quadratic residues and prime divisor Prove that exist a many infinitely positive integers $n$  such that $n^2+1$ have a prime divisor greater than $2n + \sqrt{2n}$.

I was trying to solve but without interesting advances. 

Any idea would be appreciated. Thanks in advance!
We know that there are infinitely many numbers n  such that n^2+1 is prime. And it is easy to prove that 2n+(2n)^0.5 &lt; n^2+1.
We know that there are infinitely many numbers n  such that n^2+1 is prime. And it is easy to prove that 2n+(2n)^0.5 &lt; n^2+1.