Question about Bayesian probabilities. Where did I go wrong? I was solving a question for an acquaintance, about probabilties. The original question goes like this:

Of all threats in an year, $12\%$ are Tier 1 and the remaining $88\%$ are Tier 2. If the probability that a reported Tier 1 threat is actually a Tier 2 is $21\%$ and the probability that a reported Tier 2 threat is actually a Tier 1 is $33\%$, then what is the probability that a reported Tier 1 is actually a Tier 1?


Here are my attempts to solve;

Let probability that an event is Tier 1$=P(T_1)=12\%$
Let probability that an event is Tier 2$=P(T_2)=88\%$
Let probability that a reported Tier 1 was actually Tier 2$=P(M_{1\to2})=21\%$
Let probability that a reported Tier 2 was actually Tier 1$=P(M_{2\to1})=33\%$
Let there be $10000$ events.

...

Then,
$\#T_1=1200$
$\#T_2=8800$

...

Let the number of reported Tier 1 events be $O$.
Let the number of reported Tier 2 events be $T$.

...

Then,
Number of actual Tier 1 Events from number of reported Tier 1 events $={{(100-21)}\over100}\times O=O_1$
Number of actual Tier 2 Events from number of reported Tier 1 events $={{21}\over100}\times O=T_1$
Number of actual Tier 1 Events from number of reported Tier 2 events $={{33}\over100}\times T=O_2$
Number of actual Tier 2 Events from number of reported Tier 2 events $={{(100-33)}\over100}\times T=T_2$

...

Since,
Number of Tier 1 threats $=1200$
$O_1+O_2=1200$
So $\left({{(100-21)}\over100}\times O\right)+\left({{33}\over100}\times T\right)=1200$
Since,
Number of Tier 2 threats $=8800$
$T_1+T_2=8800$
So $\left({{21}\over100}\times O\right)+\left({{(100-33)}\over100}\times T\right)=8800$

From here I get two equations in $O$ and $T$,
$\left({{79}\over100}\times O\right)+\left({{33}\over100}\times T\right)=1200$
and
$\left({{21}\over100}\times O\right)+\left({{67}\over100}\times T\right)=8800$
Wolfram|Alpha reports that $O$ is negative.
How is this possible? Where did I go wrong?

The actual question is near the middle here.
The answer should be explainable in a text-only environment.

Assumptions:


*

*All actual threats are reported threats.$\\[4pt]$

*All reported threats are actual threats.


In other words, all actual (assessed) threats are first reported. Also, there are no false alarms. If a threat is reported at any tier level, then it is later assessed as an actual threat at some tier level. 

Let the sample space be the set of pairs $(i,j)$ of reported threats, where $i \in \{1,2\}$ is the tier level reported, and $j \in \{1,2\}$ is the assessed (actual) tier level.

Let $p(i,j)$ be the probability of the event $\{(i,j)\}$.

Let $a=p(1,1),\;b=p(1,2),\;c=p(2,1),\;d=p(2,2)$.

Let $R_i$ be the event that tier level $i$ is reported.

Let $T_j$ be the event that tier level $j$ is assessed.

The goal is to find $P(T_1|R_1) = {\displaystyle{\frac{a}{a+b}}}$.

From the given information we get the following equations
\begin{align*}
P(T_1) &=  a + c = \frac{12}{100}\\[4pt]
P(T_2) &= b+ d  = \frac{88}{100}\\[4pt]
P(T_2|R_1) &= \frac{b}{a+b} = \frac{21}{100}\\[4pt]
P(T_1|R_2) &= \frac{c}{c+d} = \frac{33}{100}\\[4pt]
\end{align*}
After clearing denominators on the last two equations, we have a system of $4$ linear equations in $4$ unknowns, which yields the solutions
$$
a = -\frac{1659}{4600}
,\;\;
b = -\frac{441}{4600}
,\;\;
c = \frac{2211}{4600}
,\;\;
d = \frac{4489}{4600}
$$
If we temporily ignore the obvious issue (negative values of $a,b$), we get
$$P(T1|R1) = \frac{a}{a+b} = \frac{79}{100}$$
but of course, we can't have $a,b < 0$, so unless I made a logical or algebraic error, the problem is wrong.
