The first 3 terms of the expansion of $\left(1+\frac{x}{2}\right)\left(2-3x\right)^6$ According to the ascending powers of $x$, find the first $3$ terms if the expansion of 
$$\left(1+\frac{x}{2}\right)\left(2-3x\right)^6$$
For the expansion of $$(2-3x)^6 $$
The first 3 terms are $$64 -576x + 2160x^2$$
Now, are the required 3 terms are 
$$64-576x + 2160x^2$$
Or
$$32x -288 x^2 +1080 x^3 $$
Or otherwise ?

Add the two together, and keep the terms with $x^0$, $x^1$, and $x^2$. So the answer is $$64+(32-576)x+(2160-288)x^2$$
