SELECT COUNT(*) FROM allergy_type WHERE allergytype = "animal"
How many allergies have type animal?
CREATE TABLE student (
    stuid number,
    lname text,
    fname text,
    age number,
    sex text,
    major number,
    advisor number,
    city_code text
)

CREATE TABLE has_allergy (
    stuid number,
    allergy text
)

CREATE TABLE allergy_type (
    allergy text,
    allergytype text
)