If Internet Explorer is 47.22%, what is the Safari total?
CREATE TABLE table_22587 (
    "Period" text,
    "Internet Explorer" text,
    "Firefox" text,
    "Chrome" text,
    "Safari" text,
    "Opera" text,
    "Other Mozilla" text,
    "Mobile" text
)
SELECT "Safari" FROM table_22587 WHERE "Internet Explorer" = '47.22%'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: If Internet Explorer is 47.22%, what is the Safari total? ### Input: CREATE TABLE table_22587 (
    "Period" text,
    "Internet Explorer" text,
    "Firefox" text,
    "Chrome" text,
    "Safari" text,
    "Opera" text,
    "Other Mozilla" text,
    "Mobile" text
) ### Response: SELECT "Safari" FROM table_22587 WHERE "Internet Explorer" = '47.22%'