Help with a trig-substitution integral I'm in the chapter of trigonometric substitution for integrating different functions. I'm having a bit of trouble even starting this homework question:
$$\int \frac{(x^2+3x+4)\,dx} {\sqrt{x^2-4x}}$$

May be I was too fast even if the answer is almost correct.
First make $x = 2 (\cosh(y) + 1)$. The integrand then becomes
$(\pm) 2 (8 + 7 \cosh(y) + \cosh(2 y))$
So, the integral is $(\pm) (16 y + 14 \sinh(y) + \sinh(2 y))$
If you replace $y$, you arrive to my formula (the $\pm$ was missing) 
