Mandy has three $20 bills while Manny has two $50 bills. If both of them decide to exchange their bills for $10 bills, how many more $10 bills than Mandy will Manny have?
Mandy has a total of $20 x 3 = $<T>multiply(20, 3)=60
So, she will have $60/$10 = <T>divide(60, 10)=6.0 $10 bills.
Manny has a total of $50 x 2 = $<T>multiply(50, 2)=100
So, he will have $100/$10 = <T>divide(100, 10)=10.0 $10 bills.
Hence, Manny has 10 - 6 = <T>subtract(10, 6)=4 more $10 bills than Mandy.
