### Instruction: Henry walked on a flat field 9 meters due north from a tree. He then turned due east and walked 24 feet. He then turned due south and walked 9 meters plus 32 feet. How many feet away from his original starting point is Henry?### Response: This problem involves converting between meters and feet, as well as using the Pythagorean theorem to find the distance of the hypotenuse of a right triangle.
I know that 1 meter is approximately 3.28 feet, so I can use that to convert the distances given in meters to feet.
Henry walked 9 meters due north, which is equivalent to 9 * 3.28 = 29.52 feet.
He then walked 24 feet due east, so his total eastward displacement is 24 feet.
He then walked 9 meters plus 32 feet due south, which is equivalent to 9 * 3.28 + 32 = 61.52 feet.
His total southward displacement is 61.52 - 29.52 = 32 feet.
Now I have a right triangle with legs of 24 feet and 32 feet, and I need to find the hypotenuse, which is the distance from his original starting point.
I can use the Pythagorean theorem, which says that the square of the hypotenuse is equal to the sum of the squares of the legs.
Let x be the hypotenuse, then x^2 = 24^2 + 32^2.
Simplifying, I get x^2 = 576 + 1024, which is x^2 = 1600.
Taking the positive square root of both sides, I get x = 40.
Therefore, Henry is 40 feet away from his original starting point.