<p>Given the <code>head</code> of a linked list, return <em>the node where the cycle begins. If there is no cycle, return </em><code>null</code>.</p>

<p>There is a cycle in a linked list if there is some node in the list that can be reached again by continuously following the <code>next</code> pointer. Internally, <code>pos</code> is used to denote the index of the node that tail&#39;s <code>next</code> pointer is connected to (<strong>0-indexed</strong>). It is <code>-1</code> if there is no cycle. <strong>Note that</strong> <code>pos</code> <strong>is not passed as a parameter</strong>.</p>

<p><strong>Do not modify</strong> the linked list.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist.png" style="height: 145px; width: 450px;" />
<pre>
<strong>Input:</strong> head = [3,2,0,-4], pos = 1
<strong>Output:</strong> tail connects to node index 1
<strong>Explanation:</strong> There is a cycle in the linked list, where tail connects to the second node.
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test2.png" style="height: 105px; width: 201px;" />
<pre>
<strong>Input:</strong> head = [1,2], pos = 0
<strong>Output:</strong> tail connects to node index 0
<strong>Explanation:</strong> There is a cycle in the linked list, where tail connects to the first node.
</pre>

<p><strong class="example">Example 3:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2018/12/07/circularlinkedlist_test3.png" style="height: 65px; width: 65px;" />
<pre>
<strong>Input:</strong> head = [1], pos = -1
<strong>Output:</strong> no cycle
<strong>Explanation:</strong> There is no cycle in the linked list.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of the nodes in the list is in the range <code>[0, 10<sup>4</sup>]</code>.</li>
	<li><code>-10<sup>5</sup> &lt;= Node.val &lt;= 10<sup>5</sup></code></li>
	<li><code>pos</code> is <code>-1</code> or a <strong>valid index</strong> in the linked-list.</li>
</ul>

<p>&nbsp;</p>
<p><strong>Follow up:</strong> Can you solve it using <code>O(1)</code> (i.e. constant) memory?</p>

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution:
    def detectCycle(self, head: Optional[ListNode]) -> Optional[ListNode]:
        temp_map = dict()

        temp = head
        while temp!=None:
            if temp in temp_map:
                return temp 
            temp_map[temp] = True
        
            temp=temp.next
19400