Triple fractions I've got this simple assignment, to find out the density for a give sphere with a radius = 2cm and the mass 296g. It seems straightforward, but it all got hairy when i've got to a fraction with three elements(more precisely a fraction divided by a number actually this was wrong, the whole point was that the number is divided by a fraction, and it's different than a fraction being divided by a number.). I tend to solve these by dividing the element on the bottom by 1, and extracting from that 2 fraction division like this :
$$
\frac{a}{\frac{b}{c}} \Rightarrow \frac{\frac{a}{b}}{\frac{c}{1}} \Rightarrow \frac{a}{b} \div \frac{c}{1} => \frac{a}{b} \cdot \frac{1}{c} \Rightarrow \frac {a} {b \cdot c}
$$
And it used to work, though for the next example it doesn't seem to, it looks like another technique is used:
$$
\frac{a}{\frac{b}{c}} \Rightarrow a \div \frac{b}{c} \Rightarrow a \cdot \frac{c}{b} \Rightarrow \frac {a \cdot c}{ b}
$$
For the example below cleary the second method is used/needed, to get the right response. But i'm confused when to use each, as i've use both before, and both gave correct asnwers(matching with the answers at the end of the book).
$$
v = \frac43\pi r^3
$$
$$
d = \frac mv
$$
$$
m = 296g
$$
$$
r=2cm
$$
$$
v = \frac43\pi 2^3 \Rightarrow \frac{32\pi}{3}
$$
$$
d = \frac{m}{v} \Rightarrow \frac{296}{\frac{32\pi}{3}} \Rightarrow \frac {296}{32\pi} \div \frac31 \Rightarrow \frac{296}{32\pi} \cdot \frac{1}{3} \Rightarrow \frac{296}{96\pi} \approx 0.9814\frac{g}{cm^3}
$$
$$
d_{expected} = 8.8 \frac{g}{cm^3}
$$
I am, clearly,  missing something fundamental about the use of these. 
Can anyone enlighten me please?
Can't quite find a good explanation online. 

296/(32pi/3)=(296/32pi)/(3/1)   should be
            =(296/32pi)*(3/1)= 8.833 g/ccm
   you inverted twice
