How many papers were at nature communications 2015 ?
SELECT DISTINCT COUNT ( t1.paperid ) FROM venue AS t2 JOIN paper AS t1 ON t2.venueid  =  t1.venueid WHERE t1.year  =  2015 AND t2.venuename  =  "nature communications";
SELECT DISTINCT COUNT ( t1.paperid ) FROM venue AS t2 JOIN paper AS t1 ON t2.venueid  =  t1.venueid WHERE t1.year  =  2015 AND t2.venuename  =  "nature communications";
[{'COUNT ( t1.paperid )': 0}]