<p>Given a <code>m&nbsp;* n</code>&nbsp;matrix <code>seats</code>&nbsp;&nbsp;that represent seats distributions&nbsp;in a classroom.&nbsp;If a seat&nbsp;is&nbsp;broken, it is denoted by <code>&#39;#&#39;</code> character otherwise it is denoted by a <code>&#39;.&#39;</code> character.</p>

<p>Students can see the answers of those sitting next to the left, right, upper left and upper right, but he cannot see the answers of the student sitting&nbsp;directly in front or behind him. Return the <strong>maximum </strong>number of students that can take the exam together&nbsp;without any cheating being possible.</p>

<p>Students must be placed in seats in good condition.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img height="200" src="https://assets.leetcode.com/uploads/2020/01/29/image.png" width="339" />
<pre>
<strong>Input:</strong> seats = [[&quot;#&quot;,&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 4
<strong>Explanation:</strong> Teacher can place 4 students in available seats so they don&#39;t cheat on the exam. 
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> seats = [[&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;#&quot;,&quot;#&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;],
&nbsp;               [&quot;#&quot;,&quot;#&quot;],
&nbsp;               [&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 3
<strong>Explanation:</strong> Place all students in available seats. 

</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> seats = [[&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 10
<strong>Explanation:</strong> Place students in available seats in column 1, 3 and 5.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>seats</code>&nbsp;contains only characters&nbsp;<code>&#39;.&#39;<font face="sans-serif, Arial, Verdana, Trebuchet MS">&nbsp;and</font></code><code>&#39;#&#39;.</code></li>
	<li><code>m ==&nbsp;seats.length</code></li>
	<li><code>n ==&nbsp;seats[i].length</code></li>
	<li><code>1 &lt;= m &lt;= 8</code></li>
	<li><code>1 &lt;= n &lt;= 8</code></li>
</ul>

class Solution:
    def maxStudents(self, seats: List[List[str]]) -> int:

        def isSingleRowCompliant(status: int, row: int) -> bool:
            for j in range(n):
                if ((status >> j) & 1) == 1:
                    if seats[row][j] == '#':
                        return False
                    if j > 0 and ((status >> (j - 1)) & 1) == 1:
                        return False
            return True

        def isCrossRowsCompliant(status: int, upperRowStatus: int) -> bool:
            for j in range(n):
                if ((status >> j) & 1) == 1:
                    if j > 0 and ((upperRowStatus >> (j - 1)) & 1) == 1:
                        return False
                    if j < n - 1 and ((upperRowStatus >> (j + 1)) & 1) == 1:
                        return False
            return True

        @cache
        def dp(row: int, status: int) -> int:
            if not isSingleRowCompliant(status, row):
                return -inf
            students = bin(status).count('1')
            if row == 0:
                return students
            mx = 0
            for upperRowStatus in range(2 ** n):
                if isCrossRowsCompliant(status, upperRowStatus):
                    mx = max(mx, dp(row - 1, upperRowStatus))
            return students + mx

        m, n = len(seats), len(seats[0])
        mx = 0
        for i in range(2 ** n):
            mx = max(mx, dp(m - 1, i))
        return mx

17800