<p>You are given an integer array <code>nums</code>.</p>

<p>You should move each element of <code>nums</code> into one of the two arrays <code>A</code> and <code>B</code> such that <code>A</code> and <code>B</code> are non-empty, and <code>average(A) == average(B)</code>.</p>

<p>Return <code>true</code> if it is possible to achieve that and <code>false</code> otherwise.</p>

<p><strong>Note</strong> that for an array <code>arr</code>, <code>average(arr)</code> is the sum of all the elements of <code>arr</code> over the length of <code>arr</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4,5,6,7,8]
<strong>Output:</strong> true
<strong>Explanation:</strong> We can split the array into [1,4,5,8] and [2,3,6,7], and both of them have an average of 4.5.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,1]
<strong>Output:</strong> false
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 30</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def splitArraySameAverage(self, nums: List[int]) -> bool:
        n = len(nums)
        if n < 2:
            return False
        tgt = sum(nums)
        l1 = []
        l2 = []
        for i, v in enumerate(nums):
            u = v*n - tgt
            if i % 2 == 0:
                l1.append(u)
            else:
                l2.append(-u)
        #print(l1, l2)
        s1s = set()
        rmv = sum(l1)
        if rmv == 0:
            return True
        for v in l1:
            adds = set()
            for u in s1s:
                if rmv is not None and u+v == rmv:
                    rmv = None
                    continue
                adds.add(u+v)
            u = 0
            if rmv is not None and u+v == rmv:
                rmv = None
            else:
                adds.add(u+v)
            s1s.update(adds)
        if 0 in s1s:
            return True
        #print(s1s)
        
        s2s = set()
        rmv = sum(l2)
        if rmv == 0:
            return True
        for v in l2:
            adds = set()
            for u in s2s:
                if rmv is not None and u+v == rmv:
                    rmv = None
                    continue
                adds.add(u+v)
            u = 0
            if rmv is not None and u+v == rmv:
                rmv = None
            else:
                adds.add(u+v)
            s2s.update(adds)
        if 0 in s2s:
            return True
        
        for v in s2s:
            if v in s1s:
                return True
        return False
        
23020