Yea , but that ' s every CoD . If you can deal with playing TDM or Dom it seems ok , <| sep |> NIIIIICEEEEEE Welcome to the 5 base club ! !!<| sep |> I think I ' m more impressed with his hair . <| sep |> Hey there ! Wanna play some roguelikes if you know what I mean ? <| sep |> 311 Tiny Bee , Betelgeuse , and Rhompia . Ummm . yay ? <| sep |> So in this case the density of gold and lead don ' t matter that much the real factor is the differences in atomic weight between lead and gold a difference of 10 . 24 atomic mass units per atom . So to go from lead to gold for every atom transferred 10 . 24 amus will be left over on average . Now if this mass is converted to energy energy then Emc 2 comes into effect . With a amu being equal to 1 . 6606 e 27 kg our 10 . 24 amuatom is 1 . 7 e 26 kg multiplying that by c 2 gets 1 . 53 e 9 Jatom . Now then a teaspoon is 4 . 929 milliliters according to Google which is then 4 . 929 cm 3 . Which according to our density means that we have 55 . 99 g of lead in a teaspoon . From here we need to know how many atoms are in our lump of lead . Avogadro ' s number is the number of atoms in one mole of anything and one mole is equal to a substance ' s atomic mass in grams so dividing 55 . 99 g by 207 . 2 g the atomic mass of lead gives 0 . 27 mol of lead which ends up being 1 . 63 e 23 atoms of lead . This means that if all the leftover particles from going from a teaspoon of lead to a teaspoon of gold are converted to energy one would have 2 . 49 e 14 J of energy which is 249 terajoules . All of this assumes that breaking the nuclear binding energy holding the lead atoms together is ignored . If it isn ' t then at that point the specific isotopes of lead start to matter in the math .