You have a garland consisting of n lamps. Each lamp is colored red, green or blue. The color of the i-th lamp is s_i ('R', 'G' and 'B' — colors of lamps in the garland).

You have to recolor some lamps in this garland (recoloring a lamp means changing its initial color to another) in such a way that the obtained garland is nice.

A garland is called nice if any two lamps of the same color have distance divisible by three between them. I.e. if the obtained garland is t, then for each i, j such that t_i = t_j should be satisfied |i-j|~ mod~ 3 = 0. The value |x| means absolute value of x, the operation x~ mod~ y means remainder of x when divided by y.

For example, the following garlands are nice: "RGBRGBRG", "GB", "R", "GRBGRBG", "BRGBRGB". The following garlands are not nice: "RR", "RGBG".

Among all ways to recolor the initial garland to make it nice you have to choose one with the minimum number of recolored lamps. If there are multiple optimal solutions, print any of them.

Input

The first line of the input contains one integer n (1 ≤ n ≤ 2 ⋅ 10^5) — the number of lamps.

The second line of the input contains the string s consisting of n characters 'R', 'G' and 'B' — colors of lamps in the garland.

Output

In the first line of the output print one integer r — the minimum number of recolors needed to obtain a nice garland from the given one.

In the second line of the output print one string t of length n — a nice garland obtained from the initial one with minimum number of recolors. If there are multiple optimal solutions, print any of them.

Examples

Input


3
BRB


Output


1
GRB


Input


7
RGBGRBB


Output


3
RGBRGBR



import java.io.*;
import java.util.*;
import java.math.BigInteger; 
import java.lang.*;




public class Main {
    
    
    static class sort1 implements Comparator<List<Integer>>
   {
        public int compare(List<Integer>  a,List<Integer> b)
        {
            
            return (a.size() - b.size());
        }
   }
    
   static class sort implements Comparator<int[]>
   {
        public int compare(int[] a,int[] b)
        {
            
            return b[1]-a[1];
        }
   }
    static class sortP implements Comparator<int[]>
   {
        public int compare(int[] a,int[] b)
        {
            
            return -b[0]+a[0];
        }
   }
   static class sort2p implements Comparator<long[]>
   {
        public int compare(long[] a,long[] b)
        {
            
          return (int)(a[0]-b[0]);
        }
   }
  
   static class sort11 implements Comparator<double[]>
   {
        public int compare(double[] a,double[] b)
        {
            //if(a[0] == b[0]) return a[1]-b[1];
           if(a[1] < b[1]) return -1;
           else if(a[1] > b[1]) return 1;
           return 0;
        }
   }
   public static String[] F(BufferedReader bf) throws Exception
    {
        return (bf.readLine().split(" "));
    }
    
   public static void pr(PrintWriter out,Object o)
   {
      
    out.println(o.toString());//out.flush();
    
   }
   public static void prW(PrintWriter out,Object o)
   {
      
    out.print(o.toString());//out.flush();
    
   }
   public static int intIn(String st)
   {
      return Integer.parseInt(st);
   }
   
   
    
    public static void pr(Object o)
    {
        System.out.println(o.toString());
    }
    public static void prW(Object o)
    {
        System.out.print(o.toString());
    }
    
   
    public static int inInt(String s)
    {
        return Integer.parseInt(s);
    }
    public static long in(String s)
    {
        return Long.parseLong(s);
    }
 
 
    static int[] toIntArray(String[] m) 
    { 
        int[] p=new int[m.length];
        for(int o=0;o<m.length;o++)
        {
            p[o]= inInt(m[o]);
        }
        return p;
    }
    static double[] toDArray(String[] m) 
    { 
        double[] p=new double[m.length];
        for(int o=0;o<m.length;o=0)
        {
            p[o]= Double.parseDouble(m[o]);
        }
        return p;
    }
    static long[] toLArray(String[] m) 
    { 
       long[] p=new long[m.length];
        for(int o=0;o<m.length;o++)
        {
            p[o]= in(m[o]);
        }
        return p;
    }
   
     static long gcd(long a, long b)
        {
          if (b == 0)
            return a;
          return gcd(b, a % b); 
        }
     
        static long pow(long x, long y, long p)
      {
        if(y == 0) return 1l;
        long res = 1; // Initialize result
     
        x = x % p; // Update x if it is more than or
        // equal to p
     
        if (x == 0)
          return 0l; // In case x is divisible by p;
     
        while (y > 0)
        {
     
          // If y is odd, multiply x with result
          if ((y & 1) != 0)
            res = (res * x) % p;
     
