What's the equation of the graph $y=x^3-x^2+x-2$ after it is reflected in the x axis, and then the y axis as well? I don't fully understand the steps to reach the answer. 
I've plotted the graph and I found out that the graph is an odd graph and that after reflecting in both axes, the only thing that changes on the graph are the points where it intersects the x & y axis. 
I would like to see the algebraic steps one would take on how to solve this equation to better grasp what is going on, thanks.

1)Reflection about $x-$axis:
$(x,y) \rightarrow (x,-y)$;
2)Reflection about $y$-axis:
$(u,v) \rightarrow (-u,v)$;
Combining:
3) $(x,y) \rightarrow (x,-y) \rightarrow (-x,-y)$.
Given : $y=f(x) =x^3-x^2+x-2$;
We have $(x,f(x)) \rightarrow (-x,-f(x))$, the reflected graph .
$(-x)$ is mapped to $-f(x)$, or
$x = -(-x)$ is mapped to $-f(-x)$.
The reflected graph is $(x,-f(-x))$, or
$y = -( (-x)^3 -(-x)^2+(-x) -2)$.
