Given a die, what is the probability that the second roll of a die will be less than the first roll? If you are given a die and asked to roll it twice. What is the probability that the value of the second roll will be less than the value of the first roll?
There are various ways to answer this.  Here is one:

There is clearly a $1$ out of $6$ chance that the two rolls will be the same, hence a $5$ out of $6$ chance that they will be different.  Further, the chance that the first roll is greater than the second must be equal to the chance that the second roll is greater than the first (e.g. switch the two dice!), so both chances must be $2.5$ out of $6$ or $5$ out of $12$.
Let's look at it: $$&lt;6: 1, 2, 3, 4, 5$$$$&lt;5: 1, 2, 3, 4$$$$&lt;4: 1, 2, 3$$$$&lt;3: 1, 2$$$$&lt;2: 1$$$$&lt;1:$$ From there, there are $15$ possibilities and there are $36$ outcomes of any two numbers on a $6$-sided die rolled (one after the other), which simplifies to $5\over 12$.