Rahul has set upon the quest for a new logo of his company. He has created the following continuous logo:

    /\
   /  \
  / /\ \
 / /  \ \
/ / /\ \ \
  \ \ \/ / /
   \ \  / /
    \ \/ /
     \  /
      \/

However, his sister, Rashi, likes the following discontinuous design more

   /\
  /  \
 / /\ \
/ /  \ \
  \ \  / /
   \ \/ /
    \  /
     \/

The size of a logo is the longest continuous streak of same characters on an arm.

So, size of 1st logo is 5 while that of 2nd one is 4.

Now, he wants to paint both of these logos on a canvas. 

Given an integer N, write a program that outputs these logos for sizes N and N + 1, one below the other.

Please note that Rahul's logo is only valid for odd sizes and Rashi's logo is only valid for even values.

Input Format:

Each file has just one line containing integer N.

Output Format:

Output the two logos, one below the other.

Constraints:

N ≤ 100

Notes:

An exact checker is used, so please make sure that you strictly adhere to the output format and leave no trailing spaces.

SAMPLE INPUT
3

SAMPLE OUTPUT
  /\
 /  \
/ /\ \
  \ \/ /
   \  /
    \/
   /\
  /  \
 / /\ \
/ /  \ \
  \ \  / /
   \ \/ /
    \  /
     \/
##  \ \ \/ / /
##   \ \  / /
##    \ \/ /
##     \  /
##      \/
###n odd
#n=7
n=int(input())
def fore(n):
    for i in range(n):
        if i % 2 == 0:
            strx = ((n-1-i)*" " + "/ "*(i//2) + "/\\" + (i//2) * " \\")
            print(strx)
        else:
            print(" " * (n-1-i) + (i//2+1)*'/ ' + (i//2+1) * ' \\')
def bg(n):
    for i in range(n-1, -1, -1):
        if i % 2 == 0:
            strx = ((n-1-i+1+1)*" " + "\\ "*(i//2) + "\\/" + (i//2) * " /")
            print(strx)
        else:
            print(" " * (n-1+1-i+1) + (i//2+1)*'\\ ' + (i//2+1) * ' /')
fore(n)
bg(n)
fore(n+1)
bg(n+1)