Rolling two dice, what is the probability of getting 6 on either of them, but not both? Rolling two dice, what is the probability of getting 6 on one of them, but not both?

Lets consider two events: A - the first dice gets 6, B - the second. Then $P(A) = P(B) = 1/6$. And $P(A\cap B) = 1/36$. Then the answer: $p = P(A)+P(B)-2\cdot P(A\cap B) = 1/3-1/18 = 5/18.$
