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The dataset generation failed because of a cast error
Error code: DatasetGenerationCastError
Exception: DatasetGenerationCastError
Message: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Claim: "Only people named Floyd wearing pink are allowed to attend Pink Floyd concerts."\\nIs the claim above correct, and can it be verified by human common sense and without a web search?\\nOptions:\\n- yes\\n- no', 'no', 'The rock group would not be as popular is they had such requirements for their concerts.'}) and 3 missing columns ({'Rs. 5600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/7:1/7:1/14?\\nOptions:\\n(A) 300\\n(B) 992\\n(C) 1120\\n(D) 552\\n(E) 312', '1/7:1/7:1/14 = 2:2:1\\n1/5*5600 = 1120\\n2240-1120 = 1120', '(C)'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ewof/flan_unfiltered/tsvs/creak_train.tsv (at revision 72cf6b30a015047b0e17291367fda34f4c93ccdc)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)
Traceback: Traceback (most recent call last):
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 2011, in _prepare_split_single
writer.write_table(table)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/arrow_writer.py", line 585, in write_table
pa_table = table_cast(pa_table, self._schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2302, in table_cast
return cast_table_to_schema(table, schema)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/table.py", line 2256, in cast_table_to_schema
raise CastError(
datasets.table.CastError: Couldn't cast
Claim: "Only people named Floyd wearing pink are allowed to attend Pink Floyd concerts."\nIs the claim above correct, and can it be verified by human common sense and without a web search?\nOptions:\n- yes\n- no: string
no: string
The rock group would not be as popular is they had such requirements for their concerts.: string
-- schema metadata --
pandas: '{"index_columns": [{"kind": "range", "name": null, "start": 0, "' + 1176
to
{'Rs. 5600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/7:1/7:1/14?\\nOptions:\\n(A) 300\\n(B) 992\\n(C) 1120\\n(D) 552\\n(E) 312': Value(dtype='string', id=None), '(C)': Value(dtype='string', id=None), '1/7:1/7:1/14 = 2:2:1\\n1/5*5600 = 1120\\n2240-1120 = 1120': Value(dtype='string', id=None)}
because column names don't match
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1321, in compute_config_parquet_and_info_response
parquet_operations = convert_to_parquet(builder)
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 935, in convert_to_parquet
builder.download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1027, in download_and_prepare
self._download_and_prepare(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1122, in _download_and_prepare
self._prepare_split(split_generator, **prepare_split_kwargs)
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 1882, in _prepare_split
for job_id, done, content in self._prepare_split_single(
File "/src/services/worker/.venv/lib/python3.9/site-packages/datasets/builder.py", line 2013, in _prepare_split_single
raise DatasetGenerationCastError.from_cast_error(
datasets.exceptions.DatasetGenerationCastError: An error occurred while generating the dataset
All the data files must have the same columns, but at some point there are 3 new columns ({'Claim: "Only people named Floyd wearing pink are allowed to attend Pink Floyd concerts."\\nIs the claim above correct, and can it be verified by human common sense and without a web search?\\nOptions:\\n- yes\\n- no', 'no', 'The rock group would not be as popular is they had such requirements for their concerts.'}) and 3 missing columns ({'Rs. 5600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/7:1/7:1/14?\\nOptions:\\n(A) 300\\n(B) 992\\n(C) 1120\\n(D) 552\\n(E) 312', '1/7:1/7:1/14 = 2:2:1\\n1/5*5600 = 1120\\n2240-1120 = 1120', '(C)'}).
This happened while the csv dataset builder was generating data using
hf://datasets/ewof/flan_unfiltered/tsvs/creak_train.tsv (at revision 72cf6b30a015047b0e17291367fda34f4c93ccdc)
Please either edit the data files to have matching columns, or separate them into different configurations (see docs at https://hf.co/docs/hub/datasets-manual-configuration#multiple-configurations)Need help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
