Evaluating $\frac{(1+i)^{n+2}}{(1-i)^n}$ Evaluate $\dfrac{(1+i)^{n+2}}{(1-i)^n}$

I think that the meaning is that it need to be simplified.
Thanks
$$\dfrac{(1+i)^{n+2}}{(1-i)^n}=\frac{2i(1+i)^n}{(1-i)^n}=2i\frac{(1+i)^n}{(1-i)^n}=2i(-i)^{-n}=2ie^{\frac{1}{2}\pi in}$$
This simplifies to $2 i^{n+1}$.