Tangent of a circle through a point not on circle Given the equation of a circle: $(x+4)^2+(y-2)^2 = 1$ find the tangent that goes through the point $(-3,3)$&hellip;


&hellip;but this point IS NOT on this circle. Unfortunately, this is not something that I have seen before and the normal formula doesn't work.

Thank you
A little graphing won't hurt:

By inspection, the tangent lines are $x=-3$ and $y=3$.
You should have a system of equation the first is the circle and the second is the general equation for a line that pass from $(3,3)$ substitute one into the others and apply the tangent condition $b^2-4ac=0$ you will find the two points. Another methods is using the derivation.