the area of a square is equal to twice the squares's perimeter. Find the length of one side of the square The area of a square is equal to twice the square's perimeter. Find the length of one side of the square.

Don't know how to do this or even where to start to solve this problem.
Hint: If $s$ is the side-length of the square, the area is $s^2$ and the perimeter is $4s$.
If the length of any one side of the square is x, then the area is x2, and the perimeter is 4x. If the area is twice the perimeter, x2 = 2(4x), and x2 − 8x= 0. By factoring, we see this equation is equivalent to x(x − 8) = 0, which has solutions 0 and 8. The length cannot be 0, so it must be 8 units.