meter of circle Y, is equal to the side of the circumscribed
square A B C D, = 4, and the diameter of circle Z is, by
construction, equal to twice the diameter of circle Y, =
4x2 = 8. Then, 8* = 64, will be the area of a square
described on the diameter of circle Z; and64X 78125 = 50;
or, II (64), li X 64, = 78125 X 64, = 50, will be the area
of circle Z ; and is equal to twice the area of circle X, and
four times the area of circle Y.
The side F G, of the triangle F G H, is the diameter
of circle Y, the value of which is 4 ; and the side G H, of
the triangle F G H is, by construction, equal to three-
fourths of the side F G. Therefore, f (4), = | x 4, =
75 X 4, = 3, will be the value of G H ; and JG H ' + FG*,
= n/3* + 4', = J9+ 16, = V25, = 5 ; will be the value
of F H, the hypotheneuse or third side of the triangle F G H.
Then, the value of the side F H, of the triangle FGH, is 5.
Therefore, 5' = 25, will be the area of the square FHNP,
described on F H, and is equal to the area of circle X.
The value of the side F G, of the triangle F G H, is 4.
Therefore, 4' = 16, will be the area of square F G L M.
The value of the side G H, of the triangle F G H, is 3.
