Help with finding the $\lim_{x\to 0} \tan x \csc (2x)$ So I am trying to figure out the limit
$$\lim_{x\to 0} \tan x  \csc (2x)$$
I am not sure what action needs to be done to solve this and would appreciate any help to solving this. 

$$\lim_{x \to 0} \tan x \csc (2x) = \lim_{x \to 0} \frac{\sin x}{\cos x} \frac{1}{\sin 2x} = \lim_{x \to 0} \frac{\sin x}{\cos x} \frac{1}{2\sin x\cos x}$$ 
Can you take from here?
