What 2008 has 14.2% as the 2009?
CREATE TABLE table_65706 (
    "Score" text,
    "2007" text,
    "2008" text,
    "2009" text,
    "2010" text,
    "2011" text,
    "2012" text
)
SELECT "2008" FROM table_65706 WHERE "2009" = '14.2%'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What 2008 has 14.2% as the 2009? ### Input: CREATE TABLE table_65706 (
    "Score" text,
    "2007" text,
    "2008" text,
    "2009" text,
    "2010" text,
    "2011" text,
    "2012" text
) ### Response: SELECT "2008" FROM table_65706 WHERE "2009" = '14.2%'