In how many ways $5$ different rings can be worn on $4$ fingers? In how many ways $5$ different rings can be worn on $4$ fingers ?


Although these is similar question here In how many ways $3$ different rings can be worn in $4$ fingers with at most one in each finger?

But I want to answer it in different way which is like take $4$ fingers like $a,b,c,d$. Now $a$ can be filled in $5$ ways and so are others. So total ways are $5^4$ but answer is $4^5$. What is wrong in my reasoning? Which cases have I left out?
I'm assuming that the four fingers are given, e.g., the fingers of one hand without the thumb. An arrangement of five distinguishable rings on the four labeled fingers amounts to a linear arrangement of $1$, $2$, $3$, $4$, $5$, and three indistinguishable zeros as separators. There are ${8!\over3!}=6720$ such arrangements. Note that a green ring and a blue ring on the index finger can be worn in $2$ ways.
In your argument that finger a can be filled in $5$ ways is wrong. This means one ring can be worn in more than one finger which is not possible.

You must argue that the first ring can be worn in any of the fingers, so it has $4$ choices.
Similarly, each ring has $4$ choices.
Total ways$=4.4.4.4.4=4^5$.

Second Question: Select $3$ rings from given $4$ rings and arrange the $3$ rings.
Answer=$^4C_3\cdot 3!=24$.