How many no outs for an average of 56.38?
CREATE TABLE table_20367820_16 (
    not_out VARCHAR,
    average VARCHAR
)
SELECT COUNT(not_out) FROM table_20367820_16 WHERE average = "56.38"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: How many no outs for an average of 56.38? ### Input: CREATE TABLE table_20367820_16 (
    not_out VARCHAR,
    average VARCHAR
) ### Response: SELECT COUNT(not_out) FROM table_20367820_16 WHERE average = "56.38"