The $P(X) = 0.7$ and $P(Y) = 0.6$. What is the probability of $X$ or $Y$ occurring? So let's say we have two independent events. The $P(X) = 0.7$ and $P(Y) = 0.6$. What is the probability of $X$ or $Y$ occurring? I know how to calculate an or probability but this question is confusing me.
Recall inclusion exclusion
$$P(X\cup Y) = P(X)+P(Y)-P(X\cap Y)$$
and recall something special about
$$P(X\cap Y)$$
from the fact that they are independent.
By the way, this problem is an "or" problem.
Given that P(x) = 0.7
P(Y) = 0.6 

Then P(X or Y) = P(X) + P(Y) - P(X and Y)(If you assume independence for X and y) 

= 0.7 + 0.6 - (0.7*0.6)
= 1.3 - 0.42

P(X or Y) = 0.88