### Instruction: The graph of $y = f(x)$ passes through the point $(-3,5).$  If $f(x)$ is an odd function, then what other point must the graph pass through?  Enter your answer as an ordered pair.### Response: I know that an odd function is symmetric about the origin, meaning that $f(-x) = -f(x)$ for any $x$.
So if $y = f(x)$ passes through $(-3,5)$, then $f(-3) = 5$.
To find another point on the graph, I can use the property of odd functions and plug in the opposite of $-3$, which is $3$.
Then $f(3) = -f(-3) = -5$, since I negate the output when I negate the input.
Therefore, the graph of $y = f(x)$ also passes through the point $(3,-5)$.