Embedding $\mathbb{R}$ into $S^{2}$ Does there exist an embedding $f: \mathbb{R} \rightarrow S^{2}$ with a closed image? I believe not, but I'm stuck with how to prove that.
It would be nice to hear several different proofs if my guess is true.

Let $f: \mathbb R \to S^1$ topological embedding and let $R=f(\mathbb R)$. If $R$ is closed in $S^1$ $R$ is compact and $f$ is a homeomorphism between a compact and a non compact topological space. This is a contradiction.
