What is the probability that he counts head more that tails when tosses a coin 6 times Suppose kitty tosses a coin 6 times. What is the probability that she counts more "heads" than tails?
This is a question from the test and I got only partial marks so I am wondering what is the solution to this.
What I did was I assume the number of coin outcomes,for example: hhhhhh,tttttt,and so on and I use the formula P(E) = n(E)/n(S) 
where n(E) is the number of events n that has heads more than tails. 

Add up the following:


*

*The probability of getting $4$ heads and $2$ tails is $\dfrac{\binom64}{2^6}=\dfrac{15}{64}$

*The probability of getting $5$ heads and $1$ tails is $\dfrac{\binom65}{2^6}=\dfrac{6}{64}$

*The probability of getting $6$ heads and $0$ tails is $\dfrac{\binom66}{2^6}=\dfrac{1}{64}$


Hence the probability of getting more heads than tails is $\dfrac{15}{64}+\dfrac{6}{64}+\dfrac{1}{64}=\dfrac{22}{64}$
