if k is an integer and 0.00010101 x 10 ^ k is greater than 100 , what is the least possible value of k ?
import math
n0 = 0.00010101
n1 = 10.0
n2 = 100.0
t0 = n2 / n0
t1 = math.log(max(1e-5, 10.0), 2)
t2 = math.log(max(1e-5, t0), 2)
answer = t2 / t1
print(answer)