Derivative of exponent Looking to solve :
$$ \frac{d}{dx}[2^{0.5x}]$$
The multiplication and X value in the exponent is confusing me. Help? Thanks!

You have to write 
$$2^{0.5x}=e^{0.5x\log(2)},$$
so
$$\frac d{dx}\left(e^{0.5x\log(2)}\right)=0.5\log(2)e^{0.5x\log(2)}.$$
Finally,
$$\frac d{dx}(2^{0.5x})=\frac{\log(2)}2 2^{0.5x}.$$
