Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>

class Solution:
    def findMinDifference(self, timePoints):
        """
        :type timePoints: List[str]
        :rtype: int
        """
        minutes = sorted(list((int(i[:2])*60)+int(i[3:]) for i in timePoints))
        print(minutes)
        ans = 1440
        for i in range(len(minutes)-1):
            diff = minutes[i+1] - minutes[i]
            ends = (1440+minutes[0]) - minutes[-1]
            if minutes[i] == 0 and minutes[i+1] > 720:
                diff = 1440 - minutes[i+1]
            if diff < ans:
                ans = diff
            elif ends < ans:
                ans = ends
        return ans        
19800