Simplify and rewrite in term of i The problem click here

I believe the answer is (b) I tried it in my calculator and it's by far the closest answer from the rest of the other options but it could also be (a) and that's where I need your help guys.

Could it be non above?, Because it sure seems like it in the calculator.
Notice, we know that $\color{blue}{i^2=-1}$

Now, we have

$$\frac{\sqrt{-25}\cdot \sqrt{-64}}{\sqrt{-9}}$$
$$=\frac{\sqrt{25i^2}\cdot \sqrt{64i^2}}{\sqrt{9i^2}}$$
$$=\frac{5i\cdot 8i}{3i}$$
$$=\color{red}{\frac{40}{3}i}$$
Notice, we know that $\color{blue}{i^2=-1}$

Now, we have

$$\frac{\sqrt{-25}\cdot \sqrt{-64}}{\sqrt{-9}}$$
$$=\frac{\sqrt{25i^2}\cdot \sqrt{64i^2}}{\sqrt{9i^2}}$$
$$=\frac{5i\cdot 8i}{3i}$$
$$=\color{red}{\frac{40}{3}i}$$