<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution:
    def convert(self, s: str, numRows: int) -> str:
        rows = {}
        st = ""
        res = ""
        x = numRows
        m, n = numRows-2, 1
        for i in range(0, numRows):
            rows[i] = ""
        for idx, i in enumerate(s):
            if x == 0:
                # if (m==0) and (n==numRows-1):
                #     m = numRows - 2
                #     n = 1
                if (m!=0) and (n!=numRows-1):
                    ws1 = " "*m
                    ws2 = " "*n
                    st = f"{st}{ws1}{i}{ws2}"
                    m = m-1
                    n = n+1
                else:
                    x = numRows-1
                    st = f"{st}{i}"
                    m, n = numRows-2, 1
            else:
                st = f"{st}{i}"
                x = x-1
            
        for idx, i in enumerate(st):
            rows[divmod(idx, numRows)[1]] += i
        for i in list(rows.keys()):
            res += str("".join(list(rows[i])))
        return res.replace(" ", "")
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