the value of a scooter depreciates in such a way that its value of the end of each year is 3 / 4 of its value of the beginning of the same year . if the initial value of the scooter is rs . 40000 , what is the value at the end of 2 years ?
n0 = 3.0
n1 = 4.0
n2 = 40000.0
n3 = 2.0
t0 = n0 / n1
t1 = 100.0 * 100.0
t2 = n1 * t1
t3 = t0**min(n3, 5)
answer = t2 * t3
print(answer)