Solving inequality in complex plane I have to graphically represent the following subset in the complex plane being z a complex number:
$A={1<|z|<2}$
However after trying to do it on WolframAlpha it says that "inequalities are not well difined in the complex plane". 
What I did previously was solve it like it was a regular inequality system in the real numbers, resulting in $b<-a+4$ and $b>-a+1$
How can I solve this? 

The geometric interpretation of this would be an open annulus centred at $0$ with inner radius $1$ and outer radius $2$.
To see this, observe that $|z|$ represents the Euclidean distance from $z$ to $0$. The condition $1 < |z|$ restricts $z$ to be outside of the unit disk, and similarly for $|z| < 2$.
