Why is the additive group of rational numbers indecomposable? A group $G$ is indecomposable if $G \neq \langle e \rangle$ and $G$ cannot be written as the direct product of two of its proper subgroups. Why is the additive group of rational numbers $(\mathbb{Q},+)$ indecomposable?
I suspect, what you want to ask is why $(\mathbb{Q},+)$ is indecomposable, ie. it cannot be written as the direct sum of two subgroups.

The answer is that two non-trivial subgroups must intersect non-trivially. If $\{0\}\neq H, K &lt; \mathbb{Q}$, then choose non-zero $p/q \in H, a/b\in K$, then
$$
qa\frac{p}{q} = ap = pb\frac{a}{b} \in H\cap K\setminus \{0\}
$$
Because there are no additive primes. Every number is the sum of two other nontrivial numbers.