একটি মোটরসাইকেলের বেগ ৩০ মি/ সে। থেকে সুষমভাবে হ্রাস পেয়ে ৮ সে. এ ১৪ মি./সে. হলে গাড়িটির মন্দন কত মি./সে.^২?
To solve this problem, let's analyze it step-by-step:

Step-1: we know, acceleration a = dv/dt, where dv = change in velocity, dt = time over which the change occurs

Step-2: So, The initial velocity 30 meters per second.

Step-3: The final velocity is 14 meter per second.

Step-4:  So change in velocity,dv is = (14-30) meter per second = -16 meters per second.

Step-5: Given time period dt = 8 second. So a = dv/dt = -16/8 = -2 meter per second square

#Answer: 2 meter per second square