What percentage of users were using other Mozilla browsers during the period in which 9.00% were using Chrome?
CREATE TABLE table_name_58 (
    other_mozilla VARCHAR,
    chrome VARCHAR
)
SELECT other_mozilla FROM table_name_58 WHERE chrome = "9.00%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What percentage of users were using other Mozilla browsers during the period in which 9.00% were using Chrome? ### Input: CREATE TABLE table_name_58 (
    other_mozilla VARCHAR,
    chrome VARCHAR
) ### Response: SELECT other_mozilla FROM table_name_58 WHERE chrome = "9.00%"