the value of “ a ” varies in inverse proportion as the square of “ b ” . if the value of “ a ” is equal to 40 when “ b ” is equal to 12 . what would be the value of “ a ” when “ b ” is equal to 24 ?
n0 = 40.0
n1 = 12.0
n2 = 24.0
t0 = n1**min(2.0, 5)
t1 = n2**min(2.0, 5)
t2 = n0 * t0
answer = t2 / t1
print(answer)