Find "A" in this equation. $$ \sqrt[3] {A-15√3} + \sqrt[3] {A+15√3} = 4 $$
Find "A" ?
The way of exponentiation took too much time, is there any easier method?

If there exists a cubic polynomial of integer coefficients with roots:
$$0,\sqrt[3] {A-15√3} , \sqrt[3] {A+15√3} $$
then it will be of the form
$x^3-4x^2 + \sqrt[3]{A^2-675}x$
You just need to find $A$ such that $A^2-675$ is a perfect cube.
Trivially $A^2 = 676$ will do.
