Find the coefficient of $x^{29}$ in the given polynomial. The polynomial is :
$$
\left(x-\frac{1}{1\cdot3}\right) \left(x-\frac{2}{1\cdot3\cdot5}\right) \left(x-\frac{3}{1\cdot3\cdot5\cdot7}\right) \cdots \left(x-\frac{30}{1\cdot3\cdot5\cdots61}\right)
$$
What I've done so far : The given polynomial is an expression of degree $30$. Hence, the coefficient of $x^{29}$ will be the negative of the sum of the roots. But the resulting sum is too complicated to handle and I think I'm doing it wrong. 

HINT:$$\underbrace{1.3,1.3.5,...,1.3.5....61}_{30-terms} $$so 
$$\underbrace{(x-\frac{1}{1.3})(x-\frac{2}{1.3.5})(x-\frac{3}{1.3.5.7})......(x-\frac{30}{1.3.5.....61})}_{30-terms }$$we have 
,to obtain $x^{29}$ 
we have
when you want 
$x^{29}$ from $(x+a_1)(x+a_2)(x+a_3)...(x+a_{30})$ you have to find this
$$(x+0)(x+0)(x+0)...(x+0)(a_{30})+\\(x+0)(x+0)(x+0)...(a_{29})(x+0)+\\(x)(x)(x)...(a_{28})(x+0)(x+0)+\\
(x+0)(x+0)(x+0))...(a_{27})(x+0)(x+0)(x+0)+\\\vdots\\
(x+0)(a_{2})...(x+0)(x+0)(x+0)+\\
(x+a_1)(a+0)...(x+0)(x+0)(x+0)$$
