Calculate areas of $0 \leq x \leq \sqrt{y}, 0 \leq y \leq \sqrt{x}, x+y \leq 3 / 4$ I have to calculate the areas of this set.
Could someone explain me how do I have to interprete the following:
\begin{equation}
\left\{(x, y) \in \mathbb{R}^{2}: 0 \leq x \leq \sqrt{y}, 0 \leq y \leq \sqrt{x}, x+y \leq 3 / 4\right\}
\end{equation}
Thank you in advance.

At first i would calculate the intersection points of the curves
$$x=\sqrt{y},y=\sqrt{x},y=\frac{3}{4}-x$$
I have got
$$\frac{A}{2}=\int_{0}^{\frac{3}{4}}x-x^2dx+\int_\frac{3}{8}^{1/2}x-\frac{3}{4}-x^2dx$$
