<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution:


    def convert(self, s: str, numRows: int) -> str:
        matrix = []
        s = list(s)
        while True:
            init = s[0:numRows]
            s = s[numRows:]
            matrix.append(list(init))
            for r in [x+1 for x in range(numRows)][::-1]:
                if r-1 == 1:
                    break
                elif len(s)==0:
                    break
                else:
                    addin = ['' for x in range(numRows-1)]
                    let = s[0]
                    s = s[1:]
                    addin.insert(r-2, let)
                    matrix.append(addin)
            
            if len(s) == 0:
                break

        response = []
        for n in range(numRows):
            for x in matrix:
                if len(x)-1 < n:
                    response.append('')
                else:
                    response.append(x[n])
        
        response = [x for x in response if x != '']
        return ''.join(response)



        
        
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