List the restaurant's ID that has a review greater than the 70% of average review of all American restaurants with street number greater than 2000.
American restaurant refers to food_type = 'american'; street number greater than 2000 refers to street_num > 2000; review greater than the 70% of average review refers to review > multiply(avg(review), 0.7)
SELECT T1.id_restaurant FROM location AS T1 INNER JOIN generalinfo AS T2 ON T1.id_restaurant = T2.id_restaurant WHERE T2.food_type = 'american' AND T1.street_num > 2000 GROUP BY T1.id_restaurant ORDER BY AVG(T2.review) * 0.7 DESC