<p>Given an array of integers <code>nums</code> and an integer <code>threshold</code>, we will choose a positive integer <code>divisor</code>, divide all the array by it, and sum the division&#39;s result. Find the <strong>smallest</strong> <code>divisor</code> such that the result mentioned above is less than or equal to <code>threshold</code>.</p>

<p>Each result of the division is rounded to the nearest integer greater than or equal to that element. (For example: <code>7/3 = 3</code> and <code>10/2 = 5</code>).</p>

<p>The test cases are generated so&nbsp;that there will be an answer.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,5,9], threshold = 6
<strong>Output:</strong> 5
<strong>Explanation:</strong> We can get a sum to 17 (1+2+5+9) if the divisor is 1. 
If the divisor is 4 we can get a sum of 7 (1+1+2+3) and if the divisor is 5 the sum will be 5 (1+1+1+2). 
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [44,22,33,11,1], threshold = 5
<strong>Output:</strong> 44
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>6</sup></code></li>
	<li><code>nums.length &lt;= threshold &lt;= 10<sup>6</sup></code></li>
</ul>

class Solution:
    import math
    def smallestDivisor(self, nums: List[int], threshold: int) -> int:
        def sumdiv(nums,divisor,threshold):
            totalSum = 0
            for i in nums:
                totalSum += math.ceil(i/divisor)

            if totalSum <= threshold:
                return True
            else:
                return False

        low = 1
        high = max(nums)
        
        while(low<=high):
            mid = (low+high)//2
            if (sumdiv(nums,mid,threshold) == True):
                high = mid - 1
            else:
                low = mid+1

        return low
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