find the number of restaurant rated more than 3.5
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id  =  t1.business_id WHERE t1.rating  >  3.5 AND t2.category_name  =  "restaurant";
SELECT COUNT ( DISTINCT t1.name ) FROM category AS t2 JOIN business AS t1 ON t2.business_id  =  t1.business_id WHERE t1.rating  >  3.5 AND t2.category_name  =  "restaurant";
[{'COUNT ( DISTINCT t1.name )': 0}]