How many "cute" type of compliments does user No. 57400 get?
type of compliments refers to compliment_type; user No. refers to user_id;
SELECT COUNT(T1.compliment_type) FROM Compliments AS T1 INNER JOIN Users_Compliments AS T2 ON T1.compliment_id = T2.compliment_id WHERE T1.compliment_type LIKE 'cute' AND T2.user_id = 57400