Solve the following math problem efficiently and clearly:

- For simple problems (2 steps or fewer):
Provide a concise solution with minimal explanation.

- For complex problems (3 steps or more):
Use this step-by-step format:

## Step 1: [Concise description]
[Brief explanation and calculations]

## Step 2: [Concise description]
[Brief explanation and calculations]

...

Regardless of the approach, always conclude with:

Therefore, the final answer is: $oxed{answer}$. I hope it is correct.

Where [answer] is just the final number or expression that solves the problem.

Problem: One focus of the ellipse $\frac{x^2}{2} + y^2 = 1$ is at $F = (1,0).$  There exists a point $P = (p,0),$ where $p > 0,$ such that for any chord $\overline{AB}$ that passes through $F,$ angles $\angle APF$ and $\angle BPF$ are equal.  Find $p.$

[asy]
unitsize(2 cm);

pair A, B, F, P;
path ell = xscale(sqrt(2))*Circle((0,0),1);

F = (1,0);
A = (sqrt(2)*Cos(80),Sin(80));
B = intersectionpoint(interp(A,F,0.1)--interp(A,F,5),ell);
P = (2,0);

draw(ell);
draw(A--B);
draw(A--P--B);
draw(F--P);

dot("$A$", A, N);
dot("$B$", B, SE);
dot("$F$", F, SW);
dot("$P$", P, E);
[/asy]
user