Jaka jest pochodna funkcji x^2 + 2x + 8?
The derivative of x^2 + 2x + 8 is 2x + 2. 
This is because the derivative of x^n is nx^(n-1), and the derivative of a constant is 0. Applying these rules to the given fonction, we get: 
d/dx (x^2 + 2x + 8) = d/dx (x^2) + d/dx (2x) + d/dx (8) 
= 2x + 2(1) + 0 
= 2x + 2 
Therefore, the derivative of x^2 + 2x + 8 with respect to x is 2x + 2.