<p>Given an integer array <code>nums</code>, return <code>true</code> if any value appears <strong>at least twice</strong> in the array, and return <code>false</code> if every element is distinct.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,1]</span></p>

<p><strong>Output:</strong> <span class="example-io">true</span></p>

<p><strong>Explanation:</strong></p>

<p>The element 1 occurs at the indices 0 and 3.</p>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,2,3,4]</span></p>

<p><strong>Output:</strong> <span class="example-io">false</span></p>

<p><strong>Explanation:</strong></p>

<p>All elements are distinct.</p>
</div>

<p><strong class="example">Example 3:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">nums = [1,1,1,3,3,4,3,2,4,2]</span></p>

<p><strong>Output:</strong> <span class="example-io">true</span></p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
</ul>

class Solution:
    def containsDuplicate(self, nums: List[int]) -> bool:
        nums_dict = {}

        for i in range(len(nums)):
            if nums[i] in nums_dict:
                return True
            else:
                nums_dict[nums[i]] = 1
        return False
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