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Amanda Crawford M.D.
Orthopaedic Surgeon1801 Sunset Dr Ortho Clinic Columbia SC, 29203
Dr. Amanda Crawford is an orthopaedic surgeon practicing in Columbia, SC. Dr. Crawford specializes in the diagnosis, treatment and rehabilitation of injuries, diseases and disorders of the bodys musculoskeletal system. As an orthopaedic surgeon, Dr. Crawford tends to bones, ligaments, muscles, joints, nerves and tendons. Orthopaedic surgeons can specialize in certain areas like the hand, spine, hip, foot and ankle, shoulder and elbow or the knee.
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Size Medium Rasta Iron Lion Zion Cannabis Print Mid-Rise Panties. Made of Cotton/Lycra blend with 5% stretch.
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He was a cult hero for the New Zealand Warriors and was loved by his team-mates at the Canberra Raiders.
But now it appears Charlie Gubb — and his flowing locks — won't be gracing the rugby league field again anytime soon.
The forward has grown "disillusioned" with the sport after an unsuccessful stint in Super League and has now turned his back on the game.
Every game of every round of the NRL LIVE with no ad-breaks during play. Get it all on Foxtel.
The 28-year-old signed with Widnes last year, but after their relegation he was released.
Instead of continuing to look for a new side, the former Warriors forward has opted to retire from rugby league and has turned to teaching.
"He has left rugby league and he is doing a teaching job in Wellington," Gubb's manager, Frank Endacott told Foxsports.com.au.
"I doubt he would come back to the game unless there was an offer which was good enough, and I think he's pretty disillusioned."
Endacott has been Gubb's manager since the beginning of the prop's unorthodox rise to the NRL.
The forward began life at the Warriors, winning the 2010 Under-20s Grand Final alongside Shaun Johnson — and against a South Sydney side which included James Roberts, Josh Mansour and Adam Reynolds.
The Warriors released him shortly after, but after impressing at Wynnum Manly Seagulls, the Auckland-based side re-signed him, with the forward making his debut in the 2013 season.
In 2016, while playing for the Warriors in Perth, Gubb received a seven-week ban for a shoulder charge on Manly's Darcy Lussick.
After short-lived spells at Canberra and Widnes, Gubb was still fielding offers, but after being messed around by clubs in England he has finally called it quits.
"I know the scene in England pretty well and he was ready to sign with the London Broncos," Endacott added.
"He would have been one of their top line players and I offered them Charlie on a plate, but then they chose to stick loyal with the players that had got them promoted.
GOING, GONE: Wests Tigers chair resigns as club turmoil settles
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"Good luck to them. He would have been perfect for London and after all that, Charlie got pretty disillusioned with it all.
"He is at the perfect age, his fitness is really good and everywhere he goes he becomes a crowd favourite. His team-mates love playing with him because he is tough and plays on the fine line.
"He's too good a player not to be playing, and you can only get so many knock-backs before you give up. It is a great shame that he has chosen to have a spell out of the game."


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Hey, kids! If you liked learning the basics of three-dimensional drawing from Mark Kistler in his books Draw Squad and Imagination Station, you'll love his new book, Drawing in 3-D with Mark Kistler. Featuring a fun, action-filled tale about a family of lovable characters struggling through a series of breathtaking discoveries and hilarious adventures, Drawing in 3-D with Mark Kistler is all you need -- along with a sharpened pencil, a ready imagination, and Mark Kistler's Drawing in 3-D Wacky Workbook -- to draw cool creatures and awesome objects such as:
Mark Kistler is a cartoonist, an illustrator, and the producer and star of Mark Kistler's Imagination Station, currently airing on public television nationwide. The author of the wildly popular drawing books Mark Kistler's Draw Squad and Mark Kistler's Imagination Station, Kistler lives in Santa Barbara, California.
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The Best Guide To How To Convert Bitcoin To Cash
The 25-Second Trick For Free Bitcoin App
Sometimes, theres also a minimum post requirement each week. From our experience you can make up to $5 an hour depending no how much you compose and your membership level. This, of course, does not include the number of posts you need to write in order to earn the required membership amount on BitcoinTalk. .
One of the fastest, easiest but also riskiest ways you can make money with Bitcoin is by trading it on an exchange. Fundamentally youre trying to purchase Bitcoin when its price is reduced and sell it when the cost increases.
However, trading Bitcoin successfully is not a matter of luck or guesswork. Profitable traders spend a substantial amount of time learning how to exchange and the way to overcome the many risks involved in trading. Successful traders know they might eliminate money in the short term but they consider it as an investment in their own education, since they're aiming for the long run. .
