Find GCD $(10^6\times 6^2 \times 5 ; 6 \times 15 \times 3^7)$ Find GCD $(10^6\times 6^2 \times 5 ; 6 \times 15 \times 3^7)$

I have no idea.
Write
$$
10^6\cdot 6^2\cdot 5 = 2^8\cdot 3^2\cdot 5^7
$$
$$
6\cdot 15\cdot 3^7 = 2\cdot 3^9\cdot 5
$$
Does that help?
My bad. I was wrong in counting number of factors for 2nd number. Edited the correct answer

Your expression is same like 
$$(2^9 \times 3^3 \times 5^7 , 2 \times 3^9 \times 5)$$
which can be divided by the largest number 
$$(2 \times 3^3 \times 5)$$

So the GCD is $$(2 \times 3^3 \times 5)$$ which is equal to $90$.