<p>You are the manager of a basketball team. For the upcoming tournament, you want to choose the team with the highest overall score. The score of the team is the <strong>sum</strong> of scores of all the players in the team.</p>

<p>However, the basketball team is not allowed to have <strong>conflicts</strong>. A <strong>conflict</strong> exists if a younger player has a <strong>strictly higher</strong> score than an older player. A conflict does <strong>not</strong> occur between players of the same age.</p>

<p>Given two lists, <code>scores</code> and <code>ages</code>, where each <code>scores[i]</code> and <code>ages[i]</code> represents the score and age of the <code>i<sup>th</sup></code> player, respectively, return <em>the highest overall score of all possible basketball teams</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> scores = [1,3,5,10,15], ages = [1,2,3,4,5]
<strong>Output:</strong> 34
<strong>Explanation:</strong>&nbsp;You can choose all the players.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> scores = [4,5,6,5], ages = [2,1,2,1]
<strong>Output:</strong> 16
<strong>Explanation:</strong>&nbsp;It is best to choose the last 3 players. Notice that you are allowed to choose multiple people of the same age.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> scores = [1,2,3,5], ages = [8,9,10,1]
<strong>Output:</strong> 6
<strong>Explanation:</strong>&nbsp;It is best to choose the first 3 players. 
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= scores.length, ages.length &lt;= 1000</code></li>
	<li><code>scores.length == ages.length</code></li>
	<li><code>1 &lt;= scores[i] &lt;= 10<sup>6</sup></code></li>
	<li><code>1 &lt;= ages[i] &lt;= 1000</code></li>
</ul>

class Solution:
    def bestTeamScore(self, scores: List[int], ages: List[int]) -> int:
        
        x = []
        for i in range(len(scores)):
            x.append([ages[i],scores[i]])

        x.sort()
        

        d = {}
        def rec(i):
            if i in d:
                return d[i]
            if i >= len(x):
                return 0
            

            ans = x[i][1]
            for j in range(i+1,len(x)):
                if x[i][0] < x[j][0] and x[i][1] > x[j][1]:
                    continue
                ans = max(ans, rec(j)+x[i][1])
            
            d[i] = ans
            return ans
        
        
        
        ans = 0
        for i in range(len(x)):
            ans = max(ans, rec(i))
        
        return ans
18600