All about Irish Coins
If you want to become a dealer make sure you've got the time and funds to invest in great trading education.
9 Easy Facts About How To Trade Ethereum Explained
One of the most overlooked ways to earn money with Bitcoin is by promoting various affiliate programs. Affiliates are individuals who promote a certain business for free but get a commission if they manage to bring in paying customers.
Many Bitcoin exchanges, goods and services have an affiliate program in which you can enroll. You then get your own unique affiliate link in order to market that service or product.
Of course there are many ways that you can market your affiliate link you can share it on Facebook, run advertising campaigns on different websites or even create your own information site and promote your links within the content.
This really is how 99Bitcoins got started, and weve even published a book about it called My Dirty Little Bitcoin Keys that you can download for free. If you want to know more about this technique make certain to download the book and read it from begin to finish only then will you understand that the amount of work needed in order to become a successful affiliate marketer. .
Heres a listing of highly profitable Bitcoin affiliate programs which we've already subject tested ourselves.
A very obvious method of trying to increase your crypto wealth would be to gamble on it using one of the many Bitcoin casinos out there. Obviously theres not much to elaborate on this method but if you do choose to risk your money and try your fortune, please be certain that the casino youre using is provably fair. .
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If youre into crypto and have a knack for phrases you might want to consider becoming a crypto journalist or post writer. As the crypto industry evolves, more and more news and information sites are popping up. In many instances these websites are in dire need for writers since they're publishing dozens of articles each week. .
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Many people who start out with Bitcoin are instantly drawn to the concept of Bitcoin mining. I mean, creating magical Internet money from Your House computer What could be better


text:
NED Abstract
Copyright by European Southern Observatory (ESO).
Reproduced by permission
Ram pressure stripping in the Virgo Cluster
Verdugo, C.; Combes, F.; Dasyra, K.; Salome, P.; Braine, J.
Abstract. Gas can be violently stripped from their galaxy disks in rich
clusters, and be dispersed over 100 kpc-scale tails or plumes. Young stars
have been observed in these tails, suggesting they are formed in situ.
This will contribute to the intracluster light, in addition to tidal
stripping of old stars. We want to quantify the efficiency of intracluster
star formation. We present CO(1-0) and CO(2-1) observations, made with the
IRAM-30 m telescope, towards the ram-pressure stripped tail northeast of
NGC 4388 in Virgo. We selected HII regions found all along the tails,
together with dust patches, as observing targets. We detect molecular gas
in 4 positions along the tail, with masses between 7 x 10^5^ to 2 x
10^6^M_sun_. Given the large distance from the NGC 4388 galaxy, the
molecular clouds must have formed in situ, from the HI gas plume. We
compute the relation between surface densities of star formation and
molecular gas in these regions, and find that the star formation has very
low efficiency. The corresponding depletion time of the molecular gas can
be up to 500 Gyr and more. Since this value exceeds a by far Hubble time,
this gas will not be converted into stars, and will stay in a gaseous
phase to join the intracluster medium.
Key words: galaxies: evolution, galaxies: clusters: individual: Virgo,
galaxies: clusters: intracluster medium, galaxies: ISM, galaxies:


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Susan Stebbing, Incomplete Symbols and Foundherentist Meta-Ontology
Journal for the History of Analytical Philosophy 5 (2):6-17 (2017)
Susan Stebbing's work on incomplete symbols and analysis was instrumental in clarifying, sharpening, and improving the project of logical constructions which was pivotal to early analytic philosophy. She dispelled use-mention confusions by restricting the term 'incomplete symbol' to expressions eliminable through analysis, rather than those expressions' purported referents, and distinguished linguistic analysis from analysis of facts. In this paper I explore Stebbing's role in analytic philosophy's development from anti-holism, presupposing that analysis terminates in simples, to the more holist or foundherentist analytic philosophy of the later 20th century. I read Stebbing as a transitional figure who made room for more holist analytic movements, e.g., applications of incomplete symbol theory to Quinean ontological commitment. Stebbing, I argue, is part of a historical narrative which starts with the holism of Bradley, an early influence on her, to which Moore and Russell's logical analysis was a response. They countered Bradley's holist reservations about facts with the view that the world is built up out of individually knowable simples. Stebbing, a more subtle and sympathetic reader of the British idealists, defends analysis, but with important refinements and caveats which prepared the way for a return to foundherentism and holism within analytic philosophy.
