Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>

class Solution:
    def findMinDifference(self, timePoints: List[str]) -> int:
        for i in range(len(timePoints)):
            formatted=timePoints[i].split(":")
            if formatted[0]=="00":
                formatted[0]="24"
            if formatted[1]=="00":
                formatted[1]="00"
            timePoints[i]=int(int(formatted[0])*60+int(formatted[1]))
        timePoints.sort()
        x=timePoints[0]
        m=sys.maxsize
        for j in range(1,len(timePoints)):
            m=min(m,abs(timePoints[j]-x))
            x=timePoints[j]
        m=min(m,24*60-timePoints[-1]+timePoints[0])
        return m






        
19500