Integrating $ 3 \int \frac{\cos^5 x}{\sin x} dx$? I need to solve the integral $$3 \int  \frac{\cos^5 x}{\sin x} dx$$

I'm not sure how to proceed from here. I think Integration by Parts may be useful, but I'm not entirely sure what to make $u$ and $dv$.
A start: Note that $\cos^4x=(1-\sin^2 x)^2$. Let $u=\sin x$.
$$
\int \frac{\cos^5x}{\sin x}\,dx
=
\int\frac{\cos^4x \cdot \cos x}{\sin x}\,dx
$$
$$
=
\int \frac{(1-\sin^2 x)^2  \cos x}{\sin x}\, dx
$$
Then put $t=\sin x$ then $dt=\cos x\, dx$

Then the integral is equal to
$$\int\frac{(1-t^2)^2}{t}\, dt$$