<p>Given a string <code>s</code>, reverse only all the vowels in the string and return it.</p>

<p>The vowels are <code>&#39;a&#39;</code>, <code>&#39;e&#39;</code>, <code>&#39;i&#39;</code>, <code>&#39;o&#39;</code>, and <code>&#39;u&#39;</code>, and they can appear in both lower and upper cases, more than once.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;IceCreAm&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;AceCreIm&quot;</span></p>

<p><strong>Explanation:</strong></p>

<p>The vowels in <code>s</code> are <code>[&#39;I&#39;, &#39;e&#39;, &#39;e&#39;, &#39;A&#39;]</code>. On reversing the vowels, s becomes <code>&quot;AceCreIm&quot;</code>.</p>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;leetcode&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;leotcede&quot;</span></p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 3 * 10<sup>5</sup></code></li>
	<li><code>s</code> consist of <strong>printable ASCII</strong> characters.</li>
</ul>

class Solution:
    def reverseVowels(self, s: str) -> str:
        vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
        new_s = ["" for _ in range(len(s))]
        l, r = 0, len(s) - 1

        while l <= r:
            if s[l] not in vowels:
                new_s[l] = s[l]
                l += 1
                continue 

            if s[r] not in vowels:
                new_s[r] = s[r]
                r -= 1
                continue
                
            new_s[l], new_s[r] = s[r], s[l]
            l += 1
            r -= 1
            
        return "".join(new_s)
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