How do I add the terms in the binomial expansion of $(100+2)^6$? So, I stumbled upon the following question.
Using binomial theorem compute $102^6$.
Now, I broke the number into 100+2.
Then, applying binomial theorem
$\binom {6} {0}$$100^6(1)$+$\binom {6} {1}$$100^5(2)$+....

I stumbled upon this step. How did they add the humongous numbers? I am really confused.
Kindly help me clear my query.

That number is $1\; 12 \; 6\; 16 \; 24\;192\; 64$ (space added for emphasis).  Notice a relationship with the coefficients of the powers of $10$?
