<p>You are given a <strong>large integer</strong> represented as an integer array <code>digits</code>, where each <code>digits[i]</code> is the <code>i<sup>th</sup></code> digit of the integer. The digits are ordered from most significant to least significant in left-to-right order. The large integer does not contain any leading <code>0</code>&#39;s.</p>

<p>Increment the large integer by one and return <em>the resulting array of digits</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> digits = [1,2,3]
<strong>Output:</strong> [1,2,4]
<strong>Explanation:</strong> The array represents the integer 123.
Incrementing by one gives 123 + 1 = 124.
Thus, the result should be [1,2,4].
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> digits = [4,3,2,1]
<strong>Output:</strong> [4,3,2,2]
<strong>Explanation:</strong> The array represents the integer 4321.
Incrementing by one gives 4321 + 1 = 4322.
Thus, the result should be [4,3,2,2].
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> digits = [9]
<strong>Output:</strong> [1,0]
<strong>Explanation:</strong> The array represents the integer 9.
Incrementing by one gives 9 + 1 = 10.
Thus, the result should be [1,0].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= digits.length &lt;= 100</code></li>
	<li><code>0 &lt;= digits[i] &lt;= 9</code></li>
	<li><code>digits</code> does not contain any leading <code>0</code>&#39;s.</li>
</ul>

class Solution:
    def plusOne(self, digits: List[int]) -> List[int]:
        a=0
        for i in digits:
            a=(a*10)+i
        l=[]
        a+=1
        while(a>0):
            l.append(int(a%10))
            a=(a//10)
        return l[::-1]
16000