Rs. 5600 is divided into three parts A, B and C. How much A is more than C if their ratio is 1/7:1/7:1/14?\nOptions:\n(A) 300\n(B) 992\n(C) 1120\n(D) 552\n(E) 312
string | (C)
string | 1/7:1/7:1/14 = 2:2:1\n1/5*5600 = 1120\n2240-1120 = 1120
string |
|---|---|---|
The edge of a cube is 7a cm. Find its surface?\nOptions:\n(A) 24a8\n(B) 24a4\n(C) 24a1\n(D) 24a2\n(E) 294a2 | (E) | 6a2 = 6 * 7a * 7a = 294a2 |
A board 7ft. 9 inches long is divided into 3 equal parts . What is the length of each part?\nOptions:\n(A) 31 inches\n(B) 32 inches\n(C) 33 inches\n(D) 34 inches\n(E) 35 inches | (A) | 7 ft 9 in is 84 + 9 = 93 inches. so 93/3 = 31 inches or 2 ft. 7 inch. |
If rupee one produces rupees nine over a period of 40 years, find the rate of simple interest?\nOptions:\n(A) 22 1/8 %\n(B) 22 3/2 %\n(C) 28 1/2 %\n(D) 22 1/2 %\n(E) 32 1/2 % | (D) | 9 = (1*40*R)/100\nR = 22 1/2 % |
There are different 15 circles. What is the number of the greatest possible points with which the circles intersect?\nOptions:\n(A) 390\n(B) 100\n(C) 110\n(D) 180\n(E) 210 | (E) | Maximum points of intersection between n different circles = n*(n - 1) = 15*14 = 210 |
If x is the product of the integers from 1 to 150, inclusive, and 5^y is a factor of x, what is the greatest possible value of y ?\nOptions:\n(A) 30\n(B) 34\n(C) 36\n(D) 37\n(E) 39 | (D) | It basically asks for the number of 5s in 150!\n150/5 + 150/25 + 150/125 = 30 + 6 + 1. Hence 37 |
Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?\nOptions:\n(A) 5/14\n(B) 1/2\n(C) 17/28\n(D) 9/14\n(E) 9/11 | (D) | Total revenues = x\nSpent on marketing = x/4\nRemaining amount = x-x/4 = 3x/4\n1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28\nAmount left = 3x/4-3x/28 = 9x/14 |
A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?\nOptions:\n(A) 40 sec\n(B) 42 sec\n(C) 45 sec\n(D) 48 sec\n(E) 58 sec | (A) | Speed = 45 * 5/18 = 25/2 m/sec\nTotal distance covered = 360 + 140 = 500 m\nRequired time = 500 * 2/25 = 40 sec |
The average height in a group of 4 people is 175 cm. If the average height increased when 2 more people were added to the group, which of the following cannot be the heights of the two new people?\nOptions:\n(A) 179 cm and 172 cm\n(B) 181 cm and 169 cm\n(C) 173 cm and 178 cm\n(D) 176 cm and 176 cm\n(E) 174 cm and 177 cm | (B) | Denote X as the sum of the heights of the two new people. From the stem it follows that (700+X)6>175. This reduces to X>350. Only the heights from B add up to 350 cm. All other pairs add up to more than 350 cm. |
A shopkeeper gave an additional 20 per cent concession on the reduced price after giving 30 per cent standard concession on an article. If Arun bought that article for 1,120, what was the original price?\nOptions:\n(A) 3,000\n(B) 4,000\n(C) 2,400\n(D) 2,000\n(E) None of these | (D) | Original price = 1120 × 100⁄70 × 100⁄80 = 2000 |
If a man can cover 18 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?\nOptions:\n(A) 288\n(B) 162\n(C) 878\n(D) 168\n(E) 243 | (E) | 18 m/s = 12 * 18/5 kmph\n3 hours 45 minutes = 3 3/4 hours = 15/4 hours\nDistance = speed * time = 18 * 18/5 * 15/4 km = 243 km. |
There are two water tanks A and B, A is much smaller than B. While water fills at the rate of one liter every hour in A, it gets filled up like 10, 20, 40, 80, 160 in tank B. (At the end of first hour, B has 10 liters, second hour it has 20, third hour it has 40 and so on). If tank B is 1/32 filled after 21 hours, what is the total duration required to fill it completely?\nOptions:\n(A) 22\n(B) 28\n(C) 269\n(D) 26\n(E) 82 | (D) | The data related to the first tank A is not necessary. As you can see, the capacity that gets filled in the tank B after each hour is doubled. So If the tank is 1/32nd part is full after 21 hours, it is 1/16th part full after 22 hours, 1/8th part full after 23 hours, 1/4th part full after 24 hours, 1/2 full after 25 hours, completely full after 26 hours. |
The inverse ratio of 4: 2: 1 is?\nOptions:\n(A) 2:4:8\n(B) 2:3:9\n(C) 2:3:2\n(D) 2:3:6\n(E) 2:3:1 | (A) | 1/4: 1/2: 1/1 = 2:4:8 |
Consider a quarter of a circle of radius 20. Let r be the radius of the circle inscribed in this quarter of a circle. Find r.\nOptions:\n(A) 20*(sqr2 -1) \n(B) 8*(sqr3 -1) \n(C) 4*(sqr7 - 1) \n(D) 12* (sqr7 -1) \n(E) None of these | (A) | I got 20/(sqr2 +1) and just forgot to multiply by (sqr2 -1). |
