<p>The string <code>&quot;PAYPALISHIRING&quot;</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p>

<pre>
P   A   H   N
A P L S I I G
Y   I   R
</pre>

<p>And then read line by line: <code>&quot;PAHNAPLSIIGYIR&quot;</code></p>

<p>Write the code that will take a string and make this conversion given a number of rows:</p>

<pre>
string convert(string s, int numRows);
</pre>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 3
<strong>Output:</strong> &quot;PAHNAPLSIIGYIR&quot;
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;PAYPALISHIRING&quot;, numRows = 4
<strong>Output:</strong> &quot;PINALSIGYAHRPI&quot;
<strong>Explanation:</strong>
P     I    N
A   L S  I G
Y A   H R
P     I
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;A&quot;, numRows = 1
<strong>Output:</strong> &quot;A&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 1000</code></li>
	<li><code>s</code> consists of English letters (lower-case and upper-case), <code>&#39;,&#39;</code> and <code>&#39;.&#39;</code>.</li>
	<li><code>1 &lt;= numRows &lt;= 1000</code></li>
</ul>

class Solution:


    def convert(self, s: str, numRows: int) -> str:
        p = [["" for _ in range(math.ceil(len(s)/(numRows-(numRows-2))))] for i in range(numRows)]
        a = ["" for i in range(numRows)]
        print(a)
        if numRows == 1:
            return s

        i,j = 0,0
        up = False

        while len(s) > 0:
            p[i][j] = s[0]
            a[i] += s[0]
            s = s[1:]

            if up:
                if i == 0:
                    i = (i+1)%numRows
                    up = False    
                else:
                    j += 1
                    i = (i-1)%numRows
            else:
                if i == numRows - 1:
                    up = True
                    i -= 1
                    j += 1
                else:
                    i = (i+1)%numRows

        print(a)
        ss = ""
        for i in range(len(a)):
            ss += a[i]

        # for i in range(len(p)):
        #     ss += ''.join(p[i]).strip()

        return ss
20600