          // y must be even now
          y = y >> 1; // y = y/2
          x = (x * x) % p;
        }
        return res;
      }
    
   
    

   
   

   
    static long __gcd(long n1, long n2)
    {

        if(n1==0l) return n2;
        if(n2==0l) return n1;
        if(n1==1l || n2==1l) return 1l;
       // long gcd = 1;
        if(n1 == n2)  return n1;
        if(n1>n2) return __gcd(n1%n2,n2);
        return __gcd(n1,n2%n1);
        
    }
    
   
    
    

    public static int F(char c1,char c2,char c3,char[] arr){
      int n=arr.length;
      int c=0;
      for(int i=0;i<n;i+=3){
        if(arr[i] != c1) c++;
      }
      for(int i=1;i<n;i+=3){
        if(arr[i] != c2) c++;
      }
      for(int i=2;i<n;i+=3){
        if(arr[i] != c3) c++;
      }

      return c;
    }
    public static void main (String[] args) throws Exception {
        
        BufferedReader bf=new BufferedReader(new InputStreamReader(System.in));
        PrintWriter out = new PrintWriter(System.out);;;//
        
        //int[] map=new int[1000001];
      
       int yy=1;//inInt(bf.readLine());
       


        
        
        
        for(int w=0;w<yy;w++)
        {
             //String str = bf.readLine();
          //char[] arr = bf.readLine().toCharArray();
          out.flush();
         
            String[] xlp = bf.readLine().split(" ");
            
            //String st = bf.readLine();
         int  n;//boolean bol=false;
         int  m;//long a,b,c;
         //long k;
          // int l;
           //int double avg  k;//pr(out,"vbc");
       // boolean bol = false;
           //long mod=1000000000+7
       n=inInt(xlp[0]);//m=inInt(xlp[1]);int j=inInt(xlp[2]);int k=inInt(xlp[3]);  
      char[] arr = bf.readLine().toCharArray();
      int r1,r2,r3,r4,r5,r6,r7;
      r1 = F('R','G','B',arr);
      r2 = F('G','R','B',arr);
      r3 = F('G','B','R',arr);
      r4 = F('R','B','G',arr);
      r5 = F('B','R','G',arr);
      r7 = F('B','G','R',arr);
      int res = Math.min(r1,r2);
      res = Math.min(res,r3);
       res = Math.min(res,r4);
        res = Math.min(res,r5);
         res = Math.min(res,r7);
        pr(out,res);

        if(res == r1){
          char c1,c2,c3;
          c1 = 'R';c2='G';c3='B';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }



        }
        else if(res == r2){
              char c1,c2,c3;
          c1 = 'G';c2='R';c3='B';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }

        }
        else if(res == r3){
          char c1,c2,c3;
          c1 = 'G';c2='B';c3='R';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }
          
        }
        else if(res == r4){
              char c1,c2,c3;
          c1 = 'R';c2='B';c3='G';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }
          
        }
        else if(res == r5){

              char c1,c2,c3;
          c1 = 'B';c2='R';c3='G';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }
          
        }
        else if(res == r7){
          char c1,c2,c3;
          c1 = 'B';c2='G';c3='R';
            for(int i=0;i<n;i+=3){
              arr[i]=c1;
            }
            for(int i=1;i<n;i+=3){
              arr[i]=c2;
            }
            for(int i=2;i<n;i+=3){
              arr[i]=c3;
            }
          
        }

        for(char ch : arr) prW(out,ch+"");






       

       
    


      

       
           


       



      




       

       



   }
    out.close();
   bf.close();//
       
}}


/*


Kickstart
 String rp;
            rp = "Case #"+(w+1)+": "+(n-ans)+" ";
static int[][] dir={{0,1},{1,0},{-1,0},{0,-1}};

static class SegmentTreeRMQ 
    { 
    int st[]; 
    int minVal(int x, int y) { 
        return (x > y) ? x : y; 
    } 
  
    
    int getMid(int s, int e) { 
        return s + (e - s) / 2; 
    } 
  
    
    int RMQUtil(int ss, int se, int qs, int qe, int index) 
    { 
        
        if (qs <= ss && qe >= se) 
            return st[index]; 
  
