In roference to problem 142, J. P. Morris writes: —" I must apologise for not having given the bearings of the point B. They should have boen as follow :—Bearings of B from A, due south; true course of ship, allowing for leeway, etc., south-west; bearings of B on the seventh day, about south-east-half south 5 bear ings of B on the fiftoenth daj, about east j tho whole distance to be traversed to be on or near the equator, where the difference in longitude is immaterial."

In reference to problem 143, Kiwi writes : — "I have worked this out according to a rule given, I think, by Mr Beverly in the Witness a year ago : ' At one foot above the sea level tho distance of tho apparent, horizon is 1 325 English mile; and for all other heights on the globo tho heights in feet are in proportion to the eqaares of the distance in miles.' Ido not know whe ther refraction is considered iv this mode of solution or not. Refraction depends much on the state of the barometer and tho thermometer. According to Mrs Somorville : 'In tho mean state of the atmosphere the refraction is about the fourteenth part of the horizontal angle,' ex plained in a note and diagram, p, 464, in her Physical Soiences."

POETRY.
Zap me in soft Lydian airs, Married to immortal verse. —-Milton.
