Find the limit using L'Hopital's rule? Find $$\lim _{x\to 0}\frac{1-\cos x}{x+x^2}$$
Give your answer as an exact number.
So I did this and got .5 as my answer. What does it mean by "exact number"? .5 was not a correct answer so I am stuck, help? thanks! 

You know by L'Hopital: 
$$
\lim_{x\to 0}\frac{1-\cos(x)}{x+x^2} = \lim_{x\to 0}\frac{\sin(x)}{1+2x}
$$
And what is the limit of $\sin(x)$ for $x \to 0$ ? 
