<p>Given an array of integers <code>nums</code> sorted in non-decreasing order, find the starting and ending position of a given <code>target</code> value.</p>

<p>If <code>target</code> is not found in the array, return <code>[-1, -1]</code>.</p>

<p>You must&nbsp;write an algorithm with&nbsp;<code>O(log n)</code> runtime complexity.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> nums = [5,7,7,8,8,10], target = 8
<strong>Output:</strong> [3,4]
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> nums = [5,7,7,8,8,10], target = 6
<strong>Output:</strong> [-1,-1]
</pre><p><strong class="example">Example 3:</strong></p>
<pre><strong>Input:</strong> nums = [], target = 0
<strong>Output:</strong> [-1,-1]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>0 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>-10<sup>9</sup>&nbsp;&lt;= nums[i]&nbsp;&lt;= 10<sup>9</sup></code></li>
	<li><code>nums</code> is a non-decreasing array.</li>
	<li><code>-10<sup>9</sup>&nbsp;&lt;= target&nbsp;&lt;= 10<sup>9</sup></code></li>
</ul>

class Solution:
    def searchRange(self, nums: List[int], target: int) -> List[int]:
        # Bisect left
        def find_first():
            left, right = 0, len(nums) - 1
            while left <= right:
                mid = left + (right - left) // 2
                if nums[mid] >= target:
                    right = mid - 1
                else:
                    left = mid + 1
            return left

            # Bisect right
        def find_last():
            left, right = 0, len(nums) - 1
            while left <= right:
                mid = left + (right - left) // 2
                if nums[mid] <= target:
                    left = mid + 1
                else:
                    right = mid - 1
            return right

        first = find_first()
        last = find_last()

        if first <= last and first < len(nums) and nums[first] == target:
            return [first, last]

        return [-1, -1]

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