there is one 4 - digit whole number n , such that the last 4 digits of n 2 are in fact the original number n
n0 = 4.0
n1 = 4.0
n2 = 2.0
t0 = 100.0 * 3.0
t1 = 12.0 * 4.0
t2 = 12.0 - 3.0
t3 = t2 * 1000.0
t4 = t1 - 10.0
t5 = n2 * t4
t6 = t0 + t5
answer = t6 + t3
print(answer)