How to cancel out a negative in a denominator? The question was to make $y$ the subject in $x=5-3y$ (i.e. solve for $y$).
My working was this:
$$\begin{align*}
x&=5-3y \\
-3y&=x-5 \\
y&=(x-5)/(-3)
\end{align*}$$
But this was apparently wrong and the correct answer was $(5-x)/3$. Does anyone know how to get that and how to cancel out the $-3$ I had in the denominator of the equation?

Multiplying both the numerator and denominator with -1 will do the trick here.
