Finding the radius of the smallest circle that can circumscribe an equilateral triangle Q:A puzzle board is in the form of an equilateral triangle that has an area of $7\sqrt{3}$ if the board is placed on a circular table, what should be the min area of the table so that the whole board fits inside the table.
$\frac{88}{3}$
I get that the side of the triangle is $2\sqrt{7}$ and also that in an equilateral triangle the median, perpendicular bisector, altitude and angle bisector are the same. I'm however still stuck with how to get the radius without resorting to sin/cos etc. 
