Solving Recurrence Relation 5 How to solve the recurrence relation given by the equation below

$$T(n)=T(n-2)+T(n-4)+T(n-6)+...+T(0)$$

It seems to me that $T(n)$ will be exponential but i don't know how to proceed on this problem.
Let $T(0)$=1, then $T(2)=1=2^0$, $T(4)=2=2^1$, $T(6)=4=2^2$, $T(8)=8=2^3$.
Hint: $T(n-2)=T(n-4)+T(n-6)+T(n-8)+...T(0)$