### Instruction: A bowling ball cannot weigh more than 16 pounds and must have a diameter of $8 \frac{1}{2}$ inches. How many square inches are in the surface area of a bowling ball before the finger holes are drilled? Express your answer as a common fraction in terms of $\pi$.### Response: We can find the surface area of the bowling ball by using the formula $4\pi r^2$.
First we need to find the radius.
The diameter is $8\frac{1}{2}$ inches, so the radius is one half of that which is $4\frac{1}{4}$ inches.
That is equivalent to $17/4$ inches.
That's right. Now we can substitute that value into the formula $4\pi r^2$.
$4\pi (17/4)^2 = 4\pi (289/16) = 289\pi/4$.