which business has the most number of checkins
SELECT t1.name FROM checkin AS t2 JOIN business AS t1 ON t2.business_id  =  t1.business_id GROUP BY t1.name ORDER BY SUM ( t2.count ) DESC LIMIT 1;
SELECT t1.name FROM checkin AS t2 JOIN business AS t1 ON t2.business_id  =  t1.business_id GROUP BY t1.name ORDER BY SUM ( t2.count ) DESC LIMIT 1;
[{'Nenhum': 'Nenhum resultado encontrado'}]