What distance will be covered by a city bus moving at 72 kmph in 30 seconds?\nOptions:\n(A) 200 m\n(B) 300 m\n(C) 600 m\n(D) 500 m\n(E) 400 m | (C) | 72 kmph = 72 * 5/18 = 20 mps\nDist = Speed * time = 20 * 30 = 600 m. |
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 60 as remainder. Find the no. is?\nOptions:\n(A) 145646\n(B) 236578\n(C) 645353\n(D) 456546\n(E) 220060 | (E) | (555 + 445) * 2 * 110 + 60 = 220000 + 60 = 220060 |
What percent is 240 of 90?\nOptions:\n(A) 133 1/3 %\n(B) 134 1/3 %\n(C) 135 1/3 %\n(D) 266 2/3 %\n(E) 143 1/3 % | (D) | 240/90 = 8/3\n8/3 × 100 = 800/3 = 266 2/3 % |
The average of seven numbers is 18. The average of first three numbers is 14 and the average of last three numbers is 23. What is the middle number?\nOptions:\n(A) 25\n(B) 27\n(C) 15\n(D) 32\n(E) 34 | (C) | The total of seven numbers = 7X18 = 126\nThe total of first 3 and last 3 numbers is = 3 X 14+3 X 23 = 111\nSo, the middle number is (126 - 111 ) = 15 |
A train 300 m long is running at a speed of 99 km/hr. In what time will it pass a bridge 195 m long?\nOptions:\n(A) 17\n(B) 18\n(C) 19\n(D) 20\n(E) 21 | (B) | Speed = 99 * 5/18 = 55/2 m/sec\nTotal distance covered = 300 + 195 = 495 m\nRequired time = 495 * 2/55 = 18 sec |
The average of 13 result is 60. Average of the first 7 of them is 57 and that of the last 7 is 61. Find the 8th result?\nOptions:\n(A) 35\n(B) 37\n(C) 46\n(D) 48\n(E) 50 | (C) | Sum of all the 13 results = 13 * 60 = 780\nSum of the first 7 of them = 7 * 57 = 399\nSum of the last 7 of them = 7 * 61 = 427\nSo, the 8th number = 427 + 399 - 780 = 46. |
How much 60% of 50 is greater than 40% of 30?\nOptions:\n(A) 18\n(B) 99\n(C) 77\n(D) 66\n(E) 12 | (A) | (60/100) * 50 – (40/100) * 30\n30 - 12 = 18ch 60% of 50 is greater than 40% of 30? |
The speed of a train is 90 kmph. What is the distance covered by it in 10 minutes?\nOptions:\n(A) 15\n(B) 66\n(C) 77\n(D) 52\n(E) 42 | (A) | 90 * 10/60 = 15 kmph |
How many cubes will have 4 coloured sides and two non-coloured sides ?\nOptions:\n(A) 5\n(B) 4\n(C) 3\n(D) 2\n(E) 1 | (B) | Only 4 cubes situated at the corners of the cuboid will have 4 coloured and 2 non-coloured sides. |
John has 10pairs of dark blue socks and 10pairs of black socks. He keeps them all in the same bag. If he picks out 3socks at random, then what is the probability thathe will get a matching pair?\nOptions:\n(A) 1\n(B) 3\n(C) 5\n(D) 6\n(E) 9 | (A) | If he draws any combination of 3 socks he will definitely have the matching pair of either colour. |
Efrida and Frazer who live 12 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?\nOptions:\n(A) 6\n(B) 7\n(C) 8\n(D) 10\n(E) 11 | (D) | It's a simple geometry problem. Look at the diagram below: |
The length of a rectangle is increased by 20% and its breadth is decreased by 20%. What is the effect on its area?\nOptions:\n(A) 1288\n(B) 9600\n(C) 1000\n(D) 10000\n(E) 2887 | (B) | 100 * 100 = 10000\n120 * 80 = 9600 |
Which is odd one\n10, 25, 45, 54, 60, 75, 80\nOptions:\n(A) 10\n(B) 45\n(C) 54\n(D) 60\n(E) 75 | (C) | All numbers except 54 is multiple of 5. |
What is the are of an equilateral triangle of side 24 cm?\nOptions:\n(A) 66√3 cm2\n(B) 74√3 cm2\n(C) 64√3 cm2\n(D) 64√5 cm2\n(E) 144√3 cm2 | (E) | Area of an equilateral triangle = √3/4 S2\nIf S = 24, Area of triangle = √3/4 * 24 * 24 = 144√3 cm2; |
If P(32, 6) = kC (32, 6), then what is the value of k?\nOptions:\n(A) 6\n(B) 32\n(C) 120\n(D) 720\n(E) None | (D) | Since 32P6 = k32C6\n⇒ 32/ ( 32-6 ) = k(32/ ( 32-6 )\n⇒k = 6! = 720 |
A no. when divided by the sum of 555 and 445 gives 2times their difference as quotient & 30 as remainder. Find the no. is?\nOptions:\n(A) 124432\n(B) 145366\n(C) 157768\n(D) 178432\n(E) 220030 | (E) | (555 + 445) * 2 * 110 + 30 = 220000 + 30 = 220030 |
Which of the following expressions are different in value?\n(A) (2x + 3y)2\n(B) (2x + y)2 + 8y(x + y)\n(C) (2x – y)2 – 8y(x + y)\n(D) 22(x + y)2 + 4xy + 5y2\nOptions:\n(A) A and B\n(B) B and C only\n(C) A, B and D only\n(D) B and D only\n(E) All are different | (B) | All others are equal except (C). |
A train 650 m long is running at a speed of 117 km/hr. In what time will it pass a bridge 325 m long?\nOptions:\n(A) 30\n(B) 35\n(C) 40\n(D) 45\n(E) 50 | (A) | Speed = 117 * 5/18 = 65/2 m/sec\nTotal distance covered = 650 + 325 = 975 m\nRequired time = 975 * 2/65 = 30 sec |
