Summing the terms of a series I have a really confusing question from an investigation. It states-
Find the value of:
$$\sqrt{1^3+2^3+3^3+\ldots+100^3}$$
How would I go about answering this??

And if you don't know the formula
and don't need it exactly,
$\sum_{k=1}^{100} k^3
\approx \int_0^{100} x^3 dx
=\frac{100^4}{4}
$
so the result is
$\sqrt{\frac{100^4}{4}}
=\frac{100^2}{2}
=5000
$.
If you add in the
usual correction of
$\frac12 f(n)$,
the result is
$\sqrt{\frac{100^4}{4}+\frac12 100^3}
=\frac{100^2}{2}\sqrt{1+\frac{2}{100}}
\approx \frac{100^2}{2}(1+\frac{1}{100})
=5050
$.
Shazam!
