Solve $ 11 \cdot 16^{1/(n-1)} = 16^{n/(n-1)} - 10 $ This is probably an easy task for the users here, but I could not solve it.
$$
11 \cdot 16^{1/(n-1)} = 16^{n/(n-1)} - 10
$$
Wolfram Alpha gives the result $ n= 5 $.
What are the steps to solve this?

$11\times 16^{\frac{1}{n-1}}=16^{1+\frac{1}{n-1}}-10=16\times 16^{\frac{1}{n-1}}-10$, so $5\times 16^{\frac{1}{n-1}}=10$, so $16^{\frac{1}{n-1}}=2$, so $\frac{1}{n-1}=\frac{1}{4}$, so $n=5$.
