Alpha-beta quadratic equation Question: The equation $$3x^2-6x-4=0$$ has roots α and β. Find the value of 1/α + 1/β.
I'd just like confirmation on my answer, as I've already found the answer but am not confident in it.
since αβ=c/a and
      α+β= -b/a
    1/α +1/β= (α+β)/αβ= (-b/a)/(c/a)=2/(-4/3)=-3/2

Yes, it is correct.
You could do also like this. You have to find $a+b$ if $a,b$ are solution to $$3{1\over x^2}-6{1\over x}-4=0$$that is $$3-6x-4x^2=0$$
so $$a+b =-{-6\over -4}=-{3\over 2}$$
