Today, you have been given the task of handling the entire Taxi Network of Berland City. Berland city has a huge number of taxi travellers, and you need to help them in transportation in the most efficient manner. 

To be precise, this city consists of N users who want to travel via a Taxi today. You have a total of M taxis and need to cater to the users using these taxis. Each user has two parameters associated with them, S_{i} and J_{i}, denoting the time at which a user requests a taxi and the travel time required to reach the destination of this particular user. Each taxi can be used by a maximum of 1 user at each point in time.

If, at any point in time a user requests a taxi and all M taxis are busy, then this user's request is rejected. If multiple taxis are available at the time of the request of a user, the taxi with the lowest index that is available is alloted to them. Now, you need to find for each user, the index of the taxi alloted to them. If a particular user's request is rejected, print "-1" (without quotes) for them. 

Note: For the purpose of the problem, we consider a user gets their taxi immediately if their request is accepted. The taxi's are enumerated from 1 to M. A taxi is considered to be free as soon as the previous user's journey ends. It is guaranteed that the request time of each user is unique.

Input Format:

The first line contains two integers N  and M denoting the number of users and the number of taxis respectively. Each of the next N lines contains 2 space separated integers S_{i} and  J_{i} denoting the request and journey time of the i^{th} user.   

Output Format:

For each user from 1 to N, print the index number of the taxi alloted to them. If a user's request is rejected , print "-1"(without quotes)  for them. 

Constraints:

 1 ≤ N ≤ 10^5 

 1 ≤ M ≤ 100 

 1 ≤ S_{i} ,J_{i} ≤ 10^9   

SAMPLE INPUT
5 5
1 100
2 100
3 100
4 100
5 100

SAMPLE OUTPUT
1 2 3 4 5

Explanation

Here, user 1 is given taxi 1, user 2 is given taxi 2, user 3 is given taxi 3 and so on for user 4and 5.
try:
	M, N = map(int, raw_input().split())
	taxis = [0 for i in range(N)]
	users = []
	for i in range(M):
		S, J  = map(int, raw_input().split())
		users.append([S,J, i])
		
	users = sorted(users, key = lambda user: user[0])
	
	ans = [0]*M
	for user in users:
		flag = False
		for i in range(N):
			if taxis[i] <= user[0]:
				ans[user[2]] = i+1
				flag = True
				taxis[i] = user[0]+user[1]
				break
		if not flag:
				ans[user[2]] = -1
	
	print ' '.join(map(str, ans))
except Exception as e:
	print e