Calculate the percentage of inspections with verified quality. Among them, how many businesses were from Chicago?
verified quality refers to results like 'Pass%'; from Chicago refers to city = 'CHICAGO'; percentage = divide(count(inspection_id where results like 'Pass%'), sum(inspection_id)) * 100%
SELECT CAST(COUNT(CASE WHEN T2.results LIKE '%Pass%' THEN T2.inspection_id END) AS REAL) * 100 / COUNT(T2.inspection_id), COUNT(DISTINCT T2.license_no) FROM establishment AS T1 INNER JOIN inspection AS T2 ON T1.license_no = T2.license_no WHERE T1.city = 'CHICAGO'