Finding Tangent line from Parametric I need to find an equation of the tangent line to the curve $x=5+t^2-t$, $y=t^2+5$ at the point $(5,6)$.
Setting $x=5$ and $y = 6$ and solving for $t$ gives me $t=0,1,-1$. I know I have to do y/x, and then take the derivative. But how do I know what $t$ value to use?

Please type up or paste the image text in your problem statement.
Solving for $t: x(t)=5$ gives $t \in \{0,1\}$ and solving for $t:y(t) = 6$ gives $t \in \{ 1,-1\}$.  The common $t$ is $t=1$. Compute $dy/dx$ and not $y/x$ at $t=1$ , and substitute this into the slope of the tangent. 
