Living in California , I can tell you that fires just happen all the time , other times they ' re started through simple carelessness . I ' m not saying it ' s not deliberate , just I think the null hypothesis here is unplanned wildfires . <| sep |> Dougal is the archetypal eejit . They ' re on a camping trip so there ' s cows outside and that ' s all the context you ' re given . <| sep |> cool kid indeed <| sep |> So as someone with very poor chemistry knowledge , this means that even strong stomach acid will not dissolve those amino acids and molecules ? <| sep |> I ' m actually going to crunch some numbers on this . Assumption All fuel cell power is going to the ion engine . The probe ' s electricity comes from magic and sunshine and flowers and mostly the sunshine part . Math Biprop use The large fuel cell consumes 0 . 225 kgs of biprop to generate 18 ECs of electricity , which can be linearly scaled down to the 8 . 74 ECs that the ion engine uses , resulting in 0 . 10925 kgs of biprop use to power the ion engine . Xenon use The ion engine uses 0 . 0485 kgs of xenon . Total fuelpropellant use 0 . 10925 0 . 0485 kgs for a total of 0 . 15775 kgs consumption , which is 3 . 25 x higher than a solar electric engine . Dividing the Isp of 4200 by our ratio of 3 . 25 results in an effective Isp of 1291 . This is better than nuclear engines for a far lower mass investment . This method doesn ' t take into account increased or decreased xenon or fuel consumption due to passive power generation solar or nuclear or consumption probe cores , or any other power usages . Also , the approximate ratio you ' re going to want for this is 0 . 0203 units of liquid fuel and 0 . 0248 units of oxidizer per unit of xenon . This seems small , but unit for unit biprop is 50 x heavier than xenon gas .