<p>Given two arrays <code>arr1</code> and <code>arr2</code>, the elements of <code>arr2</code> are distinct, and all elements in <code>arr2</code> are also in <code>arr1</code>.</p>

<p>Sort the elements of <code>arr1</code> such that the relative ordering of items in <code>arr1</code> are the same as in <code>arr2</code>. Elements that do not appear in <code>arr2</code> should be placed at the end of <code>arr1</code> in <strong>ascending</strong> order.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6]
<strong>Output:</strong> [2,2,2,1,4,3,3,9,6,7,19]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [28,6,22,8,44,17], arr2 = [22,28,8,6]
<strong>Output:</strong> [22,28,8,6,17,44]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr1.length, arr2.length &lt;= 1000</code></li>
	<li><code>0 &lt;= arr1[i], arr2[i] &lt;= 1000</code></li>
	<li>All the elements of <code>arr2</code> are <strong>distinct</strong>.</li>
	<li>Each&nbsp;<code>arr2[i]</code> is in <code>arr1</code>.</li>
</ul>

class Solution:
    def relativeSortArray(self, arr1: List[int], arr2: List[int]) -> List[int]:
        counter = {}
        arr3 = [num for num in arr1 if num not in arr2]
        for x in arr1:
            counter[x] = counter.get(x, 0) + 1
        
        arr1 = []
        for y in arr2:
            while counter[y] != 0:
                arr1.append(y)
                counter[y] -= 1

        arr1.extend(sorted(arr3))
        return arr1  

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