Pipes A and B can fill a cistern in 8 and 24 minutes respectively. They are opened an alternate minutes. Find how many minutes, the cistern shall be full?\nOptions:\n(A) 22\n(B) 12\n(C) 88\n(D) 99\n(E) 27 | (B) | 1/8 + 1/24 = 1/6\n6 * 2 = 12 |
Last year, Company M made q dollars in profit. Half of the profit went to the company’s founder. The rest was split evenly among his Three other partners. In terms of q, how much did each of the other partners receive?\nOptions:\n(A) q/4\n(B) q/5\n(C) q/6\n(D) q/7\n(E) q/8 | (C) | Profit = q\nProfit to company founder = q/2\nProfit to other partners = q/2\nNumber of other partners = 3\nProfit to each partner = (q/2)/3 = q/6 |
There are 23 distinct numbers in set M, there are 28 distinct numbers in set N, and there are 12 distinct numbers that are in both sets M and N. Set H is the set containing the elements that are in at least one of sets M and N. How many elements are in set H?\nOptions:\n(A) 39\n(B) 40\n(C) 51\n(D) 58\n(E) 63 | (A) | {Total} = {M} + {N} - {Both}\n{Total} = 23 + 28 - 12 = 39. |
The average age of a class of 32 students is 16 yrs. if the teacher's age is also included, the average increases by one year. Find the age of the teacher\nOptions:\n(A) 45 Years\n(B) 46 Years\n(C) 49 Years\n(D) 52 Years\n(E) 54 Years | (C) | Total age of students is 32X16 = 512 Years\nTotal age inclusive of teacher = 33X (16+1) = 561\nSo, Teacher's age is 561-512 = 49 Yrs\nThere is a shortcut for these type of problems\nTeacher's age is 16+(33X1) = 49 Years |
A football field is 9600 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 5600 square yards?\nOptions:\n(A) 450\n(B) 600\n(C) 700\n(D) 2400\n(E) 3200 | (C) | Answer C) 9600 yards need 1200 lbs\n1 Yard will need 1200/9600 = 1/8 lbs\n3600 Yards will need 1/8* 5600 Yards = 700lbs |
A train 250 m long running at 72 kmph crosses a platform in 50 sec. What is the length of the platform?\nOptions:\n(A) 150m\n(B) 200m\n(C) 250m\n(D) 750m\n(E) 300 m | (D) | D = 72 * 5/18 = 50 = 1000 – 250 = 750m |
Which of the following numbers is divisible by 8?\nOptions:\n(A) 10021\n(B) 17511\n(C) 26778\n(D) 18520\n(E) 26711 | (D) | 18520. This is the only option with last two digits divisible by 8 |
Find the largest 4 digit number which isexactly divisible by 88?\nOptions:\n(A) 7890\n(B) 8900\n(C) 9944\n(D) 9976\n(E) 10000 | (C) | Largest 4 digit number is 9999\nAfter doing 9999 ÷ 88 we get remainder 55\nHence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944 |
The average of 11 results is 49, if the average of first six results is 49 and that of the last six is 52. Find the sixth result?\nOptions:\n(A) 21\n(B) 67\n(C) 18\n(D) 25\n(E) 23 | (B) | 1 to 11 = 11 * 49 = 539\n1 to 6 = 6 * 49 = 294\n6 to 11 = 6 * 52 = 312\n6th = 294 + 312 – 539 = 67 |
If a man can cover 12 metres in one second, how many kilometres can he cover in 3 hours 45 minutes?\nOptions:\n(A) 228\n(B) 162\n(C) 5528\n(D) 256\n(E) 191 | (B) | 12 m/s = 12 * 18/5 kmph\n3 hours 45 minutes = 3 3/4 hours = 15/4 hours\nDistance = speed * time = 12 * 18/5 * 15/4 km = 162 km. |
If the length of an edge of cube P is twice the length of an edge of cube Q, what is the ratio of the volume of cube Q to the volume of cube P?\nOptions:\n(A) 1/8\n(B) 1/4\n(C) 1/3\n(D) 1/7\n(E) 1/9 | (A) | The length of cube Q = 1;\nThe length of cube P = 2;\nThe ratio of the volume of cube Q to the volume of cube P = 1^3/2^3 = 1/8. |
Three pipes A, B and C can fill a tank from empty to full in 30 minutes, 20 minutes and 10 minutes respectively. When the tank is empty, all the three pipes are opened. A, B and C discharge chemical solutions P, Q and R respectively. What is the proportion of solution R in the liquid in the tank after 3 minutes?\nOptions:\n(A) 6/19\n(B) 6/11\n(C) 6/12\n(D) 6/10\n(E) 6/38 | (B) | Part filled by (A + B + C) in 3 minutes = 3(1/30 + 1/20 + 1/10) = 11/20\nPart filled by C in 3 minutes = 3/10\nRequired ratio = 3/10 * 20/11 = 6/11 |
Two trains are traveling on parallel tracks in the same direction. The faster train travels at 130 miles per hour, while the slower train travels at 80 miles per hour. At 2 o’clock the faster train is 20 miles behind the slower one. How far apart are the two trains at 5 o'clock?\nOptions:\n(A) 60 miles\n(B) 80 miles\n(C) 90 miles\n(D) 130 miles\n(E) 400 miles | (D) | Answer = D. 130 miles\nRelational speed = 130 - 80 = 50 miles per hour\nIn 3 hours, difference = 50 * 3 = 150 miles\nFast train trailing 20 miles, so effective difference = 150 - 20 = 130 miles |
