<p>You are given an array <code>words</code> of size <code>n</code> consisting of <strong>non-empty</strong> strings.</p>

<p>We define the <strong>score</strong> of a string <code>word</code> as the <strong>number</strong> of strings <code>words[i]</code> such that <code>word</code> is a <strong>prefix</strong> of <code>words[i]</code>.</p>

<ul>
	<li>For example, if <code>words = [&quot;a&quot;, &quot;ab&quot;, &quot;abc&quot;, &quot;cab&quot;]</code>, then the score of <code>&quot;ab&quot;</code> is <code>2</code>, since <code>&quot;ab&quot;</code> is a prefix of both <code>&quot;ab&quot;</code> and <code>&quot;abc&quot;</code>.</li>
</ul>

<p>Return <em>an array </em><code>answer</code><em> of size </em><code>n</code><em> where </em><code>answer[i]</code><em> is the <strong>sum</strong> of scores of every <strong>non-empty</strong> prefix of </em><code>words[i]</code>.</p>

<p><strong>Note</strong> that a string is considered as a prefix of itself.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;abc&quot;,&quot;ab&quot;,&quot;bc&quot;,&quot;b&quot;]
<strong>Output:</strong> [5,4,3,2]
<strong>Explanation:</strong> The answer for each string is the following:
- &quot;abc&quot; has 3 prefixes: &quot;a&quot;, &quot;ab&quot;, and &quot;abc&quot;.
- There are 2 strings with the prefix &quot;a&quot;, 2 strings with the prefix &quot;ab&quot;, and 1 string with the prefix &quot;abc&quot;.
The total is answer[0] = 2 + 2 + 1 = 5.
- &quot;ab&quot; has 2 prefixes: &quot;a&quot; and &quot;ab&quot;.
- There are 2 strings with the prefix &quot;a&quot;, and 2 strings with the prefix &quot;ab&quot;.
The total is answer[1] = 2 + 2 = 4.
- &quot;bc&quot; has 2 prefixes: &quot;b&quot; and &quot;bc&quot;.
- There are 2 strings with the prefix &quot;b&quot;, and 1 string with the prefix &quot;bc&quot;.
The total is answer[2] = 2 + 1 = 3.
- &quot;b&quot; has 1 prefix: &quot;b&quot;.
- There are 2 strings with the prefix &quot;b&quot;.
The total is answer[3] = 2.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> words = [&quot;abcd&quot;]
<strong>Output:</strong> [4]
<strong>Explanation:</strong>
&quot;abcd&quot; has 4 prefixes: &quot;a&quot;, &quot;ab&quot;, &quot;abc&quot;, and &quot;abcd&quot;.
Each prefix has a score of one, so the total is answer[0] = 1 + 1 + 1 + 1 = 4.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= words.length &lt;= 1000</code></li>
	<li><code>1 &lt;= words[i].length &lt;= 1000</code></li>
	<li><code>words[i]</code> consists of lowercase English letters.</li>
</ul>

class Solution:
    def sumPrefixScores(self, words: List[str]) -> List[int]:
        class Trie_node():
            def __init__(self):
                self.children=[None for i in range(26)]
                self.count=0
                
        
        def add_word(root,word):
            cur=root
            for i in range(len(word)):
                child_ind=ord(word[i])-ord('a')
                if cur.children[child_ind]:
                    cur=cur.children[child_ind]
                    cur.count+=1
                else:
                    new_node=Trie_node()
                    cur.children[child_ind]=new_node
                    cur=cur.children[child_ind]
                    cur.count+=1
        
        def get_score(root,word):
            cur=root
            cur_ans=0
            for i in range(len(word)):
                child_ind=ord(word[i])-ord('a')
                if cur.children[child_ind]:
                    cur_ans+=cur.count
                    cur=cur.children[child_ind]
                else:
                    return 0
            return cur_ans+cur.count



        
        root=Trie_node()
        for word in words:
            add_word(root,word)

        ans=[]
        for word in words:
            cur=get_score(root,word)
            ans.append(cur)
        
        return ans
                



    


            

        
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