### Instruction: Find $\frac{1}{-6} \cdot 6 \cdot 7 + 8 \cdot 2 \div 8 \cdot (7-1)$.### Response: This problem involves order of operations, so I need to follow the rules of PEMDAS: parentheses, exponents, multiplication/division, and addition/subtraction.
I will start by simplifying the expression inside the parentheses: $7-1 = 6$.
Next, I will look for any exponents, but there are none in this problem.
Then, I will perform the multiplication and division operations from left to right.
I can rewrite the expression as $\frac{1}{-6} \cdot 6 \cdot 7 + 8 \cdot \frac{2}{8} \cdot 6$.
The first multiplication, $\frac{1}{-6} \cdot 6$, gives me $-1$.
The second multiplication, $-1 \cdot 7$, gives me $-7$.
The third multiplication, $8 \cdot \frac{2}{8}$, gives me $2$.
The fourth multiplication, $2 \cdot 6$, gives me $12$.
Now I have $-7 + 12$, which is a simple addition problem.