Simplify this expression fully How would i simplify fully the following expression?

$\dfrac{{\sqrt 2}({x^3})}{\sqrt{\frac {32}{x^2}}}$

So far i have got this

$\dfrac{{\sqrt 2}{x^3}}{{\frac{\sqrt 32}{\sqrt x^2}}}$ = $\dfrac{{\sqrt 2}{x^3}}{{\frac{4\sqrt 2}{x}}}$

Am not quite sure if this is correct however, could someone help explain how i would simplify this expression?
There is a mistake in the OP.  Recall that $\sqrt{x^2}=|x|\ne x$ when $x&lt;0$.  To simplify, we can write

$$\frac{\sqrt 2 x^3}{\sqrt{\frac{32}x}}=\frac{\sqrt 2 x^3}{\frac{4\sqrt 2}{|x|}}=\frac{x^3|x|}{4}$$
$\frac{\sqrt{2}x^3}{\sqrt{\frac{32}{x^2}}} = \frac{\sqrt{2}x^3}{\frac{\sqrt{32}}{\sqrt{x^2}}} = \frac{\sqrt{2}x^3}{\frac{4\sqrt{2}}{x}} = \frac{x^3}{\frac{4}{x}} = \frac{x^4}{4}$