A certain linear functional in the subspace of summable sequences in $\ell^2.$ Let $S=\{ a \in \ell^2 \setminus \sum_{n=1}^\infty a_n <\infty \}$ be the subspace  of $\ell^2$ of summable sequences over $C$.
Let $T:S \to C$ be the linear functional such that $T(a)=\sum_{n=1}^\infty a_n$
My question is: is $T$ a bounded linear functional?
Thanks for any suggestion.

Consider the sequences $(x_i)_{i=1,2,\dots}$ defined by
$$(x_i)_n = \frac{1}{n^{1+1/i}}.$$
The sequences are all summable, because the improper integrals
$$\int_{1}^{\infty} \frac{1}{x^{1+1/i}}\, dx$$
are finite, so they all belong to $S$. They are also bounded in $\ell^2$, because
$$ \sum_{n=1}^{\infty} (x_i)_n^2 \leq \sum_{n=1}^{\infty} \frac{1}{n^2} \quad i = 1,2,\dots.$$
However, $T(x_i) \to \infty$ as $i\to \infty$, because the sequence $x_i$ converges pointwise to $1/n$, which is not summable.
