Got it ! Missed out on the Amazon . Walmart wouldn ' t ship to me in Hawaii . GameStop worked . Now . I kinda have buyers remorse but I know this is a great deal . <| sep |> I ' m going to interpret that as , I ' m bad at math because people give me shitty explanations like this . Whether or not that ' s what you meant . I wasn ' t sure you were looking for a good explanation before , so I was snarky . It sounds like you might like a good explanation now , thoughSay we flip a coin , we could write the potential outcomes in a table like this Hheads , Ttails H T Now say we flip a coin and role a 6 sided die numbered 16 . The potential outcomes would be H 1 H 2 H 3 H 4 H 5 H 6 T 1 T 2 T 3 T 4 T 5 T 6 So you can see that for each side of the coin 2 , it ' s possible to have each side of the die 6 come up . For a total of 2 6 12 possible outcomes . If we then added the spin of a roulette wheel to the mix call it 38 possible outcomes , then for each possible outcome above , any one of the 38 numbers on the roulette wheel could come up . For a total of 12 38 456 possible outcomes . Hopefully you ' re starting to see why we multiply to figure out the total number of possible outcomes . From there , if we know all outcomes are equally likely , we just go 1 over the number of possible outcomes . This is just like with the coin in the first place there are two possible outcomes , and we know they both come up equally frequently , so one out of two 12 50 %. After that , things start to get a little more complicated . Like what if our coin was weighted and came up heads 80 % of the time ? Well , 80 % 45 . We could do something very similar to our table . This time we ' ll picture our coin as a spinner with 4 Hs and one T . We ' ll do this because the spinner and the coin are probabilistically identical . They ' ll both give you an H four out of five times H 1 H 2 H 3 H 4 T Now let ' s bring back our 6 sided die . I ' ll let , eg , H 1 denote the first ' H ' on the spinner . Here ' s the possible outcomes we could have H 1 1 H 1 2 H 1 3 H 1 4 H 1 5 H 1 6 H 2 1 H 2 2 H 2 3 H 2 4 H 2 5 H 2 6 H 3 1 H 3 2 H 3 3 H 3 4 H 3 5 H 3 6 H 4 1 H 4 2 H 4 3 H 4 4 H 4 5 H 4 6 T 1 T 2 T 3 T 4 T 5 T 6 Anyways , if you count up the outcomes in our table , you ' ll see that there ' s 30 possible outcomes . And if you count the number of times , eg , any H comes with a 6 , you ' ll see four such outcomes . Again , since our spinner is fair , and our die is fair , and the two events are not related spinning the spinner does not affect how the die rolls , we know that all events are equally likely to occur . So four times out of thirty 430 215 13 . 3 repeating percent of the time you ' ll spin a heads and roll a 6 . At the same time , the probability of heads is 45 , and the probability of a 6 is 16 . And 45 16 430 . It turns out that multiplication is the right thing to do because for every event we add , we have to a turn the event into something fair like a spinner , just like we did the coin , and b repeat the entire table once for each outcome on the spinner and if we do something for each of something else , that ' s exactly the word problem that multiplication describes . So , it turns out that the probability of a and b happening , assuming one does not affect the other , is equal the the probability a happening times the probability of b happening . Now , finally , if the first event does affect the second event you ' d have a situation like , back to a fair 12 coin . But when the coin lands on heads , it magically changes your 6 sided die so that there are five 6 s and one 1 . Then your outcomes would be H 1 H 61 H 62 H 63 H 64 H 65 T 1 T 2 T 3 T 4 T 5 T 6 Now , we can see that the probability of flipping heads and rolling a 6 512 56 12 , just like everything we ' ve been doing . So it ' s still just multiplication . The only new trick is knowing how the first event affects the second event . Hopefully this is a slightly less shitty answer than because you multiply .