Possible number of arrangement. Question:
How many cars are there with number GJ-X-AB-abcd. GJ and A are constant.X is digit between 1 to 9, B is english alphabet and abcd is 4 digit number.(a can be zero)
My Efforts:
It is but natural car's number plate have repetition. 
So, X can be arranged in 9 different ways.
AB can be arranged in 26 different ways. 
abcd can be arranged in $10\times10\times10\times10=10000$ different ways.
So the total number of arrangement is $2340000$. But answer given is $2339766$, which is a little less than the expected.

abcd can be arranged in $10 \times 10 \times 10 \times 10=10000$ different ways, but it also contain 0000, which need to be excluded from total arrangement.
0000 can come $26 \times 9= 234$ times in arrangement.
Therefore, $234$ is to be subtracted from total possible arrangement.
$2340000-234=23393766$
Thank you Gerry Myerson for your help.
