system of linear congruences How can I solve this system of linear congruences? $$2x\equiv 0\, \text{mod 3}\\ 3x\equiv 2\, \text{mod 5}\\ 5x\equiv 4\, \text{mod 7}$$
I don´t know where to start, I am having a lot of troubles, can you lend me a hand please?

Hint $\ {-}2x\equiv -3\,$ mod $5,7\!\iff\! {\rm mod}\ 35\!:\ x\equiv 3/2\equiv 38/2\equiv 19\equiv 54.\,$ $\ 2(54)\equiv 0\pmod 3.$
