Oh , I meant that as in , personally I wouldn ' t have run the two polls simultaneously . Sorry if I wasn ' t too clear ! But having revisted this thought , now I think it ' ll work out just fine . Cheers . <| sep |> Toate commentariile ar trebui s aib un 99 n 3 XG 1 kBE linkuit la videoul sta . <| sep |> Actually , the overall probabilities would be the same in either case . knowledge of the previous result doesn ' t change the overall probability , but does give you insight to where you are on the probability tree . For instance , David is 2 nd to draw in a group of 6 . In both scenarios , there is a 16 chance that The person who drew first Jessica drew the odd rock , which means there is 0 % chance of him going home . There is also a 56 chance that Jessica didn ' t draw the odd rock , which means David has a 15 chance of drawing it . Multiply the fractions together and you will get the 16 probability number that everyone would have if you worked it out . However , knowing who draws what rock when it happens lets you in on where the probability tree is currently . So , when David is to draw , we would know there is no chance of him going home , because Jess already picked the odd rock . But that doesn ' t change the fact that everyone had an equal overall probability of occurring .