Calculate Exact Value of $\sin\theta, \cos\theta$ and $\tan\theta$ Having trouble getting a start on this problem, any help would be appreciated!

Given point $P = (-3,5)$ is on the terminal arm of angle $\theta$ in standard position. Calculate the exact value of $\sin\theta, \cos\theta$, and $\tan\theta$.
Hints: 

What quadrant is the point $\;P = ({\bf x, y}) = (-3, 5)$ located? 

Draw the right triangle that point $P$ makes with the $x$ axis - the length of the hypotenuse of the right triangle will equal $\;{\bf h} = \sqrt{(-3)^2 + 5^2} = \sqrt{34}$

Use SOH CAH TOA  to unpack the definitions of $\tan \theta, \;\sin\theta,\;\cos\theta$:

$$\tan\theta = \frac{\text{opposite}}{\text{adjacent}} = \frac yx = \quad?\;$$
$$\sin\theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac yh = \quad?\;$$
$$\cos \theta= \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{x}{h} = \quad?$$
$\sin \theta = p/h$ means perpendicular/hypotenuse
$\cos \theta = b/h$ means base/hypotenuse
$\tan \theta = p/b$ means perpendicular/base 

This all means, if given two values in a right-angle triangle, we can find another third side of triangle.  Especially for 10 class, this formula helps.