<p>You are given a list of&nbsp;<code>preferences</code>&nbsp;for&nbsp;<code>n</code>&nbsp;friends, where <code>n</code> is always <strong>even</strong>.</p>

<p>For each person <code>i</code>,&nbsp;<code>preferences[i]</code>&nbsp;contains&nbsp;a list of friends&nbsp;<strong>sorted</strong> in the <strong>order of preference</strong>. In other words, a friend earlier in the list is more preferred than a friend later in the list.&nbsp;Friends in&nbsp;each list are&nbsp;denoted by integers from <code>0</code> to <code>n-1</code>.</p>

<p>All the friends are divided into pairs.&nbsp;The pairings are&nbsp;given in a list&nbsp;<code>pairs</code>,&nbsp;where <code>pairs[i] = [x<sub>i</sub>, y<sub>i</sub>]</code> denotes <code>x<sub>i</sub></code>&nbsp;is paired with <code>y<sub>i</sub></code> and <code>y<sub>i</sub></code> is paired with <code>x<sub>i</sub></code>.</p>

<p>However, this pairing may cause some of the friends to be unhappy.&nbsp;A friend <code>x</code>&nbsp;is unhappy if <code>x</code>&nbsp;is paired with <code>y</code>&nbsp;and there exists a friend <code>u</code>&nbsp;who&nbsp;is paired with <code>v</code>&nbsp;but:</p>

<ul>
	<li><code>x</code>&nbsp;prefers <code>u</code>&nbsp;over <code>y</code>,&nbsp;and</li>
	<li><code>u</code>&nbsp;prefers <code>x</code>&nbsp;over <code>v</code>.</li>
</ul>

<p>Return <em>the number of unhappy friends</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 4, preferences = [[1, 2, 3], [3, 2, 0], [3, 1, 0], [1, 2, 0]], pairs = [[0, 1], [2, 3]]
<strong>Output:</strong> 2
<strong>Explanation:</strong>
Friend 1 is unhappy because:
- 1 is paired with 0 but prefers 3 over 0, and
- 3 prefers 1 over 2.
Friend 3 is unhappy because:
- 3 is paired with 2 but prefers 1 over 2, and
- 1 prefers 3 over 0.
Friends 0 and 2 are happy.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 2, preferences = [[1], [0]], pairs = [[1, 0]]
<strong>Output:</strong> 0
<strong>Explanation:</strong> Both friends 0 and 1 are happy.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> n = 4, preferences = [[1, 3, 2], [2, 3, 0], [1, 3, 0], [0, 2, 1]], pairs = [[1, 3], [0, 2]]
<strong>Output:</strong> 4
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= n &lt;= 500</code></li>
	<li><code>n</code>&nbsp;is even.</li>
	<li><code>preferences.length&nbsp;== n</code></li>
	<li><code>preferences[i].length&nbsp;== n - 1</code></li>
	<li><code>0 &lt;= preferences[i][j] &lt;= n - 1</code></li>
	<li><code>preferences[i]</code>&nbsp;does not contain <code>i</code>.</li>
	<li>All values in&nbsp;<code>preferences[i]</code>&nbsp;are unique.</li>
	<li><code>pairs.length&nbsp;== n/2</code></li>
	<li><code>pairs[i].length&nbsp;== 2</code></li>
	<li><code>x<sub>i</sub> != y<sub>i</sub></code></li>
	<li><code>0 &lt;= x<sub>i</sub>, y<sub>i</sub>&nbsp;&lt;= n - 1</code></li>
	<li>Each person is contained in <strong>exactly one</strong> pair.</li>
</ul>

class Solution:
    def unhappyFriends(
        self, n: int, preferences: List[List[int]], pairs: List[List[int]]
    ) -> int:

        db = {}

        unhappy_count = 0

        for a, b in pairs:
            db[a] = {
                "pair": b,
                "priority": {
                    priority_person: -priority_val
                    for priority_val, priority_person in enumerate(preferences[a])
                },
            }
            db[b] = {
                "pair": a,
                "priority": {
                    priority_person: -priority_val
                    for priority_val, priority_person in enumerate(preferences[b])
                },
            }

        for person in db:
            pair = db[person]["pair"]

            person_likes_their_pair = db[person]["priority"][pair]

            unhappy = False

            prefered_candidates = [
                candidate
                for candidate in db[person]["priority"]
                if db[person]["priority"][candidate] > person_likes_their_pair
            ]

            for candidate in prefered_candidates:
                candidats_pair = db[candidate]["pair"]

                candidate_likes_their_pair = db[candidate]["priority"][candidats_pair]

                candidate_likes_person = db[candidate]["priority"][person]

                if candidate_likes_person > candidate_likes_their_pair:
                    unhappy = unhappy or True

            if unhappy:
                unhappy_count += 1

        return unhappy_count

    

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