Two defective balls out of ten There are 2 defective balls in a batch of 10. To inspect, someone will randomly check 2 balls to see if they're defective and will reject if at least 1 ball they check is defective.
What's the probability of finding at least 1 defective ball when randomly selecting 2 from the batch of 10?

The solution should deal with permutations, but I'm not sure how to initially approach this.
Hint:  the number of ways you could get a defective ball is 
\begin{align}
\binom{2}{1}\binom{8}{1} + \binom{2}{2}\binom{8}{0}.
\end{align}
hey actually it is a quite easy question u dont need to worry
wat we have to do is select two balls out of 10 that is 10c2 which comes out to be 45 and then non defective once that is 8c2 which comes out to be 28
after doing this the probablity of non defctive comes out to be 28/45 and for non defctive just subtract from 1*here u r done*