Percent Change Question If 150 were increased by 60% and then decreased by y%, the result would be 192. What is the value of y?
My solution is to use percent change. Here are my steps and yet my answer is incorrect. Can someone please advise why my answer is incorrect? Thanks.

$150 * 0.60 = 90$
$150 + 90 = 240$
Percent change = ((New value − Old value) /Old value) $∗ 100$
New value = $240$, Old Value = $192$
$((240-192)/192)*100 = 25$
&quot;Increasing by 60%&quot; is multiplying by $1.60$.
&quot;Decreasing by $y$%&quot; is mutiplying by $1-\tfrac{y}{100}$.
You know that $150(1.60)(1-\tfrac{y}{100}) = 192$.
So, solving for $y$, the desired percentage is $y = 100\left(1 - \dfrac{192}{150(1.60)}\right) = \boxed{20}$.
to increase by 60% you multiply by 1,6 so you get 240 wich you did
to decrease bei y% yo u multiply by 1-y/100
so you have 240*(1-y/100)=192
1-(y/100)=192/240=0.8 so y is 0.2*100=20
your kind of reasoning 240-192=48 but 240 is the old value, 192 the new, and 48 is 20% of 240  or 48/240=0.2=20%