How do I to prove that Sec 8θ - 1 / Sec 8θ - 1 = Tan 8θ/ Tan 2θ?
How can you prove that: (Sec 8A-1) / (sec 4A - 1) = Tan 8A/Tan 2A?
איך אני מוכיח ש-Sec 8θ - 1 / Sec 8θ - 1 = Tan 8θ/ Tan 2θ?
איך אתה יכול להוכיח ש: (Sec 8A-1) / (Sec 4A - 1) = Tan 8A/Tan 2A?