Partial fractions for inverse laplace transform I have the following function for which I need to find the inverse laplace transform:
$$\frac1{s(s^2+1)^2}$$
Am I correct in saying the partial fraction is:
$$\frac1{s(s^2+1)^2}=\frac{A}{s}+\frac{Bs+C}{s^2+1}+\frac{Ds+E}{(s^2+1)^2}$$

Your guess is correct. The coefficients are...SPOILER ALERT...























$$A=1,$$
$$B=-1,$$
$$C=E=0,$$
$$D=-1.$$
