Find Elementary Matrics E1 and E2 such that $E_2E_1$A = I I am studying Linear Algebra part-time and would like to know if anyone has advice on solving the following type of questions:
Considering the matrix:
$$A = \begin{bmatrix}1 & 0 & \\-5 & 2\end{bmatrix}$$
Find elementary Matrices $E_1$ and $E_2$ such that $E_2E_1A = I$
Firstly can this be re-written as?
$$E_2E_1 = IA^{-1}$$
and that is the same as?
$$E_2E_1 = A^{-1}$$
So I tried to find $E_1$ and $E_2$ such that $E_2E_1 = A^{-1}$:
My solution:
$$A^{-1} = \begin{bmatrix}1 & 0 & \\{\frac {5}{2}} & {\frac {1}{2}}\end{bmatrix}$$
$$E_2 = \begin{bmatrix}1 & 0 & \\0 & {\frac {5}{2}}\end{bmatrix}$$
$$E_1 = \begin{bmatrix}1 & 0 & \\1 & {\frac {1}{5}}\end{bmatrix}$$
This is the incorrect answer. Any help as to what I did wrong as well as suggestions on how to approach these questions would be aprpeciated.
Thanks

You can reduce A to I in two elementary row transformation,


*

*$R_2 + 5R_1 \rightarrow R_2$

*$\frac{1}{2} R_2 \rightarrow R_2$


An elementary matrix is a matrix that differs from I in exactly one elementary transformation. It turns out that you just need matrix corresponding to each of the row transformation above to come up with your elementary matrices. For example, the elementary matrix corresponding to the first row transformation is,
$$\begin{bmatrix}1 & 0\\5&1\end{bmatrix}$$
Notice that when you multiply this matrix with A, it does exactly the first elementary row transformation. So, this is $E_1$. Similarly, figure out $E_2$ by getting the elementary matrix corresponding to the second transformation.
