Is $x^{-0}$ defined? In the form of mathematics that most of humanity is taught, the following operation is undefined:
$\Large{\frac{x}{0}}$
But, how about the following operation?
$\Large{x^{-0}}$
Is the following statement true?
$\Large{x^{-0}=\frac{1}{x^0}=\frac{1}{1}=1}$

$x^y=e^{ylog(x)}$ so $x^0=x^{-0}$ are defined for $x>0$.
