What occurrs as of September 1, 2012 when the value for vs. all is 65.47%?
CREATE TABLE table_name_61 (
    as_of_september_1 VARCHAR,
    _2012 VARCHAR,
    vs_all VARCHAR
)
SELECT as_of_september_1, _2012 FROM table_name_61 WHERE vs_all = "65.47%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What occurrs as of September 1, 2012 when the value for vs. all is 65.47%? ### Input: CREATE TABLE table_name_61 (
    as_of_september_1 VARCHAR,
    _2012 VARCHAR,
    vs_all VARCHAR
) ### Response: SELECT as_of_september_1, _2012 FROM table_name_61 WHERE vs_all = "65.47%"