Floating point number,Mantissa,Exponent In this computer, numbers are stored in $12$-bits. We will also assume
that for a floating point (real) number, $6$ bits of these bits are reserved for
the mantissa (or significand) with $2^{k-1}-1$ as the exponent bias (where
$k$ is the number of bits for the characteristic).
$011100100110010111110011$
What pair of floating point numbers could be represented by these
$24$-bits?
I have gone this far:
As described above that each number is of $12$ bit so we get each number 
$011100100110$
First one is $0$ bit so it is positive and 
Mantissa will be $100110$
Exponent will be $11100b=28$
my unbiased exponent will be $2^{28-15}=2^{13}$
How to find the floating point number from here?

Usually the mantissa is considered to have a binary point after the first bit, so your mantissa would be $1.1100_2=\frac 74=1.75_{10}$. Sometimes a leading $1$ is assumed, so your mantissa would be $(1).11100_2=\frac{15}8=1.875_{10}$  This gives one more bit of precision. To find the exponent, you subtract the offset from the stored value.  You probably meant $2^{k-1}-1$ as the offset.  Can you do that?