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On Denoting.Russell, Bertrand
Evidence and Inquiry: Towards Reconstruction in Epistemology.Vogel, Jonathan & Haack, Susan
Meta-Ontology, Epistemology & Essence: On the Empirical Deduction of the Categories.MacBride, Fraser & Janssen-Lauret, Frederique
The Nature of Judgment.Moore, G. E.
Committing to an Individual: Ontological Commitment, Reference and Epistemology.Janssen-Lauret, Frederique
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The sofa is a classic staple for comfortable seating. Little did we know that there are some other alternative to sofa if you find yourself wanting to get a little off the mainstream. One of the best alternatives to sofa out there is wide chaise lounge. Chaise is originated in 18th century France. It is essentially an upholstered recliner, made for style, comfort and stretching out. With this in mind, the idea of replacing sofa with wide chaise lounge became even more understandable. So if you're thinking of going on this route, here are 4 instances where wide chaise lounge is a better option than a sofa.
What will you do if you want to put comfortable seating furniture in front of a huge window with a beautiful view? Will you choose a sofa? Yes, a sofa may sound great, but it will block the view when you're not sitting on the sofa. Therefore, if you want to preserve the view and keep them out of obstacles, a chaise can be your answer. It will give you more access to the view while still providing comfortable seating.
In small rooms, the sofa can get a little tricky. Because the sofa is typically large, it may block the traffic flow in such a small room. Chaise can solve this problem by providing more space to move and therefore unblocking the traffic flow. You can replace the sofa with two chaises and place them apart so people can easily move between the chaise.
Have you realized that you can push two chaises together and create an L shaped sectional? Yes, even though chaise doesn't have enough back support, but the length and depth of the chaise still speak comfort. Also, with this DIY sectional, you can easily move them around if you want to change the look of your room.
If you have a media room, you can add more comfort to it by choosing two wide chaise lounges instead of a sofa. The chaise offers more space to snuggle and stretch even when compared with deep‐seated sofa. You can take up the coffee table space for the chaise and replace it with a small table between the two chaises.
Of course, there are several downsides to wide chaise lounge compared to a sectional sofa. Such as the non‐existent back support and arm support. These downsides make wide chaise lounge a lot more uncomfortable when you placed them in the living room. However, the shape can gain your advantages when you want to convert your living room into an emergency guest room. Since sleeping in a wide chaise lounge would feel better than a sofa. You can easily put some pillows and blanket and turn them into a place where your guest can lay down.
Not to mention, the relatively smaller size of wide chaise lounge compared to sectional sofa makes them a perfect alternative for smaller spaces. See? It's totally okay to replace your sectional sofa with wide chaise lounge!
Home Decor Ideas
Architects can't force people to connect, it can only plan the crossing points, remove barriers, and make the meeting places useful and attractive. – Denise Scott Brown
For homeowners that can't afford to have a separate guest room for their guests, sleeper sofa can be their best bet. It can turn your living room into a guest room so you can have friends or family spend the night at your home. Aside from being an instant bedroom, modern sleeper sofa queen can also be a great spot to hang out and watch movies with your loved ones. Imagine cuddling under the blanket with your spouse and children, having a movie night and a good time in general, doesn't sleeper sofa sounds like a dream?
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Designing or remodelling home office is actually quite exciting. It refreshes the room and at the same time boosts our mood and energy to work. There are so many ideas you can apply to your home office, but not all of them actually functional or even practical. Instead of putting too much decoration or stuff that we thought can be necessary but turns out unused at all, we may need to sort those office design ideas first and stick to the ones that are actually functional. So here are some functional design ideas you may want to consider.
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You want to highlight a curved architectural detail When you have curved walls, it makes more sense to use a round carpet as well. This will highlight your unique architectural details like a curved wall or curved ceiling. And pull the attention to that particular unique feature.
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Most of us can't help but think about dual sink bathroom vanity when it comes to decorating a master bathroom. Since it will be used by two people, it only makes sense to have double vanity so you don't have to wait for each other. But dual sink bathroom vanity can be quite tricky. Especially if your master bathroom is not that big and there is not much space to use. So heed these guides when searching for the perfect bathroom vanity.Placement and size First of all, you need to determine how many spaces you have for your dual sink ...


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Road in Deshaun Watson's hometown could be named after him
Deshaun Watson Drive could become a fixture in Gainesville, Ga.
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MORE: SN staffers make picks for the New Year's Six
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Watson will play potentially his last game as a college player on Saturday, when Clemson takes on Ohio State in the semifinals of the College Football Playoff.


