using binomial theorem, evaluate : `(96)^3`
using binomial theorem, evaluate : `(96)^3`




solution: `(96)^3=(100-4)^3`  

`(x+a)^n=sum\_(r=0)^(n).^nc\_ra^rr^(n-r)`  

`(100-4)^3= .^3c\_0(100)^3+.^3c\_1(100)^2(-4)^(1).+^3c\_2(100)^1(-4)^(2)+.^3c\_3(100)^0(-4)^(3)`  

=>`1000000-120000+4800-64`  

=>`884736`.


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