every year an amount increases by 1 / 8 th of itself . how much will it be after two years if its present value is rs . 57600 ?
n0 = 1.0
n1 = 8.0
n2 = 57600.0
t0 = n0 / n1
t1 = n2 * t0
t2 = n2 + t1
t3 = t2 * t0
answer = t2 + t3
print(answer)