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Giancoli 7th Edition, Chapter 18, Problem 36By tuh20232 on Thu, 02/09/2017 - 15:50
I got confused with the P= 75 w and the P = the power consumed would you please explain the difference? Thank you
Hi tuh20232, thanks for the question. P = the power consumed, always. On the packaging for a bulb, the manufacturer will give the answer to the power calculation, assuming a particular voltage. For a bulb sold in the US, the manufacturer will assume 120 V in the calculation for the bulb power, where for a bulb sold in the EU, the manufacturer will assume 240 V.
P = the power consumed, whereas the P = ## rating for a bulb depends on where the bulb is sold.
Hope that helps,
Mr. Dychko
Giancoli 7th Edition, Chapter 19, Problem 18By saie.joshi on Sun, 02/05/2017 - 11:21
do the nodes initially not mean anything then? I thought the nodes would make the resistors not in parallel or series.
Hi saie.joshi,
Thanks for the question. This diagram is a bit tricky since some resistors are in series, whereas others are in parallel. We break it down step by step. If current reaching a node has a choice between multiple paths, then the resistors along the two (or more) paths are in parallel. If current reaching a node has only one option, and that is to proceed through another resistor, then that next resistor is in series. Does that help?
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 10, Problem 22By rdattafl on Thu, 02/02/2017 - 11:00
In the video, you wrote 1.29 * 10^5 Pa, but in the main answer section, you wrote 1.20 * 10^5 Pa. Merely for clarity, can you correct the second answer?
Thank you very much for spotting that rdattafl. I've updated the quick answer.
Giancoli 7th Edition, Chapter 2, Problem 30By m_iqbal on Tue, 01/31/2017 - 19:20
I have a question that if the object has constant negative velocity, will the object speed up or slow down?
Hi m_iqbal, thanks for the question. The negative sign for velocity indicates direction only. It says nothing about whether the object is speeding up or slowing down. A negative velocity means only that the object is moving in the negative direction, which is typically to the left, although a person solving a problem is free to redefine the coordinate system by saying "I feel like making the negative direction to the right". It's a bit unusual to say "right is negative", but you do need to be prepared for this idea since occasionally I do say "let down be the positive direction", rather than the traditional "up is positive", when doing so simplifies the mathematics by avoiding so many negative signs in a formula.
A change in speed is given by acceleration, so your next question might be: does a negative acceleration mean the object is speeding up or slowing down. The answer here depends on whether the object currently has a negative velocity, or not. If the acceleration has the same sign as the velocity, it's speeding up. An acceleration with an opposite sign to the velocity means the object is slowing down. So, running through the list of possibilities: +a & +v => speeding up, -a & +v => slowing down, +a & -v => slowing down, -a & -v => speeding up. The last scenario is probably the one you'll want to take note of, where a negative acceleration means the object is speeding up when it already has negative velocity.
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 9, Problem 48By jsh2672 on Tue, 01/31/2017 - 15:56
Why are you multiplying by 1/100? Shouldn't you be multiplying by 100 to get the percentage?
Thank you very much jsh2672 for noticing that! I've corrected the quick answer to show the result after multiplying by 100, and put a note about the error in the video.
Best wishes,
Mr. Dychko
Giancoli 7th Edition, Chapter 3, Problem 25By sophiaswimgirl on Tue, 01/24/2017 - 23:29
Hi! Would you be able to explain something to me? I don't understand why solving for that x component gives the average horizontal speed. I thought that x component is only applicable to the instantaneous initial velocity?
Hi sophiaswimgirl,
Thanks a lot for the question, and I'm sorry for taking so long to get back. I hope you're still working on this unit....
Sure, it's true that the x-component of the velocity is that of the instantaneous initial velocity, as you say. However, the x-component of the velocity never changes. There is no horizontal acceleration. Since the x-component of the velocity never changes, this means that whatever value it has initially will also be the value it has at any other time, and so in this circumstance it's initial value is also it's average. The average of a value that's constant is whatever that value is, at any time.
Hope this helps,
Mr. Dychko
Giancoli 7th Edition, Chapter 3, Problem 13By sophiaswimgirl on Fri, 01/20/2017 - 17:16
In part a) I'm confused as to why By is negative.
sin 56 = By/(-26.5) will result in a negative - I get that - but in question number 9, which uses the same vectors, the solution to By was positive, so why aren't they the same?
Is it because in the equation we're asked to solve for, we have to subtract vector B? Then why isn't Bx negative?
