### Instruction: Compute $\arccos (\sin 2).$  All functions are in radians.### Response: I want to find an angle $\theta$ such that $\cos \theta = \sin 2.$
I know that $\cos \theta = \sin (\frac{\pi}{2} - \theta)$ for any angle $\theta.$
So, if I set $\frac{\pi}{2} - \theta = 2,$ I can find $\theta$ by solving for it.
Adding $\theta$ to both sides, I get $\frac{\pi}{2} = \theta + 2.$
Subtracting $2$ from both sides, I get $\frac{\pi}{2} - 2 = \theta.$
This is the answer I'm looking for.