<p>You are given a string <code>s</code>, and an array of pairs of indices in the string&nbsp;<code>pairs</code>&nbsp;where&nbsp;<code>pairs[i] =&nbsp;[a, b]</code>&nbsp;indicates 2 indices(0-indexed) of the string.</p>

<p>You can&nbsp;swap the characters at any pair of indices in the given&nbsp;<code>pairs</code>&nbsp;<strong>any number of times</strong>.</p>

<p>Return the&nbsp;lexicographically smallest string that <code>s</code>&nbsp;can be changed to after using the swaps.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;dcab&quot;, pairs = [[0,3],[1,2]]
<strong>Output:</strong> &quot;bacd&quot;
<strong>Explaination:</strong> 
Swap s[0] and s[3], s = &quot;bcad&quot;
Swap s[1] and s[2], s = &quot;bacd&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;dcab&quot;, pairs = [[0,3],[1,2],[0,2]]
<strong>Output:</strong> &quot;abcd&quot;
<strong>Explaination: </strong>
Swap s[0] and s[3], s = &quot;bcad&quot;
Swap s[0] and s[2], s = &quot;acbd&quot;
Swap s[1] and s[2], s = &quot;abcd&quot;</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;cba&quot;, pairs = [[0,1],[1,2]]
<strong>Output:</strong> &quot;abc&quot;
<strong>Explaination: </strong>
Swap s[0] and s[1], s = &quot;bca&quot;
Swap s[1] and s[2], s = &quot;bac&quot;
Swap s[0] and s[1], s = &quot;abc&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 10^5</code></li>
	<li><code>0 &lt;= pairs.length &lt;= 10^5</code></li>
	<li><code>0 &lt;= pairs[i][0], pairs[i][1] &lt;&nbsp;s.length</code></li>
	<li><code>s</code>&nbsp;only contains lower case English letters.</li>
</ul>

class Solution(object):
    def smallestStringWithSwaps(self, s, pairs):
        """
        :type s: str
        :type pairs: List[List[int]]
        :rtype: str
        """
        s = list(s)
        nodes = [i for i in range(len(s))]
        rank = [1 for i in range(len(s))]

        def find(x):
            if x == nodes[x]:
                return x
            nodes[x] = find(nodes[x])
            return nodes[x]

        def union(x, y):
            rootx = find(x)
            rooty = find(y)
            if rootx != rooty:
                if rank[rootx] >= rank[rooty]:
                    nodes[rooty] = rootx
                    rank[rootx] += rank[rooty]
                else:
                    nodes[rootx] = rooty
                    rank[rooty] += rank[rootx]
                

        for e1, e2 in pairs:
            union(e1, e2)
        
        print(nodes)

        root2comp = defaultdict(list)

        for i in range(len(s)):
            root = find(i)
            root2comp[root].append(i)

        for k, indices in root2comp.items():
            chars = []
            for i in indices:
                chars.append(s[i])
            chars = sorted(chars)

            for c, i in zip(chars, indices):
                s[i] = c

        return "".join(s)
478