<p>Given a string <code>s</code> containing only lowercase English letters and the <code>&#39;?&#39;</code> character, convert <strong>all </strong>the <code>&#39;?&#39;</code> characters into lowercase letters such that the final string does not contain any <strong>consecutive repeating </strong>characters. You <strong>cannot </strong>modify the non <code>&#39;?&#39;</code> characters.</p>

<p>It is <strong>guaranteed </strong>that there are no consecutive repeating characters in the given string <strong>except </strong>for <code>&#39;?&#39;</code>.</p>

<p>Return <em>the final string after all the conversions (possibly zero) have been made</em>. If there is more than one solution, return <strong>any of them</strong>. It can be shown that an answer is always possible with the given constraints.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;?zs&quot;
<strong>Output:</strong> &quot;azs&quot;
<strong>Explanation:</strong> There are 25 solutions for this problem. From &quot;azs&quot; to &quot;yzs&quot;, all are valid. Only &quot;z&quot; is an invalid modification as the string will consist of consecutive repeating characters in &quot;zzs&quot;.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;ubv?w&quot;
<strong>Output:</strong> &quot;ubvaw&quot;
<strong>Explanation:</strong> There are 24 solutions for this problem. Only &quot;v&quot; and &quot;w&quot; are invalid modifications as the strings will consist of consecutive repeating characters in &quot;ubvvw&quot; and &quot;ubvww&quot;.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 100</code></li>
	<li><code>s</code> consist of lowercase English letters and <code>&#39;?&#39;</code>.</li>
</ul>

class Solution:
    def modifyString(self, s: str) -> str:
        # Convert the string to a list to allow modifications
        s = list(s)
        # Define the length of the string
        n = len(s)
        
        # Iterate through each character in the string
        for i in range(n):
            if s[i] == '?':
                # Iterate through possible lowercase letters
                for c in 'abc':
                    # Check the adjacent characters to avoid consecutive repeats
                    if (i > 0 and s[i-1] == c) or (i < n-1 and s[i+1] == c):
                        continue
                    # Assign the character to the current position
                    s[i] = c
                    break
        
        # Convert the list back to a string and return
        return ''.join(s)
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