<p>Given an integer <code>n</code> represented as a string, return <em>the smallest <strong>good base</strong> of</em> <code>n</code>.</p>

<p>We call <code>k &gt;= 2</code> a <strong>good base</strong> of <code>n</code>, if all digits of <code>n</code> base <code>k</code> are <code>1</code>&#39;s.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = &quot;13&quot;
<strong>Output:</strong> &quot;3&quot;
<strong>Explanation:</strong> 13 base 3 is 111.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = &quot;4681&quot;
<strong>Output:</strong> &quot;8&quot;
<strong>Explanation:</strong> 4681 base 8 is 11111.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> n = &quot;1000000000000000000&quot;
<strong>Output:</strong> &quot;999999999999999999&quot;
<strong>Explanation:</strong> 1000000000000000000 base 999999999999999999 is 11.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n</code> is an integer in the range <code>[3, 10<sup>18</sup>]</code>.</li>
	<li><code>n</code> does not contain any leading zeros.</li>
</ul>

class Solution:
  def smallestGoodBase(self, n: str) -> str:
    n = int(n)

    for m in range(int(math.log(n, 2)), 1, -1):
      k = int(n**m**-1)
      if (k**(m + 1) - 1) // (k - 1) == n:
        return str(k)

    return str(n - 1)
16400