Improper integral of $\frac{1}{(x^2 + y^2)}$ on $(x-1)^2 + y^2 \leq 1$ Integrate $\frac{1}{(x^2 + y^2)}$
Domain : $(x-1)^2 + y^2 \leq 1$
Hint
$$
{x=r\cos\theta
\\
y=r\sin\theta
}
$$
and
$$
(x-1)^2+y^2\le 1\equiv r\le 2\cos\theta\quad,\quad -\frac{\pi}{2}\le\theta\le \frac{\pi}{2}
$$
Hint
$$
{x=r\cos\theta
\\
y=r\sin\theta
}
$$
and
$$
(x-1)^2+y^2\le 1\equiv r\le 2\cos\theta\quad,\quad -\frac{\pi}{2}\le\theta\le \frac{\pi}{2}
$$