Find the least value of x which when divided by 3 leaves remainder 1, ... A number when divided by 3 gives a remainder of 1; when divided by 4, gives a remainder of 2; when divided by 5, gives a remainder of 3; and when divided by 6, gives a remainder of 4. Find the smallest such number.
How to solve this question in 1 min?
Any help would be appreciated. :)

Hint $\ $ Apply the ubiquitous constant case optimization of CRT 
$$\ x\equiv m_i\!-\!2\!\!\!\pmod{m_i}\iff x\!+\!2\equiv 0\!\!\pmod {m_i}\iff m_i\mid x\!+\!2\iff {\rm lcm}\{m_i\}\!\mid x\!+\!2$$
