### Instruction: If $p (x) = 2-x^2$ and $q(x) = \frac{6}{x}$, what is the value of $p (q(2))$?### Response: To find the value of $p (q(2))$, I need to first evaluate $q(2)$ and then plug that result into $p(x)$.
To evaluate $q(2)$, I just replace $x$ with $2$ in the expression for $q(x)$ and simplify.
That gives me $q(2) = \frac{6}{2} = 3$.
Now I have $p (q(2)) = p (3)$.
To evaluate $p(3)$, I replace $x$ with $3$ in the expression for $p(x)$ and simplify.
That gives me $p(3) = 2 - 3^2 = 2 - 9 = -7$.
Therefore, the value of $p (q(2))$ is -7.