        // If segment of this node is outside the given range 
        if (se < qs || ss > qe) 
            return Integer.MIN_VALUE; 
  
        // If a part of this segment overlaps with the given range 
        int mid = getMid(ss, se); 
        return minVal(RMQUtil(ss, mid, qs, qe, 2 * index + 1), 
                RMQUtil(mid + 1, se, qs, qe, 2 * index + 2)); 
    } 
  
    // Return minimum of elements in range from index qs (query 
    // start) to qe (query end).  It mainly uses RMQUtil() 
    int RMQ(int n, int qs, int qe) 
    { 
        // Check for erroneous input values 
        
  
        return RMQUtil(0, n - 1, qs, qe, 0); 
    } 
  
    // A recursive function that constructs Segment Tree for 
    // array[ss..se]. si is index of current node in segment tree st 
    int constructSTUtil(int arr[], int ss, int se, int si) 
    { 
        // If there is one element in array, store it in current 
        //  node of segment tree and return 
        if (ss == se) { 
            st[si] = arr[ss]; 
            return arr[ss]; 
        } 
  
        // If there are more than one elements, then recur for left and 
        // right subtrees and store the minimum of two values in this node 
        int mid = getMid(ss, se); 
        st[si] = minVal(constructSTUtil(arr, ss, mid, si * 2 + 1), 
                constructSTUtil(arr, mid + 1, se, si * 2 + 2)); 
        return st[si]; 
    } 
  
    
    void con(int arr[]) 
    { 
        // Allocate memory for segment tree 
  
        //Height of segment tree 
        int n = (arr.length);
        int x = (int) (Math.ceil(Math.log(n) / Math.log(2))); 
  
        //Maximum size of segment tree 
        int max_size = 2 * (int) Math.pow(2, x) - 1; 
        st = new int[max_size]; // allocate memory 
  
        // Fill the allocated memory st 
        constructSTUtil(arr, 0, n - 1, 0); 
    }
    }
     static class DSU {
    
    int[] p;int[] sz;int op;int c;;
    int[] last;
    public void G(int n)
    {
        last=new int[n];
        p=new int[n];
        sz=new int[n];c=n;
        op=n;
        for(int h=0;h<n;h++)
        {
            sz[h]=1;p[h]=h;
            last[h]=h;
        }
    }
    public int find(int x)
    {
        int y=x;
        while(x!=p[x]) x=p[x];
        while(y!=p[y])
        {
            int tem=p[y];
            p[y]=x;y=tem;
        }
        return p[y];
    }
    public void union(int a,int b)
    {
        int x,y;
        x=find(a);y=find(b);
        if(x==y) return;
        if(sz[x]>sz[y])
        {
            p[y] = x;
            sz[x]+=sz[y];
            last[x]=Math.max(last[x],last[y]);
        }
        else
        {
            p[x]=y;sz[y]+=sz[x];
            last[y]=Math.max(last[y],last[x]);
        }
        c--;
        
    }}

    static long pow(long x, long y, long p)
      {
        long res = 1; // Initialize result
     
        x = x % p; // Update x if it is more than or
        // equal to p
     
        if (x == 0)
          return 0l; // In case x is divisible by p;
     
        while (y > 0)
        {
     
          // If y is odd, multiply x with result
          if ((y & 1) != 0)
            res = (res * x) % p;
     
          // y must be even now
          y = y >> 1; // y = y/2
          x = (x * x) % p;
        }
        return res;
      }
      static long gcd(long a, long b)
        {
          if (b == 0)
            return a;
          return gcd(b, a % b); 
        }
        static int gcd(int a, int b,int o)
        {
          if (b == 0)
            return a;
          return gcd(b, a % b,o); 
        }

Geometric median

public static double F(double[] x,double[] w)
    {
        double d1,d2;
        double S=0.00;
        for(double dp : w) S += dp;
        int k = 0;
        double sum = S - w[0]; // sum is the total weight of all `x[i] > x[k]`

        while(sum > S/2)
        {
            ++k;
            sum -= w[k];
        }
        d1=x[k];
        return d1;
        k = w.length-1;
       sum = S - w[k]; // sum is the total weight of all `x[i] > x[k]`

        while(sum > S/2)
        {
            --k;
            sum -= w[k];
        }
        d2=x[k];
        return new double[]{d1,d2};
    }
*/