<p>Given a string <code>date</code> representing a <a href="https://en.wikipedia.org/wiki/Gregorian_calendar" target="_blank">Gregorian calendar</a> date formatted as <code>YYYY-MM-DD</code>, return <em>the day number of the year</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-01-09&quot;
<strong>Output:</strong> 9
<strong>Explanation:</strong> Given date is the 9th day of the year in 2019.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> date = &quot;2019-02-10&quot;
<strong>Output:</strong> 41
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>date.length == 10</code></li>
	<li><code>date[4] == date[7] == &#39;-&#39;</code>, and all other <code>date[i]</code>&#39;s are digits</li>
	<li><code>date</code> represents a calendar date between Jan 1<sup>st</sup>, 1900 and Dec 31<sup>th</sup>, 2019.</li>
</ul>

class Solution:
    def dayOfYear(self, date: str) -> int:
        day_month=[31,28,31,30,31,30,31,31,30,31,30,31]
        date_list = date.split('-')
        year = int(date_list[0])
        month = int(date_list[1])
        day = int(date_list[2])
        if year % 400 == 0:
            day_month[1] = 29 
        elif year % 100 == 0:
            day_month[1] = 28
        elif year % 4 == 0:
            day_month[1] = 29
        else:
            day_month[1] = 28
        total_days = sum(day_month[:month - 1]) + day
        return total_days

16400