Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>

class Solution:
    def findMinDifference(self, timePoints: List[str]) -> int:
        def time_to_min(t):
            hour,minute=map(int,t.split(":"))
            return 60*hour+minute
        
        exists =[False]*(60*24)
        first_m,last_m=60*24,0
        for t in timePoints:
            m=time_to_min(t)
            if exists[m]:
                return 0
            exists[m]=True
            first_m =min(first_m,m)
            last_m =max(last_m,m)
        res=(60*24-last_m + first_m)
        prev_m=first_m
        for m in range(first_m+1,len(exists)):
            if exists[m]:
                diff= m-prev_m
                res=min(res,diff)
                prev_m=m
        return res
19100