<p>You are given an <code>m x n</code> binary matrix <code>grid</code>.</p>

<p>A <strong>move</strong> consists of choosing any row or column and toggling each value in that row or column (i.e., changing all <code>0</code>&#39;s to <code>1</code>&#39;s, and all <code>1</code>&#39;s to <code>0</code>&#39;s).</p>

<p>Every row of the matrix is interpreted as a binary number, and the <strong>score</strong> of the matrix is the sum of these numbers.</p>

<p>Return <em>the highest possible <strong>score</strong> after making any number of <strong>moves</strong> (including zero moves)</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/07/23/lc-toogle1.jpg" style="width: 500px; height: 299px;" />
<pre>
<strong>Input:</strong> grid = [[0,0,1,1],[1,0,1,0],[1,1,0,0]]
<strong>Output:</strong> 39
<strong>Explanation:</strong> 0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> grid = [[0]]
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == grid.length</code></li>
	<li><code>n == grid[i].length</code></li>
	<li><code>1 &lt;= m, n &lt;= 20</code></li>
	<li><code>grid[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>

class Solution:
    def matrixScore(self, grid: List[List[int]]) -> int:
        n=len(grid)
        m=len(grid[0])
        for i in range(n):
            if(grid[i][0]==0):
                self.flip_row(grid,i)
        #print(grid)
        for j in range(1,m):
            zeros=0
            ones=0
            for i in range(0,n):
                if(grid[i][j]==0):
                    zeros+=1
                else:
                    ones+=1
            if(zeros>ones):
                self.flip_col(grid,j)
        #print(grid)
        res=0
        for i in range(n):
            l=grid[i]
            s="".join(str(j) for j in l)
            res=res+int(s,2)
        return res

    def flip_row(self,grid,r):
        n=len(grid[0])
        for i in range(n):
            grid[r][i]=grid[r][i]^1

    def flip_col(self,grid,c):
        n=len(grid)
        m=len(grid[0])
        for i in range(n):
            grid[i][c]=grid[i][c]^1

        
16500