Distance of the Focus of an Hyperbola to the X-Axis For a National Board Exam Review:

How far from the $x$-axis is the focus of the hyperbola $x^2 -2y^2 + 4x + 4y + 4$?

Answer is $2.73$
Simplify into Standard Form:
$$ \frac{ (y-1)^2 }{} - \frac{ (x+2)^2 }{-2} = 1$$
$$ a^2 = 1 $$
$$ b^2 = 2 $$
$$ c^2 = 5 $$
Hyperbola is Vertical: 
$$ C(-2,1) ; y = 1 $$
$$ y = 1 + \sqrt5 = 3.24 $$
$$ y = 1 - \sqrt5 = 1.24 $$
Both answers don't match; What am I doing wrong?

$\frac{(x + 2)^2}{2} - \frac{(y - 1)^2}{1}; C = (-2, 1)$
$C = \sqrt{2 + 1} = \sqrt{3}$
Answer: $1 + \sqrt(3) = 2.73$
