The second of three numbers is 1 less than the first . The third number is 5 less than the second . If the first number is twice as large as the third , Find the three numbers .
from sympy import *
x,y,z = symbols('x y z')
answer = solve([Eq(y, x-1.0),Eq(z, y-5.0),Eq(x, 2.0*z)])
print(answer)
