Total number of outcomes for flipping 2 coins 4 times? I just wanted to make sure I understand this correctly.

Total number of outcomes for $2$ coins on $1$ flip is $2^2 = 4$.
Therefore, would flipping the $2$ coins $4$ times have $4^4 = 256$ possible outcomes?

The equation for the exponent. The base represents the total outcomes and the exponent is the total number of flips or number of coins?
let's mark $ L_i - $ the number of possibility's for one turn (flipping)
we see that for any $i \neq j$ the event $L_i \ and \ L_j$ are independence and there for the total outcome for n turn is $\Pi_{i=1}^{n} L_i $ and because $L_i = 4 $ for every i:

(h - h , h - t , t -h , t - t)
then the total outcomes number is $4^n$
let's mark $ L_i - $ the number of possibility's for one turn (flipping)
we see that for any $i \neq j$ the event $L_i \ and \ L_j$ are independence and there for the total outcome for n turn is $\Pi_{i=1}^{n} L_i $ and because $L_i = 4 $ for every i:

(h - h , h - t , t -h , t - t)
then the total outcomes number is $4^n$