### Instruction: Evaluate $\lfloor\sqrt{80}\rfloor$.### Response: To evaluate $\lfloor\sqrt{80}\rfloor$, I need to find the largest integer that is less than or equal to $\sqrt{80}$.
I know that $\sqrt{81}=9$, so $\sqrt{80}$ must be slightly less than 9.
Therefore, the largest integer that is less than or equal to $\sqrt{80}$ is 8.
So $\lfloor\sqrt{80}\rfloor=8$.