A coach placed 15 tennis balls and 5 soccer balls each into 5 baskets. He gave 5 of his students a short period of time to remove as many balls each from a basket as they could. 3 of them removed 8 balls each and the other 2 removed a certain number of balls each. If a total of 56 balls are still in the baskets, how many balls did the other 2 students each remove?
Combining the tennis and soccer balls, there are 15+5=<T>add(15, 5)=20 balls in each basket
There are 5 baskets, hence 5*20=<T>multiply(5, 20)=100 balls in total
3 students removed 8 balls each, they removed 3*8=<T>multiply(3, 8)=24 balls
From the total number of balls, they left 100-24=<T>subtract(100, 24)=76 balls
There are 56 balls left so the other 2 students must have removed a total of 76-56=20 balls
This means that each of these 2 students removed 20/2=<T>divide(20, 2)=10.0 balls.