Thank you.
Hi sophiaswimgirl,
In question 13 the vector B is the negative of what it was in problem #9, which makes it point in the opposite direction. When I see a vector being subtracted, as vector B is in this case, I like to think of it as 'adding it's negative', which mean apply the usual rules for adding vectors, but flip around the one that's being subtracted. Instead of up and to the left in #9, it is now down and to the right here in #13. Since it's pointing downish, that makes the y-component, $B_y$, negative.
In both cases, the calculation for $B_y$ was $26.5 \sin(56^\circ)$ but here in #13 the result gets a negative in front if it despite the calculator saying 'positive'. This has to do with our understanding of the physical situation, in that the vector is pointing down, and so with that understanding we just put the negative there, regardless of what the calculator says. This might be going on a tangent, but just for arguments sake, if you wanted to always have the calculator say the correct sign, you would have to enter angles in standard position which is measured counter clockwise starting from the positive x-axis. In problem 13 the standard position angle of vector B is $360 - 56 = 304^\circ$, in which case $26.5 \times \sin(304^\circ) = -21.97...$ with the negative sign, rather than $26.5 \times \sin(124^\circ) = +21.97...$ (where $124^\circ$ is the standard position angle in #9). I don't recommend changing your angles to standard position, but I just mention it so that you're more comfortable placing negative signs where they belong 'by decrie', secure in knowing that there is a way to make the mathematics consistent with the physical reality if you felt like it. You're not doing anything wrong, in other words, by overriding the sign of what the calculator says and choosing the sign that fits the physical situation.
Maybe that was a bit long, but I hope it helps.
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 4, Problem 5By sophiaswimgirl on Thu, 01/19/2017 - 00:23
I guess I missed this in chapter 2, but why do we square the magnitude of the velocity when using the kinematic equation (when trying to solve for the acceleration, blue writing, 2 minutes 3 seconds in)? It's a mistake I keep making but I can't figure it out why.
Thanks so much for your help.
Wait, I figured it out. It was staring me right in the face - I had the wrong formula. Sorry, thanks!
Giancoli 6th Edition, Chapter 14, Problem 25By sulaiman_gos on Tue, 01/10/2017 - 12:21
hi .. I have a question here .. why you keep solving with ΔT as it's ( Ti - Tf ) but it is actually ΔT = ( Tf - Ti ) !? please I need explanation!!
Giancoli 7th Edition, Chapter 17, Problem 2By a_murayyan on Tue, 01/10/2017 - 06:51
in the answer box, don't you mean 2.72 X 10^-17 J?
Giancoli 6th Edition, Chapter 7, Problem 35By upasna.us1 on Sun, 01/08/2017 - 20:28
I still don't understand why the initial velocity of the moving car is equal to the final velocity of both vehicles together? Could you explain this please?
Giancoli 6th Edition, Chapter 2, Problem 44By dmorochnick on Sat, 12/31/2016 - 07:40
At about -2:05, shouldn't acceleration be negative: -9.8 yielding the solution d=4.3m instead of 2.1m?
Hi dmorochnick, thanks for the question. Earlier in the video I mentioned that the coordinate system was chosen so that down is positive. While the convention is that if one says nothing about the coordinate system, the assumption is that up is positive, is OK to explicitly change that. The choice is just personal preference. Where it's convenient, I sometimes prefer to make down positive to avoid substituting many negative values into the formula since I find so many negatives, and subtracting negatives, to be confusing. If you wish to have up as positive, it's totally OK to do so. You would arrive at the same answer (not $4.3 \textrm{ m}$), since keep in mind that the displacement past the window would also have to be negative since it's downward (which in your coordinate system is the negative direction if up is positive).
All the best,
Mr. Dychko
Giancoli 6th Edition, Chapter 6, Problem 3By nalakija on Thu, 12/08/2016 - 15:52
Why are all the editions labeled as one??? Messing me up..
Hi nalakija, thanks for the comment. Could you please be more specific? I'm seeing editions labeled as "7th Edition", "6th Edition" and "Global Edition" in the menu bar. Where are you seeing them labelled as one?
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 37By jmarra_villanova on Wed, 12/07/2016 - 20:31
Hi, how do you distinguish whether to use KEf + PEf = KEi + PEi on a spring question like this, rather than using Wext = DeltaPE in a question like #35?
