Calculate: $\int 3^{3^{3^{x}}}3^{3^{x}}3^{x} dx$ How to calculate following integration?

$$\int \left(3^{3^{3^{x}}}3^{3^{x}}3^{x}\right)\ dx$$
Substituting $u=3^x, du=\ln 3\cdot 3^x dx$, we get

$$\frac{1}{\ln 3}\int 3^{3^u}3^u du$$

If you keep doing this, can you see how to finish?
in the given problem,
all u need to do is
Substitute $t=3^{3^x}$
then you will get ur answer