<p>Given an array <code>nums</code> of integers, a <em>move</em>&nbsp;consists of choosing any element and <strong>decreasing it by 1</strong>.</p>

<p>An array <code>A</code> is a&nbsp;<em>zigzag array</em>&nbsp;if either:</p>

<ul>
	<li>Every even-indexed element is greater than adjacent elements, ie.&nbsp;<code>A[0] &gt; A[1] &lt; A[2] &gt; A[3] &lt; A[4] &gt; ...</code></li>
	<li>OR, every odd-indexed element is greater than adjacent elements, ie.&nbsp;<code>A[0] &lt; A[1] &gt; A[2] &lt; A[3] &gt; A[4] &lt; ...</code></li>
</ul>

<p>Return the minimum number of moves to transform the given array <code>nums</code> into a zigzag array.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3]
<strong>Output:</strong> 2
<strong>Explanation:</strong> We can decrease 2 to 0 or 3 to 1.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [9,6,1,6,2]
<strong>Output:</strong> 4
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 1000</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def movesToMakeZigzag(self, nums: List[int]) -> int:
        def calculate_moves(start: int) -> int:
            moves = 0
            for i in range(start, len(nums), 2):
                left = nums[i - 1] if i - 1 >= 0 else float('inf')
                right = nums[i + 1] if i + 1 < len(nums) else float('inf')
                decrease_to = min(left, right) - 1
                if nums[i] >= decrease_to:
                    moves += nums[i] - decrease_to
            return moves

        return min(calculate_moves(0), calculate_moves(1))
16500