Limits in Indeterminate form. Why is the   $\lim_{x  \rightarrow \ 0}$$x^x$ indeterminate and not $1$ ?.

I first approached this as the zero polynomial, but still couldn't wrap my head around why this would still be an indeterminate form.
Use the fact that $e^{lnx}=x$ to rewrite the problem as $$\lim_{x\to 0} e^{lnx^x}=\lim_{x\to 0} e^{xlnx}=e^{\lim_{x\to 0}xlnx}=e^0=1$$
Giving it $1$ as result would assume giving a meaning to $\frac{0}{0}$. 

If $0^0 = n$, where $n$ is a number, then $n=0^0 =0^{1-1} = \frac{0}{0}$.

And this would be in contrast with other math rules.