Anmol can eat 27 pastries in a hour.\nAakriti can eat 2 pastries in 10 minutes.\nDivya can eat 7 pastries in 20 minutes.\nHow long will it take them to eat a 180 pastries ?\nOptions:\n(A) 2 hours.\n(B) 1 hours.\n(C) 5 hours.\n(D) 4 hours.\n(E) 3 hours. | (E) | In one hour, Anmol eats 27 pastries, Aakriti eats 12, and Divya eats 21. A total of 60 pastries. Therefore 180 pastries would take 180 ÷ 60 = 3 hours. |
There are 6561 balls out of them 1 is heavy.Find the min. no. of times the balls have to be weighed for finding out the haevy ball.\nOptions:\n(A) 7\n(B) 8\n(C) 9\n(D) 10\n(E) 11 | (B) | The simple logic is to divide total balls into three sets. Weigh any two sets against each other(these two must contain equal number of balls). From this we can identify which set contains the heavy ball. Divide this set into three and repeat until you find the heavier ball. Under this logic, the minimum number of weighings required turns out to be the smallest integer greater than or equal to log(n), where n is the total number of balls and the base of logarithm is 3. Or simply [log(n)/log(3)] with any base. Here, n = 6561. log 6561 / log 3 = 8 |
What is the area of a square with perimeter 12P ?\nOptions:\n(A) 16p^2\n(B) 4P\n(C) 9P^2\n(D) P/16\n(E) P^2/16 | (C) | Each side is 3p\nA = (3p)^2 = 9p^2 |
The average of five numbers is 9. The average of first two numbers is 7 and the average of last two numbers is 12. What is the middle number?\nOptions:\n(A) 7\n(B) 8\n(C) 5\n(D) 10\n(E) 6 | (A) | The total of five numbers = 5x9 = 45\nThe total of first 2 and last 2 numbers is = 2 X 7+2 X 12 = 38\nSo, the middle number is (45 - 38 ) = 7 |
A can do a piece of work in 12 days. When he had worked for 2 days B joins him. If the complete work was finished in 8 days. In how many days B alone can finish the work?\nOptions:\n(A) 18 days\n(B) 11 days\n(C) 77 days\n(D) 188 days\n(E) 66 days | (A) | 8/12 + 6/x = 1\nX = 18 days |
Express 50 mps in kmph?\nOptions:\n(A) 172\n(B) 160\n(C) 150\n(D) 180\n(E) 120 | (D) | 25 * 18/5 = 180 kmph |
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?\nOptions:\n(A) 5 kmph\n(B) 7 kmph\n(C) 9 kmph\n(D) 8 kmph\n(E) 1 kmph | (D) | Speed downstream = d/t = 85/(2 1/2) = 34 kmph\nSpeed upstream = d/t = 45/(2 1/2) = 18 kmph\nThe speed of the stream = (34 - 18)/2 = 8 kmph |
A train 250 m long is running at a speed of 27 km/hr. In what time will it pass a bridge 200 m long?\nOptions:\n(A) 40\n(B) 45\n(C) 50\n(D) 55\n(E) 60 | (E) | Speed = 27 * 5/18 = 15/2 m/sec\nTotal distance covered = 250 + 200 = 450 m\nRequired time = 450 * 2/15 = 60 sec |
A man rows his boat 85 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?\nOptions:\n(A) 7 kmph\n(B) 6 kmph\n(C) 5 kmph\n(D) 8 kmph\n(E) 2 kmph | (D) | Speed downstream = d/t = 85/(2 1/2) = 34 kmph\nSpeed upstream = d/t = 45/(2 1/2) = 18 kmph\nThe speed of the stream = (34 - 18)/2 = 8 kmph |
A train 280 m long, running with a speed of 63 km/hr will pass a tree in?\nOptions:\n(A) 22 sec\n(B) 16 second\n(C) 77 sec\n(D) 55 sec\n(E) 17 sec | (B) | Speed = 63 * 5/18 = 35/2 m/sec\nTime taken = 280 * 2/35 = 16 sec |
The speed of a car is 90 km in the first hour and 60 km in the second hour. What is the average speed of the car?\nOptions:\n(A) 22\n(B) 75\n(C) 44\n(D) 28\n(E) 12 | (B) | S = (90 + 60)/2 = 75 kmph |
What is the are of an equilateral triangle of side 14 cm?\nOptions:\n(A) 66√3 cm2\n(B) 74√3 cm2\n(C) 64√3 cm2\n(D) 49√3 cm2\n(E) 14√3 cm2 | (D) | Area of an equilateral triangle = √3/4 S2\nIf S = 14, Area of triangle = √3/4 * 14 * 14 = 49√3 cm2; |
If six persons sit in a row, then the probability that three particular persons are always together is?\nOptions:\n(A) 1/5\n(B) 1/4\n(C) 1/9\n(D) 1/6\n(E) 1/1 | (C) | Six persons can be arranged in a row in 6! ways. Treat the three persons to sit together as one unit then there four persons and they can be arranged in 4! ways. Again three persons can be arranged among them selves in 3! ways. Favourable outcomes = 3!4! Required probability = 3!4!/6! = 1/5 |
How many seconds will a train 100 meters long take to cross a bridge 250 meters long if the speed of the train is 36 kmph?\nOptions:\n(A) 54 sec\n(B) 35 sec\n(C) 25 sec\n(D) 45 sec\n(E) 24 sec | (B) | D = 100 + 250 = 350\nS = 36 * 5/18 = 10 mps\nT = 350/10 = 35 sec |
