<p>Given a 2D <code>grid</code> of size <code>m x n</code>&nbsp;and an integer <code>k</code>. You need to shift the <code>grid</code>&nbsp;<code>k</code> times.</p>

<p>In one shift operation:</p>

<ul>
	<li>Element at <code>grid[i][j]</code> moves to <code>grid[i][j + 1]</code>.</li>
	<li>Element at <code>grid[i][n - 1]</code> moves to <code>grid[i + 1][0]</code>.</li>
	<li>Element at <code>grid[m&nbsp;- 1][n - 1]</code> moves to <code>grid[0][0]</code>.</li>
</ul>

<p>Return the <em>2D grid</em> after applying shift operation <code>k</code> times.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/11/05/e1.png" style="width: 400px; height: 178px;" />
<pre>
<strong>Input:</strong> <code>grid</code> = [[1,2,3],[4,5,6],[7,8,9]], k = 1
<strong>Output:</strong> [[9,1,2],[3,4,5],[6,7,8]]
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://assets.leetcode.com/uploads/2019/11/05/e2.png" style="width: 400px; height: 166px;" />
<pre>
<strong>Input:</strong> <code>grid</code> = [[3,8,1,9],[19,7,2,5],[4,6,11,10],[12,0,21,13]], k = 4
<strong>Output:</strong> [[12,0,21,13],[3,8,1,9],[19,7,2,5],[4,6,11,10]]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> <code>grid</code> = [[1,2,3],[4,5,6],[7,8,9]], k = 9
<strong>Output:</strong> [[1,2,3],[4,5,6],[7,8,9]]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m ==&nbsp;grid.length</code></li>
	<li><code>n ==&nbsp;grid[i].length</code></li>
	<li><code>1 &lt;= m &lt;= 50</code></li>
	<li><code>1 &lt;= n &lt;= 50</code></li>
	<li><code>-1000 &lt;= grid[i][j] &lt;= 1000</code></li>
	<li><code>0 &lt;= k &lt;= 100</code></li>
</ul>

class Solution:
    def shiftGrid(self, grid: List[List[int]], k: int) -> List[List[int]]:
        col = len(grid[0])
        row = len(grid)
        arr = [0] * row
        for x in range(k):
            for i in range(col):
                for j in range(row):
                    if i == 0:
                        arr[j] = grid[j][i]
                    else:
                        temp = arr[j]
                        arr[j] =  grid[j][i]
                        grid[j][i] = temp
            last = arr.pop()
            arr.insert(0, last)
            for y in range(row):
                grid[y][0] = arr[y]
        
        return grid

16800