if 2nc
if 2nc
given:⇒ we know that and also n! = n(n – 1)(n – 2)…………2.1⇒ ⇒ ⇒ 2 × (2n – 1) × 2 = 44⇒ 2n – 1 = 11⇒ 2n = 12⇒ ⇒ n = 6∴ the value of n is 6.
given:⇒ we know that and also n! = n(n – 1)(n – 2)…………2.1⇒ ⇒ ⇒ 2 × (2n – 1) × 2 = 44⇒ 2n – 1 = 11⇒ 2n = 12⇒ ⇒ n = 6∴ the value of n is 6.