### Instruction: If $5a=-4b+5$ and $3a=-2b+3$, what is $6b$?### Response: I notice that both equations involve $a$ and $b$, so I might try to eliminate one of them by combining the equations.
One way to do that is to multiply the first equation by $3$ and the second one by $5$, so I get $15a=-12b+15$ and $15a=-10b+15$.
Then I can subtract the second equation from the first one to get $0=-2b$.
This means that $b=0$, so $6b=0$ as well.