### Instruction: Solve for $z$ in the following equation: $2-iz = -1 + 3iz$.

Express your answer in standard form.### Response: To solve for $z$, I need to isolate it on one side of the equation.
I can do this by adding $iz$ to both sides and adding $1$ to both sides.
This gives me $3 = 4iz$.
Now I can divide both sides by $4i$ to get $z = \frac{3}{4i}$.
However, this is not in standard form, which requires the coefficient of $i$ to be real.
To fix this, I can multiply the numerator and denominator by $i$, since $i \times i = -1$.
This gives me $z = \frac{3i}{-4}$.
Simplifying the sign, I get $z = -\frac{3i}{4}$.
This is the final answer in standard form.