In eight years, Mr. Bernard will be 3 times as old as Luke is now. If Luke is 20, what is 10 years less than their average age?
If Luke is 20, he will be 20+8 = <T>add(20, 8)=28 years old in eight years.
In eight years, Mr. Bernard will be 3 times as old as Luke is now, a total of 3*20= <T>multiply(3, 20)=60 years old.
Mr. Bernard is now 60-8= <T>subtract(60, 8)=52 years old
The sum of their current ages is 52+20 = <T>add(52, 20)=72
Their average age is 72/2 =<T>divide(72, 2)=36.0
10 less than their average age is 36-10 = <T>subtract(36, 10)=26 years.
