<p><strong>No-Zero integer</strong> is a positive integer that <strong>does not contain any <code>0</code></strong> in its decimal representation.</p>

<p>Given an integer <code>n</code>, return <em>a list of two integers</em> <code>[a, b]</code> <em>where</em>:</p>

<ul>
	<li><code>a</code> and <code>b</code> are <strong>No-Zero integers</strong>.</li>
	<li><code>a + b = n</code></li>
</ul>

<p>The test cases are generated so that there is at least one valid solution. If there are many valid solutions, you can return any of them.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 2
<strong>Output:</strong> [1,1]
<strong>Explanation:</strong> Let a = 1 and b = 1.
Both a and b are no-zero integers, and a + b = 2 = n.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 11
<strong>Output:</strong> [2,9]
<strong>Explanation:</strong> Let a = 2 and b = 9.
Both a and b are no-zero integers, and a + b = 9 = n.
Note that there are other valid answers as [8, 3] that can be accepted.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= n &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def getNoZeroIntegers(self, n: int) -> List[int]:
        lista=[]

        a=n//2
        while '0' in str(a) or '0' in str(abs(n-a)):
            a=a//2
        lista.append(a)
        lista.append(abs(n-a))
        return lista
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