Computing probabilities involving increasing event outcomes Suppose I have an unfair die with three outcomes: $A,B,C$
\begin{align*}
A &\sim 1/512 \\
B &\sim 211/512 \\
C &\sim 300/512 \\
\end{align*}
The case of one dice is trivial. However, if I roll two of these dice, what is the probability of at least one of the dice having outcome $A$? 
I do not know how to tackle this problem since the outcomes in the sample space do not all have the same probability of occurring.
Thanks!

Laars method in the comments is the most straight-forward method, but if you want another method you could add up the other 5 probabilities that do include at least one A
$$\frac{1}{512}\cdot\frac{211}{512}+\frac{1}{512}\cdot\frac{300}{512}+\frac{1}{512}\cdot\frac{1}{512}+\frac{211}{512}\cdot\frac{1}{512}+\frac{300}{512}\cdot\frac{1}{512}$$
Or, lumping B and C together as "not A"
$$\frac{1}{512}\cdot\frac{511}{512}+\frac{1}{512}\cdot\frac{1}{512}+\frac{511}{512}\cdot\frac{1}{512}$$
In general, when you see the phrase, "at least one" it is a good i deal to just calculate the complement and subtract from one.
