How can you find the number of sides on this polygon? I'm currently studying for the SAT.  I've found a question that I can't seem to figure out.
I'm sure there is some logical postulate or assumption that is supposed to be made here.  Here is the exact problem:

I don't really care for an answer, I would rather know steps on how to solve this.  I'm trying to be prepared for all types of questions on the SAT.
Thanks!
EDIT:
Thanks so much for the help guys!  I've figured it out and wanted to explain it in detail for anybody who wanted to know:

 SOLUTION SPOILER:
 1. The figure displayed is a non-regular quadrilateral.
 2. Because we know that, we know that the interior angles of the shape are 360 because of the formula (n-2)180.
 3. I then created two statements.  x+y=80 and x+y+z where z is the top two full angles (above both x and z).
 4. I then simply solved for z (the total of the two angles above x and y).
 5. I found z to equal 280.  When split between the two angles it represented, I determined that each angle in the shape was equal to 140 degrees.
 6. Because each angle is congruent (the shape is regular) we now know the measurement of every angle.
 7. I then plugged this into the interior angle formula: (n-2)180=n140.
 8. After solving for n, you learn that the number of sides is 9 :)

Hope this helps!

Hints: 
The sum of the measures of the interior angles of an $n$-sided convex  polygon is $(n-2)*180^\circ$. So, if the polygon is regular, each interior angle has measure $180^\circ-{360^\circ\over n}$. (You could also use the fact that the sum of the exterior angles of a convex polygon is $360^\circ$. An "exterior angle" is the angle formed by a line coinciding with a side and the "next" side.)