Thank you
Hi jmarra_villanova,
Thanks for the question. The formula $KE_f + PE_f = KE_i + PE_i$ is a law, which means it's always valid. This is an algebraic way of saying energy is conserved after a movement of some kind. As a law, it could also be used in #35 instead of $W_{ext} = \Delta PE$. Doing so would have looked like this: $0 + mgy_2 = 0 + mgy_1 + \dfrac{1}{2}k(y_2 - y_1)^2$, where the zero's are substituting for kinetic energy, of which there's none since in #35 the block isn't moving (or the movement is so slow as to be negligible), and $(y_2 - y_1)$ is the amount the spring was stretched. Using $W_{ext} = \Delta PE$ is just a convenience since it reduces a couple of algebra steps. When in doubt, use conservation of energy.
Hope that helps,
Mr. Dychko
Giancoli 7th "Global" Edition, Chapter 12, Problem 35By maia.fehr.oth23 on Thu, 12/01/2016 - 21:44
Why 331 and not 343?
Giancoli 7th Edition, Chapter 10, Problem 40By odelay.chewy on Fri, 11/25/2016 - 00:47
I am struggling understanding the funky algebra used in this step. You kind of gloss over it. Could you show it step for step?
Hi odelay.chewy,
Thanks for the question. I'm away from my recording equipment at the moment, but I'll try to give some highlights here. We start with saying the total forces directed up equal the total forces directed down, then I make a substitution for each up force with the archimedes principle that the buoyant force is the weight of fluid displaced, which is $F = \rho V g$, and the down forces are the usual weight formula $F = mg$. Then, in green, the volume of the wood and lead is expressed in terms of their density and mass. This is in turn substituted (using red) for each volume factor in the up force terms. The specific gravity of wood replaces the ratio of the density of water to wood. Then comes a confusing line where the mass of the wood is shown moving to the left, but actually ends up on the right. The thing to notice with that line is that we're collecting like terms. We're placing the wood terms together on one side, and the lead terms on the other side. The mass of lead and mass of wood are factored out on their respective sides, leaving us with some bracket multiplied by a mass on each side. We're interested in knowing the mass of lead, so we divide both sides by the bracket by which the lead mass is multiplied. Then we plug and chug. Hopefully this video commentary is a bit helpful...
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 13, Problem 14By saie.joshi on Thu, 11/24/2016 - 08:42
Why do you subtract the values instead of adding them together? Don't both the water and the glass reduce volume?
Giancoli 7th Edition, Chapter 8, Problem 22By taylorreilley on Mon, 11/14/2016 - 08:32
Why did you plug the Wf value in for b when you wrote Wi
Hi taylerreilley,
Thanks for the question. "initial" and "final" is a bit confusing in this questions since there are more than one time periods to consider, each with their own "initial" and "final" moment. For part a), the "final" moment is when the car has reached $55 \textrm{ km/h}$, making $\omega_f = 38.194 \textrm{ rad/s}$. However, for part b), the initial moment is when the car is at $55 \textrm{ km/h}$, so for part b) $\omega_i = 38.194 \textrm{ rad/s}$. The initial moment of part b) is the final moment of part a).
I can see where you're coming from, and technically it would be more correct for me to put a subscript on the variables to assign them to parts of the question, such as for the angular speed for part a) written as $\omega_{iA}$ and $\omega_{fA}$, and then say $\omega_{fA} = \omega_{iB}$, and so on, but I think that also creates it's own source of confusion by presenting so many more subscripts.
All the best,
Mr. Dyckho
Giancoli 7th Edition, Chapter 7, Problem 41By sheumangutman on Fri, 11/11/2016 - 16:12
Why is this collision deemed "inelastic" in terms of the treatment of kinetic energy conservation. Seems based on the diagram, the objects are not sticking together, which would suggest its inelastic.
Hi sheumangutman,
Thanks for the question. The term "inelastic" means there is less total kinetic energy after a collision compared with before a collision. Since that's the case here, we can call it inelastic. It is not "completely inelastic", that's true. A completely inelastic collision involves the two particles sticking together, and this type of collision results in the maximum loss in kinetic energy that's possible while still conserving momentum. Seeing two particles bounce apart means either the collision is "inelastic" (but not "completely inelastic"), or maybe the collision is "perfectly elastic", in which case the total kinetic energy after collision is the same as it was before. In this case, the collision is a regular inelastic collision since some kinetic energy was lost, but not the maximum loss that would have otherwise been possible had they stuck together.
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 9By sheumangutman on Thu, 11/10/2016 - 08:28
Could you also approach the problem by first solving for final velocity by using V=a*t, and then plugging this velocity into v^2=vo^2+2AD to solve for displacement?
