### Instruction: The positive difference between the squares of two consecutive odd integers is 128. What is the product of the two integers?### Response: I need to find two consecutive odd integers whose squares have a difference of 128.
Let me call the smaller integer x and the larger one x + 2, since odd integers differ by 2.
Then I have the equation (x + 2)^2 - x^2 = 128, which I need to solve for x.
I can expand the square and simplify the equation: x^2 + 4x + 4 - x^2 = 128, which gives me 4x + 4 = 128.
Subtracting 4 from both sides, I get 4x = 124, and dividing by 4, I get x = 31.
So the smaller integer is 31 and the larger one is 31 + 2 = 33.