### Instruction: Find the domain of the function $\frac{x^4-4x^3+6x^2-4x+1}{x^2-4}$.### Response: So to find the domain of this function, we need to find the values of $x$ where the function is defined.
Right. So the function is defined everywhere except where the denominator is equal to zero.
That's right. So we need to solve $x^2-4=0$.
That's easy. $x^2-4=0$ implies $x^2=4$, so $x=\pm 2$.
So the domain of the function is $\{x\in\mathbb{R}\mid x\neq 2, x\neq -2\}$.