### Instruction: Compute $\sin(-60^\circ)$.### Response: To find the sine of a negative angle, I need to use the property that $\sin(-\theta) = -\sin(\theta)$.
This means I can change the sign of the angle and the sign of the sine value.
So, $\sin(-60^\circ) = -\sin(60^\circ)$.
Now, I need to recall the value of $\sin(60^\circ)$.
I can use the special right triangle with angles $30^\circ$, $60^\circ$, and $90^\circ$, and sides in the ratio of $1:\sqrt{3}:2$.
The sine of an angle is the opposite side over the hypotenuse, so $\sin(60^\circ) = \sqrt{3}/2$.