How is the distribution law working in this Boolean Algebraic equation? I am working on a sample boolean algebraic question as study for my upcoming exam, my full expression is $(A\overline B(C + BD) + \overline{AB})C$
I have simplified my expression to 
$A\overline BC + \overline {AB}C$
My example papers solution book says the next step uses the distributive law to reduce the expression to 
$\overline BC ( A + A)$
But I do not understand this distribution, shouldn't $\overline {AB}$ become $\overline A + \overline B$ , how are we getting two positive A variables?

Yes, $\overline {AB}$ becomes $\overline A + \overline B$, so you get:
$A \overline BC + (\overline A + \overline B) C=$
$A \overline B C + \overline A C + \overline B C=$
$(A \overline B + \overline A + \overline B)C=$ (Absorption)
$(\overline A + \overline B)C =$
$\overline {AB}C$
...So no, I have no idea where the book gets their expression from ...
