How do I solve $(x+1)^5 +36x+36 = 13(x+1)^3$? I tried $$(x+1)^5 + 36 x + 36 = 13 (x +1)^3\\
(x+1)^5 + 36(x+1)   = 13 (x +1)^3\\
(x+1)^4 +36         = 13 (x+1)^2
$$
But, don't understand how to solve further. Can somebody show step by step please. Thanks!

Hint:
$$(x+1)^5-13(x+1)^3+36(x+1)=0$$
$$\left[(x+1)^4-13(x+1)^2+36\right](x+1)=0$$
$$\left((x+1)^2-9\right)\left((x+1)^2-4\right)(x+1)=0$$
