# Time:  O(n)
# Space: O(1)

class Solution(object):
    def maxChunksToSorted(self, arr):
        """
        :type arr: List[int]
        :rtype: int
        """
        result, max_i = 0, 0
        for i, v in enumerate(arr):
            max_i = max(max_i, v)
            if max_i == i:
                result += 1
        return result

# Time:  O(n)
# Space: O(1)

# Given an array arr that is a permutation of [0, 1, ..., arr.length - 1],
# we split the array into some number of "chunks" (partitions), and individually sort each chunk.
# After concatenating them, the result equals the sorted array.
#
# What is the most number of chunks we could have made?
#
# Example 1:
#
# Input: arr = [4,3,2,1,0]
# Output: 1
# Explanation:
# Splitting into two or more chunks will not return the required result.
# For example, splitting into [4, 3], [2, 1, 0] will result in [3, 4, 0, 1, 2], which isn't sorted.
#
# Example 2:
#
# Input: arr = [1,0,2,3,4]
# Output: 4
# Explanation:
# We can split into two chunks, such as [1, 0], [2, 3, 4].
# However, splitting into [1, 0], [2], [3], [4] is the highest number of chunks possible.
#
# Note:
# - arr will have length in range [1, 10].
# - arr[i] will be a permutation of [0, 1, ..., arr.length - 1].

class Solution(object):
    def maxChunksToSorted(self, arr):
        """
        :type arr: List[int]
        :rtype: int
        """
        result, max_i = 0, 0
        for i, v in enumerate(arr):
            max_i = max(max_i, v)
            if max_i == i:
                result += 1
        return result

Update max-chunks-to-make-sorted-i.py