<p>You are given an integer array <code>nums</code> and an integer <code>k</code>.</p>

<p>For each index <code>i</code> where <code>0 &lt;= i &lt; nums.length</code>, change <code>nums[i]</code> to be either <code>nums[i] + k</code> or <code>nums[i] - k</code>.</p>

<p>The <strong>score</strong> of <code>nums</code> is the difference between the maximum and minimum elements in <code>nums</code>.</p>

<p>Return <em>the minimum <strong>score</strong> of </em><code>nums</code><em> after changing the values at each index</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1], k = 0
<strong>Output:</strong> 0
<strong>Explanation:</strong> The score is max(nums) - min(nums) = 1 - 1 = 0.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [0,10], k = 2
<strong>Output:</strong> 6
<strong>Explanation:</strong> Change nums to be [2, 8]. The score is max(nums) - min(nums) = 8 - 2 = 6.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,3,6], k = 3
<strong>Output:</strong> 3
<strong>Explanation:</strong> Change nums to be [4, 6, 3]. The score is max(nums) - min(nums) = 6 - 3 = 3.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= k &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def smallestRangeII(self, nums: List[int], k: int) -> int:
        n = len(nums)
        if (n == 1) :
           return 0 
        nums.sort()
        res = nums[n - 1] - nums[0]
        for i in range(n - 1) :
            mini = min(nums[0] + k, nums[i + 1] - k)
            maxi = max(nums[i] + k, nums[n - 1] - k)
            res = min(res, maxi - mini)
        return res
17700