### Instruction: Expand $(x+3)(2x-6)$.### Response: I know that I can use the distributive property to multiply two binomials, so I can write $(x+3)(2x-6)$ as $x(2x-6) + 3(2x-6)$.
Now I need to distribute again for each term, so I get $x(2x-6) + 3(2x-6) = 2x^2 - 6x + 6x - 18$.
I see that the $-6x$ and $+6x$ terms cancel out, so I can simplify the expression to $2x^2 - 18$.
This is the expanded form of the original product.