Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>

def getMinutes(time):
    hours, min = time.split(':')
    return 60 * int(hours) + int(min)
def minuteDiff(time1, time2):
    diff1 = 1440 - time1 + time2
    diff2 = abs(time1 - time2)
    return min(diff1, diff2)
    
class Solution:
    def findMinDifference(self, timePoints: List[str]) -> int:
        sortedTimePoints = sorted([getMinutes(x) for x in timePoints])
        minDiff = 1440
        for i in range(1, len(sortedTimePoints)):
            diff = minuteDiff(sortedTimePoints[i], sortedTimePoints[i-1])
            minDiff = min(diff, minDiff)
        firstAndLastDiff = minuteDiff(sortedTimePoints[-1], sortedTimePoints[0])
        return min(firstAndLastDiff, minDiff)
19900