The annoying thing is it ' s not my local surgery that prescribed it , it ' s our inhouse work doctor who is only around every few weeks . I ' ll try to find out the number for his regular surgery though . Thanks for replying ! <| sep |> Isn ' t this already kinda possible ? afaik Janna always faces the direction the whirlwind will go the moment she casts it . It could be interesting if it would be more obvious for the team , but that would be a buff in tense situations , where it normally is harder to communicate . And i don ' t think Janna needs a buff . She already has a way to high winrate for her pickrate . So something else would have to be nerfed in her kit for this change . <| sep |> For 50 % duty cycle R 2 the resistor between pin 6 and 7 should be very large in relation to R 1 , and th will always be a bit higher than tl . So you ' re better off using 50 % duty cycle alternate configuration , where you place only one resistor between pin 6 and the output at pin 3 , and disconnect pin 7 . Like this . Said that , the formulas you ' re using look right 0 . 693 the constant is rounded but close enough , so it ' s a matter of solving a linear equation system . You can do that using substitution easily . tl 0 . 7 R 2 C 1 solving that for R 2 gives R 2 tl C 1 0 . 7 2 1 e 6 0 . 7 2 . 857 e 6 And using that on the th equation you get th 0 . 7 R 1 R 2 C 1 R 1 th C 1 0 . 7 R 2 2 1 e 6 0 . 7 2 . 857 e 6 0 Notice what I said earlier for 50 % duty cycle , once th and tl are the same things go weird . But if you use 2 . 1 s instead of 2 s for the th because remember that you need th tl as duty cycle cannot go below or equal to 50 % in this configuration . Then , things go better R 1 2 . 1 1 e 6 0 . 7 2 . 857 e 6 143 e 3 So can you can use 3 x 1 Meg in series for R 2 and a 144 k ohm resistor for R 1 . Btw , if you allow for larger C 1 the resistor values can be smaller .