Stuck on boolean algebra problem Could someone please explain me why
$x.y+x.z+y'.z$
Is equal to
$x.y+y'.z$?
I just can't simplificate it..

$x.y+x.z+y'.z$
$=x.y+x.z.1+y'z$ [as,$a.1=a$]
$=x.y+x.z.(y+y')+y'z$ [as $(a+a')=1$]
$=x.y+x.z.y+x.z.y'+y'z$
$=x.y(1+z)+y'z(x+1)$
$=(x.y+y'z)$ [as $(a+1)=1$]
Hope you got your answer.
