How many titles had an average rating of 8.9%?
CREATE TABLE table_18539834_2 (
    romaji_title VARCHAR,
    average_ratings VARCHAR
)
SELECT COUNT(romaji_title) FROM table_18539834_2 WHERE average_ratings = "8.9%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: How many titles had an average rating of 8.9%? ### Input: CREATE TABLE table_18539834_2 (
    romaji_title VARCHAR,
    average_ratings VARCHAR
) ### Response: SELECT COUNT(romaji_title) FROM table_18539834_2 WHERE average_ratings = "8.9%"