Solving for $x$: $3^x + 3^{x+2} = 5^{2x-1}$ $3^x + 3^{x+2} = 5^{2x-1}$
Pretty lost on this one. I tried to take the natural log of both sides but did not get the result that I desire. 
I have the answer but I would like to be pointed in the right direction. Appreciated if you can give me some hints to this question, thanks!

Just take $$3^x$$ as common factor on right side then
$$3^x(1+3^2)=5^{2x-1}\Rightarrow  ln({3^x(1+3^2)}) = ln(5^{2x-1})\Rightarrow xln(3) + ln(10) = (2x-1)ln(5)\Rightarrow ln(10)+ln(5)=2xln(5)-xln(3)\Rightarrow x=\frac{ln(10)+ln(5)}{2ln(5)-ln(3)}$$
