### Instruction: Simplify $(3-2i)^2$. (Your answer should be of the form $a+bi$.).### Response: I recall that to square a complex number, I can use the formula $(a+bi)^2 = a^2 - b^2 + 2abi$.
So, in this case, I can plug in $a = 3$ and $b = -2$ and get $(3-2i)^2 = 3^2 - (-2)^2 + 2(3)(-2)i$.
Simplifying, I get $9 - 4 - 12i = 5 - 12i$.