### Instruction: A line containing the points $(2, 16)$ and $(-8, -4)$ intersects the $y$-axis at what point?### Response: We first need to find the slope of the line passing through the points $(2,16)$ and $(-8,-4)$.
The slope is equal to $\frac{16--4}{2--8}=\frac{20}{10}=2$.
So the equation of the line is $y=2x+b$.
To find b, we plug in the x- and y-coordinates of one of the points into the equation.
Let's use $(2,16)$.
So $16=2(2)+b$, which means $b=12$.
Therefore, the equation of the line is $y=2x+12$.
Now we just plug in $x=0$ to find the y-intercept.
So $y=2(0)+12$, which means $y=12$.