What is the sum of the solutions to $6x^3+7x^2-x-2=0$ What is the easy way to solve the problem? 

The sum of the solutions to $6x^3+7x^2-x-2=0$ is:
  $$A) \ \frac{1}{6}$$ $$B) \ \frac{1}{3}$$ $$C) \ \frac{-7}{6}$$ $$D) -2$$ $$E) \text{ none of above}$$


For a cubic equation of the form $ax^3 + bx^2 + cx +d$, the sum of all the roots is given by $\frac{-b}{a}$. Here, $b=7,a=6$ so sum of the roots $= \frac{-7}{6}$.
