How to plot the polar equation theta = pi/6 on wolframalpha I need to plot the polar equation 
theta = pi/6
My question has two parts.
1) Is it a line? I'm pretty sure it is, since the angle theta in the polar equation is a constant, but since I was not able to plot this on wolframalpha, I'm not 100% sure and I would like to confirm this.
2) How do I plot this on wolframalpha? I know that I can write polar plot $r = \sin (\theta)$`, for exeample and this will give me a circle, as it should. But if $\theta = pi/6$ is a line, writing polar plot theta = $\pi/6$ gives me the wrong answer. 

Converting to Cartesian,
$$\begin{cases}x=r\cos\dfrac\pi6=\dfrac{\sqrt 3}2r,\\y=r\sin\dfrac\pi6=\dfrac{1}2r.\end{cases}$$
or
$$y=\dfrac x{\sqrt 3}$$ with $x,y\ge0$.
I don't have the slightest idea how to plot this with Alpha.
