<p>Given an integer array <code>nums</code>, return <em>the <strong>maximum possible sum </strong>of elements of the array such that it is divisible by three</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,6,5,1,8]
<strong>Output:</strong> 18
<strong>Explanation:</strong> Pick numbers 3, 6, 1 and 8 their sum is 18 (maximum sum divisible by 3).</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [4]
<strong>Output:</strong> 0
<strong>Explanation:</strong> Since 4 is not divisible by 3, do not pick any number.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4,4]
<strong>Output:</strong> 12
<strong>Explanation:</strong> Pick numbers 1, 3, 4 and 4 their sum is 12 (maximum sum divisible by 3).
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 4 * 10<sup>4</sup></code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def maxSumDivThree(self, nums: List[int]) -> int:
        sample1=[]
        sample2=[]
        
        if (sum(nums)%3 ==0):
            return sum(nums)
        else :   
            
            for x in range (0, len(nums)):
                if (nums[x] %3 == 1):
                    sample1.append(nums[x])
                elif (nums[x] % 3  == 2):
                    sample2.append(nums[x])
            sample1.sort()
            sample2.sort()
            remainder=sum(nums)%3
            if (remainder == 1):
                option1=sum(nums)-sample1[0] if sample1 else -1
                option2=sum(nums)-sum(sample2[:2]) if len(sample2) >= 2 else -1
                return (max(option1 , option2))

            elif (remainder == 2):
                option1=sum(nums)-sample2[0] if sample2 else -1
                option2=sum(nums)-sum(sample1[:2]) if len(sample1) >= 2 else -1
                return max(option1,option2)    
            
           
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