There are N people numbered 1 to N. Each person wears a red hat or a blue hat.

You are given a string s representing the colors of the people. Person i wears a red hat if s_i is `R`, and a blue hat if s_i is `B`.

Determine if there are more people wearing a red hat than people wearing a blue hat.

Constraints

* 1 \leq N \leq 100
* |s| = N
* s_i is `R` or `B`.

Input

Input is given from Standard Input in the following format:


N
s


Output

If there are more people wearing a red hat than there are people wearing a blue hat, print `Yes`; otherwise, print `No`.

Examples

Input

4
RRBR


Output

Yes


Input

4
BRBR


Output

No
import java.util.Scanner;

public class Main {
	public static void main(String[] args){
		Scanner sc = new Scanner(System.in);
		
		int N = sc.nextInt();
		String s = sc.next();
		
		Main redOrBlue = new Main();
		System.out.println(redOrBlue.judgeRedOrBlue(N, s));
	}
	
	private String judgeRedOrBlue(int n, String s) {
		if(n < 1 || n > 100 || s == null || s.length() != n) return "No";
		
		char r = 'R', b = 'B';
		int countR = 0, countB = 0;
		for(char c : s.toCharArray()){
			if(c == r) countR++;
			if(c == b) countB++;
		}
		
		if(countR > countB) return "Yes";
		else return "No";
	}
}
