### Instruction: A square has a perimeter of $28 \text{ cm}.$ What is the area of the square, in $\mbox{cm}^2?$.### Response: I know that the perimeter of a square is the sum of the lengths of its four sides, and that all sides of a square are equal.
So, if I call the length of one side of the square $x$, then the perimeter is $4x = 28$.
Solving for $x$, I get $x = \frac{28}{4} = 7$.
Therefore, the length of one side of the square is $7 \text{ cm}$.
The area of a square is the square of the length of one side, so the area is $x^2 = 7^2 = 49$.
The units of area are $\mbox{cm}^2$, so the final answer is $49 \text{ cm}^2$.