<p>Given two integers representing the <code>numerator</code> and <code>denominator</code> of a fraction, return <em>the fraction in string format</em>.</p>

<p>If the fractional part is repeating, enclose the repeating part in parentheses.</p>

<p>If multiple answers are possible, return <strong>any of them</strong>.</p>

<p>It is <strong>guaranteed</strong> that the length of the answer string is less than <code>10<sup>4</sup></code> for all the given inputs.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> numerator = 1, denominator = 2
<strong>Output:</strong> &quot;0.5&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> numerator = 2, denominator = 1
<strong>Output:</strong> &quot;2&quot;
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> numerator = 4, denominator = 333
<strong>Output:</strong> &quot;0.(012)&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-2<sup>31</sup> &lt;=&nbsp;numerator, denominator &lt;= 2<sup>31</sup> - 1</code></li>
	<li><code>denominator != 0</code></li>
</ul>

class Solution:
    def fractionToDecimal(self, numerator: int, denominator: int) -> str:

        sig = numerator < 0
        sig2 = denominator < 0
        
        numerator = abs(numerator)
        denominator = abs(denominator)
        
        before = numerator//denominator
        res = str(before)
        
        if(numerator % denominator != 0):
            res += "."
        else:
            return res if sig == sig2 or res == "0" else "-" + res
        
        number = numerator%denominator
        
        back = ""
        
        s = {}
        iterr = 0
        while number != 0 and number not in s:
            s[number] = iterr
            iterr += 1
            number *= 10
            k = number//denominator
            
            back += str(k)
            number = number%denominator
            
        # res +=  str(number//denominator)
        result = res + back
        if(number != 0):
            pos = s[number]
            result = res + back[0:pos] + f"({back[pos:]})"
        
        return result if sig == sig2 or result == "0" else "-" + result
        
        
            
        

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