What was the percentage of safari when firefox was 24.66%
CREATE TABLE table_65410 (
    "Date" text,
    "Internet Explorer" text,
    "Chrome" text,
    "Firefox" text,
    "Safari" text
)
SELECT "Safari" FROM table_65410 WHERE "Firefox" = '24.66%'
Below are sql tables schemas paired with instruction that describes a task. Using valid SQLite, write a response that appropriately completes the request for the provided tables. ### Instruction: What was the percentage of safari when firefox was 24.66% ### Input: CREATE TABLE table_65410 (
    "Date" text,
    "Internet Explorer" text,
    "Chrome" text,
    "Firefox" text,
    "Safari" text
) ### Response: SELECT "Safari" FROM table_65410 WHERE "Firefox" = '24.66%'