<p>Given two strings <code>s</code> and <code>goal</code>, return <code>true</code> <em>if and only if</em> <code>s</code> <em>can become</em> <code>goal</code> <em>after some number of <strong>shifts</strong> on</em> <code>s</code>.</p>

<p>A <strong>shift</strong> on <code>s</code> consists of moving the leftmost character of <code>s</code> to the rightmost position.</p>

<ul>
	<li>For example, if <code>s = &quot;abcde&quot;</code>, then it will be <code>&quot;bcdea&quot;</code> after one shift.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> s = "abcde", goal = "cdeab"
<strong>Output:</strong> true
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> s = "abcde", goal = "abced"
<strong>Output:</strong> false
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length, goal.length &lt;= 100</code></li>
	<li><code>s</code> and <code>goal</code> consist of lowercase English letters.</li>
</ul>

class Solution:
    def rotateString(self, s: str, goal: str) -> bool:
        return len(s)==len(goal) and s in goal+goal
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