How do I integrate the function $\sqrt{(6x + 2)}$? How do you integrate $\sqrt{(6x + 2)}$? 
I've tried to use the following substitutions: let $x = \sin(u)$ and $dx = \cos(u)$ (along the lines of the Yahoo Answers link). I tried looking for simple examples of integrals with square roots on Yahoo Answers and elsewhere by Googling, but couldn't find any simpler ones, and that substitution got me nowhere.

Hints:


*

*Make the $u$-substitution $u = 6x+2$.

*Don't forget that $\sqrt u = u^{1/2}$ and that, for all $n \neq -1$, we have 


$$\int x^n dx = \frac{x^{n+1}}{n+1} + C$$
