Solving quadratic equation $$\frac{1}{x^2} - 1 = \frac{1}{x} -1$$
Rearranging it I get: $1-x^2=x-x^2$, and so $x=1$. But the question Im doing says to find 2 solutions. How would I find the 2nd solution?
Thanks.

$$\frac{1}{x^2} - 1 = \frac{1}{x} -1$$
$$\frac{1}{x^2}  = \frac{1}{x} $$
multiply by x suppose that $x \ne0$
$$x^2-x=0$$
$$x(x-1)=0$$
The unique solution is  $x=1$ solution $x=0$ is excluded.
