What's the percentage of votes for other candidates in the county where Bush got 51.6% of the votes?
CREATE TABLE table_1304443_2 (
    others_percentage VARCHAR,
    bush_percentage VARCHAR
)
SELECT others_percentage FROM table_1304443_2 WHERE bush_percentage = "51.6%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What's the percentage of votes for other candidates in the county where Bush got 51.6% of the votes? ### Input: CREATE TABLE table_1304443_2 (
    others_percentage VARCHAR,
    bush_percentage VARCHAR
) ### Response: SELECT others_percentage FROM table_1304443_2 WHERE bush_percentage = "51.6%"