Solve in Python:
Bob watches TV every day. He always sets the volume of his TV to $b$. However, today he is angry to find out someone has changed the volume to $a$. Of course, Bob has a remote control that can change the volume.

There are six buttons ($-5, -2, -1, +1, +2, +5$) on the control, which in one press can either increase or decrease the current volume by $1$, $2$, or $5$. The volume can be arbitrarily large, but can never be negative. In other words, Bob cannot press the button if it causes the volume to be lower than $0$.

As Bob is so angry, he wants to change the volume to $b$ using as few button presses as possible. However, he forgets how to do such simple calculations, so he asks you for help. Write a program that given $a$ and $b$, finds the minimum number of presses to change the TV volume from $a$ to $b$.


-----Input-----

Each test contains multiple test cases. The first line contains the number of test cases $T$ ($1 \le T \le 1\,000$). Then the descriptions of the test cases follow.

Each test case consists of one line containing two integers $a$ and $b$ ($0 \le a, b \le 10^{9}$) — the current volume and Bob's desired volume, respectively.


-----Output-----

For each test case, output a single integer — the minimum number of presses to change the TV volume from $a$ to $b$. If Bob does not need to change the volume (i.e. $a=b$), then print $0$.


-----Example-----
Input
3
4 0
5 14
3 9

Output
2
3
2



-----Note-----

In the first example, Bob can press the $-2$ button twice to reach $0$. Note that Bob can not press $-5$ when the volume is $4$ since it will make the volume negative. 

In the second example, one of the optimal ways for Bob is to press the $+5$ twice, then press $-1$ once.

In the last example, Bob can press the $+5$ once, then press $+1$.
T = int(input())

for _ in range(T):
	a, b = map(int, input().split())

	d = abs(a - b)

	ans = (d // 5)

	d = d % 5

	if d == 1 or d == 2:
		ans += 1

	if d == 3 or d == 4:
		ans += 2

	print(ans)