Kids never listen . <| sep |> Overhyped I think . I picked Scharenberg to fall still thought he ' d be drafted though . Just nothing elite about him , you need something that makes you stand out a bit . <| sep |> If you don ' t like using Ableton I ' d suggest experimenting with other DAWs to see what sticks . <| sep |> Even if it did , was your intention to let each copy cascade one more time than the last ? Unfortunately , all the storm copies are created from the original card , so you ' d end up with 2 n 1 Cascade triggers where n is the number of spells cast before it . Luckily , we can preserve that with a bit of math . So with no spells cast before it , you ' d get 1 cascade trigger . With one spell you ' d get one copy that has Cascade , Cascade in addition to the original , so 3 triggers . With two , 6 , with three , 10 , so on . Each element An of the sequence is equal to the previous element An 1 plus its own index n plus one . So An An 1 n 1 . We can express that as the sum of all k 1 for k ranging from 0 to n n An k 1 k 0 This , again , can be simplified to remove the sum sign . The sum is equal to its first element plus the last element divided by 2 times the amount of elements , soAn n 11 n 12 Simplify a bit and you getAn n 2 2 2 n 1 So , you could simply write on it Maelstrom Rupture has n 2 2 2 n 1 instances of Cascade , where n is the number of spells cast before it . Easy , right ? Or use union and make it Cascade Storm triangular numbers . When you cast this spell , exile cards from the top of your library until you exile a nonland card that costs less . You may cast it without paying its mana cost . Put the exiled cards on the bottom in a random order . Then determine the Xth triangular number , where X is equal to the number of spells cast before it this turn . Repeat this process that often . The triangular numbers are 1 , 3 , 6 , and so on .