if n is an integer and 101 n ^ 2 is less than or equal to 6400 , what is the greatest possible value of n ?
import math
n0 = 101.0
n1 = 2.0
n2 = 6400.0
t0 = n2 / n0
t1 = math.sqrt(max(0, t0))
answer = math.floor(t1)
print(answer)