<p>An element <code>x</code> of an integer array <code>arr</code> of length <code>m</code> is <strong>dominant</strong> if <code>freq(x) * 2 &gt; m</code>, where <code>freq(x)</code> is the number of occurrences of <code>x</code> in <code>arr</code>. Note that this definition implies that <code>arr</code> can have <strong>at most one</strong> dominant element.</p>

<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> of length <code>n</code> with one dominant element.</p>

<p>You can split <code>nums</code> at an index <code>i</code> into two arrays <code>nums[0, ..., i]</code> and <code>nums[i + 1, ..., n - 1]</code>, but the split is only <strong>valid</strong> if:</p>

<ul>
	<li><code>0 &lt;= i &lt; n - 1</code></li>
	<li><code>nums[0, ..., i]</code>, and <code>nums[i + 1, ..., n - 1]</code> have the same dominant element.</li>
</ul>

<p>Here, <code>nums[i, ..., j]</code> denotes the subarray of <code>nums</code> starting at index <code>i</code> and ending at index <code>j</code>, both ends being inclusive. Particularly, if <code>j &lt; i</code> then <code>nums[i, ..., j]</code> denotes an empty subarray.</p>

<p>Return <em>the <strong>minimum</strong> index of a <strong>valid split</strong></em>. If no valid split exists, return <code>-1</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,2,2]
<strong>Output:</strong> 2
<strong>Explanation:</strong> We can split the array at index 2 to obtain arrays [1,2,2] and [2]. 
In array [1,2,2], element 2 is dominant since it occurs twice in the array and 2 * 2 &gt; 3. 
In array [2], element 2 is dominant since it occurs once in the array and 1 * 2 &gt; 1.
Both [1,2,2] and [2] have the same dominant element as nums, so this is a valid split. 
It can be shown that index 2 is the minimum index of a valid split. </pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [2,1,3,1,1,1,7,1,2,1]
<strong>Output:</strong> 4
<strong>Explanation:</strong> We can split the array at index 4 to obtain arrays [2,1,3,1,1] and [1,7,1,2,1].
In array [2,1,3,1,1], element 1 is dominant since it occurs thrice in the array and 3 * 2 &gt; 5.
In array [1,7,1,2,1], element 1 is dominant since it occurs thrice in the array and 3 * 2 &gt; 5.
Both [2,1,3,1,1] and [1,7,1,2,1] have the same dominant element as nums, so this is a valid split.
It can be shown that index 4 is the minimum index of a valid split.</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,3,3,3,7,2,2]
<strong>Output:</strong> -1
<strong>Explanation:</strong> It can be shown that there is no valid split.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>1 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
	<li><code>nums</code> has exactly one dominant element.</li>
</ul>

class Solution:
    def minimumIndex(self, nums: List[int]) -> int:
        n = len(nums)
        def most_frequent(data):
            # Create Counter object, which is a dictionary subclass for counting hashable objects.
            counter = Counter(data)
            
            # Initialize max_count and max_item
            max_count = -1
            max_item = None

            # Iterate over dictionary items
            for item, count in counter.items():
                # Update max_item and max_count if a higher count is found
                if count > max_count:
                    max_count = count
                    max_item = item

            return max_item, max_count
        

        dom, cnt = most_frequent(nums) # returns dominant number and it's count
        left, right = 0, cnt
        for i in range(n):
            if nums[i] == dom:
                left += 1
                right -= 1
            if left * 2 > i + 1 and right * 2 > n - (i + 1):
                return i
        
        return -1
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