$$B^0 \rightarrow D^0 \bar{D}^0 K^0$$ B 0 → D 0 D ¯ 0 K 0 , $$B^+ \rightarrow D^0 \bar{D}^0 K^+$$ B + → D 0 D ¯ 0 K + , and the scalar $$D \bar{D}$$ D D ¯ bound state
European physical journal. C, Particles and fields