How to find the probability? John invites 12 people to a dinner party, half of which are men. Exactly one man and one woman are bringing desserts. If one person from this group is selected at random,what is the probability that it is a woman, or a man who is not bringing a dessert?
There are $6+5=11$ persons of the $12$ that fall in one of the classes: 1) women 2) men that do not bring a desert. So the probability is $\frac{11}{12}$.

(If the first class is meant to be: women that do not bring a desert, then there are $5+5=10$ persons and the probability is $\frac{10}{12}$)
I could be wrong, but I would have said that 10 people didn't bring deserts so we are looking at a 1/10 probability?