### Instruction: A laboratory has 22 beakers of liquid in a fume hood, and 8 of the beakers have copper ions in them. Adding three drops of a solution will turn the liquid in a beaker blue if there are copper ions present. If the beakers are tested one by one for copper ions and 45 drops are used before all 8 beakers with copper ions are found, how many beakers without copper ions were tested? Let's write a Python program.### Response: # calculate the number of beakers tested using the drops of solution used
beakers_tested = 45 // 3
# subtract the number of beakers with copper ions to find the number without
beakers_without_copper = beakers_tested - 8
print(beakers_without_copper)