There are 5 sweets – Jumun, Kulfi, Peda, Laddu and Jilabi that I wish to eat on 5 consecutive days – Monday through Friday, one sweet a day, based on the following self imposed constraints:\n1) Laddu is not eaten on Monday\n2) If Jamun is eaten on Monday, then Laddu must be eaten on Friday\n3) If Laddu is eaten on Tuesday, Kulfi should be eaten on Monday\n4) Peda is eaten the day following the day of eating Jilabi\nBased on the above, peda can be eaten on any day except?\nOptions:\n(A) Tuesday\n(B) Monday\n(C) Wednesday\n(D) Friday\n(E) Sunday | (B) | Peda is eaten the day following the day of eating Jilabi, So Peda can never be had on the starting day, which is Monday. |
A train 280 m long, running with a speed of 63 km/hr will pass a tree in?\nOptions:\n(A) 11\n(B) 16\n(C) 188\n(D) 199\n(E) 12 | (B) | Speed = 63 * 5/18 = 35/2 m/sec\nTime taken = 280 * 2/35 = 16 sec |
Find 12 ×× 19\nOptions:\n(A) 238\n(B) 228\n(C) 208\n(D) 277\n(E) 101 | (B) | Mentally imagine this number as (10 + 2 ) ×× 19 = 190 + 38 = 228. |
3 candidates in an election and received 1136, 7636 and 11628 votes respectively. What % of the total votes did the winningcandidate got in that election?\nOptions:\n(A) 45%\n(B) 54%\n(C) 57%\n(D) 60%\n(E) 65% | (C) | Total number of votes polled = (1136 + 7636 + 11628) = 20400\nSo, Required percentage = 11628/20400 * 100 = 57% |
If the cost price of 50 articles is equal to the selling price of 15 articles, then the gain or loss percent is?\nOptions:\n(A) 16\n(B) 127\n(C) 12\n(D) 18\n(E) 233 | (E) | Percentage of profit = 35/15 * 100 = 233% |
In May Mrs Lee's earnings were 60 percent of the Lee family's total income. In June Mrs Lee earned 20 percent more than in May. If the rest of the family's income was the same both months, then, in June, Mrs Lee's earnings were approximately what percent of the Lee family's total income ?\nOptions:\n(A) 64%\n(B) 68%\n(C) 72%\n(D) 76%\n(E) 80% | (A) | Say May income = 100\nL's income = 60 and rest of the family = 40\nIn June L's income = 60 * 120 /100 = 72\nSo 72 /72 + 40 = 64% |
In Sam's hanger there are 23 boxes, 19 out of the boxes are filled with toys and the rest are filled with electrical appliances. 8 boxes are for sale, 5 of them are filled with toys. How many boxes with electrical appliances are in Sam's hanger that is not for sale?\nOptions:\n(A) 1.\n(B) 2.\n(C) 3.\n(D) 4.\n(E) 5. | (A) | Total boxes = 23\nFilled with toys = 19\nFilled with appliance = 4\nTotal boxes for sale = 8\nToy boxes for sale = 5\nAppliance boxes for sale = 3\nAppliance boxes not for sale = 4 - 3 = 1 |
The speed of a boat in still water is 50kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?\nOptions:\n(A) 40, 68 kmph\n(B) 40, 30 kmph\n(C) 70, 30 kmph\n(D) 40, 60 kmph\n(E) 20, 60 kmph | (C) | Speed downstream = 50 + 20 = 70 kmph\nSpeed upstream = 50 - 20 = 30 kmph |
The length Q of a rectangle is decreased by 15% and its width is increased by 40%. Does the area of the rectangle decrease or increase and by what percent?\nOptions:\n(A) Decreases by 19%\n(B) Decreases by 25%\n(C) Increases by 6%\n(D) Increases by 19%\n(E) Increases by 25% | (D) | Let the length Q of the rectangle be 100x, and width be 100y. Area = 100x * 100y = 10000xy\nNow after the change Length = 85x, and width = 140 y. Area = 11900xy\n% Change = (11900xy - 10000xy)/(10000xy) = 19 % Increase. Hence |
A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 600. How much did he have with him in the beginning?\nOptions:\n(A) s 200\n(B) s 1500\n(C) s 300\n(D) s 450\n(E) s 550 | (B) | Suppose the amount in the beginning was Rs ’x’\nMoney spent on clothes = Rs 1x/3 Balance = Rs 2x/3\nMoney spent on food = 1/5 of 2x/3 = Rs 2x/15\nBalance = 2x/3 - 2x/15 = Rs 8x/15\nMoney spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5\nTherefore 2x/5 = 100 = 1500 |
Steve traveled the first 2 hours of his journey at 40 mph and the last 3 hours of his journey at 80 mph. What is his average speed of travel for the entire journey?\nOptions:\n(A) 61mph\n(B) 62mph\n(C) 63mph\n(D) 64mph\n(E) 65mph | (D) | (2*40+3*80)/5 = 64mph |
The compound ratio of 2/3, 6/7, 1/3 and 1/8 is given by?\nOptions:\n(A) 1/45\n(B) 1/42\n(C) 1/46\n(D) 1/48\n(E) 1/43 | (B) | 2/3 * 6/7 * 1/3 * 1/8 = 1/42 |
