<p>You are given an integer <code>n</code> and an integer <code>start</code>.</p>

<p>Define an array <code>nums</code> where <code>nums[i] = start + 2 * i</code> (<strong>0-indexed</strong>) and <code>n == nums.length</code>.</p>

<p>Return <em>the bitwise XOR of all elements of</em> <code>nums</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 5, start = 0
<strong>Output:</strong> 8
<strong>Explanation:</strong> Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.
Where &quot;^&quot; corresponds to bitwise XOR operator.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 4, start = 3
<strong>Output:</strong> 8
<strong>Explanation:</strong> Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= n &lt;= 1000</code></li>
	<li><code>0 &lt;= start &lt;= 1000</code></li>
	<li><code>n == nums.length</code></li>
</ul>

class Solution:
    def xorOperation(self, n: int, start: int) -> int:
        i = 0
        for j in range(0,n):
            number = start + (2*j)
            i = i ^ number
        return i
        
16400