<p>Given two integers representing the <code>numerator</code> and <code>denominator</code> of a fraction, return <em>the fraction in string format</em>.</p>

<p>If the fractional part is repeating, enclose the repeating part in parentheses.</p>

<p>If multiple answers are possible, return <strong>any of them</strong>.</p>

<p>It is <strong>guaranteed</strong> that the length of the answer string is less than <code>10<sup>4</sup></code> for all the given inputs.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> numerator = 1, denominator = 2
<strong>Output:</strong> &quot;0.5&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> numerator = 2, denominator = 1
<strong>Output:</strong> &quot;2&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> numerator = 4, denominator = 333
<strong>Output:</strong> &quot;0.(012)&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-2<sup>31</sup> &lt;=&nbsp;numerator, denominator &lt;= 2<sup>31</sup> - 1</code></li>
	<li><code>denominator != 0</code></li>
</ul>

class Solution:
    def fractionToDecimal(self, numerator: int, denominator: int) -> str:
        if numerator % denominator == 0:
            return str(numerator // denominator)
        
        sign = '-' if (numerator < 0) != (denominator < 0) else ''
        numerator, denominator = abs(numerator), abs(denominator)
        
        result = sign + str(numerator // denominator) + '.'
        numerator %= denominator
        
        i = len(result)
        table = {}
        
        while numerator:
            if numerator in table:
                i = table[numerator]
                result = result[:i] + '(' + result[i:] + ')'
                break
            
            table[numerator] = i
            
            numerator *= 10
            result += str(numerator // denominator)
            numerator %= denominator
            i += 1
            
        if result[-1] == '.':
            result = result[:-1]
        
        return result
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