### Instruction: Find $\left\lceil \sqrt[3]{-25}\right\rceil$.### Response: The expression $\left\lceil x\right\rceil$ means the smallest integer that is greater than or equal to $x$.
So I need to find the smallest integer that is greater than or equal to $\sqrt[3]{-25}$.
I know that $\sqrt[3]{-27}=-3$, so $\sqrt[3]{-25}$ must be slightly larger than -3.
But the next integer that is larger than -3 is -2.
So $\left\lceil \sqrt[3]{-25}\right\rceil=-2$.