find large no . from below question the difference of two numbers is 1365 . on dividing the larger number by the smaller , we get 6 as quotient and the 15 as remainder
n0 = 1365.0
n1 = 6.0
n2 = 15.0
t0 = n0 - n2
t1 = n1 - 1.0
t2 = t0 / t1
answer = n1 * t2
print(answer)