Solve in Python:
We have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.
The square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.
We will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.
How many times do we need to cut the bar so that every block after the cuts has K or less white squares?

-----Constraints-----
 - 1 \leq H \leq 10
 - 1 \leq W \leq 1000
 - 1 \leq K \leq H \times W
 - S_{i,j} is 0 or 1.

-----Input-----
Input is given from Standard Input in the following format:
H W K
S_{1,1}S_{1,2}...S_{1,W}
:
S_{H,1}S_{H,2}...S_{H,W}

-----Output-----
Print the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.

-----Sample Input-----
3 5 4
11100
10001
00111

-----Sample Output-----
2

For example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.
Note that we cannot cut the bar in the ways shown in the two figures to the right.
# E - Dividing Chocolate
import numpy as np

H, W, K = list(map(int, input().split()))
S = np.zeros((H, W), dtype=np.int64)

ans = H+W

for i in range(H):
    S[i] = list(str(input()))

for m in range(2**(H-1)):
    wp = np.zeros((H, W), dtype=np.int64)
    wq = np.zeros((H, ), dtype=np.int64)
    wp[0] = S[0]
    cut = 0
    for n in range(H-1):
        if m>>n&1:
            cut += 1
        wp[cut] += S[n+1]

    if cut >= ans or np.count_nonzero(wp > K):
        continue

    for j in range(W):
        wq += wp[:,j]
        if np.count_nonzero(wq > K):
            cut += 1
            wq = wp[:,j]
    ans = min(ans, cut)

print(ans)