### Instruction: Three positive integers $a,$ $b,$ and $x$ form an O'Hara triple $(a,b,x)$ if $\sqrt{a}+\sqrt{b}=x.$ For example, $(1,4,3)$ is an O'Hara triple because $\sqrt{1}+\sqrt{4}=3.$

If $(36,25,x)$ is an O'Hara triple, determine the value of $x.$.### Response: I need to find a positive integer $x$ that satisfies $\sqrt{36}+\sqrt{25}=x.$
I know that $\sqrt{36}=6$ and $\sqrt{25}=5,$ so I can simplify the equation to $6+5=x.$
Therefore, $x=11.$