Find an angle in a given triangle $\triangle ABC$ has sides $AC = BC$ and $\angle ACB = 96^\circ$. $D$ is a point in $\triangle ABC$ such that $\angle DAB = 18^\circ$ and $\angle DBA = 30^\circ$. What is the measure (in degrees) of $\angle ACD$?

Hint: 
Have you drawn your picture? 
I drew the picture out and I got an isosceles triangle, with base angles being ∠A and ∠B. Then I placed point D inside the triangle and connected that point to the 3 vertices of the triangle. 
The first statement tells us that we are in an isosceles triangle ( meaning base angles are the congruent ). Therefore we can find the measure of the base angles since we know that ∠ACB=96∘. Each base angle turns out to be 42∘ each. 
Consider triangle ABD. Can you find all angles of that triangle? And can you then find the angles of triangle BDC? and ADC?
I hope this helped! If you are still stuck let us know!