Hi sheumangutman,
Yes you can! Substituting $v=at$ info $v^2 = v_o^2 + 2aD$ gives $a^2t^2 = v_o^2 + 2aD$, which, with $v_o = 0$ rearranges to $D = \dfrac{1}{2}at^2$ after you divide both sides by $2a$. $D = \dfrac{1}{2}at^2$ is the formula I used in the video. Good work!
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 4, Problem 52By schamorg on Wed, 11/09/2016 - 07:09
Thank you so much. This was very helpful actually.
Giancoli 7th Edition, Chapter 3, Problem 37By kmoons25 on Mon, 11/07/2016 - 20:00
why do you do these things?
Hi kmoons25, Well, I know physics can be confusing. When you have a more specific question, just let me know.
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 53By taylorreilley on Sun, 11/06/2016 - 15:46
Why is there still potential energy at the end?
Hi taylorreilley,
Thanks for the question. One thing to understand about potential energy is that you can never know how much there is. :) There's no such thing as an "absolute" potential energy. It's possible only to tell what is the change in potential energy. Sometimes we speak as though there is an absolute potential energy, such as "the book is 3m above the ground, so it has $mg(3 \textrm{ m})$ of potential energy, but don't be fooled by that as it's just a concise (maybe lazy?) way of speaking, when in fact it means the difference in potential energy of the book with respect to the ground is $mg(3 \textrm{ m})$. With that in mind, the skier has a change in potential energy resulting from their drop in altitude of $230 \textrm{ m}$, and this change in potential energy is turned into other forms of energy, namely kinetic energy and heat. Subtracting away the kinetic energy gained from the loss of potential energy, we're left with how much of that potential energy loss was turned into heat.
To put it in one sentence, the "potential energy" term you see in the final calculation is not the "potential energy at the end", but rather, it is the change in potential energy when the skier descends.
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 9, Problem 28By leopinzon18 on Sat, 11/05/2016 - 10:02
what formulas are being used
Hi leopinzon18, for formulas being used are $\tau = Fl_{\bot}$ which says torque equals force times the perpendicular component of the lever arm, and the other formula is that $\Sigma \tau = 0$ for static equilibrium, which is also to say $\Sigma \tau_{ccw} = \Sigma \tau_{cw}$ meaning the counter-clockwise torques equal the clockwise torques. If you have a more specific question, just let me know and I'll see if I can answer it.
Mr. Dychko
Giancoli 7th Edition, Chapter 4, Problem 52By schamorg on Thu, 11/03/2016 - 19:43
I am still confused as to why the diagrams for a) and b) are the same. I don't understand how in a) the box has static friction, but b) has kinetic friction and their diagrams are the same. Shouldn't b) have a velocity vector pointing downward?
Thank you so much for your time!
Hi schamorg, thanks for asking this question. Understanding free body diagrams is really important, so it's good your digging into the topic. A free body diagram does not include a velocity vector. I sketched one in for part "c", but that was just to emphasize which direction the box is moving in order to explain why the force arrows are pointing the way they are. Notice that the velocity vector does not begin on the center of the box, since I didn't want to make is seem like another force vector. Force vectors are always written with their beginning a the center of mass of the object (usually the geometric center... just ignore this point if it's confusing). Technically, velocity vectors do not belong on free body diagrams. OK, so to answer your question, for parts "a" and "b" there is intentionally no velocity vector at all since free body diagrams only show force vectors. In both parts "a" and "b", the friction force is directed up the ramp, and so the arrow representing these frictions forces point in the same direction. I suppose there is a case for making separate diagrams, but the distinction is only this: the kinetic force vector of part "b" should be shorter than the static friction force vector of part "a" since kinetic friction is always weaker than static friction.
Hope this helps,
Mr. Dychko
Giancoli 7th Edition, Chapter 7, Problem 10By lcbishop on Wed, 11/02/2016 - 11:51
Why is the negative sign from the v2 prime early not considered in the final calculation. Thanks.
Hi Ichbishop, thanks for the question. I suppose there's a bit of an oversight here, although it isn't a critical one since in the end we're looking for a ratio of masses, which we know must be positive. In the substitution shown in green, it would be slightly better to write $\dfrac{2V_2^{'2}}{v_1'} = \dfrac{-v_2'}{v_1'}$ in which case $\dfrac{v_2'}{v_1'} = \dfrac{-1}{2}$. Then the substitution into $\dfrac{m_1}{m_2} = \dfrac{-v_2'}{v_1'}$ would lead to the negatives cancelling, resulting in the expected positive final answer. Thanks for noticing that detail.
