Seating four girls and two boys in a row such that the boys do not sit together If $2$ boys are never to sit together and $4$ girls and $2$ boys are to sit in linear line.? Then total number of such arrangements is:
My solution:
The total number of linear arrangements is $6!$ and the number of arrangements when $2$ boys are to sit together is $5!$ so the answer should be $6!-5!=600$. Am I right here?

Consider 2 boys as a single unit .. then possible ways of arranging boys & 4 girls = arrangements such  that 2 boys sit together  => 5! => 120 
Now ,since 2 boys are never to sit together ,
the number of required arrangements  => 6! -(2*120) => 720-240 => 480
