derivative of $\frac{2}{3}x^{3-e}$ 
Find the derivative:$\;\;\;\;\;\;\dfrac{2}{3}x^{3-e}$  

I am not sure how to solve this problem. My try:  
$\ln y=\dfrac{2}{3}(3-e)\ln x$
$\dfrac{1}{y}\times y\;'=\dfrac{2}{3}(3-e)\dfrac{1}{x}$  
I'm not sure how to proceed from here. The answer is $\dfrac{2}{3}x^{2-e}(e-3)$ and I don't see how to arrive at that answer. 

Let $f\colon\Bbb{R}\to\Bbb{R}$, with $f(x)=\frac{2}{3}x^{3-e}$, then
$$
\frac{\mathrm{d}f}{\mathrm{d}x}=
\frac{2}{3}\frac{\mathrm{d}}{\mathrm{d}x}\Big(x^{3-e}\Big)
=
\frac{2}{3}(3-e)x^{3-e-1}
=
\frac{2(3-e)}{3}x^{2-e}
$$
