### Instruction: The graph of $y = f(x)$ passes through the point $(-3,5).$  If $f(x)$ is an odd function, then what other point must the graph pass through?  Enter your answer as an ordered pair.### Response: An odd function is a function that satisfies $f(-x) = -f(x)$ for all $x$.
This means that the graph of an odd function is symmetric about the origin.
To find another point that the graph passes through, I can use the property of odd functions and plug in the opposite of $-3$, which is $3$, into $f(x)$.
This gives me $f(3) = -f(-3)$.
Since I know that $f(-3) = 5$, I can substitute that and simplify.
This gives me $f(3) = -(-5) = 5$.
So the graph also passes through the point $(3,5)$.
That is my answer.