Finding the antiderivative of $f(x)=\sqrt[3]{x^2+2x}$ $$f(x)=\sqrt[3]{x^2+2x}$$. 
Let $g(x)$ be an antiderivative of $f(x)$. If $g(5)=7$, then what is the value of $g(1)$? 
I tried doing integrating by parts repeatedly, but no success. Wolfram Alpha also gives something in a different type of function which I don't know. 
Please help?
If you are confident with a numerical solution , here is it :

Because of 

$$g(5)-g(1)=\int_1^5 (x^2+2x)^\frac{1}{3}dx=9.729162187801335050406060297$$

we get

$$g(1)=g(5)-9.729162187801335050406060297=-2.729162187801335050406060298$$
Which is the exact phrasing of the question? I mean, maybe you are not asked to compute but just to express the value in terms of $g$, i.e.:
$$g(1)=\int_5^1 \sqrt[3]{x^2+2 x} \, dx +7$$
because, at the end of the day, the definition of $g$ is simply:
$$g(x)=\int_5^x \sqrt[3]{t^2+2 t} \, dt +7$$