if ( 8000 ) ( 6000 ) = ( 480 ) ( 10 ^ y ) , what is the value of y ?
import math
n0 = 8000.0
n1 = 6000.0
n2 = 480.0
n3 = 10.0
t0 = math.log(max(1e-5, 10.0), 2)
t1 = n0 * n1
t2 = t1 / n2
t3 = math.log(max(1e-5, t2), 2)
answer = t3 / t0
print(answer)