<p>You are given an integer <code>num.</code> <strong>Rearrange</strong> the digits of <code>num</code> such that its value is <strong>minimized</strong> and it does not contain <strong>any</strong> leading zeros.</p>

<p>Return <em>the rearranged number with minimal value</em>.</p>

<p>Note that the sign of the number does not change after rearranging the digits.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> num = 310
<strong>Output:</strong> 103
<strong>Explanation:</strong> The possible arrangements for the digits of 310 are 013, 031, 103, 130, 301, 310. 
The arrangement with the smallest value that does not contain any leading zeros is 103.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> num = -7605
<strong>Output:</strong> -7650
<strong>Explanation:</strong> Some possible arrangements for the digits of -7605 are -7650, -6705, -5076, -0567.
The arrangement with the smallest value that does not contain any leading zeros is -7650.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-10<sup>15</sup> &lt;= num &lt;= 10<sup>15</sup></code></li>
</ul>

class Solution:
    def smallestNumber(self, num: int) -> int:
        l=[]
        x=0
        rev=''
        count=0
        n=int(num)
        if n<0:
            f=1
            n*=-1
            num*=-1
        else:
            f=0
        for i in range(len(str(num))):
            r=n%10
            l.append(int(r))
            n/=10
        l.sort()
        if(num==0):
            return 0
        if f==1:
            l.reverse()
            while l[0]==0:
                l.pop(0)
                l.append(0)
            for i in range(len(str(num))):
                rev+=str(l[i])
            return int(rev)*-1
        else:
            while l[0]==0:
                l.pop(0)
                x+=1
            rev+=str(l.pop(0))
            for i in range(x):
                rev+='0'
            for i in l:
                rev+=str(i)
            return int(rev)
16600