Determine which of the following relation is a function? Given two set $ A = \{0, 2, 4, 6\}$ and $B = \{1, 3, 5, 7\}$, determine which of the following relation is a function?
$(a) \{(6, 3), (2, 1), (0, 3), (4, 5)\}$,
$(b) \{(2, 3), (4, 7), (0, 1), (6, 5)\}$,
$(c) \{(2, 1), (4, 5), (6, 3)\}$,
$(d) \{(6, 1), (0, 3), (4, 1), (0, 7), (2, 5)\}$.

My attempt :
"So far I know that for an equation to be functional, any x value cannot be repeated. You cannot have two x's. Y can repeat however much it wants to but despite that not being able to determine which are functional.

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output.
So, according definition of function, given relations with domain $A = \{0, 2, 4, 6\}$,
$(a) \{(6, 3), (2, 1), (0, 3), (4, 5)\} = \{ (0, 3),(2, 1), (4, 5),(6, 3)\}$ is function , since it defines for every element of function $(i.e.\{0, 2, 4, 6\})$ and has exactly one output for each element.
$(b) \{(2, 3), (4, 7), (0, 1), (6, 5)\} = \{(0, 1),(2, 3), (4, 7), (6, 5)\}$ is function , since it defines for every element of function $(i.e.\{0, 2, 4, 6\})$ and has exactly one output for each element.
$(c) \{(2, 1), (4, 5), (6, 3)\}$ is not a function, since it defines on element $0$ of element of function $(i.e.\{0, 2, 4, 6\})$.
$(d) \{(6, 1), (0, 3), (4, 1), (0, 7), (2, 5)\} = \{(0, 3),(0, 7),(2, 5),(4, 1),(6, 1) \}$ is not a function, since it not has exactly one output of element of function $(i.e.\{0, 2, 4, 6\})$. Element $0$ have two output $3$ and $7$.
Reference@Wikipedia.
