Simple question about probability I'm a bit confused about something.

Let's say I want to cross a road to my friend's house. The probability of the road to be opened is $p$, and $1-p$ to be closed. So I know the probability for one direction at a time. What would it be if I would like to go and return on the same day? 
note: Let's assume that the road was opened/closed for the whole day.  

My answer is $p^2$ (or $(1-p)^2$), depends on the status of the road.
If it is given that the status of the road is the same for the entire day, then the answers of "$p^2$ or $(1-p)^2$" don't make sense. With this interpretation, only the status of the road matters, but it does not matter at all how many times you want to cross the road. With probability $p$ the road is open for the entire day &mdash; so this is the probability that you can visit your friend, or visit him and come back home, or visit him and come back home and visit him again, or &hellip; (you get the idea). And the probability that you can't cross the road is just $1-p$, regardless of how many times you want to cross it.
I think answer is p,because who comes back and who went are the same,so he knows the road is open or closed,when the probabality of being open is P when he wants to come back anything changes,so thats just one job,so answer is P