<p>Given an <code>m x n</code> integers <code>matrix</code>, return <em>the length of the longest increasing path in </em><code>matrix</code>.</p>

<p>From each cell, you can either move in four directions: left, right, up, or down. You <strong>may not</strong> move <strong>diagonally</strong> or move <strong>outside the boundary</strong> (i.e., wrap-around is not allowed).</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/01/05/grid1.jpg" style="width: 242px; height: 242px;" />
<pre>
<strong>Input:</strong> matrix = [[9,9,4],[6,6,8],[2,1,1]]
<strong>Output:</strong> 4
<strong>Explanation:</strong> The longest increasing path is <code>[1, 2, 6, 9]</code>.
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2021/01/27/tmp-grid.jpg" style="width: 253px; height: 253px;" />
<pre>
<strong>Input:</strong> matrix = [[3,4,5],[3,2,6],[2,2,1]]
<strong>Output:</strong> 4
<strong>Explanation: </strong>The longest increasing path is <code>[3, 4, 5, 6]</code>. Moving diagonally is not allowed.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> matrix = [[1]]
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == matrix.length</code></li>
	<li><code>n == matrix[i].length</code></li>
	<li><code>1 &lt;= m, n &lt;= 200</code></li>
	<li><code>0 &lt;= matrix[i][j] &lt;= 2<sup>31</sup> - 1</code></li>
</ul>

class Solution:
    def longestIncreasingPath(self, matrix: List[List[int]]) -> int:
        if not len(matrix):
            return 0
        maxVal = 0
        rows = len(matrix)
        cols = len(matrix[0])
        cache = [[0 for _ in range(cols)] for _ in range(rows)]
        print(cache)
        for i in range(rows):
            for j in range(cols):
                maxVal = max(maxVal, self.subPath(matrix, i, j, rows, cols, cache))
        return maxVal
        
    def subPath(self, matrix, row, col, rows, cols, cache):
        if cache[row][col] != 0:
            return cache[row][col]
        for x, y in [(1, 0), (-1, 0), (0, 1), (0, -1)]:
            xval = row + x
            yval = col + y
            if xval >= 0 and xval < rows and yval >= 0 and yval < cols and matrix[xval][yval] > matrix[row][col]:
                cache[row][col] = max(cache[row][col], self.subPath(matrix, xval, yval, rows, cols, cache))
        cache[row][col] += 1
        return cache[row][col]
    
17165