### Instruction: If we express $2x^2 + 6x + 11$ in the form $a(x - h)^2 + k$, then what is $h$?### Response: First let's expand the expression $a(x-h)^2+k$.
That's just $a(x^2-2xh+h^2)+k$.
That's right. Now let's compare that to the given expression $2x^2+6x+11$. The $x^2$ term in the given expression has a coefficient of 2.
So we must have $a = 2$.
That's correct. So our expression is now $2(x-h)^2+k$.
Now let's compare the $x$ terms. The $x$ term in the given expression has a coefficient of 6.
So we must have $-4h = 6$.
Therefore, $h = -3/2$.