<p>Given two arrays of integers with equal lengths, return the maximum value of:</p>

<p><code>|arr1[i] - arr1[j]| + |arr2[i] - arr2[j]| + |i - j|</code></p>

<p>where the maximum is taken over all <code>0 &lt;= i, j &lt; arr1.length</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,2,3,4], arr2 = [-1,4,5,6]
<strong>Output:</strong> 13
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,-2,-5,0,10], arr2 = [0,-2,-1,-7,-4]
<strong>Output:</strong> 20
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= arr1.length == arr2.length &lt;= 40000</code></li>
	<li><code>-10^6 &lt;= arr1[i], arr2[i] &lt;= 10^6</code></li>
</ul>

class Solution:
    def maxAbsValExpr(self, arr1, arr2):
        n = len(arr1)
        max1, max2, max3, max4 = -float('inf'), -float('inf'), -float('inf'), -float('inf')
        min1, min2, min3, min4 = float('inf'), float('inf'), float('inf'), float('inf')

        for i in range(n):
            max1 = max(max1, arr1[i] + arr2[i] + i)
            max2 = max(max2, arr1[i] + arr2[i] - i)
            max3 = max(max3, arr1[i] - arr2[i] + i)
            max4 = max(max4, arr1[i] - arr2[i] - i)

            min1 = min(min1, arr1[i] + arr2[i] + i)
            min2 = min(min2, arr1[i] + arr2[i] - i)
            min3 = min(min3, arr1[i] - arr2[i] + i)
            min4 = min(min4, arr1[i] - arr2[i] - i)

        return max(max1 - min1, max2 - min2, max3 - min3, max4 - min4)

# Example usage:
# sol = Solution()
# print(sol.maxAbsValExpr([1, 2, 3, 4], [-1, 4, 5, 6]))  # Output: 13
# print(sol.maxAbsValExpr([1, -2, -5, 0, 10], [0, -2, -1, -7, -4]))  # Output: 20
23300