If 12 men can reap 120 acres of land in 16 days, how many acres of land can 36 men reap in 32 days?\nOptions:\n(A) 269\n(B) 512\n(C) 369\n(D) 720\n(E) 450 | (D) | 12 men 120 acres 16 days\n36 men ? 32 days\n120 * 36/12 * 32/16\n120 * 3 * 2\n120 * 6 = 720 |
A train of 25 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 2.5 km long?\nOptions:\n(A) 4\n(B) 3\n(C) 5\n(D) 7\n(E) 9 | (A) | D = 25 * 60 + 2500 = 4000 m\nT = 4000/60 * 18/5 = 240 sec = 4 mins |
The average amount with a group of seven numbers is Rs. 30. If the newly joined member has Rs. 60 with him, what was the average amount with the group before his joining the group?\nOptions:\n(A) s. 25.6\n(B) s. 25\n(C) s. 16.6\n(D) s. 26\n(E) s. 25.6 | (B) | Total members in the group = 7\nAverage amount = Rs. 30\nTotal amount with them = 7 * 30 = Rs. 210\nOne number has Rs. 60. So, the amount with remaining 6 people = 210 - 60 = Rs. 150\nThe average amount with them = 150/6 = Rs. 25 |
The average of 13 result is 20. Average of the first 8 of them is 20 and that of the last 8 is 40. Find the 8th result?\nOptions:\n(A) 35\n(B) 37\n(C) 46\n(D) 90\n(E) 100 | (E) | Sum of all the 13 results = 13 * 20 = 260\nSum of the first 7 of them = 8 * 20 = 160\nSum of the last 7 of them = 8 * 40 = 320\nSo, the 8th number = 260 + 160 - 320 = 100. |
How many common two-digit whole numbers are there which gives a remainder of 2 when divided by 9 and gives a remainder of 5 when divided by 8?\nOptions:\n(A) Five\n(B) Three\n(C) One\n(D) Two\n(E) Four | (C) | Answer = C) One\nTwo digit numbers giving remainder 2 when divided by 9 = 11, 20, 29, 38, 47, 56, 65, 74, 83, 92\nTwo digit numbers giving remainder 5 when divided by 8 = 13, 21, 29, 37, 45, 53, 61, 69, 77, 85, 93\nCommon Numbers = 29 = 1 |
Find the least number must be subtracted from 427398 so that remaining no.is divisible by 15?\nOptions:\n(A) 3\n(B) 4\n(C) 6\n(D) 9\n(E) 8 | (A) | On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted |
Anmol can eat 27 pastries in a hour.\nAakriti can eat 2 pastries in 10 minutes.\nDivya can eat 7 pastries in 20 minutes.\nHow long will it take them to eat a 420 pastries ?\nOptions:\n(A) 2 hours.\n(B) 1 hours.\n(C) 5 hours.\n(D) 4 hours.\n(E) 7 hours. | (E) | In one hour, Anmol eats 27 pastries, Aakriti eats 12, and Divya eats 21. A total of 60 pastries. Therefore 420 pastries would take 420 ÷ 60 = 7 hours. |
What is the greatest positive integer x such that 6^x is a factor of 216^10?\nOptions:\n(A) 5\n(B) 9\n(C) 10\n(D) 20\n(E) 30 | (E) | 216^10 = (6^3)^10 = 6^30 |
The purchase price of an article is $48. In order to include 30% of cost for overhead and to provide $12 of net profit, the markup should be\nOptions:\n(A) 15%\n(B) 25%\n(C) 35%\n(D) 40%\n(E) 55% | (E) | Cost price of article = 48$\n% of overhead cost = 30\nNet profit = 12 $\nWe need to calculate % markup\nNet profit as % of cost price = (12/48)*100 = 25%\nTotal markup should be = 25 + 30 = 55% |
The length of a rectangle is increased by 25% and its breadth is decreased by 20%. What is the effect on its area?\nOptions:\n(A) 10000\n(B) 297\n(C) 9279\n(D) 2767\n(E) 2676 | (A) | 100 * 100 = 10000\n125 * 80 = 10000 |
Henry earns $120 a week from his job. His income increased and now makes $180 a week. What is the percent increase?\nOptions:\n(A) 70%\n(B) 60%\n(C) 50%\n(D) 40%\n(E) 30% | (C) | Increase = (60/120)*100 = (1/2)*100 = 50%. |
A person deposits 1/16 of his income as Provident Fund and 1/15 of the remaining as insurance premium. If he spends 5/7 of the balance on domestic needs and deposits an amount of Rs. 50 in the bank, his total income would be\nOptions:\n(A) 150\n(B) 200\n(C) 250\n(D) 300\n(E) 350 | (B) | (1-(1/16))(1-(1/15))(1-(5/7)) of Income = 50\nHence income = 200 |
396, 462, 572, 427, 671, 264\nOptions:\n(A) 396\n(B) 427\n(C) 671\n(D) 264\n(E) 572 | (B) | In each number except 427, the middle digit is the sum of other two. |
There are 25 balls in a jar. You take out 5 blue balls without putting them back inside, and now the probability of pulling out a blue ball is 1/5. How many blue balls were there in the beginning?\nOptions:\n(A) 12.\n(B) 9.\n(C) 8.\n(D) 7.\n(E) 6. | (B) | 9 = 5 blue balls + 20/ 5 |
The average of first 10 odd numbers is?\nOptions:\n(A) 44\n(B) 10\n(C) 99\n(D) 77\n(E) 62 | (B) | Sum of 10 odd no. = 100\nAverage = 100/10 = 10 |
