How can I use the sum of squares formula to create blocks of a certain dimension? 
The previous expression was just the sum of consecutive squares so $1^2+2^2+...+n^2 = \frac{n(n+1)(2n+1)}{6}$
I know how to derive this formula but can someone please explain the claim that 
"This expression says that a box with dimensions $n(n+1)(2n+1)$ should contain six copies of $1^2+2^2+...+n^2$"
For a box that has a 4 x 5 x 9 dimension, $n=4$
So I have to construct a video out of individual $1^2+2^2+3^2+4^2$ building units
I have no idea what this means. $1^2+2^2+3^2+4^2 = 30$ cubes in total and  4 x 5 x 9 = 180 unit squares. 
So am I supposed to build this with $1^2$ unit squares and $2^2 = 4$, 2 x 2 squares and $3^2=9$, 3 x 3 squares and $4^2 = 16$ 4 x 4 squares? and if so how can I organize it so that the box has dimensions 4 x 5 x 9?
I don't know how to organize the blocks and I don't know if my interpretation of the problem is correct?
EDIT: He also says that there should be 6 units? That means only six blocks? How is he getting that?
EDIT: stacking blocks
1B
2B 2B 
3B 3B 3B
4B 4B 4B 4B 
4B 4B 4B 4B 
3B 3B 3B 
  2B 2B


     1B 

Then combine so 
1B 4B 4B 4B 4B 
2B 2B 3B 3B 3B 
3B 3B 3B 2B 2B 
4B 4B 4B 4B 1B 

I can make 6 pyramid like structures starting with a base of 4 x 4, then on top 3 x 3, then 2 x 2 then 1 x 1. then I can combine them all. I found this from 
https://ckrao.wordpress.com/2012/03/14/the-sum-of-consecutive-squares-formula/
