List the income and number of inhabitants of customers with an age greater than the 80% of average age of all customers?
age greater than the 80% of average age refers to age > (AVG(age) * 0.8); income refers to INCOME_K; number of inhabitants refers to INHABITANTS_K;
SELECT T2.INCOME_K, T2.INHABITANTS_K FROM Customers AS T1 INNER JOIN Demog AS T2 ON T1.GEOID = T2.GEOID GROUP BY T2.INCOME_K, T2.INHABITANTS_K HAVING T1.age > 0.8 * AVG(T1.age)