A company has a tank that is already filled at a maximum capacity of 350,000 gallons of water. One day the tank starts losing 32,000 gallons/hour for 5 hours, after that time the company repaired the tank but it wasn't enough because the tank was still losing 10,000 gallons/hour. It stayed like that for 10 hours. In the second attempt, they managed to repair the tank and started filling it with 40,000 gallons/hour. After 3 hours, how many gallons are missing for the tank to be at maximum capacity again?
In the first 5 hours the tank losses 32000 gallons/hour x 5 hours = <T>multiply(32000, 5)=160000 gallons
In the next 10 hours the tank losses 10,000 gallons/hour x 10 hours = <T>multiply(10000, 10)=100000 gallons
The total amount of water loss so far is 100000+160000 = <T>add(100000, 160000)=260000 gallons
The total amount of water remaining in the tank is 350000-260000 = <T>subtract(350000, 260000)=90000 gallons.
Once repaired, after 3 hours, the tank gains 40000 gallons/hour x 3 hours = <T>multiply(40000, 3)=120000 gallons
The total amount of water in the tank after the tank is filled for 3 hours is 120000+90000 = <T>add(120000, 90000)=210000 gallons.
The amount of water missing in the tank for it to be full is 350000-210000 = <T>subtract(350000, 210000)=140000 gallons
