Derivative function went wrong I am trying to take the derivative of this function but I am facing some difficulties.
$$f(x)= e^{\ln(e^{7x^2+11})}$$
My answer was : $7e^{(7(x^2))}*14x$
 I cancelled the $\ln$ with the $e$ first, then I downgrade the $7$ and keep the $\exp$. as it is, after that I took the derivative of the $7x^2$ and the result was the one on top.

$$f(x)= e^{\ln(e^{7x^2+11})}=\exp(\ln(\exp(7x^2+11)))$$
So
$$f(x)= \exp(7x^2+11), \implies f'(x)=14x\exp(7x^2+11)$$
