Simple Calculus Function I am doing a course in calculus and I was given this problem :

Given that $f(x)=3x^4−6x^3+4x^2−7x+3$, evaluate $f(−2)$.

The answer is meant to be 129 according to the tutor, but no matter how many times I try and work it out I can't see how they got that answer.
Observe the magic of color:$$f(\color{#C00}{x}) = 3\color{#C00}{x}^4 - 6\color{#C00}{x}^3  + 4\color{#C00}{x}^2 - 7\color{#C00}{x} + 3$$Now, we essentially have to replace our colored expressions with numbers.$$f(-2) = 3(-2)^4 - 6(-2)^3 + 4(-2)^3 - 7(-2) + 3$$Now use the order of operations to simplify. For example, $3(-2)^4 = 3\times(-2)^4 = 3\times16 = {48}$.
Horner's method?
$$3 + x \cdot ( -7 + x \cdot (4 + x \cdot (-6 + 3\cdot x)))=$$
$$=3 + (-2 )\cdot ( -7 + (-2) \cdot (4 + (-2) \cdot (-12)))=$$
$$=3 + (-2) \cdot ( -7 + (-2) \cdot (4 + 24))=$$
$$=3 + (-2) \cdot ( -7 + (-2) \cdot 28)=$$
$$=3 + (-2) \cdot ( -7 - 56)=$$
$$=3 + (-2) \cdot (-63)=$$
$$=129$$