How to evaluate $ \int\left[\left(\frac{x}{e}\right)^x+\left(\frac{e}{x}\right)^x\right]\ln(x)\,dx$? $$ \int \left[ \left( \frac {x}{e}\right) ^ x + \left( \frac {e}{x}\right) ^ x \right] \ln(x)\, dx$$
Here I have no clue from where to start with.
I already tried some 


*

*substitutions

*taking out ${e} ^ {x}$
But none seems to work please help

We have
$\frac{d}{dx}\left(x\ (\ln x - 1)\right) = (\ln x - 1) + 1 = \ln x$, and
$\left(\frac xe\right)^x = e^{x(\ln x - 1)}$
