Integrate $\int\frac{5x-7}{x^2-3x+2}$ I want to integrate $\int\frac{5x-7}{x^2-3x+2}$ but my result differs from the one on Wolframalpha http://www.wolframalpha.com/input/?i=integrate+%285x-7%29%2F%28x%5E2-3x%2B2%29
I did the following steps:
$$\frac{5x-7}{(x-2)(x-1)} = \frac{A}{x-2}+\frac{B}{x-1}$$
$$5x-7 = A(x-1)+B(x-2)$$
$$5 = A + B$$
$$-7 = -A-2B$$
$$A=5-B\\
-7= -(5-B)-2B\\
-2 = -B\\
2 = B$$
Therefore $A = 3$ and $B=2$
$$\int\frac{3}{x-2}+\int\frac{2}{x-1}=3\ln(x-2)+2\ln(x-1) + C$$
While on Wolframalpha it is $3\ln(2-x)+2\ln(1-x)$ Where did I do the error?

Neither is quite right. We have $\int \frac{1}{u}\,du=\ln(|u|)+C$. 
