What's the name of the county where 48.3% voted for Bush?
CREATE TABLE table_1304443_2 (
    county VARCHAR,
    bush_percentage VARCHAR
)
SELECT county FROM table_1304443_2 WHERE bush_percentage = "48.3%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What's the name of the county where 48.3% voted for Bush? ### Input: CREATE TABLE table_1304443_2 (
    county VARCHAR,
    bush_percentage VARCHAR
) ### Response: SELECT county FROM table_1304443_2 WHERE bush_percentage = "48.3%"