Divergence of the sequence $\sin(n!)$ Does the sequence $\sin(n!)$ diverge(converge)?

It seems the sequence diverges. I tried for a contradiction but with no success.
Thanks for your cooperation.
Depends on whether the parameter of $\sin$ is in radians or degrees. If in degree, $n!$ becomes multiple of 360 and after that function value will be zero, for all value of $n$. 

In radians this will not happen as $\pi$ is irrational.
Hint: Take a subsequence in which $a_{n_i} \approx \pi ( 4i+1)/2 $ and another where $b_{n_j} \approx \pi ( 4i +3)/2$.