<p>A <strong>self-dividing number</strong> is a number that is divisible by every digit it contains.</p>

<ul>
	<li>For example, <code>128</code> is <strong>a self-dividing number</strong> because <code>128 % 1 == 0</code>, <code>128 % 2 == 0</code>, and <code>128 % 8 == 0</code>.</li>
</ul>

<p>A <strong>self-dividing number</strong> is not allowed to contain the digit zero.</p>

<p>Given two integers <code>left</code> and <code>right</code>, return <em>a list of all the <strong>self-dividing numbers</strong> in the range</em> <code>[left, right]</code> (both <strong>inclusive</strong>).</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> left = 1, right = 22
<strong>Output:</strong> [1,2,3,4,5,6,7,8,9,11,12,15,22]
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> left = 47, right = 85
<strong>Output:</strong> [48,55,66,77]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= left &lt;= right &lt;= 10<sup>4</sup></code></li>
</ul>

class Solution:
    def selfDividingNumbers(self, left: int, right: int) -> List[int]:
        def test(l):
            if "0" in str(l):
                return False
            i = 0
            while i<len(str(l)):
                if l%int(str(l)[i])!=0:
                    return False
                i+=1
            return True
        res = []
        for i in range(left,right+1):
            if test(i):
                res.append(i)
        return res
        
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