How to evaluate $\frac{d}{dx}\sin^2x$ I'm having trouble understanding how  $\frac{d}{dx}\sin^2x =2\sin(x)\cos(x)$.
Please show as many steps of the proof as necessary so that I can apply this to other problems.
Thank you for your time~! ^_^

$\frac{d}{dx}\sin^2x= 2\sin(x)(\sin(x))'= 2\sin(x)\cos(x)$
