Boundedly generated group

In mathematics, a group is called boundedly generated if it can be expressed as a finite product of cyclic subgroups. The property of bounded generation is also closely related with the congruence subgroup problem (see ).
Definitions.
A group "G" is called "boundedly generated" if there exists a finite subset "S" of "G" and a positive integer "m" such that every element "g" of "G" can be represented as a product of at most "m" powers of the elements of "S":
The finite set "S" generates "G", so a boundedly generated group is finitely generated.
An equivalent definition can be given in terms of cyclic subgroups. A group "G" is called "boundedly generated" if there is a finite family "C"1, …, "C""M" of not necessarily distinct cyclic subgroups such that "G" = "C"1…"C""M" as a set.
Properties.
A "pseudocharacter" on a discrete group "G" is defined to be a real-valued function "f" on a "G" such that 
Free groups are not boundedly generated.
Several authors have stated in the mathematical literature that it is obvious that finitely generated free groups are not boundedly generated. This section contains various obvious and less obvious ways of proving this. Some of the methods, which touch on bounded cohomology, are important because they are geometric rather than algebraic, so can be applied to a wider class of groups, for example Gromov-hyperbolic groups.
Since for any "n" ≥ 2, the free group on 2 generators "F"2 contains the free group on "n" generators "F""n" as a subgroup of finite index (in fact "n" – 1), once one non-cyclic free group on finitely many generators is known to be not boundedly generated, this will be true for all of them. Similarly, since "SL"2(Z) contains "F"2 as a subgroup of index 12, it is enough to consider "SL"2(Z). In other words, to show that no "F""n" with "n" ≥ 2 has bounded generation, it is sufficient to prove this for one of them or even just for "SL"2(Z) .
Burnside couterexamples.
Since bounded generation is preserved under taking homomorphic images, if a single finitely generated group with at least two generators is known to be not boundedly generated, this will be true for the free group on the same number of generators, and hence for all free groups. To show that no (non-cyclic) free group has bounded generation, it is therefore enough to produce one example of a finitely generated group which is not boundedly generated, and any finitely generated infinite torsion group will work. The existence of such groups constitutes Golod and Shafarevich's negative solution of the generalized Burnside problem in 1964; later, other explicit examples of infinite finitely generated torsion groups were constructed by Aleshin, Olshanskii, and Grigorchuk, using automata. Consequently, free groups of rank at least two are not boundedly generated.
Symmetric groups.
The symmetric group "S""n" can be generated by two elements, a 2-cycle and an "n"-cycle, so that it is a quotient group of "F"2. On the other hand, it is easy to show that the maximal order "M"("n") of an element in "S""n" satisfies
(Edmund Landau proved the more precise asymptotic estimate log "M"("n") ~ ("n" log "n")1/2). In fact if the cycles in a cycle decomposition of a permutation have length "N"1, ..., "N""k" with "N"1 + ··· + "N""k" = "n", then the order of the permutation divides the product "N"1 ···"N""k", which in turn is bounded by ("n"/"k")"k", using the inequality of arithmetic and geometric means. On the other hand, ("n"/"x")"x" is maximized when "x"="e". If "F"2 could be written as a product of "m" cyclic subgroups, then necessarily "n"! would have to be less than or equal to "M"("n")"m" for all "n", contradicting Stirling's asymptotic formula.
Hyperbolic geometry.
There is also a simple geometric proof that "G" = "SL"2(Z) is not boundedly generated. It acts by Möbius transformations on the upper half-plane H, with the Poincaré metric. Any compactly supported 1-form α on a fundamental domain of "G" extends uniquely to a "G"-invariant 1-form on H. If "z" is in H and γ is the geodesic from "z" to "g"("z"), the function defined by
satisfies the first condition for a pseudocharacter since by the Stokes theorem
where Δ is the geodesic triangle with vertices "z", "g"("z") and "h"−1("z"), and geodesics triangles have area bounded by π. The homogenized function
defines a pseudocharacter, depending only on α. As is well known from the theory of dynamical systems, any orbit ("g""k"("z")) of a hyperbolic element "g" has limit set consisting of two fixed points on the extended real axis; it follows that the geodesic segment from "z" to "g"("z") cuts through only finitely many translates of the fundamental domain. It is therefore easy to choose α so that "f"α equals one on a given hyperbolic element and vanishes on a finite set of other hyperbolic elements with distinct fixed points. Since "G" therefore has an infinite-dimensional space of pseudocharacters, it cannot be boundedly generated.
Dynamical properties of hyperbolic elements can similarly be used to prove that any non-elementary Gromov-hyperbolic group is not boundedly generated.
Brooks pseudocharacters.
Robert Brooks gave a combinatorial scheme to produce pseudocharacters of any free group "F""n"; this scheme was later shown to yield
an infinite-dimensional family of pseudocharacters (see ). Epstein and Fujiwara later extended these results to all non-elementary Gromov-hyperbolic groups.
Gromov boundary.
This simple folklore proof uses dynamical properties of the action of hyperbolic elements on the Gromov boundary of a Gromov-hyperbolic group. For the special case of the free group "F""n", the boundary (or space of ends) can be identified with the space "X" of semi-infinite reduced words
in the generators and their inverses. It gives a natural compactification of the tree, given by the Cayley graph with respect to the generators. A sequence of semi-infinite words converges to another such word provided that the initial segments agree after a certain stage, so that "X" is compact (and metrizable). The free group acts by left multiplication on the semi-infinite words. Moreover, any element "g" in "F""n" has exactly two fixed points "g"±∞, namely the reduced infinite words given by the limits of "g""n" as "n" tends to ±∞. Furthermore, "g""n"·"w" tends to "g"±∞ as "n" tends to ±∞ for any semi-infinite word "w"; and more generally if "w""n" tends to "w"≠ "g" ±∞, then "g""n"·"w""n" tends to "g"+∞ as "n" tends to ∞.
If "F""n" were boundedly generated, it could be written as a product of cyclic groups "C""i"
generated by elements "h""i". Let "X"0 be the countable subset given by the finitely many "F""n"-orbits
of the fixed points "h""i" ±∞, the fixed points of the "h""i" and all their conjugates. Since "X" is uncountable, there
is an element of "g" with fixed points outside "X"0 and a point "w" outside "X"0 different from these fixed points. Then for
some subsequence ("g"m) of ("g"n)
On the one hand, by successive use of the rules for computing limits of the form "h""n"·"w""n", the limit of the right hand side applied to "x" is necessarily a fixed point of one of the conjugates of the "h""i"'s. On the other hand, this limit also must be "g"+∞, which is not one of these points, a contradiction.