b"\n_START_ARTICLE_\nLogaritmas\n_START_SECTION_\nVeiksmai su logaritmais\n_START_PARAGRAPH_\nLogaritm\xc5\xb3 sud\xc4\x97ties pakeitimas sandauga_NEWLINE_log_b(x)+log_b(y) yra lygus log_b(xy)_NEWLINE_Pavyzd\xc5\xbeiui: log_2(4)+log_2(8)=log_2(4*8)=log_2(32)=5_NEWLINE_\xc4\xaerodymas: log_2(4)=2,o log_2(8)=3, taigi 2+3=5.;_NEWLINE_Logaritm\xc5\xb3 atimties pakeitimas dalyba_NEWLINE_Logaritm\xc5\xb3 atimtis yra prie\xc5\xa1ingas veiksmas sud\xc4\x97\xc4\x8diai, tod\xc4\x97l pologaritminius rei\xc5\xa1kinius (pa\xc5\xbeym\xc4\x97ta raide 'X') reik\xc4\x97s dalinti._NEWLINE_Pavyzd\xc5\xbeiui: log_2(8)-log_2(4). \xc5\xa0is rei\xc5\xa1kinys bus lygus log_2(8/4), taigi jis lygus log_2(2)=1._NEWLINE_\xc4\xaerodymas: 3-2=1._NEWLINE_Pastaba: logaritmo pagrindas (pa\xc5\xbeym\xc4\x97ta raide b) turi b\xc5\xabti didesnis u\xc5\xbe nul\xc4\xaf ir nelygus 1, o pologaritminis rei\xc5\xa1kinys (X) didesnis u\xc5\xbe 0.\n_START_SECTION_\nLogaritm\xc5\xb3 savyb\xc4\x97s\n_START_PARAGRAPH_\na^{log_ab}=b_NEWLINE_log_{10}a=lga_NEWLINE_log_ea=lna_NEWLINE_ln1=0_NEWLINE_log_a1=0_NEWLINE_log_aa=1_NEWLINE_log_a(x \\cdot y)=log_ax+log_ay_NEWLINE_log_a \\Big(\\frac {x} {y}\\Big)=log_ax-log_ay_NEWLINE_log_a(x^k)=k \\cdot log_ax_NEWLINE_log_ax= \\frac {log_cx} {log_ca}\xc2\xa0\xe2\x80\x93 pagrind\xc5\xb3 keitimo formul\xc4\x97._NEWLINE_log_{a^n}x^n=log_ax_NEWLINE_log_{a^n}x= \\frac {1} {n} log_ax_NEWLINE_log_{a^n} {x^m}= \\frac {m} {n} log_ax"