<p>Solve a given equation and return the value of <code>&#39;x&#39;</code> in the form of a string <code>&quot;x=#value&quot;</code>. The equation contains only <code>&#39;+&#39;</code>, <code>&#39;-&#39;</code> operation, the variable <code>&#39;x&#39;</code> and its coefficient. You should return <code>&quot;No solution&quot;</code> if there is no solution for the equation, or <code>&quot;Infinite solutions&quot;</code> if there are infinite solutions for the equation.</p>

<p>If there is exactly one solution for the equation, we ensure that the value of <code>&#39;x&#39;</code> is an integer.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> equation = &quot;x+5-3+x=6+x-2&quot;
<strong>Output:</strong> &quot;x=2&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> equation = &quot;x=x&quot;
<strong>Output:</strong> &quot;Infinite solutions&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> equation = &quot;2x=x&quot;
<strong>Output:</strong> &quot;x=0&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>3 &lt;= equation.length &lt;= 1000</code></li>
	<li><code>equation</code> has exactly one <code>&#39;=&#39;</code>.</li>
	<li><code>equation</code> consists of integers with an absolute value in the range <code>[0, 100]</code> without any leading zeros, and the variable <code>&#39;x&#39;</code>.</li>
	<li>The input is generated that if there is a single solution, it will be an integer.</li>
</ul>

def conv(eq):
    x = 0
    c = 0
    s = ''
    for ch in (eq+'+').replace('-', '+-'):
        if ch=='+':
            if s=='':
                pass
            else:
                if s[-1] == 'x':
                    if s == 'x':
                        x += 1
                    elif s == '-x':
                        x -= 1
                    else:
                        x += int(s[:-1])
                else:
                    c += int(s)
            s = ''
        else:
            s += ch
    return x, c


class Solution:
    def solveEquation(self, equation: str) -> str:
        eq1, eq2 = equation.split('=')
        x1, c1 = conv(eq1)
        x2, c2 = conv(eq2)
        x = x1 - x2
        c = c2 - c1
        if x == 0:
            if c == 0:
                return "Infinite solutions"
            else:
                return "No solution"
        else:
            return f"x={c//x}"
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