When Keey has 58.1% what % does Bush have?
CREATE TABLE table_71025 (
    "County" text,
    "Kerry%" text,
    "Kerry#" real,
    "Bush%" text,
    "Bush#" real,
    "Others%" text,
    "Others#" real
)
SELECT "Bush%" FROM table_71025 WHERE "Kerry%" = '58.1%'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: When Keey has 58.1% what % does Bush have? ### Input: CREATE TABLE table_71025 (
    "County" text,
    "Kerry%" text,
    "Kerry#" real,
    "Bush%" text,
    "Bush#" real,
    "Others%" text,
    "Others#" real
) ### Response: SELECT "Bush%" FROM table_71025 WHERE "Kerry%" = '58.1%'