<p>Given an integer <code>n</code>, return <strong>any</strong> array containing <code>n</code> <strong>unique</strong> integers such that they add up to <code>0</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 5
<strong>Output:</strong> [-7,-1,1,3,4]
<strong>Explanation:</strong> These arrays also are accepted [-5,-1,1,2,3] , [-3,-1,2,-2,4].
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 3
<strong>Output:</strong> [-1,0,1]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> n = 1
<strong>Output:</strong> [0]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 1000</code></li>
</ul>

class Solution:
    def sumZero(self, n: int) -> List[int]:
        ans = []
        if n%2==0:
            pass
        else:
            ans.append(0)
            n = n-1
        for i in range(n//2):
            k =i+1
            ans.append(k)
            ans.append(-k) 
        return ans
        
        
16500