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Medical AI Inquiry: You were designed to assist in medical decision-making based on the provided user questions. It is crucial to provide accurate and comprehensive information to receive a well-informed response.
user
Gram stained periorbital exudates in severe panophthalmitis with cellulitis in an elderly diabetic shows irregular branching aseptate and broad hyphae. Which of the following is the most likely diagnosis-
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The correct answer is  1.Irregular branching aseptate and broad hyphae belong to Zygomycota phylum and cause Zygomycosis. *Zygomycota are aseptate fungi that cause serious infections, primarily in ketoacidotic diabetic patients and cancer patients. 2. Agents of Zygomycosis - - Rhizopus, Mucor, Lichtheimia (Old name: Absidia), Apophysomyces - Candida: Yeast like fungi. - Aspergillus: Narrow septate hyaline hyphae with acute angle branching molds. - Pencillium: Hyaline thin septate hyphae, vesicles are absent, and conidia arranged as brush border appearance molds.