How to solve this quadratic congruence equation? Well, we have :
$$n^2+n+2+5^{4n+1}\equiv0\pmod{13}$$
i'm little bit confused, I think i can solve this using the reminders of $n^2$, $n$ and $5^{4n+1}$ over $13$, by the way I have no idea about the Chinese Reminder Theorem no need to use it. and thanks in advance
edit:
$4 \le n \le 25$


I'm very sorry about this bad resolution i've used a webcam, i'm going to update it later on.
