Show that a number is not prime? Show that for any integer $n&gt;1$, all the numbers $n!+2, n!+3, \ldots, n!+n$ are composite (i.e. not prime).
Hint:
Try to show, that if for two numbers $a$ and $b$, $a$ is divisible by $d$ and $b$ is divisible by $d$, then so is their sum. Then go looking for such a common divisor in your sums.
Take an arbitrary number $n! + k$, where $n > 1, 1 &lt; k \leq n$.

The following is the definition of the factorial function:

$$n! = \prod_{i=1}^n i$$

Hence every i where $1 \leq i \leq n$ is a factor of $n!$. Since the range k covers is within the range of i, this is clearly true for all k.

We know that k is a factor of $n!$, so let us say $n! = qk, k \in \mathbb{Z}$. Hence $n! + k = qk + k = (q + 1)k$, which implies q + 1 and k are integral factors of $n! + k$. QED

This is a reasonably rigorous proof. When you become more familiar with the concepts of divisibility and factorials the result should be fairly apparent from first sight.