You have a sequence A composed of N positive integers: A_{1}, A_{2}, \cdots, A_{N}.

You will now successively do the following Q operations:

* In the i-th operation, you replace every element whose value is B_{i} with C_{i}.



For each i (1 \leq i \leq Q), find S_{i}: the sum of all elements in A just after the i-th operation.

Constraints

* All values in input are integers.
* 1 \leq N, Q, A_{i}, B_{i}, C_{i} \leq 10^{5}
* B_{i} \neq C_{i}

Input

Input is given from Standard Input in the following format:


N
A_{1} A_{2} \cdots A_{N}
Q
B_{1} C_{1}
B_{2} C_{2}
\vdots
B_{Q} C_{Q}


Output

Print Q integers S_{i} to Standard Output in the following format:


S_{1}
S_{2}
\vdots
S_{Q}


Note that S_{i} may not fit into a 32-bit integer.

Examples

Input

4
1 2 3 4
3
1 2
3 4
2 4


Output

11
12
16


Input

4
1 1 1 1
3
1 2
2 1
3 5


Output

8
4
4


Input

2
1 2
3
1 100
2 100
100 1000


Output

102
200
2000
import java.util.*;
import java.io.*;
 
public class Main{
    
	public static void main(String[] $){
		Scanner s = new Scanner(System.in);
		int N = s.nextInt();
		long sum = 0;
		long[] S = new long[100000+1];
		for(int i = 0; i < N; i++){
			int A = s.nextInt();
			sum += A;
			S[A]++;
		}

		int Q = s.nextInt();
		StringBuilder sb = new StringBuilder();
		for(int i = 0; i < Q; i++){
			int B = s.nextInt();
			int C = s.nextInt();
			int result = C - B;
			sum = sum + S[B]*result;
			S[C] = S[C] + S[B];
			S[B] = 0;
			sb.append(sum + "\n");
		}
		System.out.print(sb.toString());
		
		
			
	}
} 