What are the names of students who have more than one advisor?
SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id  =  T2.s_id GROUP BY T2.s_id HAVING count(*)  >  1
SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id  =  T2.s_id GROUP BY T2.s_id HAVING count(*)  >  1
[{'Nenhum': 'Nenhum resultado encontrado'}]