What is the differential equation given $y=C_1 x^{2}+C_2 x^{3}$ I have worked the problem, but I keep getting the wrong answer. I've also looked at some other similar questions from here, but I still don't understand what I'm doing incorrectly.

Attempt:

First, the derivations I got:

$y=C_1 x^{2}+C_2 x^{3}$

$y'=2C_1x+3C_2x^2$

$y''=2C_1+6C_2x$  

$\Longrightarrow C_2=\dfrac{y''-2C_1}{6x}$

Then, I started substituting:

$y'=2C_1 x+3\left(\dfrac{y''-2C_1}{6x}\right) x^2=2C_1 x+\left(\dfrac{1}{2}\right) xy''-C_1 x$

$y'=C_1x+\left(\dfrac{1}{2}\right) xy''$

$\Longrightarrow C_1=\dfrac{y'}{x}-\dfrac{y''}{2}$

When I plugged $C_1$ and $C_2$ back into $y=C_1 x^{2}+C_2 x^{3}$:

$y=\left(\dfrac{y'}{x}-\dfrac{y''}{2}\right) x^2+\left(\dfrac{y''-2\left(\dfrac{y'}{x}-\dfrac{y''}{2}\right)}{6x}\right) x^3$

And when I simplify, I end up with:

$y=\dfrac{2xy'}{3}-\dfrac{x^2 y''}{2}$

But I'm being told this is incorrect. Is there a different approach to this problem and/or have I made a mistake somewhere?

Thanks in advance!
You want to perform differentiations that remove the constants directly. So I would probably start with dividing everything by $x^2$ and differentiating the result, like thus:

$\begin{eqnarray}y &amp; = &amp; C_1 x^2 + C_2 x^3 \\
\frac{y}{x^2} &amp; = &amp; C_1 + C_2 x \\
\frac{d}{dx}\left(yx^{-2}\right) &amp; = &amp; \frac{d}{dx}\left(C_1 + C_2 x\right) \\
y'x^{-2} - 2yx^{-3} &amp; = &amp; C_2 \\
\frac{d}{dx}\left(y'x^{-2} - 2yx^{-3}\right) &amp; = &amp; \frac{d}{dx} C_2 \\
y''x^{-2} - 4y'x^{-3} + 6yx^{-4} &amp; = &amp; 0 \\
y'' - 4y'x^{-1} + 6yx^{-2} &amp; = &amp; 0\\
y'' &amp; = &amp; \frac{4y'}{x} - \frac{6y}{x^2} \end{eqnarray}$

Which is, I believe, equivalent to the corrected answer @Galc127 has suggested, but where I've focused on the highest order derivative of $y$.
It is true that $y=C_1x^2+C_2x^3\Rightarrow y=\frac{2xy'}{3}-\frac{x^2y''}{2}$.
But conversely, it doesn't hold. Maybe because of this reason, your answer is not incorrect. The correct answer should be such that $y=C_1x^2+C_2x^3\Leftrightarrow$correct answer