Given an integer array <code>arr</code>, return <code>true</code>&nbsp;if there are three consecutive odd numbers in the array. Otherwise, return&nbsp;<code>false</code>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr = [2,6,4,1]
<strong>Output:</strong> false
<b>Explanation:</b> There are no three consecutive odds.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr = [1,2,34,3,4,5,7,23,12]
<strong>Output:</strong> true
<b>Explanation:</b> [5,7,23] are three consecutive odds.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr.length &lt;= 1000</code></li>
	<li><code>1 &lt;= arr[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def threeConsecutiveOdds(self, arr: List[int]) -> bool:
        cnt = 0
        for i in range(len(arr)):
            if arr[i]%2==1:
                cnt+=1
                if cnt>=3:
                    return True
            else:
                cnt=0
        return False

        
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