relation betwn ln and e If $f(x) = ln(x)$ and $f^-1(x) = e^x$ then is $e^x = 1/ln(x)$???
because I see $e^9 = 8103$ but $1/ln9 = .455$
How are they reverse? I don't understand!

$f^{-1}$ is the inverse function of $f$. That is,
$$ f(f^{-1}(x)) = x, f^{-1}(f(x)) = x
$$
when this statement makes sense. It is not $\frac{1}{f}$ or anything. The $^{-1}$ is not an exponent.
