How many non prime factors are in the number $N=2^5 \cdot 3^7 \cdot 9^2 \cdot 11^4 \cdot 13^3$. to find non prime factors in the number
$N=2^5 \cdot 3^7 \cdot 9^2 \cdot 11^4 \cdot 13^3$.
First I tried finding all the factors by adding 1 to each of the exponents and then multiplying them
and then finding the prime factors of the given number
and then subtracting the prime factors from the total factors 
but I'm not getting the answer.
Answer is $1436$.

Consider 1 as a default prime factor of any number in this type of problem as well. Then the number of non prime factors is the number of factors minus the number of prime factors, or $1440-5=1435$.
