<p>You are given two integer arrays of equal length <code>target</code> and <code>arr</code>. In one step, you can select any <strong>non-empty subarray</strong> of <code>arr</code> and reverse it. You are allowed to make any number of steps.</p>

<p>Return <code>true</code> <em>if you can make </em><code>arr</code><em> equal to </em><code>target</code><em>&nbsp;or </em><code>false</code><em> otherwise</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> target = [1,2,3,4], arr = [2,4,1,3]
<strong>Output:</strong> true
<strong>Explanation:</strong> You can follow the next steps to convert arr to target:
1- Reverse subarray [2,4,1], arr becomes [1,4,2,3]
2- Reverse subarray [4,2], arr becomes [1,2,4,3]
3- Reverse subarray [4,3], arr becomes [1,2,3,4]
There are multiple ways to convert arr to target, this is not the only way to do so.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> target = [7], arr = [7]
<strong>Output:</strong> true
<strong>Explanation:</strong> arr is equal to target without any reverses.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> target = [3,7,9], arr = [3,7,11]
<strong>Output:</strong> false
<strong>Explanation:</strong> arr does not have value 9 and it can never be converted to target.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>target.length == arr.length</code></li>
	<li><code>1 &lt;= target.length &lt;= 1000</code></li>
	<li><code>1 &lt;= target[i] &lt;= 1000</code></li>
	<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def canBeEqual(self, target: List[int], arr: List[int]) -> bool:
        # easy solution
        # return sorted(target) == sorted(arr)
# ============================
        # return Counter(target) == Counter(arr)
# ============================
        # freq = Counter(arr)
        # for num in target:
        #     if num not in freq or not freq[num]:
        #         return False
        #     freq[num] -= 1
        # return True
# ===============================
        arr.sort()
        target.sort()
        for x in range(len(arr)):
            if arr[x] != target[x]:
                return False
        
        return True


        


        
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