Which establishment has the highest number of inspections done? Give the name of the establishment and calculate for its average score per inspection.
establishment refers to business_id; the highest number of inspections refers to MAX(COUNT(business_id)); avg(score);
SELECT T2.name, AVG(T1.score) FROM inspections AS T1 INNER JOIN businesses AS T2 ON T1.business_id = T2.business_id GROUP BY T2.name ORDER BY COUNT(T2.business_id) DESC LIMIT 1