Note. — In the above solution, we multiply the first ratio, 8 : 40,
by 8, making 24 : 120. Then by adding, we get 24 : 24 : 160,
which reduced gives 3 : 8 : 20.
8




24


24


3




24




24


3


40


40


120


160


20



(374)



ALLIGATION.
191



Ex. 1



(635, page 375.) ^

NoTB. — Divide the
terms in the 3d col-
umn by 3, and to
the result add the
terms in the 4th.
Ans. 4 gal. of the first two kinds, 8 gal. of tha

third, and 11 gal. of the fourth.
ts




12




4


4




H




4




4




^




8




8


A




33




11


11



Ex.2.
10



7


i




1




6


5


8


%9


1

2




6




5


13
15


I


^0

1
If


1


2


6


5
2



Am, hy 5, 5, and 2.
Note. -Multiply the
terms in the third col-
umn by 6, and add the
result to the terms in the
fourth column.
Ex.8.
For the first mixture.
( 30
•70^ 50
' (lOO



(* 30

70 4 50
(lOO



?v




3




3


1




1




B


3


1


^\


.V


4


2^


6


2



Ans, 1, 1, ^d 2.
For the second mixture.
jV




3






3


1




1
3U




3


12


12


4


1k




4


2


8


12


4



Ans.
ly 4 and 4.
Note. — Multiply the terms in the fourth column by 4, and to
the result add the terms in the third column, and then divide by 3.
(636, page 376.)



Ex.1.
22



fl6


h






1






1


10


18


V


1






1




1


10


' 20




*m


1
5






1


1


10


24


1

3


1
3


1
2


3


2


1


6


'60



Ans, 10 at
$16, 10 at $18
and60at$24.
