Provide the ranking criteria and scores in 2005 that were received by Harvard University.
Harvard University refers to university_name = 'Harvard University'; in 2005 refers to year = 2005; ranking criteria refers to criteria_name;
SELECT T1.criteria_name, T2.score FROM ranking_criteria AS T1 INNER JOIN university_ranking_year AS T2 ON T1.id = T2.ranking_criteria_id INNER JOIN university AS T3 ON T3.id = T2.university_id WHERE T3.university_name = 'Harvard University' AND T2.year = 2005