Archimedean Solids Definition: Is Uniformity Necessary? Is every convex and isogonal polyhedron uniform? That is, are the faces of a convex isogonal polyhedron all regular polygons?
If so, then the Archimedean solids could be defined as convex and isogonal, ditching uniformity. If not, then any counterexample would be helpful.
The reason I think this would be interesting is because the Catalan solids need not be uniform, since the dual of a uniform polyhedron need not be uniform. However, it would make the definitions symmetrical to define the Catalan solids as convex isohedral polyhedra, setting aside the Platonic solids and infinite families.

A rectangular box with different side lengths, e.g. side lengths $2$-by-$2$-by-$4$, has all angles $90^\circ$. So it is convex and isogonal but not regular.
