Show institution names along with the number of proteins for each institution.
SELECT T1.institution ,  count(*) FROM institution AS T1 JOIN protein AS T2 ON T1.institution_id  =  T2.institution_id GROUP BY T1.institution_id
SELECT T1.institution ,  count(*) FROM institution AS T1 JOIN protein AS T2 ON T1.institution_id  =  T2.institution_id GROUP BY T1.institution_id
[{'Institution': 'Dakota State University', 'count(*)': 1}, {'Institution': 'Haskell Indian Nations University', 'count(*)': 1}, {'Institution': 'Lindenwood University–Belleville', 'count(*)': 2}, {'Institution': 'Valley City State University', 'count(*)': 1}]