Utterly boring until I saw you . now its time to stroke <| sep |> 12 hours later and nothing on our store currently after 9 am where I am in EuropeAt this point I ' m assuming we aren ' t getting a sale , unless something appears in the next hour or two as WG ' S France office get to work <| sep |> Ok , for the second problem you have to calculate xt respect the school . This isxt x 0 integral from 0 to t of vt dt . Here , x 0 is 50 the distance to the school , negative since we are at the left and the velocity is 11 . 11 2 t . Then we havext 50 integral from 0 to t of 11 . 11 2 t 50 11 . 11 t t 2 . For the third problem we have to find the time at which the car arrives to the school x 0 , since we are measuring the distance respect the school . That is xt 0 50 11 . 11 t t 2 0 I don ' t have a calculator here , but you can solve this equation by using the quadratic formula . This should give you two times , one positive and one negative . If you substitute the positive time in the expression vt second problem you will find the velocity when it crosses the school .