Finding equilibrium in a predator prey system Using predator prey system 

$\frac{dR}{dt}=6R\:-2RW$

$\frac{dW}{dt}=-4W\:+5RW$

$When\:the\:system\:is\:equilibrium\:with\:W\ne 0,\:R\:\ne 0\:then\:RW\:=?$

Apologize for formatting
you are looking for the non trivial special solutions where $w = constant, r = constant.$  that is $$r \neq 0, w \neq 0, 2r(3 - w) = 0 \text{ and } w(-4 + 5r)=0 $$ that is $$ w = 3, r = \frac 45.$$
"When the derivatives are 0 and it's an equation, use Cramer and some determination!" (It's a linear equation, solve for R and W and multiply them together)

"I like the rhyme because it's sublime"