surface area of a sphere above a cylinder I need to find the surface area of the sphere $x^2+y^2+z^2=4$ above the cone $z = \sqrt{x^2+y^2}$, but I'm not sure how. I know that the surface area of a surface can be calculated with the equation $A=\int{\int_D{\sqrt{f_x^2+f_y^2+1}}}dA$, but I'm not sure how to take into account the constraint that it must lie above the cone. How is this done?

Hint: Use spherical coordinates. $dA = r^2\sin\theta d\theta d\phi$ with $0<\theta<\pi$. The surface area becomes $\iint_D dA$.
