Odds of rolling a $6$ in three chances I'm working on a dice game to play with the kids I work with. I'm trying to recall calculating probability but its been a while. Its for a table top DND type game and they are rolling for the properties of their character.
What are the odds of rolling a $6$ with a D6 given $3$ chances? They are trying to get a $6$ and they are given $3$ rolls to do so. 
I want to say its $50\%$ ($\frac16 + \frac16 + \frac16 = \frac36$) but it's been a while since I studied this. Am I on the right track?
Thanks for your time.

It's easier to calculate the chances of not obtaining any $6$ in three rolls. The probability of not otaining a $6$ in a roll is $5/6$, so in three rolls you have
$$5/6\cdot 5/6 \cdot 5/6= \sim 0.58$$
So the probablity of not obtaining any $6$ is $\sim 58 \% $, hence the probability of obtaining a $6$ is  $\sim 42 \%$.
