Is the quotients of a group of triangular distributed numbers still following a triangular distribution? I have a group of numbers (about 10000 numbers) between 0.8 and 1.0 which follows simple triangular distribution (for example, lower limit: 0.8, upper limit: 1.0, mode: 0.9).
If I divide 2 by each number from this group, I got the quotients forming the second group of numbers which follows another distribution (i.e. lower limit: 2.0, upper limit: 2.5, mode: 20/9).
Here is my question: is the second distribution still a triangular distribution? If not, then how can I know quantitatively what kind of distribution it is?
I will appreciate very much for your kind answers!

The mgf of the triangular distribution is $$M_{X}(t) = \frac{2(b-c)e^{at}-(b-a)e^{ct}+(c-a)e^{bt}}{(b-a)(c-a)(b-c)t^{2}}$$
where $a,b,c$ are the lower limit, upper limit, and mode respectively. Note that this is an alternate way of characterizing the probability distribution function. Replacing $a := 2/a$, $b:= 2/b$ and $c:= 2/c$ still produces a triangular distribution.
