Converting to a partial fraction. I'm trying to do an inverse Laplace operation on $I(s)$ shown below but I'm struggling on finding what $A$ & $C$ are on the partial fraction and how to do it. I calculated what $B$ equals by making $s=0$.
$$I(s)=\frac{1}{s^2(R+L)}=\frac{A}{s}+\frac{B}{s^2}+\frac{C}{R+Ls} \\
1=As(R+Ls)+B(R+Ls)+Cs^2 \\
B=\frac{1}{R}$$

Set $s$ to $-\frac{R}{L}$, eliminating $A$ and $B$ to find $C$ so that
$$C\frac{R^2}{L^2}=1\Rightarrow C=\left(\frac{L}{R}\right)^2$$
Note that the coefficient of $s^2$ is zero in your second equation:-
$$AL+C=0\Rightarrow A=-\frac{C}{L}=-\frac{L}{R^2}$$
