An aquarium holds an equal number of clownfish and blowfish. 26 of the blowfish stay in their own tank, and the remaining blowfish swim into a display tank.  An equal number of clownfish join the blowfish in the display tank, but then a third of these clownfish swim back into their own tank.  If the aquarium holds a combined total of 100 fish, how many clownfish are now in the display tank?
There is an equal number of clownfish and blowfish, which means there are 100 fish / 2 = <T>divide(100, 2)=50.0 blowfish.
Since some stay in their tanks, there are 50 blowfish – 26 blowfish = <T>subtract(50, 26)=24 blowfish in the display tank.
There were the same amount of clownfish until 24 clownfish / 3 = <T>divide(24, 3)=8.0 clownfish swam back to their own tank.
This leaves 24 clownfish – 8 clownfish = <T>subtract(24, 8)=16 clownfish in the display tank.
