What Kerry's percentage where 66 people voted for another candidate?
CREATE TABLE table_47911 (
    "County" text,
    "Kerry%" text,
    "Kerry#" real,
    "Bush%" text,
    "Bush#" real,
    "Others%" text,
    "Others#" real
)
SELECT "Kerry%" FROM table_47911 WHERE "Others#" = '66'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What Kerry's percentage where 66 people voted for another candidate? ### Input: CREATE TABLE table_47911 (
    "County" text,
    "Kerry%" text,
    "Kerry#" real,
    "Bush%" text,
    "Bush#" real,
    "Others%" text,
    "Others#" real
) ### Response: SELECT "Kerry%" FROM table_47911 WHERE "Others#" = '66'