sum of the squares of 3 no . ' s is 62 and the sum of their products taken two at a time is 131 . find the sum ?
import math
n0 = 3.0
n1 = 62.0
n2 = 131.0
t0 = n2 * 2.0
t1 = n1 + t0
answer = math.sqrt(max(0, t1))
print(answer)