How to solve the following system of equations. $2x^2-3xy+2y^2=2\frac{3}{4}\\x^2-4xy+y^2+\frac{1}{2}=0$
I tried all the methods that I know, but I could't isolate $x$ or $y$ to form one equation.

Hint 
Multiply the second by $2$, substract the result from the first. So, $x^2$ is gone and you express $x$ as a function of $y$. Plug it into one of the equations to get one equation in $y$.
