Show that $2x^3+2x^2-10x+6$ is positive if $x>1$ 
Show that $2x^3+2x^2-10x+6$ is positive if $x>1$ 

I have tried to solve it using mean value theorem but it doesn't work. Please anyone help me to solve this.

Alt. hint:  let $\,x-1 = y \gt 0\,$, then:
$$
2x^3+2x^2-10x+6 = 2(y+1)^3+2(y+1)^2-10(y+1)+6=2 y^3 + 8y^2 \gt 0
$$
