How to apply L'Hopital's rule to the limit of $\tan x/(1+\sin x)$ as $x\to 0$? Help me find the limit as x approaches 0 from the left: $\quad\lim\limits_{x \to 0} \dfrac {\tan x}{1+\sin x}$
To apply l'Hopital's rule, I am not able to get this to: $0/0$

You do not need l'Hopital's rule. The expression evaluates to $\frac{0}{1+0} = 0$
