### Instruction: A bowling ball cannot weigh more than 16 pounds and must have a diameter of $8 \frac{1}{2}$ inches. How many square inches are in the surface area of a bowling ball before the finger holes are drilled? Express your answer as a common fraction in terms of $\pi$.### Response: I need to find the surface area of a sphere with a diameter of $8 \frac{1}{2}$ inches.
The formula for the surface area of a sphere is $4\pi r^2$, where $r$ is the radius of the sphere.
To find the radius, I can divide the diameter by 2.
So the radius is $4 \frac{1}{4}$ inches.
Plugging this into the formula, I get $4\pi (4 \frac{1}{4})^2 = 4\pi (\frac{17}{4})^2 = 4\pi \frac{289}{16} = \pi \frac{289}{4}$.
This is the surface area of the bowling ball before the finger holes are drilled.