How to evaluate the limits of $\int (\sin y) dy$? How to evaluate this integral of $$\int^{\arctan2}_{\arctan \frac{1}{2}} \sin y ~dy$$?
Now I know this is $$-[\cos(\arctan 2)-\cos(\arctan 0.5)]=[\cos(\arctan 0.5)-\cos(\arctan 2)]$$ but I have no idea how to figure this out without a calculator.

So in my answer I mention the significance of triangles. Another poster has so I'll reiterate.
For $\arctan(\frac{1}{2})$ draw a right angled triangle, denote one side (not the hyp) to be of length 2, and the other not-hyp as length 1.
Which angle is $\arctan(\frac{1}{2})$ - good, now what's the $\cos$ of this angle.
Repeat or relate $\tan(\theta)$ to $\tan(\frac{1}{\theta})$ to complete answer.
(SE is against doing homework questions)
