Find the numbers in A.P. those sum is $24$ and product is $440$ 
If the sum of three numbers in A.P. is $24$ and their product is $440$, find the numbers.

My Approach: Let the numbers be $a,a+d,a+2d$ 
So, according to question $$3a+3d=24$$ $$a+d=8$$ and $$a(a+d)(a+2d)=440$$ $$8a+ad=55$$ I can’t proceed from here. 
Please help.

Whenever You struggle with such problems, choose such a sequence so that you can get at least the value of first term. Notice that If you will choose an AP such that three terms are $a-b,a,a+b$, on adding them, all the $b's$ will cancel out and You will be left with $a$.
So, $a-b+a+a+b=24\implies 3a=24\implies a=8$. And then You will deal with something like$$(a-b)(a)(a+b)=440\implies (8-b)(b)(8+b)$$
Now, you have a quadratic equation, solve it and get the answer.
