Determine how many $4$ digit numbers divisible by $5$ can be generated using the set: $\{1,3,5,6,7,8\}$ 
Determine how many $4$ digit numbers divisible by $5$ can be generated using the set: $\{1,3,5,6,7,8\}$. Repetion is not allowed.

If I am not wrong, we have to use permutation in this question right? I still do not understand how to solve this question. I know that the numbers must end with either $5$ or $0$. Looking at the question I can also tell that there are $5$ possibilities ($1,3,6,7$, or $8$) for the thousands digit, $4$ possibilities for the hundreds digit, $3$ possibilities for the tens digit, and $1$ possibility for the ones digit. I just don't know how to use the formula, and how to show my work. I need someone to show me all the steps, and the answer, so I can use this to solve similar questions. Can someone please help me?

You've almost got the answer to the question.
Just use the multiplication principle.
If you want to use permutations, it's $P(5,3)$.
