How to solve: $\frac{3·x-5}{8·x-2}<6$ I'm trying to solve $\frac{3x-5}{8x-2}<6$ ?
I'm not sure which first step to take. I mean if I multiply both sides by $8x-2$ then I'm not sure if the sign would switch, as this could be positive or negative depending on $x$.

Multiply both sides of $\frac{3x-5}{8x-2}<6$ by $(8x-2)^2$ will make you free from the worry (if the sign would switch). 
