Help with simple algebra Wolfram Alpha tells me that
$$\frac{a+1}{1-a^2}=\frac{1}{1-a}.$$
but can't see how! Any help would be very appreciated!

$$\frac{a+1}{1-a^2}=\frac{a+1}{1-a+a-a^2}=\frac{a+1}{1(1-a)+a(1-a)}=$$
$$=\frac{a+1}{(1-a)(1+a)}=\frac{1(1+a)}{(1-a)(1+a)}=\frac{1}{1-a}.$$
