How do you solve this exponential equation? $3(16)^x+2(81)^x=5(36)^x$
How do you change the bases to combine the terms? The correct answer should be 0 and 0.5.
Edit: So this equation can't be solved algebraically? I have to use creative logic to solve it?

Note that
$$3(16)^x=3(4)^{2x}, 2(81)^x=2(9)^{2x}, \text{and}\; 5(36)^x=5(6)^{2x}$$
If $2x=1$, you get that $12+18=30$, a true statement. Thus, $x=\frac{1}{2}$.
The case where $x=0$ is trivial.
