How to evaluate $\lim\limits_{h \to 0} \frac {3^h-1} {h}=\ln3$? How is
$$\lim_{h \to 0} \frac {3^h-1} {h}=\ln3$$
evaluated?

Using the formula
$$\lim_{x \to 0} \frac {a^x-1} {x}=\ln a,$$
we have for $a = 3$
$$\lim_{h \to 0} \frac {3^h-1} {h}=\ln 3.$$
