If the first and third of 3 consecutive odd integers are added , the result is 57 less than 5 times the second integer . Find the 3rd integer .
from sympy import *
k = symbols('k')
answer = solve([Eq((2.0*k-1.0)+(2.0*k+3.0), 5.0*(2.0*k+1.0)-57.0)])
print(answer)
