Number of participants with a score 8.895 in preliminary
CREATE TABLE table_17088705_2 (
    interview VARCHAR,
    preliminary VARCHAR
)
SELECT COUNT(interview) FROM table_17088705_2 WHERE preliminary = "8.895"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: Number of participants with a score 8.895 in preliminary ### Input: CREATE TABLE table_17088705_2 (
    interview VARCHAR,
    preliminary VARCHAR
) ### Response: SELECT COUNT(interview) FROM table_17088705_2 WHERE preliminary = "8.895"