### Instruction: What is the area, in square units, of a triangle that has sides of $4,3$ and $3$ units? Express your answer in simplest radical form.### Response: I remember that there is a formula for the area of a triangle when I know the lengths of its three sides, called Heron's formula.
It says that the area A is given by A = sqrt(s(s-a)(s-b)(s-c)), where a, b, and c are the side lengths and s is the semi-perimeter, or half of the perimeter.
So let me find s first.
The perimeter is 4 + 3 + 3 = 10, so s is half of that, or 5.
Now I can plug in the values of s, a, b, and c into the formula.
I get A = sqrt(5(5-4)(5-3)(5-3)), which simplifies to A = sqrt(5(1)(2)(2)).