Does Yelp business No."4960" have TV?
business No. refers to business_id; have TV refers to attribute_name = 'Has TV';
SELECT DISTINCT CASE WHEN T1.attribute_name LIKE 'Has TV' THEN 'yes' ELSE 'no' END FROM Attributes AS T1 INNER JOIN Business_Attributes AS T2 ON T1.attribute_id = T2.attribute_id WHERE T2.business_id = 4960