solving an equation of the type: $t \sin (2t)=2$ where $0Need to solve:
How many solutions are there to the equation,
 $t\sin (2t)=2$ where  $0<t<3 \pi$
I am currently studying calc 3 and came across this and realized i dont have a clue as to how to get started on it.

As an alternate approach, you could rewrite the equation as $$\frac{1}{2}\sin{2t}=\frac{1}{t}$$ and then observe that since $\frac{1}{t}\le\frac{1}{2}$ for $t\ge2$,
the graph of $y=\frac{1}{t}$ will intersect the graph of $y=\frac{1}{2}\sin{2t}$
twice in each interval $[n\pi,(n+1)\pi]$ for $n\ge1$.
