If a fair die is rolled 3 times, what are the odds of getting an even number on each of the first 2 rolls, and an odd number on the third roll? If a fair die is rolled 3 times, what are the odds of getting an even number on each of the first 2 rolls, and an odd number on the third roll?
I think the permutations formula is needed i.e. $n!/(n-r)!$ because order matters but I'm not sure if n is 3 or 6 and what would r be?
Any help would be much appreciated!

All of the above or below :-} answers are correct that is 50:50 for each throw so your "formula" is
  n
(2 -1):1 against where n is the number of throws
