the volume of the sphere qq is ( dfrac { 37 } { 64 } % ) less than the volume of sphere pp and the volume of sphere rr is ( dfrac { 19 } { 27 } % ) less than that of sphere qq . by what is the surface areaof sphere rr less than the surfacearea of sphere pp ?
n0 = 37.0
n1 = 64.0
n2 = 19.0
n3 = 27.0
t0 = 1.0 / 3.0
t1 = n1**min(t0, 5)
t2 = n3**min(t0, 5)
t3 = t1 * t2
t4 = t3 + t1
t5 = t4 - t1
t6 = t1 + t5
t7 = t6 - t1
t8 = t7 / t6
answer = t8 * 100.0
print(answer)