Find the first name and age of students who have a pet.
SELECT DISTINCT T1.fname ,  T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid  =  T2.stuid
SELECT DISTINCT T1.fname ,  T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid  =  T2.stuid
[{'Fname': 'Linda', 'Age': 18}, {'Fname': 'Tracy', 'Age': 19}]