In mathematics,  $$1!=1$$  $$2!=2\times 1$$  $$3!=3\times 2\times 1$$  $$\textasciitilde\textasciitilde\textasciitilde\textasciitilde\textasciitilde$$$$\vdots $$  Find the last two digits in $$1!+2!+3!+4!+5!+6!+7!+8!$$. 
Overseas Competition->Knowledge Point->Number Theory Modules->Division without Remainders->Applying the Properties of Dividing without Remainders->Maximum/Minimum Problems of Division without Remainders 