Number of winning tern in a deck of cards and other 3 related questions There is a deck made of $81$ different card. On each card there are $4$ seeds and each seeds can have $3$ different colors, hence generating the $ 3\cdot3\cdot3\cdot3 = 81 $ card in the deck.
A tern is a winning one if,for every seed, the correspondent colors on the three card are or all the same or all different.
-1 How many winning tern there are in the deck?
-2 Shows that $4$ cards can have at most one winning tern.
-3 Draw $4$ card from the deck. What is the probability that there is a winning tern?
-4 We want delete $4$ cards from the decks to get rid of as many tern as possible. How we choose the $4$ cards?
I've no official solution for this problem and i don't know where to start.
Rather than a complete solution i would appreciate more some hints to give me the input to start thinking a solution.

For question one, ask a simpler question: Look at just the first seeds, how many ways can you color them?
Two possibilities are: Card 1: Red, Card 2: Red, Card 3: Red
and Card1:Red, Card2: Blue, Card3: Yellow.
Now for four seeds, you make the choice of colors four times.
You should check that you haven't chosen the same card three times - how many ways could you have done that?
