How to find the radix in number system.? I have 
$(132)_{10} = (2010)_r$ 
I have tried the above .. I got the answer that $2(r^3)+r =132 $
From this I am unable to find the value of $r$. Can anyone help me out to solve this problem?

Our goal is to find a positive integer solution to $2 r^3 + r - 132 = 0$.
To proceed, we use the rational root theorem, which states that any rational solutions $\frac{p}{q}$ must have $p$ dividing $-132$ and $q$ dividing $2$.
Factoring $132$ gives you $2^2 \cdot 3 \cdot 11$. So here are all the possibilities (ignoring sign):
$q = 1$ or $2$
$p = 2$ or $3$ or $4$ or $6$ or $11$ or $\dots$ or $132$
Now observe $4$ is a solution to $2 r^3 + r - 132 = 0$.
