Find at least one solution or prove that it does not exist Please help me to find solution or prove that it does not exist.
$$
C^{2^k}_{2^n} < 2^{2^k (n - k)}, 1<k<n, k \in \mathbb{N}, n \in \mathbb{N}
$$
I tried to find solution numerically, but when $n$ > 20, the numbers grows very fast, so it seems like it has not solution (because I didn't find it when $n$ < 20). I am looking for analytical methods to prove this.

I've found an answer.
Firstly we can introduce $N = 2^n$, $K = 2^k$. So the inequality will be rewritten as 
$C_N^K < 2^{K(\log_2(N)-\log_2(K))}$
or
$\log_2(C_N^K) < K \log_2(N/K)$.
Secondly, according to Best upper and lower bound for a binomial coeficient we can use inequality
$C_N^K \ge (N / K)^K$.
It shows that there are no solutions.
