### Instruction: If $t(x) = 9+2f(x)$ and $f(x) = x^2-3$, then what is $t(f(-2))$?### Response: To find $t(f(-2))$, I need to first evaluate $f(-2)$ and then plug that into $t(x)$.
I know that $f(x) = x^2-3$, so $f(-2) = (-2)^2-3 = 4-3 = 1$.
Now I have $t(f(-2)) = t(1)$.
To find $t(1)$, I need to use the definition of $t(x)$, which is $9+2f(x)$.
So $t(1) = 9+2f(1)$.
To find $f(1)$, I need to use the definition of $f(x)$ again, which is $x^2-3$.
So $f(1) = 1^2-3 = -2$.
Now I have $t(1) = 9+2(-2) = 9-4 = 5$.