Taylor's Tangent Approximation This is my question,
A function of 2 variable is given by,
$f(x,y) = e^{2x-3y}$
How to find tangent approximation to $f(0.244, 1.273)$ near $(0,0)?$
I need some guidance for this question.
Am i suppose to do the linear approximation or quadratic approximation?
Need some explanation for the formula. Thanks

More precise approximation we obtain if represent $f(x,\,y)$ as $$f(x,\,y)=e^{2x-3y}=e^3e^{2x-3y-3}=e^3e^{2x-3(y-1)}.$$ Then apply formula for tangent approximation to function $g(x,\,y)=e^{2x-3(y-1)}$
with $a=0; \,b=1.$
