Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.
<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>

class Solution:
    def findMinDifference(self, timePoints: List[str]) -> int:
        co = Counter(timePoints)
        if max(co.values())  > 1:
            return 0
        timePoints = sorted(timePoints)
        minDiff = 24*60
        for i in range(len(timePoints)):
            for j in range(0, len(timePoints)):
                if i == j:
                    continue
                first = timePoints[i].split(":")
                second = timePoints[j].split(":")
                if first > second:
                    second[0] = f'{int(second[0])+24}'
                secondToMinutes = (int(second[0]) * 60 + int(second[1]))
                firstToMinutes = (int(first[0]) * 60 + int(first[1]))
                diff = abs(secondToMinutes - firstToMinutes)
                minDiff = min(minDiff, diff)  
        return minDiff
        
19700