if x is an integer and 2.13 × 10 ^ x is less than 2100 , what is the greatest possible value for x ?
import math
n0 = 2.13
n1 = 10.0
n2 = 2100.0
t0 = n2 / n0
t1 = math.log(max(1e-5, n1), 2)
t2 = math.log(max(1e-5, t0), 2)
t3 = t2 / t1
answer = math.floor(t3)
print(answer)