Solve in Python:
Dreamoon is standing at the position 0 on a number line. Drazil is sending a list of commands through Wi-Fi to Dreamoon's smartphone and Dreamoon follows them.

Each command is one of the following two types:   Go 1 unit towards the positive direction, denoted as '+'  Go 1 unit towards the negative direction, denoted as '-' 

But the Wi-Fi condition is so poor that Dreamoon's smartphone reports some of the commands can't be recognized and Dreamoon knows that some of them might even be wrong though successfully recognized. Dreamoon decides to follow every recognized command and toss a fair coin to decide those unrecognized ones (that means, he moves to the 1 unit to the negative or positive direction with the same probability 0.5). 

You are given an original list of commands sent by Drazil and list received by Dreamoon. What is the probability that Dreamoon ends in the position originally supposed to be final by Drazil's commands?


-----Input-----

The first line contains a string s_1 — the commands Drazil sends to Dreamoon, this string consists of only the characters in the set {'+', '-'}. 

The second line contains a string s_2 — the commands Dreamoon's smartphone recognizes, this string consists of only the characters in the set {'+', '-', '?'}. '?' denotes an unrecognized command.

Lengths of two strings are equal and do not exceed 10.


-----Output-----

Output a single real number corresponding to the probability. The answer will be considered correct if its relative or absolute error doesn't exceed 10^{ - 9}.


-----Examples-----
Input
++-+-
+-+-+

Output
1.000000000000

Input
+-+-
+-??

Output
0.500000000000

Input
+++
??-

Output
0.000000000000



-----Note-----

For the first sample, both s_1 and s_2 will lead Dreamoon to finish at the same position  + 1. 

For the second sample, s_1 will lead Dreamoon to finish at position 0, while there are four possibilites for s_2: {"+-++", "+-+-", "+--+", "+---"} with ending position {+2, 0, 0, -2} respectively. So there are 2 correct cases out of 4, so the...
#!/usr/bin/env python3
# -*- coding: utf-8 -*-

import itertools


s1 = input()
s2 = input()

s1_p = s1.count('+')
s1_n = s1.count('-')

s2_p = s2.count('+')
s2_n = s2.count('-')
s2_q = s2.count('?')

correct_pos = s1_p - s1_n
drea_pos = s2_p - s2_n

diff_pos = correct_pos - drea_pos

if s2_q == 0:
    if diff_pos == 0:
        print(1.0)
    else:
        print(0.0)
else:
    #print("diff_pos = ", diff_pos)
    num = 0
    den = 0
    for c in itertools.product([1, -1], repeat=s2_q):
        if sum(c) == diff_pos:
           num += 1 
        den += 1
    print("{0:.10f}".format(float(num) / den))