Calculating speed of minute hand on a clock 
The minute hand on a clock is $12 \text{ cm}$ long. Calculate the speed of its free end.

Is the following correct ? I have already worked out its angular speed from the previous question.
$$v = \omega r \\
\omega = 1.75\times 10^{-3} \text{ rad s$^{-1}$} \\
r = 12\text{ cm} = 1200\text{ m}$$
$$\begin{align}\therefore v &= (1.75\times 10^{-3} \text{ rad s$^{-1}$})\times (1200\text{ m}) \\
\therefore v &= 2.1\text{ ms$^{-1}$}\end{align}$$

12 cm = 0.12 m, not 1200 m ,,,,,,,
