### Instruction: How many numbers are in the list $ -36, -29, -22, \ldots, 41, 48?$.### Response: This problem asks me to find the number of terms in an arithmetic sequence, where each term is obtained by adding 7 to the previous term.
One way to do this is to use a formula for the general term of an arithmetic sequence: $a_n = a_1 + (n - 1)d$, where $a_n$ is the $n$th term, $a_1$ is the first term, and $d$ is the common difference.
In this problem, I can see that $a_1 = -36$ and $d = 7$.
I want to find the value of $n$ that makes $a_n = 48$, since that is the last term in the list.
So I can set up an equation: $48 = -36 + (n - 1)7$.
Simplifying this equation, I get $84 = (n - 1)7$, so $n - 1 = 12$, and $n = 13$.