<p>Given the roots of two binary trees <code>p</code> and <code>q</code>, write a function to check if they are the same or not.</p>

<p>Two binary trees are considered the same if they are structurally identical, and the nodes have the same value.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/12/20/ex1.jpg" style="width: 622px; height: 182px;" />
<pre>
<strong>Input:</strong> p = [1,2,3], q = [1,2,3]
<strong>Output:</strong> true
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/12/20/ex2.jpg" style="width: 382px; height: 182px;" />
<pre>
<strong>Input:</strong> p = [1,2], q = [1,null,2]
<strong>Output:</strong> false
</pre>

<p><strong class="example">Example 3:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2020/12/20/ex3.jpg" style="width: 622px; height: 182px;" />
<pre>
<strong>Input:</strong> p = [1,2,1], q = [1,1,2]
<strong>Output:</strong> false
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in both trees is in the range <code>[0, 100]</code>.</li>
	<li><code>-10<sup>4</sup> &lt;= Node.val &lt;= 10<sup>4</sup></code></li>
</ul>

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def isSameTree(self, p: Optional[TreeNode], q: Optional[TreeNode]) -> bool:
        # structure, and node value
        # dfs 
        # not same return false 
        if not p and not q:  # both empty 
            return True 
        if (p and not q) or (q and not p):
            return False 
        if p and q and p.val != q.val:
            return False 
        return self.isSameTree(p.left, q.left) & self.isSameTree(p.right, q.right)
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