if p # q denotes the least common multiple of p and q , then e = ( ( 12 # 16 ) # ( 18 # 24 ) ) = ?
n0 = 12.0
n1 = 16.0
n2 = 18.0
n3 = 24.0
t0 = n2 * n3
t1 = n0 * n1
t2 = t0 - t1
t3 = t2 / 2.0
answer = n3 + t3
print(answer)