Find the winning rate of award in 2010. Describe the winner name, award name, episode title and role of the winner in that episode.
in 2010 refers to year = 2010; winning rate refers to DIVIDE(COUNT(result = 'winner'), COUNT(*));
SELECT T3.rate, T4.person, T4.award, T5.title, T4.role FROM ( SELECT CAST(SUM(CASE WHEN T1.result = 'Winner' THEN 1 ELSE 0 END) AS REAL) / SUM(CASE WHEN T1.result IN ('Winner', 'Nominee') THEN 1 ELSE 0 END) AS rate , T1.person, T1.award, T2.title, T1.role FROM Award AS T1 INNER JOIN Episode AS T2 ON T1.episode_id = T2.episode_id WHERE SUBSTR(T1.year, 1, 4) = '2010' ) AS T3 INNER JOIN Award AS T4 INNER JOIN Episode AS T5 ON T4.episode_id = T5.episode_id WHERE T4.year = 2010 AND T4.result = 'Winner';