How do you find the height of a triangle given $3$ angles and the base side? Image given. 
This question has me absolutely stumped. This is the image of the question, how can I work out $x$? I've been doing a variety of attempts but I just cant get it.

Call the side opposite $33^\circ$ as $a$. Therefore we have: $$\dfrac {x}{a}=\sin 25^\circ$$
and from the sine rule for the triangle we know that: $$\dfrac {20}{\sin 122^\circ}=\dfrac {a}{\sin 33^\circ}$$
Therefore from the above two equations we have $x=\dfrac{20\times\sin 33^\circ \times \sin 25^\circ}{\sin 122^\circ} $, or $$x\approx5.428336828982414$$
