Chance for picking a series of numbers (with repetition, order doesn't matter) I want to calculate the chance for the following situation:
You throw a die 5 times. How big is the chance to get the numbers "1,2,3,3,5" if the order does not matter (i.e. 12335 = 21335 =31235 etc.)?
I have 4 different solutions here, so I won't include them to make it less confusing. 
I'm thankful for suggestions!

There are $5$ options for placing the $1$, then $4$ for placing the $2$, and then $3$ for placing the $5$, for a total of $5\cdot4\cdot3=60$. Alternatively, there are $5!=120$ permutations in all, and pairs of these are identical because you can exchange the $3$s, which also gives $120/2=60$. The total number of combinations you can roll is $6^5=7776$, so the chance is $60/7776=5/648\approx0.77\%$.
