How do you write an equation in point slope form given (5,-4), (1/2, -1/4)?
Algebra Forms of Linear Equations Linear Equations in Point-Slope Form
Binayaka C.
The equation of the line in slope-intercept form is #y= -5/6x + 1/6.#
The slope of the line passing through #(5,-4) and (1/2,-1/4)# is #m= (y_2-y_1)/(x_2-x_1)= (-1/4+4)/(1/2-5)=(15/4)/(-9/2) =-5/6#
Let the equation of the line in slope-intercept form be #y=mx+c or y=-5/6x+c# The point (5,-4) will satisfy the equation . So, # -4= -5/6*5+c or c= 25/6-4= 1/6 #
Hence the equation of the line in slope-intercept form is #y= -5/6x + 1/6.# graph{-5/6x+1/6 [-10, 10, -5, 5]}[Ans]
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