### Instruction: In pentagon $MATHS$, $\angle M \cong \angle T \cong \angle H$ and $\angle A$ is supplementary to $\angle S$. How many degrees are in the measure of $\angle H$?### Response: I notice that this is a pentagon, so the sum of its interior angles must be $180(5-2) = 540$ degrees.
I also notice that three of the angles are congruent, so I can call their measure $x$.
Then I have $3x + \angle A + \angle S = 540$.
But $\angle A$ is supplementary to $\angle S$, which means they add up to $180$ degrees.
So I can simplify the equation to $3x + 180 = 540$.
Solving for $x$, I get $x = \frac{540 - 180}{3} = 120$.