How many ways are there to place $5$ balls into $8$ boxes? $8$ boxes are arranged in a row. In how many ways can $5$ distinct balls be put into the boxes if each box can hold at most one ball and no two boxes without balls are adjacent?

HINTS:
Start by satisfying the claim that "no two empty boxes are adjacent".
For this you will need $4$ balls and I let you figure out in how many ways these can be arranged so that there are no empty boxes next to each other.
Finally you have $1$ ball left. How many empty boxes are left? 
Hope this helped
If you need more guidance, please let me know.
