find out the value of $\dfrac {x^2}{9}+\dfrac {y^2}{25}+\dfrac {z^2}{16}$ If $(x-3)^2+(y-5)^2+(z-4)^2=0$,then find out the value of $$\dfrac {x^2}{9}+\dfrac {y^2}{25}+\dfrac {z^2}{16}$$
just give hint to start solution.

HINT: Assuming real solutions, there is only one possibility for values of $x, y$ and $z$. Then put in the corresponding values in the 2nd expression. If they are complex then there are infinite values.
