How many non prime factors are in the number $N=2^5 \cdot 3^7 \cdot 9^2 \cdot 11^4 \cdot 13^3$. to find non prime factors in the number
$N=2^5 \cdot 3^7 \cdot 9^2 \cdot 11^4 \cdot 13^3$.
First I tried finding all the factors by adding 1 to each of the exponents and then multiplying them
and then finding the prime factors of the given number
and then subtracting the prime factors from the total factors 
but I'm not getting the answer.
Answer is $1436$.

Write it as $2^5 * 3^{11} * 11^4 * 13^3$. Thus, as you said, adding one to each exponent and multiplying, we get the total number of divisors, which is $6* 12 * 5* 4 = 1440$. Subtracting the four prime factors ($2,3,11,13$) leaves us with 1436.
