How do I find the coefficient of restitution COR when a sphere is hanging from a roof? The problem is as follows:

The diagram from below shows a sphere labeled $A$ and is moving with a horizontal speed of $v=4\sqrt{10}\,\frac{m}{s}$ over a frictionless table. After the collision the cable makes an angle of $53^{\circ}$ with the vertical and the sphere $A$ ends at rest. Find the $COR$ (coefficient of restitution) and the relationship between the masses.



The alternatives given are as follows:

$\begin{array}{ll}
1.&amp;\frac{1}{2},\, \frac{1}{2}\\
2.&amp;\frac{1}{3},\, \frac{1}{6}\\
3.&amp;\frac{1}{2},\, \frac{1}{3}\\
4.&amp;\frac{1}{8},\, \frac{1}{2}\\
5.&amp;\frac{1}{2},\, \frac{1}{6}\\
\end{array}$

When it mentions the COR for the collision I'm assuming that it is an inelastic collision. Therefore if treated as such then

$p_1=p_2$

$m_1 v_1=m_2 v_2$

$v_2=4\sqrt{10} \frac{m_1}{m_2}$

But that's how far I went. I'm stuck with this problem, can someone help me here?.
Initial momentum of $A$ is $4\sqrt{10}m_A$. This is equal to the momentum of $B$ after the collision. The kinetic energy of $B$ after the collision is then $p^{2}/2m_B = 80m_{A}^{2}\big/m_B$.

As has been noted, $B$ is raised by $2\text{m}$ by the collision, giving it a potential energy of $20m_{B} = \frac{1}{2}m_{B}v_{B}^{2}$. Note therefore that $v_{B} = \sqrt{40} = 2\sqrt{10}$.

Therefore $80m_{A}^{2} = 20m_{B}^{2}$, meaning $m_{A}/m_{B} = 1/2$.

The COR is then $$\frac{v_{B}}{v_A} = \frac{2\sqrt{10}}{4\sqrt{10}} = 1/2.$$
Total mechanical energy using $g=10$ and $\cos(53)=\frac 35$ ...
$$E = \frac 12 m_a (4\sqrt {10})^2=80m_a
\\E'= m_bg[5(1-\cos(53))] = 20 m_b$$
$E'$must be equal to the total Kinetic energy immediately after collision so .
$$C_r =\sqrt{ \frac{KE'}{KE}}= \frac 14 \frac {m_b}{m_a}   $$
The only option that could possibly make sense would be the one in which $C_r=\frac 12$ which must have $m_b = m_a$ 
It is not entirely clear what they mean by "the relationship between the masses" , it is possible that they mean $\frac{m_b}{m_a+m_b}$, in which case you should choose the option with both numbers equal to $\frac 12$