Solve $(y+\sqrt{x^2+y^2})dx-xdy=0$ Solve $(y+\sqrt{x^2+y^2})dx-xdy=0$
I suspect this is homogoneus equation after we divide sides by $y$. But I don't know how to contiunue.

note that we can write $$1+\sqrt{\left(\frac{x}{y}\right)^2+1}-\frac{x}{y}\frac{dy}{dx}=0$$ for $$y>0$$
