Limit as $x$ approaches 2 is undefined? Does following function have a limit if x approaches 2. Calculate what the limit is and motivate why if it is missing.
$$
\frac{(x-2)^2}{(x-2)^3} =\frac{ 1 }{ x-2}. 
$$
I answered $\frac{1 }{ 0 }= 0 $ undefined is that correct?

The denominator approaches zero and the numerator doesn't, so the limit "does not exist". If you've seen the term "indeterminate", then the reason is that 1/0 is undefined rather than indeterminate.  However it's important to note that 1/0 is not 0, it's undefined.
