Which source reported 32.60% of browsers used Chrome?
CREATE TABLE table_name_43 (
    source VARCHAR,
    chrome VARCHAR
)
SELECT source FROM table_name_43 WHERE chrome = "32.60%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: Which source reported 32.60% of browsers used Chrome? ### Input: CREATE TABLE table_name_43 (
    source VARCHAR,
    chrome VARCHAR
) ### Response: SELECT source FROM table_name_43 WHERE chrome = "32.60%"