The area under the curve 1/x in the first quadrant (integral) I've got a problem that I can't remember how to solve. 
I'm meant to calculate the area under a curve 1/x in the first quadrant. Or, in other words, the integral of 1/x within these limits.

How do I go about doing this? I know that the primitive function (is that the correct term in English?) is: * ln(x) + C *.
What do I do now to get the area?

Thanks in advance!
You have an improper integral.  You get $\lim_{x\to\infty}\ln(x)-\lim_{x\to0}\ln x=\infty$...
You have an improper integral.  You get $\lim_{x\to\infty}\ln(x)-\lim_{x\to0}\ln x=\infty$...