<p>Given a string <code>s</code> containing an out-of-order English representation of digits <code>0-9</code>, return <em>the digits in <strong>ascending</strong> order</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> s = "owoztneoer"
<strong>Output:</strong> "012"
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> s = "fviefuro"
<strong>Output:</strong> "45"
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>
	<li><code>s[i]</code> is one of the characters <code>[&quot;e&quot;,&quot;g&quot;,&quot;f&quot;,&quot;i&quot;,&quot;h&quot;,&quot;o&quot;,&quot;n&quot;,&quot;s&quot;,&quot;r&quot;,&quot;u&quot;,&quot;t&quot;,&quot;w&quot;,&quot;v&quot;,&quot;x&quot;,&quot;z&quot;]</code>.</li>
	<li><code>s</code> is <strong>guaranteed</strong> to be valid.</li>
</ul>

from collections import Counter

class Solution:
    def originalDigits(self, s: str) -> str:
        digits = {
            "0": "zero", # z
            "2": "two", # w
            "4": "four", # u
            "6": "six", # x
            "8": "eight", # g
            
            "1": "one", # o
            "5": "five", # f
            "7": "seven", # s
            "3": "three", # t
            "9": "nine"
        }
        ctr = Counter(s)
        result = ""
        for d, ds in digits.items():
            ctrd = Counter(ds)
            while not len(ctrd - ctr):
                ctr -= ctrd
                result += d
        return "".join(sorted(result))

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