Big Oh power difference? Can a function with higher power like $n^3$ become big oh for a lower power function let say $O(n^2)$

To say that $f(n) = O(n^2)$ is the same as saying there exists a constant $C$ such that $f(n) \le Cn^2$ for large enough $n$.
However, $$\frac {n^3} {n^2} \to \infty \ \ \ \ \ {\text{as } n\to\infty}$$
so there cannot exist such a constant.
