Finding $H'(1)$ Given $H(x)=F(x)G(x)$ Find $H'(1)$
Suppose:
$F(1)=2$
$F'(1)=3$
$G(1)=5$
$G'(1)=-2$
Then using the product rule I assumed $H(1)=11$ because:
$H(1)=((2)(-2))+((3)(5))=11$ using the product rule. However I am unsure as to how to derrive $H'(1)$ from $H(1)$ Would anyone mind giving me some insight on this?

$$H'(x)=F(x)G'(x)+G(x)F'(x),$$ and so 
$$H'(1)=F(1)G'(1)+G(1)F'(1)=2 \cdot (-2)+5 \cdot 3=11.$$
There is not much else to say here.
