imaginary equation of second degree I have the follow equation:
$$ix^2−x+2i=0$$
After resolve it with mathway (a web that resolves the equation step by step) I can't understand the last step.
Having:
$$x=\dfrac{1\pm3}{2i}$$
I take $+2i,-i$ from "$4/2i$" and "$-2/2$". But the app say that the answer is $-2i,1$.
What I'm doing wrong?

Antoher way of solving $x$:
Use the quadratic formula:


*

*$$ax^2+bx+c=0\Longleftrightarrow x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$


So, solving your question, using the quadratic formula, where $a=i,b=-1,c=2i$:
$$ix^2-x+2i=0\Longleftrightarrow x=\frac{-(-1)\pm\sqrt{(-1)^2-4\cdot i\cdot2i}}{2\cdot i}\Longleftrightarrow$$
$$x=\frac{1\pm\sqrt{1^2-4\cdot -2}}{2i}\Longleftrightarrow x=\frac{1\pm\sqrt{1+8}}{2i}\Longleftrightarrow$$
$$x=\frac{1\pm\sqrt{9}}{2i}\Longleftrightarrow x=\frac{1\pm3}{2i}$$
