Cubic Equation with one real root Question:

Suppose the equation $x^3-hx^2+kx-9=0$ has only one real root which has a value of $1$. Find the range of values of $k$.

I really have no idea when it comes to a cubic equation. Any advice to solving?

I would start by factoring the polynomial based on the known route. By doing polynomial division $(x^3-hx^2+kx-9) : (x-1)$. 
By doing so, you will get a residue, that must be zero (since you factoring by a root), so you will get one restriction on $k$ and $h$, to ensure $1$ being a root. 
In addition, you will have a quadratic polynomial, that has to have complex roots. By inspecting the root of the $pq$-formula to be negative, there is an additional restriction on $k$ and $h$.
