Provide any 5 customers' full names who have rented from Mike Hillyer.
full name refers to first_name, last_name; 'Mike Hillyer' is a full name of a staff;
SELECT T3.first_name, T3.last_name FROM staff AS T1 INNER JOIN address AS T2 ON T1.address_id = T2.address_id INNER JOIN customer AS T3 ON T2.address_id = T3.address_id WHERE T1.first_name = 'Mike' AND T1.last_name = 'Hillyer' LIMIT 5