Help solving the following inequality $$
\frac{x|x + 1|(x + 2)}{|x - 1|} \ge 0
$$
My idea was to multiply the denominator to $0$ and $| x + 1 |$ to solve it  in two cases  (when is positive and when is negative). No luck

Hint:
$$\frac{x|x + 1|(x + 2)}{|x - 1|} =\underbrace{\frac{|x + 1|}{|x - 1|}}_+.\left(x^2+2x\right)$$
