### Instruction: In $\triangle PQR,$ the sum of $\angle P$ and $\angle Q$ is $60^\circ.$ What is the measure of $\angle R?$.### Response: I know that the sum of the angles in a triangle is $180^\circ.$
So, if $\angle P + \angle Q = 60^\circ,$ then $\angle R = 180^\circ - 60^\circ = 120^\circ.$