Find all complex numbers $z$ satisfying the equation I need some help on this question. How do I approach this question?

Find all complex numbers $z$ satisfying the equation

$$
(2z - 1)^4 = -16.
$$

Should I remove the power of $4$ of $(2z-1)$ and also do the same for $-16$?
HINT: How many solutions does $x^4+16=0$ have?


   $x_{1,2,3,4}= \sqrt{2}(\pm 1 \pm i)$, substitute $x$ with $2z-1$, solve for $z$ and you're done.
The answer to this problem lies in roots of a polynomial.
From an ocular inspection we know we will have complex roots and they always
Come in pairs! The power of our equation is 4 so we know will have a pair of
Complex conjugates. I believe it is called the Fundamental
Theorem.
Addendum
A key observation is how to represent -1 in its general term using Euler's identity and the concept of odd powers in EF.