<p>You are given an integer <code>num.</code> <strong>Rearrange</strong> the digits of <code>num</code> such that its value is <strong>minimized</strong> and it does not contain <strong>any</strong> leading zeros.</p>

<p>Return <em>the rearranged number with minimal value</em>.</p>

<p>Note that the sign of the number does not change after rearranging the digits.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> num = 310
<strong>Output:</strong> 103
<strong>Explanation:</strong> The possible arrangements for the digits of 310 are 013, 031, 103, 130, 301, 310. 
The arrangement with the smallest value that does not contain any leading zeros is 103.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> num = -7605
<strong>Output:</strong> -7650
<strong>Explanation:</strong> Some possible arrangements for the digits of -7605 are -7650, -6705, -5076, -0567.
The arrangement with the smallest value that does not contain any leading zeros is -7650.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-10<sup>15</sup> &lt;= num &lt;= 10<sup>15</sup></code></li>
</ul>

class Solution:
    def smallestNumber(self, num: int) -> int:
        if num==0:
            return 0
        arr = []
        numm = list(str(num))
        zeros = numm.count('0')
        if numm[0]=='-':
            neg = True
        else:
            neg = False
        
        if neg:
            del numm[0]
            arrneg = sorted(numm, key=lambda x: x*10)
            arrneg = arrneg[::-1]
            arrneg = int(''.join(arrneg))
            return -arrneg
        else:
            arrpos = sorted(numm, key=lambda x: x*10, reverse=True)
            arrpos = arrpos[::-1]
            arrpos = [int(p) for p in arrpos]
            if zeros:
                for f, g in groupby(arrpos):
                    if f==0:
                        idx = len(list(g))
                        arrpos[0] = arrpos[idx]
                        arrpos[idx] = 0
                        break
            arrpos = [str(p) for p in arrpos]
            return int(''.join(arrpos))
        
        return 0
        
        


        

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