<story><title>How do you find integer solutions to x/(y + z) + y/(x + z) + z/(x + y) = 4?</title><url>https://www.quora.com/How-do-you-find-the-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4/answer/Alon-Amit?share=1</url></story><parent_chain></parent_chain><comment><author>mrkgnao</author><text>For anyone looking to learn more about elliptic curves, which are astoundingly &amp;quot;well-connected&amp;quot; as math topics go, here&amp;#x27;s a good book that should be accessible to anyone with some calculus under their belt:&lt;p&gt;&lt;a href=&quot;https:&amp;#x2F;&amp;#x2F;www.amazon.com&amp;#x2F;Elliptic-Tales-Curves-Counting-Number&amp;#x2F;dp&amp;#x2F;0691151199&quot; rel=&quot;nofollow&quot;&gt;https:&amp;#x2F;&amp;#x2F;www.amazon.com&amp;#x2F;Elliptic-Tales-Curves-Counting-Number...&lt;/a&gt;&lt;p&gt;It&amp;#x27;s not a textbook, which is both good and bad. In my case, it did a good job whetting my appetite for more!&lt;p&gt;A really well-written and not-extremely-difficult undergrad textbook on elliptic curves:&lt;p&gt;&lt;a href=&quot;https:&amp;#x2F;&amp;#x2F;www.amazon.com&amp;#x2F;Rational-Points-Elliptic-Undergraduate-Mathematics&amp;#x2F;dp&amp;#x2F;331918587X&quot; rel=&quot;nofollow&quot;&gt;https:&amp;#x2F;&amp;#x2F;www.amazon.com&amp;#x2F;Rational-Points-Elliptic-Undergraduat...&lt;/a&gt;&lt;p&gt;(Non-affiliate links, just so you know.)</text></comment>
<story><title>How do you find integer solutions to x/(y + z) + y/(x + z) + z/(x + y) = 4?</title><url>https://www.quora.com/How-do-you-find-the-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4/answer/Alon-Amit?share=1</url></story><parent_chain></parent_chain><comment><author>AbacusAvenger</author><text>The Wolfram Alpha results for this one are pretty intimidating:&lt;p&gt;&lt;a href=&quot;http:&amp;#x2F;&amp;#x2F;www.wolframalpha.com&amp;#x2F;input&amp;#x2F;?i=(a%2F(b%2Bc))%2B(b%2F(a%2Bc))%2B(c%2F(a%2Bb))%3D4&quot; rel=&quot;nofollow&quot;&gt;http:&amp;#x2F;&amp;#x2F;www.wolframalpha.com&amp;#x2F;input&amp;#x2F;?i=(a%2F(b%2Bc))%2B(b%2F(a...&lt;/a&gt;</text></comment>