Prove $(1+ \tan{A}\tan{2A})\sin{2A} = \tan{2A}$. Prove the following statement
$$ (1+ \tan{A}\tan{2A})\sin{2A} = \tan{2A}. $$
On the left hand side I have put the value of $\tan{2A}$ and have then taken the LCM.
I got $\sin{2A}\cos{2A}$. How do I proceed?
Thanks

Noting that
$$\cot \theta\tan\theta=1$$
We have
$$(1+\tan A\tan 2A)\sin 2A = (1+\tan A\tan 2A)\sin 2A\cot 2A\tan 2A$$
Now just show that 
$$(1+\tan A\tan 2A)\sin 2A\cot 2A = 1$$
:)
