How many roots does the equation $z^{2018}=2018^{2018}+i$ have? 
Consider the equation
  $$ z^{2018}=2018^{2018}+i$$ where $i=\sqrt{-1}$.
  How many complex solutions as well as real solutions does this equation have?

My attempt:
I took the polar form as the equation has very difficult to handle when using $z=x+iy$.
So I set $z=re^{iθ}$, which yields
$$ (re^{iθ})^{2018}=2018^{2018}+e^{i\frac{\pi}{2}}$$
After this I was not able to handle it. 

The equation $z^{2018} = 2018^{2018} + i$ has a total of 2018 roots, in which some are real. It is clear that there is no real roots. So it has 2018 complex roots.
