Converting Polar Equation to Cartesian Equation problem So I have
1. $$\frac{r}{3\tan \theta} = \sin \theta$$
2. $$r=3\cos \theta$$
What would be the Cartesian equation???

the first
$$\frac{r}{3\tan \theta} = \sin \theta$$
$$\frac{r\cos \theta}{3\sin \theta} = \sin \theta$$
$$\frac{x}{3\sin \theta} =\sin \theta$$
$$x =3\sin^2 \theta$$
$$r^2x =3r^2\sin^2 \theta$$
$$x(x^2+y^2)=3y^2$$
The second
$$r=3\cos \theta$$
$$r^2=3r\cos \theta$$
$$r^2=3x$$
$$x^2+y^2=3x$$
