triangle inquality question If $C_1$ and $C_2$ are two given contstants such that $|x|\le C_1$ and $|y|\le C_2$ find a constant $C$ such that $|x-y|\le C$.
Would I use the second form of triangle inequality :
$|a-b| \geq ||a|-|b||$ and in particular $|a-b| \geq |a|-|b|$
and how would I begin it?

Note
$$|x-y|=|x+(-y)|\le |x|+|-y|=|x|+|y|\le C_1+C_2.$$