All the best,
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 5By lyonsca1 on Fri, 10/28/2016 - 08:23
Why don't you use cosine theta in the work formula at the very end of the problem if W=Fdcos(theta)? instead of just d (just displacement) in incline problems like this?
Hi lyonsca1,
Thanks for the question. I don't mean at all to contradict $W = Fd \cos(\theta)$ (which can also be written $W = F \cos(\theta) (d)$). That formula means that you multiply the force by the displacement, then multiply by cosine of the angle between them. In this particular solution, the force and displacement are actually parallel. The force I'm referring to is the force applied by some person or machine to make the car move up the ramp at constant speed. This applied force is directed along the ramp, so it's parallel to the length of the ramp. This means $W = F d \cos(0)$. Since $\cos(0) = 1$, it's common to not bother writing it at all, and to just write $W = F d$ for the special case where $\theta = 0$, which is the case where the force and displacement are parallel, as they are in this problem.
The applied force, according to the diagram, is $F_a = mg \sin(\theta)$, where theta here is referring to the angle of the incline. That's confusing, since the "theta" in the formula you wrote is referring to something different: namely the angle between the applied force and the displacement. If I were to write things out completely, using numbers in place of the angles, it would be $W = mg \sin(9.0^\circ) d \cos(0^\circ)$, where I added the $\cos(0^\circ)$ to try and be clear that that angle is the one in the $W = Fd\cos(\theta)$ formula, not the $9.0^\circ$ used to calculate the component of gravity along the incline.
Hope that helps,
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 52By lcbishop on Mon, 10/24/2016 - 11:35
Can you give a brief explanation of what you mean by "energy goes into heat"? Is it transformed into heat? Thanks.
Hi Icbishop, yes exactly. By "energy goes into heat" I mean to say "energy is transformed into heat energy". Rather than being gravitational potential energy, or kinetic energy, some of the energy is transformed into heat. This is the result of friction between particles in the ball when it gets squished upon colliding with the ground. The same could be said for particles in the ground internally "rubbing" and creating heat as the result of friction. Plus particles of the ground rub against particles of the ball. What I didn't mention is that some energy turns into sound energy, but this is typically very small compared to the amount turned into heat.
Hope that helps,
Mr. Dychko
Giancoli 7th Edition, Chapter 6, Problem 31By jessicasingh001 on Sun, 10/23/2016 - 18:46
Does anyone know why the 8 degree incline is ignored?
Hi jessicasingh001,
Thanks for the question. Only the change in height is important for questions involving gravitational potential energy, so the 8 degree incline is an extraneous detail. It's the vertical change in height that's important.
Hope that helps,
Mr. Dychko
Hi gellander97, thanks for the comment. The sound plays fine on this end, so just let me know if that happens again.
All the best,
Mr. Dychko


text:
Hello, it's me (shout out to JenFruzz), I was wondering if after all these years you'd like to read my Daily Deviation Guidelines.
I am now a CV for Macro photography but also for Abstract & Surreal.
How to suggest a Daily Deviation?
- Make sure that the deviant hasn't already received a Daily Deviation within the past 6 months. FAQ #313: How can I find out if someone already has a Daily Deviation?
- Send me a note with the title: "DD Suggestion", or "DD S".
- Include in this note the thumbnail of the deviation that you are suggesting (in the bottom right of the deviation: thumb#######). I accept that you include several Daily Deviations Suggestions in one note, as long as it is organized.
- You can, subsidiarily, include in your note the reason(s) why you think that the artist(s) deserve(s) a Daily Deviation (preferred, but not required).
- I can't give a Daily Deviation to a person who hasn't logged in within the last 30 days. But if you're not sure if the user you want to suggest has logged in, you can always send me a note! I'll look into it for you.
- Self DD Suggestions are accepted.
- Please send one note to one Community Volunteer at a time.
- I only accept Macro photographs or closeups. They can be from the Macro Gallery (with the Human, Nature and Objects sub-galleries), but also from other galleries, as long as they are Macro photographs or closeups.
- I will only feature high quality Macro photographs or closeups.
- I will only DD artworks less than a year old.
- Since this is Macro photography that we are dealing with, I would like to receive suggestions with large enough photographs so that I can see as many details as possible.
- Now, what exactly am I looking for? Well, basically, I want Macro photographs or closeups that would make me go "Wow.", Macro photographs that would make me want to have hypothetical children with the artist.... Surprise me!
Official FAQs
I'm waiting now.