Yea . I ' ll definitely try out the current shunt with a resistor . I ' ll be experimenting with a short strip first . I think the shortest section is three leds so the current shouldn ' t be high and I should get an idea of what to expect . I definitely won ' t be using my current multimeter UniT DT 830 D as it is an unfused input on the 10 A . My calculations are based off info I found online about the max power of a 5630 LED . Most strips pull much lower currents but I wanted to know what the worse case scenario would be . Better to be safe than sorry . So based on my understanding of using the voltmeter with a current shunt 1 ohm resistor I should be having a 12 . 5 V reading voltage drop across the resistor with a max 12 . 5 amps . Even with a 5 times spike that is still 62 . 5 V and way below onetenth of the CAT III rating of the UT 61 E . I ' m basing my research on this currentchpt 8 ammeterdesignThe UniT UT 61 E voltage inputs are rated CATIII 1000 V and CAT IV 600 V but I obviously do not trust that . The problem for me is the CAT rating system is a little confusing for me in this scenario . It seems that CAT II is for single phase power which is probably home AC mains ? Do measuring the DC current between the 12 V DC adaptor and the LED strip then count as just CAT I ? I also can ' t find info regarding current , it always mentions voltages . But isn ' t current the more dangerous element here ? Or is the CAT rating system only for voltages . I ' ve been reading the Fluke documentationdmm 0518 d m m c a m p a i g n d m m f l u k e d m m chfrfilessafetyguidelines . pdf .