Two trains are moving at 50 kmph and 70 kmph in opposite directions. Their lengths are 150 m and 100 m respectively. The time they will take to pass each other completely is?\nOptions:\n(A) 7 1/7 sec\n(B) 7 7/2 sec\n(C) 7 1/8 sec\n(D) 7 1/2 sec\n(E) 7 3/2 sec | (D) | 70 + 50 = 120 * 5/18 = 100/3 mps\nD = 150 + 100 = 250 m\nT = 250 * 3/100 = 15/2 = 7 1/2 sec |
A train 540 meters long is running with a speed of 54 kmph. The time taken by it to cross a tunnel 180 meters long is?\nOptions:\n(A) 66 sec\n(B) 46 sec\n(C) 48 sec\n(D) 65 sec\n(E) 64 sec | (C) | D = 540 + 180 = 720\nS = 54 * 5/18 = 15 mps\nT = 720/15 = 48 se |
The average age of A, B and C is 25 years. If the average age of A and C is 29 years, what is the age of B in years ?\nOptions:\n(A) 17\n(B) 35\n(C) 20\n(D) 32\n(E) 21 | (A) | Age of B = Age of (A + B + C) – Age of (A + C) = 25 × 3 – 29 × 2 = 75 – 58 = 17 years |
In a group of dogs and peacocks, the number of legs are 18 less than four times the number of heads How many peacocks are there in that group?\nOptions:\n(A) 9\n(B) 8\n(C) 7\n(D) 6\n(E) 5 | (A) | Let the number of dogs be 'x' and the number of peacocks by 'y'. Then, number of legs in the group = 4x + 2y. Number of heads in the group = x+y So, 4x+2y = 4(x+y) – 18 ⇒ 2y = 18 ⇒ y = 9 Number of peacocks in that group = 9. |
The average of first four prime numbers greater than 30 is?\nOptions:\n(A) 38\n(B) 20\n(C) 30\n(D) 40\n(E) 50 | (A) | 31 + 37 + 41 + 43 = 152/4 = 38 |
In a race with 30 runners where 5 trophies will be given to the top 7 runners (the trophies are distinct: first place, second place, etc), how many ways can this be done?\nOptions:\n(A) 8^8 ways\n(B) 8^9 ways\n(C) 7^5 ways\n(D) 8^7 ways\n(E) 8^6 ways | (C) | 7 people can be prized with 5 distinct prizes in 7^5 ways |
The edge of a cube is 6a cm. Find its surface?\nOptions:\n(A) 116a2 cm2\n(B) 126a2 cm2\n(C) 256a2 cm2\n(D) 150a2 cm2\n(E) 216a2 cm2 | (E) | 6a2 = 6 * 6a * 6a = 216a2 |
252 can be expressed as a product of primes as:\nOptions:\n(A) 2 x 2 x 3 x 3 x 7\n(B) 2 x 2 x 3 x 3 x 8\n(C) 2 x 2 x 3 x 3 x 6\n(D) 2 x 2 x 3 x 3 x 1\n(E) 2 x 2 x 3 x 3 x 2 | (A) | Clearly, 252 = 2 x 2 x 3 x 3 x 7. |
The average of seven numbers is 18. The average of first three numbers is 14 and the average of last three numbers is 16. What is the middle number?\nOptions:\n(A) 27\n(B) 29\n(C) 36\n(D) 34\n(E) 35 | (C) | The total of seven numbers = 7X18 = 126\nThe total of first 3 and last 3 numbers is = 3 X 14+3 X 16 = 90\nSo, the middle number is (126 - 90 ) = 36 |
A person spends 1/3rd of the money with him on clothes, 1/5th of the remaining on food and 1/4th of the remaining on travel. Now, he is left with Rs 500. How much did he have with him in the beginning?\nOptions:\n(A) s 200\n(B) s 1250\n(C) s 300\n(D) s 450\n(E) s 550 | (B) | Suppose the amount in the beginning was Rs ’x’\nMoney spent on clothes = Rs 1x/3 Balance = Rs 2x/3\nMoney spent on food = 1/5 of 2x/3 = Rs 2x/15\nBalance = 2x/3 - 2x/15 = Rs 8x/15\nMoney spent on travel = 1/4 of 8x/15 = Rs 2x/15 = 8x/15 - 2x/15 = 6x/15 = Rs2x/5\nTherefore 2x/5 = 500 = 1250 |
A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?\nOptions:\n(A) 118\n(B) 150\n(C) 277\n(D) 258\n(E) 191 | (B) | Speed = 60 * 5/18 = 50/3 m/sec\nLength of the train = speed * time = 50/3 * 9 = 150 m |
Which of the following is equal to the average (arithmetic mean) of (x+2)^2 and (x-4)^2?\nOptions:\n(A) x^2\n(B) x^2+2\n(C) x^2-2x+10\n(D) x^2+2x+10\n(E) x^2+4x+5 | (C) | Avg = [(x+2)^2 + (x-4)^2] / 2\nExpanding and simplifying, (x^2 + 4x + 4 + x^2 - 8x + 16 ) / 2 = x^2 - 2x +10 |
Look at this series: 53, 53, 39, 39, 25, 25, ... What number should come next?\nOptions:\n(A) A) 12\n(B) B) 11\n(C) C) 27\n(D) D) 53\n(E) E) 86 | (B) | In this series, each number is repeated, then 14 is subtracted to arrive at the next number. |
Four of the five parts numbered (a), (b), (c), (d) and (e) in the following equation are exactly equal. Which of the parts is not equal to the other four? The number of that part is the answer.\nOptions:\n(A) 371.587 + 46.32 – 217.907\n(B) 4 × 125 – 75 × 4\n(C) 58.25 × 4.5 – 65.875\n(D) 25 × 12 – 2 × 5 × 10\n(E) 121 × 3.5 – 2 × 111.75 | (C) | The other parts are equal to 200. |
What is the units digit of the expression 14^7−19^4?\nOptions:\n(A) 0\n(B) 3\n(C) 4\n(D) 6\n(E) 8 | (E) | I think answer on this one should be E too. Since we know that 14^7>19^4, as Will said one should always check if the number is positiv |
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