant 5 (6 steps).
Steps needed = 3 + 3 + 4 + 4 + 5 + 5 + 6 = 30.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> plants = [7,7,7,7,7,7,7], capacity = 8
<strong>Output:</strong> 49
<strong>Explanation:</strong> You have to refill before watering each plant.
Steps needed = 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 = 49.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == plants.length</code></li>
	<li><code>1 &lt;= n &lt;= 1000</code></li>
	<li><code>1 &lt;= plants[i] &lt;= 10<sup>6</sup></code></li>
	<li><code>max(plants[i]) &lt;= capacity &lt;= 10<sup>9</sup></code></li>
</ul>

class Solution:
    def wateringPlants(self, plants: List[int], capacity: int) -> int:
        n = len(plants)
        ans = 0
        curr = -1
        cap = capacity
        while(curr<n-1):
            # print(curr, ans)
            if(cap>=plants[curr+1]):
                ans += 1
                cap -= plants[curr+1]
                curr += 1
                continue

            # print(ans)
            ans += 2*curr + 2
            cap = capacity

        return ans

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