an error 2 % in excess is made while measuring the sideofa square . the % of error in the calculated area of the square is ?
n0 = 2.0
t0 = n0 + 100.0
t1 = 100.0**2
t2 = t0**2
t3 = t2 - t1
t4 = t3 * 100.0
answer = t4 / t1
print(answer)