what is the tv station when the average ratings is 19.5%?
CREATE TABLE table_name_36 (
    tv_station VARCHAR,
    average_ratings VARCHAR
)
SELECT tv_station FROM table_name_36 WHERE average_ratings = "19.5%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: what is the tv station when the average ratings is 19.5%? ### Input: CREATE TABLE table_name_36 (
    tv_station VARCHAR,
    average_ratings VARCHAR
) ### Response: SELECT tv_station FROM table_name_36 WHERE average_ratings = "19.5%"