You're given an array a of length 2n. Is it possible to reorder it in such way so that the sum of the first n elements isn't equal to the sum of the last n elements?

Input

The first line contains an integer n (1 ≤ n ≤ 1000), where 2n is the number of elements in the array a.

The second line contains 2n space-separated integers a_1, a_2, …, a_{2n} (1 ≤ a_i ≤ 10^6) — the elements of the array a.

Output

If there's no solution, print "-1" (without quotes). Otherwise, print a single line containing 2n space-separated integers. They must form a reordering of a. You are allowed to not change the order.

Examples

Input


3
1 2 2 1 3 1


Output


2 1 3 1 1 2

Input


1
1 1


Output


-1

Note

In the first example, the first n elements have sum 2+1+3=6 while the last n elements have sum 1+1+2=4. The sums aren't equal.

In the second example, there's no solution.
import java.util.*;
public class A{
    public static void main(String args[])
    {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();
        int a[]=new int[n*2];
        boolean flag=false;
        int cnt=1;
        for(int i=0;i<n*2;i++)
        {
            a[i]=sc.nextInt();
            if(i!=0 && a[0]==a[i])
            {
                cnt++;
            }
        }
        if(cnt==2*n)
        {
            System.out.println("-1");
        }
        else
        {
            Arrays.sort(a);
            for(int i:a)
            {
                System.out.print(i+" ");
            }
        }
    }
    
}