$6$ women and $4$ men wait in line. If their order in line is random, find the probability that all of the women are adjacent to one another. My thoughts on the problem are that the number of ways the women can be adjacent to each other is $5!$ and the total number of arrangements for all the people is $10!$. Is this correct?
Some hints: $10$ people can be arranged in a line in $10!$ ways. Four men and a bench can be arranged in $5!$ ways. Six women can be placed on the bench in $6!$ ways.
((women factorial - men factorial) $\times$ possible permutations)/Total possible arrangements irrespective of order factorial

((6!-4!)$\times$5)/10! = 3600/3628800 = 0.00099206
or a 0.0992% probability