<p>You are given two integer arrays <code>nums1</code> and <code>nums2</code> of lengths <code>m</code> and <code>n</code> respectively. <code>nums1</code> and <code>nums2</code> represent the digits of two numbers. You are also given an integer <code>k</code>.</p>

<p>Create the maximum number of length <code>k &lt;= m + n</code> from digits of the two numbers. The relative order of the digits from the same array must be preserved.</p>

<p>Return an array of the <code>k</code> digits representing the answer.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [3,4,6,5], nums2 = [9,1,2,5,8,3], k = 5
<strong>Output:</strong> [9,8,6,5,3]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [6,7], nums2 = [6,0,4], k = 5
<strong>Output:</strong> [6,7,6,0,4]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [3,9], nums2 = [8,9], k = 3
<strong>Output:</strong> [9,8,9]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == nums1.length</code></li>
	<li><code>n == nums2.length</code></li>
	<li><code>1 &lt;= m, n &lt;= 500</code></li>
	<li><code>0 &lt;= nums1[i], nums2[i] &lt;= 9</code></li>
	<li><code>1 &lt;= k &lt;= m + n</code></li>
</ul>

def max_number_from_single_array(nums, k):
    stack = []
    to_pop = len(nums) - k
    
    for num in nums:
        while to_pop > 0 and stack and stack[-1] < num:
            stack.pop()
            to_pop -= 1
        stack.append(num)
    
    return stack[:k]

def merge(nums1, nums2):
    result = []
    while nums1 or nums2:
        if nums1 > nums2:
            result.append(nums1[0])
            nums1 = nums1[1:]
        else:
            result.append(nums2[0])
            nums2 = nums2[1:]
    return result

def max_number(nums1, nums2, k):
    m, n = len(nums1), len(nums2)
    max_result = [0] * k
    
    for i in range(max(0, k - n), min(k, m) + 1):
        j = k - i
        max1 = max_number_from_single_array(nums1, i)
        max2 = max_number_from_single_array(nums2, j)
        merged = merge(max1, max2)
        max_result = max(max_result, merged)
    
    return max_result

class Solution:
    def maxNumber(self, nums1: List[int], nums2: List[int], k: int) -> List[int]:
        return max_number(nums1, nums2, k)


# Example usage
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