৫ মিটার ব্যাসার্ধের একটি বৃত্তাকার পথে পরিধির এক-চতুর্থাংশ অতিক্রম করলে সরণ কত মিটার হবে?
To solve this problem, let's analyze it step-by-step:

Step-1: The radius (r) is given as 5 meter. We know the circumference is C = 2*π*r

Step-2: Total distance covered by travelling ¼ if the circumference is (1/4)*(2*π*5) = 5π/2 ≈ 7.85 meter s

Step-3: But we have to find the displacement between the starting point and the ending point.

Step 4: Travelling ¼ of the circumference creates θ = s/r => θ = (5π/2)/5 => θ = π/2 radian which is actually 90 degree.

Step 5: So the shortest path creates a right triangle with two of radii. We can find the shortest path between starting and ending points (Which is actually the hypotenuse of the right triangle) using the Pythagoras law.

Step-6: Now the displacement  (shortest distance between two points) is sqrt(r^2 + r^2) = sqrt(5^2 + 5^2) = sqrt(50) ≈ 7.07 meters

#Answer: 7.07 meters