Show that an ordered 4-tuple is also an ordered $m$-tuple for every positive integer $m$ less than 4. I'm not really sure what this question is asking me to do. Can someone please explain this to me just a little bit more? Maybe give some examples. 

This question was taken from Enderton's Elements of Set Theory.
Here is a hint:

Suppose we have the ordered $3$-tuple $\langle x_1, x_2, x_3\rangle=\langle\langle x_1, x_2\rangle, x_3\rangle$.

What happens if we define $y_1=\langle x_1, x_2\rangle$ and $y_2=x_3$?
A complete solution is:Take,$y_4=\langle x_1, x_2, x_3, x_4\rangle$ , $y_3=\langle x_1, x_2, x_3\rangle$  and $y_2=\langle x_1, x_2\rangle$ .
Now, $\langle x_1, x_2, x_3, x_4\rangle=\langle\langle x_1, x_2, x_3\rangle, x_4\rangle=\langle y_3, x_4\rangle$, which is a two tuple.
 Again,  $\langle x_1, x_2, x_3, x_4\rangle=\langle\langle x_1, x_2, x_3\rangle, x_4\rangle=\langle\langle \langle x_1, x_2\rangle, x_3\rangle, x_4\rangle=\langle\langle  y_2, x_3\rangle, x_4\rangle=\langle  y_2, x_3, x_4\rangle$ (by Definition), which is a triplet.
By definition,  $\langle y_4\rangle=y_4=\langle x_1, x_2, x_3, x_4\rangle$. Hence $\langle x_1, x_2, x_3, x_4\rangle=\langle y_4 \rangle$, which is a one tuple.
 Is this ans correct?