What percentage of people were opposed to the candidate based on the Time Poll poll that showed 6% of people were unsure?
CREATE TABLE table_name_22 (
    oppose VARCHAR,
    poll_source VARCHAR,
    unsure VARCHAR
)
SELECT oppose FROM table_name_22 WHERE poll_source = "time poll" AND unsure = "6%"
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What percentage of people were opposed to the candidate based on the Time Poll poll that showed 6% of people were unsure? ### Input: CREATE TABLE table_name_22 (
    oppose VARCHAR,
    poll_source VARCHAR,
    unsure VARCHAR
) ### Response: SELECT oppose FROM table_name_22 WHERE poll_source = "time poll" AND unsure = "6%"