Find the number and averaged salary of all instructors who are in the department with the highest budget.
SELECT avg(T1.salary) ,  count(*) FROM instructor AS T1 JOIN department AS T2 ON T1.dept_name  =  T2.dept_name ORDER BY T2.budget DESC LIMIT 1
SELECT avg(T1.salary) ,  count(*) FROM instructor AS T1 JOIN department AS T2 ON T1.dept_name  =  T2.dept_name ORDER BY T2.budget DESC LIMIT 1
[{'avg(T1.salary)': 77600.18819999999, 'count(*)': 50}]