Is following tautology: $((A∧B)→C)≡((A→C)∨(B→C))$ I came across following problem:

Is following tautology:
$((A ∧ B) → C) ≡ ((A → C) ∨ (B → C))$

I solved it like this:

$(A\wedge B)\rightarrow C$
$=\neg(A\wedge B)\vee C$
$=(\neg A\vee \neg B) \vee C$
$=\neg A\vee \neg B \vee C$
$=\neg A\vee \neg B \vee C \vee C$ $\hspace{15pt}(\because C\vee C=C)$
$=(\neg A\vee C)\vee(\neg B\vee C )$
$=(A\rightarrow C)\vee(B\rightarrow C)$

So I concluded that it is a tautology.
But when I checked the answer it was given that it is not a tautology. So I checked wolframalpha and it also seem to give different truth tables for the two: 
$(A\wedge B)\rightarrow C$:

$(A\rightarrow C)\vee(B\rightarrow C)$:

Where did I make mistake?

There is no mistake.  The order of the rows in the tables are different, that's all.
The one False entry in the last column is when $A=T, B=T, C=F$ in both tables.
Look here
