Among all the users who received the high number of compliments, what percent received the 'cute' type of compliment.
high number of compliments refers to number_of_compliments = 'High'; percentage = divide(count(user_id where compliment_type = 'cute'), count(user_id))*100%
SELECT CAST(SUM(CASE WHEN T1.compliment_type = 'cute' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(T2.user_id) FROM Compliments AS T1 INNER JOIN Users_Compliments AS T2 ON T1.compliment_id = T2.compliment_id WHERE T2.number_of_compliments = 'High'