Card Drawing Probability If three cards are drawn randomly from a normal playing deck without replacement, what is the probability that two end up being black and one red? I did the problem and came up with 13/102. My Saxon book said 39/102 or 13/34. They got that by adding together the probabilities of the three color combinations, which are all equal to each other. But I don't care what order I draw those colors in. Why do they add together those three events when I only draw the three cards once?

'Without replacement' means that you draw the cards one after the other, hence the order in which the cards are drawn is important. The red card may be drawn on the first, second or third draw, so the required probability is $3\times\frac{13}{102}$.
Edit. You may do the same exercise by assuming the cards are drawn simultaneously, as noted by @JMoravitz in the comments. The same answer is obtained without talking about order of drawing.
