<p>Given two strings <code>s</code> and <code>t</code>, return <code>true</code> if <code>t</code> is an <span data-keyword="anagram">anagram</span> of <code>s</code>, and <code>false</code> otherwise.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;anagram&quot;, t = &quot;nagaram&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">true</span></p>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">s = &quot;rat&quot;, t = &quot;car&quot;</span></p>

<p><strong>Output:</strong> <span class="example-io">false</span></p>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length, t.length &lt;= 5 * 10<sup>4</sup></code></li>
	<li><code>s</code> and <code>t</code> consist of lowercase English letters.</li>
</ul>

<p>&nbsp;</p>
<p><strong>Follow up:</strong> What if the inputs contain Unicode characters? How would you adapt your solution to such a case?</p>

class Solution:
    def isAnagram(self, s: str, t: str) -> bool:
        import collections

        s_dict = collections.Counter(s)
        t_dict = collections.Counter(t)

        if len(s) != len(t):
            return False

        for key, value in s_dict.items():
            if not key in t_dict.keys():
                return False
            else:
                if value != t_dict[key]:
                    return False
        return True

         

        
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