A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly n pixels. 

Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels a and the number of columns of pixels b, so that:

  * there are exactly n pixels on the display; 
  * the number of rows does not exceed the number of columns, it means a ≤ b; 
  * the difference b - a is as small as possible. 

Input

The first line contains the positive integer n (1 ≤ n ≤ 106) — the number of pixels display should have.

Output

Print two integers — the number of rows and columns on the display. 

Examples

Input

8


Output

2 4


Input

64


Output

8 8


Input

5


Output

1 5


Input

999999


Output

999 1001

Note

In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.

In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.

In the third example the minimum possible difference equals 4, so on the display should be 1 row of 5 pixels.
/*
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 */

import java.util.Scanner;

/**
 *
 * @author asus
 */
public class sizemonitor {

    public static void main(String args[]) {
        Scanner in = new Scanner(System.in);
        int size = in.nextInt();
        int width = Integer.MAX_VALUE;
        int height = Integer.MAX_VALUE;
        int raznica = Integer.MAX_VALUE;
        for (int i = 1; i <= size; i++) {
            if (size == i * (size / i)) {
                int temp = raznica;
                raznica = Math.min(raznica, Math.abs(i - (size / i)));
                if (temp != raznica) {
                    height = Math.min(i, (size / i));
                    width = Math.max(i, (size / i));

                }
            }
        }
        System.out.println(height + " " + width);

    }
}
