### Instruction: Evaluate $\log_2\frac{1}{16}$.### Response: I recognize that 16 is a power of 2, namely $2^4$.
So, $\frac{1}{16}$ is the same as $2^{-4}$.
That means I can rewrite the logarithm as $\log_2(2^{-4})$.
Now, I recall the property of logarithms that says $\log_b(b^x) = x$ for any base b and any exponent x.