Solving $f'''+\frac{n+1}{2}ff''-nf'^2+n=0$ with $n=e^\pi$ How do I solve
$$f'''+\frac{n+1}{2}ff''-nf'^2+n=0$$
with $n=e^\pi$ or arbitrary $n$?
This equation occurs in my model for the time evolution of the value of Bitcoin.

This is a third order non-linear autonomous ODE. It can be reduced to a second order non-linear ODE. I think that it cannot be analytically solved in the general case with a finite number of elementary and/or current referenced special functions.!
$$\text{Change of notation for clarity: $f(x)\equiv y(x)$}\\\,\\
\dfrac{\mathrm d^3y}{\mathrm dx^3}+\dfrac{n+1}{2}y\dfrac{\mathrm d^2y}{\mathrm dx}-n\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+n=0\\\,\\
\text{Let : }\dfrac{\mathrm dy}{\mathrm dx}=F(y)\quad\to\quad\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm dF}{\mathrm dy}\dfrac{\mathrm dy}{\mathrm dx}=F\dfrac{\mathrm dF}{\mathrm dy}\\\,\\
\dfrac{\mathrm d^3y}{\mathrm dx^3}=\dfrac{\mathrm d}{\mathrm dy}\left(\dfrac{\mathrm d^2y}{\mathrm dx^2}\right)\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dy}\left(F\dfrac{\mathrm dF}{\mathrm dy}\right)F=F^2\dfrac{\mathrm d^2F}{\mathrm dy^2}+F\left(\dfrac{\mathrm dF}{\mathrm dy}\right)^2\\\,\\
F^2\dfrac{\mathrm d^2F}{\mathrm dy^2}+F\left(\dfrac{\mathrm dF}{\mathrm dy}\right)^2+\dfrac{n+1}{2}yF\dfrac{\mathrm dF}{\mathrm dy}-nF^2+n=0
$$
