How do you solve this radical equation $\sqrt{2x+5} + 2\sqrt{x+6} = 5$? I have a radical equation 
$$
\sqrt{2x+5} + 2\sqrt{x+6} = 5
$$
and I am having trouble calculating an answer. I keep on getting weird numbers that are not correct as my answer. How do you solve this?  A step-by-step procedure would be highly appreciated.

In fact my answer is the practical explanation of Old John's answer:
$$ [\sqrt{2x+5}+2 \sqrt{x+6}]^{2} = (2x+5)+4\sqrt{(2x+5)(x+6)} +4(x+6) = 25$$
$$ -4-6x = 4\sqrt{(2x+5)(x+6)}$$
$$ 16+48x+36{x}^{2} = 32{x}^{2}+272x+480$$
$$ x= -2 $$
$$ x= 58 $$
Then you check if they are solutions to the initial equation. You will get $x=-2$
