What is the safari value with a 2.4% opera and 29.9% internet explorer?
CREATE TABLE table_name_7 (
    safari VARCHAR,
    opera VARCHAR,
    internet_explorer VARCHAR
)
SELECT safari FROM table_name_7 WHERE opera = "2.4%" AND internet_explorer = "29.9%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What is the safari value with a 2.4% opera and 29.9% internet explorer? ### Input: CREATE TABLE table_name_7 (
    safari VARCHAR,
    opera VARCHAR,
    internet_explorer VARCHAR
) ### Response: SELECT safari FROM table_name_7 WHERE opera = "2.4%" AND internet_explorer = "29.9%"