Prove: For any integer $n \geq 2$, there is an odd number P such that $2n \lt P \lt 3n$ I am in high school and had this for a homework problem.  I got it wrong, but the teacher did not post the correct answer.  Any help would be appreciated.  It is about writing proofs.
Prove that for any integer n greater than or equal to 2, there is always an odd number P between 2n and 3n.

$\color{green}{2n+1}$ is odd and $2n<\color{green}{2n+1}<3n\impliedby 0<1<n$.
