### Instruction: In right triangle $ABC$ with $\angle B = 90^\circ$, we have $2\sin A = 3\cos A$.  What is $\tan A$?### Response: I know that $\tan A = \frac{\sin A}{\cos A}$, so I want to find the ratio of $\sin A$ and $\cos A$.
I can use the given equation $2\sin A = 3\cos A$ to eliminate one of the variables.
If I divide both sides by $2\cos A$, I get $\frac{\sin A}{\cos A} = \frac{3}{2}$.
This means $\tan A = \frac{3}{2}$.