<p>Given two integer arrays <code>arr1</code> and <code>arr2</code>, and the integer <code>d</code>, <em>return the distance value between the two arrays</em>.</p>

<p>The distance value is defined as the number of elements <code>arr1[i]</code> such that there is not any element <code>arr2[j]</code> where <code>|arr1[i]-arr2[j]| &lt;= d</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
<strong>Output:</strong> 2
<strong>Explanation:</strong> 
For arr1[0]=4 we have: 
|4-10|=6 &gt; d=2 
|4-9|=5 &gt; d=2 
|4-1|=3 &gt; d=2 
|4-8|=4 &gt; d=2 
For arr1[1]=5 we have: 
|5-10|=5 &gt; d=2 
|5-9|=4 &gt; d=2 
|5-1|=4 &gt; d=2 
|5-8|=3 &gt; d=2
For arr1[2]=8 we have:
<strong>|8-10|=2 &lt;= d=2</strong>
<strong>|8-9|=1 &lt;= d=2</strong>
|8-1|=7 &gt; d=2
<strong>|8-8|=0 &lt;= d=2</strong>
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
<strong>Output:</strong> 2
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr1.length, arr2.length &lt;= 500</code></li>
	<li><code>-1000 &lt;= arr1[i], arr2[j] &lt;= 1000</code></li>
	<li><code>0 &lt;= d &lt;= 100</code></li>
</ul>

class Solution:
    def findTheDistanceValue(self, arr1: List[int], arr2: List[int], d: int) -> int:
        count=0
        for num in arr1:
            for num2 in arr2:
                if abs(num-num2)<=d:
                    count+=1
                    break
        return len(arr1)-count
16300