Probability Of a 4 sided die A fair $4$-sided die is rolled twice and we assume that all sixteen
possible outcomes are equally likely. Let $X$ and $Y$ be the result of the $1^{\large\text{st}}$ and the
$2^{\large\text{nd}}$ roll, respectively. We wish to determine the conditional probability $P(A|B)$
where
$A = \max(X,Y)=m$
and
$B= \min(X,Y)=2,\quad m\in\{1,2,3,4\}$.
Can somebody first explain me this question and then explain its answer. I'm having trouble in approaching it.

min(X,Y)=2. So 5 outcomes left: (2,2) (2,3) (2,4) (3,2) (4,2)
Q: What values can m take? 