Can't seem to solve a radical equation? Question is : $\sqrt{x+19} + \sqrt{x-2} = 7$ So there is this equation that I've been trying to solve but keep having trouble with.   
The unit is about solving Radical equations and the question says
Solve:
$$\sqrt{x+19} + \sqrt{x-2} = 7$$
I don't want the answer blurted, I want to know how it's done, including steps please.
Thank you!

Multiply both sides by $\sqrt{x+19} -\sqrt{x-2} $ to get
$$x+19 -(x-2) = 7 (\sqrt{x+19} - \sqrt{x-2}) \\
21 = 7 (\sqrt{x+19} - \sqrt{x-2}) \\
3 =\sqrt{x+19} - \sqrt{x-2}$$
Adding this to the original equation you get
$$2\sqrt{x+19}=10 \Rightarrow x+19=25 \Rightarrow x=6$$
P.S. You can find the same method employed in my answer here:
to this similar question
