For $p$ prime, every prime divisor of $p!+1$ is greater than $p$ I am not sure how to start this queston. Could you give me some hint?

Show that for any prime number $p$, every prime divisor of $p!+1$ is greater than $p$.

Thanks
Notice that all primes less than or equal to $p$ divide $p!$. Therefore, they cannot also divide $p!+1$. Therefore, $p!+1$ can be represented as a product of primes which are all greater than $p$. This is actually one of the nice proofs showing that there are infinitely many primes.
Hint. If $q\leq p$ then $q\mid p!$