How many ways to come up with four teammates? A Math teacher has to choose 4 people for a competition. If there are 6 boys and 6 girls, and the teacher must select 2 boys and 2 girls, how many ways are there?
I came up with ${4 \choose 2} \cdot {4 \choose 2}$. This is because there are 4 spots and there must be 2 from each gender. Is this the right method? 

If the spots given to each selected person does not matter:
To select 2 Boys out of 6, combinations are:6C2. 
Similarly to select 2 Girls: 6C2.
Therefore total choices is 6C2*6C2 or (6C2)^2
If spots given to each person does matter, multiply the previous answer by 4! as the number of ways of arranging 4 people in 4 places is 4! 
Note: 'C' denotes the combinatorial function
And '!' Denotes factorial function
