<p>Given a fixed-length integer array <code>arr</code>, duplicate each occurrence of zero, shifting the remaining elements to the right.</p>

<p><strong>Note</strong> that elements beyond the length of the original array are not written. Do the above modifications to the input array in place and do not return anything.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr = [1,0,2,3,0,4,5,0]
<strong>Output:</strong> [1,0,0,2,3,0,0,4]
<strong>Explanation:</strong> After calling your function, the input array is modified to: [1,0,0,2,3,0,0,4]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr = [1,2,3]
<strong>Output:</strong> [1,2,3]
<strong>Explanation:</strong> After calling your function, the input array is modified to: [1,2,3]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr.length &lt;= 10<sup>4</sup></code></li>
	<li><code>0 &lt;= arr[i] &lt;= 9</code></li>
</ul>

class Solution:
    def duplicateZeros(self, arr: List[int]) -> None:
        """
        Do not return anything, modify arr in-place instead.
        """
        indices = []
        
        for index, val in enumerate(arr):
            if val == 0 and index+1 < len(arr)-1:
                indices.append(index)

                
                
        print(indices)

        for ind2, index in enumerate(indices):

            if len(indices)-1 > ind2+1:
                
                if indices[ind2+1] - indices[ind2] == 1:
                    # print(index)
                    index += 1
            
            if len(indices[:ind2]) + index > len(arr):
                # print(index)
                continue
                
            for i in range((len(arr)-1), len(indices[:ind2]) + index, -1):
                
                arr[i] = arr[i-1]
                
        # print(len([9,0,9,0,6,0,0,0,1,1,6,5,4,4,8,3,0,0,0,1,5,3,0,0,7,2,1,0,2,0,9,1,0,2,0,0,0,0,0,0,0,6,0,0,7,9,0,8,7,0,9,7,1,0,2,0,0,0,0,9,0,0,0,0]))
            
        if len(indices):
            arr[indices[0]] = 0

        

        
17200