In the figure two regular pentagons are shown. Calculate "x". For reference:
In the figure two regular pentagons are shown. Calculate "x".

My progress..I marked the angles I found but I couldn't find the equation to solve
$a_i = \frac{180(5-2)}{5}=108^o\\ \triangle BCG (isosceles) \therefore \measuredangle CGB = 36^o$
If we find $\measuredangle DCF$ the problem is solved because $\measuredangle DJF$ is half of $\measuredangle DCF$


$\angle{FDC} = \angle{DFC} = 180 - 108 = 72$
Therefore, $\angle{DCF} = 180 - 72 \times 2 = 36$
Therefore, $\angle{DCG} = 36 + 108 = 144$
Therefore, $\angle{CDG} = \angle{CGD} = \frac{180 - 144}2 = 18$
Therefore, $\angle{JDF} = 180 - 108 -18 = 54$
Therefore, $x = \angle{DJF} = 180 - 54 \times 2 = 72$.
