Logarithm Expansion Question How do you expand the following logarithm:
$$ \log_5 \left(\frac{u}{v^3}\right)^6 $$
The result I got was:
$$ 6\log_5u -18\log_5v $$
Is that fully expanded?

It is correct!!!
$$\log_5 \left ( \frac{u}{v^3}\right )^6=6 \cdot \log_5 \left (\frac{u}{v^3} \right) \\= 6 \cdot (\log_5(u)- \log_5(v^3))=6 \cdot (\log_5 u-3 \log_5 v)=6\log_5 u-18 \log_5 v $$
