A Teacher wrote either of words $PARALLELOGRAM$ or $PARALLELOPIPED$ A Teacher wrote either of words $PARALLELOGRAM$ or $PARALLELOPIPED$ on board but due to malfunction of marker words are not properly written and only two consecutive letters $RA$ are visible, then the chance that the written word is $PARALLELOGRAM$ is $\frac{p}{q}$, where $p$ and $q$ are co-primes. Prove that $p+q=32$
Could someone help me in understanding the line: "only two consecutive letters $RA$ are visible" ? I can't understand this question properly.

Counting pairs of consecutive positions as $1-2,\;\; 2-3$ etc,
there are $12$ such positions in parallelogram, and $13$ in parallelopiped,
thus P(saw RA) $= 2/12$ in parallelogram and $1/13$  in parallelopiped 
and P(word "parallelogram" | saw $RA) = \dfrac{2/12}{2/12 + 1/13}=$
Continue.... 
