Double integrals over general regions Set up iterated integrals for both orders of integration. Then evaluate the double integral using the easier order and explain why it's easier. $$\int\int_{D}{ydA}, \text{$D$ is bounded by $y=x-2, x=y^2$}$$
I'm having trouble with setting up the integral for both type I and type 2 and choosing which one would be easier. I'm sure I'll be able to integrate it with no problem, but setting them up is where I would need some help. 

I found the answer. $\int_{0}^1\int_{-\sqrt{x}}^\sqrt{x}{ydydx}+\int_{1}^4\int_{x-2}^\sqrt{x}{ydydx}=\int_{-1}^2\int_{y^2}^{x+2}{ydxdy}$
It's easier to to integrate $\int_{-1}^2\int_{y^2}^{x+2}{ydxdy}$ and after integrating it, the answer comes out to be $\frac94$
