<p>You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security systems connected and <b>it will automatically contact the police if two adjacent houses were broken into on the same night</b>.</p>

<p>Given an integer array <code>nums</code> representing the amount of money of each house, return <em>the maximum amount of money you can rob tonight <b>without alerting the police</b></em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,1]
<strong>Output:</strong> 4
<strong>Explanation:</strong> Rob house 1 (money = 1) and then rob house 3 (money = 3).
Total amount you can rob = 1 + 3 = 4.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [2,7,9,3,1]
<strong>Output:</strong> 12
<strong>Explanation:</strong> Rob house 1 (money = 2), rob house 3 (money = 9) and rob house 5 (money = 1).
Total amount you can rob = 2 + 9 + 1 = 12.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 100</code></li>
	<li><code>0 &lt;= nums[i] &lt;= 400</code></li>
</ul>

class Solution:
    def rob(self, nums: List[int]) -> int:

        if not nums: 
            return 0 

        n = len(nums)
        dp = [0] * (n+1) 
        dp[n], dp[n-1] = 0, nums[n-1]
        for i in range(n-2, -1, -1):
            dp[i] = max(dp[i+1], dp[i+2]+nums[i])

        return dp[0]

        
16600