Big O definition and showing equality On this problem, I'm not sure what Big O definition they are referring. How would the big o definition help show this?
Use the definition of $O$ to show that if $y = y_h + O(h^p)$, then $hy = hy_h + O(h^{p+1})$.

The first statement is saying, taking big O as $x$ approaches some $a$ for some $M>0$
$$
|y-y_h|<M|h^p|\implies \frac{|y-y_h|}{|h^p|}<M
$$
for any $|x-a|<\delta$ for some $\delta>0$.
Now what happens if you multiply the LHS by $\frac{|h|}{|h|}=1$?
