What percentage of users were using other Mozilla browsers during the period in which 2.29% were using Opera?
CREATE TABLE table_name_97 (
    other_mozilla VARCHAR,
    opera VARCHAR
)
SELECT other_mozilla FROM table_name_97 WHERE opera = "2.29%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What percentage of users were using other Mozilla browsers during the period in which 2.29% were using Opera? ### Input: CREATE TABLE table_name_97 (
    other_mozilla VARCHAR,
    opera VARCHAR
) ### Response: SELECT other_mozilla FROM table_name_97 WHERE opera = "2.29%"