Simplify sum of angles expression (Trigonometry) I'm stuck on this.I need to simplify this given expression
$$\cot(\fracπ4+\theta)(\cos^2\theta-\sin^2\theta)$$
So far I simplified the first parentheses to $\frac{\cos\theta-\sin\theta}{\cos\theta\sin\theta}$ which I dont if this is correct but now I dont know how to multiply this by the second parenthesis
Remember this:

$$\cos^2(x) - \sin^2(x) = \cos(2x)$$

and $$\cot\left(\frac{\pi}{4} - x \right) = \tan\left(\frac{\pi}{4} + x\right)$$
Remember this:

$$\cos^2(x) - \sin^2(x) = \cos(2x)$$

and $$\cot\left(\frac{\pi}{4} - x \right) = \tan\left(\frac{\pi}{4} + x\right)$$