<p>You are given a string <code>s</code> that consists of the digits <code>&#39;1&#39;</code> to <code>&#39;9&#39;</code> and two integers <code>k</code> and <code>minLength</code>.</p>

<p>A partition of <code>s</code> is called <strong>beautiful</strong> if:</p>

<ul>
	<li><code>s</code> is partitioned into <code>k</code> non-intersecting substrings.</li>
	<li>Each substring has a length of <strong>at least</strong> <code>minLength</code>.</li>
	<li>Each substring starts with a <strong>prime</strong> digit and ends with a <strong>non-prime</strong> digit. Prime digits are <code>&#39;2&#39;</code>, <code>&#39;3&#39;</code>, <code>&#39;5&#39;</code>, and <code>&#39;7&#39;</code>, and the rest of the digits are non-prime.</li>
</ul>

<p>Return<em> the number of <strong>beautiful</strong> partitions of </em><code>s</code>. Since the answer may be very large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>

<p>A <strong>substring</strong> is a contiguous sequence of characters within a string.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;23542185131&quot;, k = 3, minLength = 2
<strong>Output:</strong> 3
<strong>Explanation:</strong> There exists three ways to create a beautiful partition:
&quot;2354 | 218 | 5131&quot;
&quot;2354 | 21851 | 31&quot;
&quot;2354218 | 51 | 31&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;23542185131&quot;, k = 3, minLength = 3
<strong>Output:</strong> 1
<strong>Explanation:</strong> There exists one way to create a beautiful partition: &quot;2354 | 218 | 5131&quot;.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;3312958&quot;, k = 3, minLength = 1
<strong>Output:</strong> 1
<strong>Explanation:</strong> There exists one way to create a beautiful partition: &quot;331 | 29 | 58&quot;.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= k, minLength &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of the digits <code>&#39;1&#39;</code> to <code>&#39;9&#39;</code>.</li>
</ul>

class Solution:
    def beautifulPartitions(self, s: str, k: int, minLength: int) -> int:
        MOD = 10**9 + 7
        n = len(s)

        def isPrime(c):
            return c in {'2', '3', '5', '7'}

        # If the first character is not prime or the last character is prime, return 0
        if not isPrime(s[0]) or isPrime(s[-1]):
            return 0

        # Initialize DP table
        dp = [[0] * (k + 1) for _ in range(n + 1)]
        dp[0][0] = 1

        for j in range(1, k + 1):
            prefix_sum = 0
            for i in range(minLength, n + 1):
                if i - minLength >= 0 and not isPrime(s[i-minLength-1]) and isPrime(s[i-minLength]):
                    prefix_sum = (prefix_sum + dp[i-minLength][j-1]) % MOD
                if not isPrime(s[i-1]) and (i == n or isPrime(s[i])):
                    dp[i][j] = prefix_sum

        return dp[n][k]
25900