<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution:
    def convert(self, s: str, numRows: int) -> str:
        l=[]
        j=0
        while j<len(s):
            for b in range(1):
                a=[]
                k=0
                while k<numRows:
                    if j<len(s):
                        a.append(s[j])
                        j=j+1
                        k=k+1
                    else:
                        for b in range(k,numRows+1):
                            a.append(" ")
                        l.append(a)
                        print(l)
                        k=0
                        st=""
                        while k<numRows:
                            for i in l:
                                if len(st)<len(s) and i[k]!=" ":
                                    st=st+i[k]
                                    print(i[k])
                                    print(st)
                                    print(len(st))    
                                else:
                                    continue
                            k+=1
                        return st                  
                l.append(a)       
            for i in range(numRows-1,1,-1):
                a=[]
                for m in range(1,numRows+1):
                    if i!=m:
                        a.append(" ")
                    else:
                        if j<len(s):
                            a.append(s[j])
                            j=j+1
                        else:
                            for b in range(m,numRows+1):
                                a.append(" ")
                            l.append(a)
                            k=0
                            st=""
                            while k<numRows:
                                for i in l:
                                    if len(st)<len(s) and i[k]!=" ":
                                        st=st+i[k]
                                    else:
                                        continue
                                    print(len(st))    
                                k+=1
                            return st             
                l.append(a)              
        st=""
        k=0
        while k<numRows:
            for i in l:
                if len(st)<len(s) and i[k]!=" ":
                    st=st+i[k]
                else:
                    continue    
            k=k+1
        return st        
20500