Probability All Players Receive a Spade 52 cards were distributed among 4 players, 13 cards for each. Calculate the probability that all players have received at least one spade. 

I do not know what to do with this question, i have the answer in my textbook however i do not understand where does it come from. How to solve this question?

EDIT: I am still looking for a good explanation.
Consider 4 compartments, each having $13$ slots, and although cards are not distributed in this manner, it will not matter if we first distribute all the spades.

If one compartment is barred, all the spades have to go into the remaining $39$ slots, if two compartments are barred, they have to go into the remaining 26 slots, and so on.

Then applying the principle of inclusion and exclusion, $Pr = \frac{\dbinom{52}{13} - \dbinom41\dbinom{39}{13} + \dbinom42\dbinom{26}{13} - \dbinom43\dbinom{13}{13}}{\dbinom{52}{13}} \approx 0.9489$
I would say

Favorable event: Each player has one spade + 12 additional cards of, selected from the remaining 48 cards.

The number of favorable events: $\quad \omega ={48\choose12}$ 

the number of possible events: $\quad \Omega ={52\choose13}$

$\displaystyle P = \frac{\omega}{\Omega}=\frac{{48\choose12}}{{52\choose13}}=\frac{9139}{83300} \doteq 0.110$

Edit: $\color{green}{ \text{Apparently the wrong solution.}}$ georg