x varies inversely as square of y . given that y = 3 for x = 1 . the value of x for y = 9 will be equal to :
n0 = 3.0
n1 = 1.0
n2 = 9.0
t0 = n0**min(2.0, 5)
t1 = n2**min(2.0, 5)
t2 = n1 * t0
answer = t2 / t1
print(answer)