Power Series -- Radius of Convergence and Interval of Convergence Find both the radius of convergence and interval of convergence of the power series.
$$\sum_n\frac{(-1)^n\ln n}{\sqrt{n}}(x-2)^n$$
I believe that the radius of convergence is $R=1$. But I'm having a hard time with this entire question. the $\ln n$ is really throwing me off when I use the ratio test.

Denote $u_n(x)$ the given expression and since 
$$\frac{\ln(n+1)}{\ln n}=\frac{\ln n+\ln\left(1+\frac1n\right)}{\ln n}\xrightarrow{n\to\infty}1$$
then we see that
$$\lim_{n\to\infty}\left|\frac{u_{n+1}(x)}{u_n(x)}\right|=|x-2|<1\iff 1<x<3$$
hence the radius of convergence is $R=1$.


*

*If $x=3$ then by the Leibniz theorem the series is convergent

*If $x=1$ the series is divergent since
$$\frac{\ln n}{\sqrt n}\ge \frac{ 1}{\sqrt n}$$
hence the interval of convergence is $(1,3]$.

