<p>Given a 32-bit integer <code>num</code>, return <em>a string representing its hexadecimal representation</em>. For negative integers, <a href="https://en.wikipedia.org/wiki/Two%27s_complement" target="_blank">two&rsquo;s complement</a> method is used.</p>

<p>All the letters in the answer string should be lowercase characters, and there should not be any leading zeros in the answer except for the zero itself.</p>

<p><strong>Note:&nbsp;</strong>You are not allowed to use any built-in library method to directly solve this problem.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> num = 26
<strong>Output:</strong> "1a"
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> num = -1
<strong>Output:</strong> "ffffffff"
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>-2<sup>31</sup> &lt;= num &lt;= 2<sup>31</sup> - 1</code></li>
</ul>

class Solution:
    def toHex(self, num: int) -> str:
        if num==0:return "0"
        mp="0123456789abcdef"
        ans=""
        for i in range(8):
            ans=mp[num%16]+ans
            num=num//16
        return ans.lstrip('0')
        # if num < 0:
        #     return "ffffffff"
        # elif num == 0:
        #     return "0"
            

        # hex_dict = {10: "a", 11:"b", 12:"c", 13:"d", 14:"e", 15:"f"}
        # result = ""
        # while num != 0:
        #     rem = num % 16
        #     num = num // 16
        #     if rem in hex_dict.keys():
        #         result += str(hex_dict[rem])
        #     else:
        #         result += str(rem)

        # return result[::-1]
16500