Napoleon has 17 jelly beans and Sedrich has 4 more jelly beans than Napoleon. If twice the sum of Napoleon and Sedrich's jelly beans is 4 times the number of jelly beans that Mikey has, how many jelly beans does Mikey have?
Sedrich has 17 + 4 = <T>add(17, 4)=21 jelly beans.
The sum of Napoleon and Sedrich's jelly beans is 17 + 21 = <T>add(17, 21)=38 jelly beans.
Twice the sum is 38 x 2 = <T>multiply(38, 2)=76 jelly beans.
Mikey has 76/4 = <T>divide(76, 4)=19.0 jelly beans.
