Need help calculating a simple inverse function Quick question.
$$y=\sqrt{2x-x^2}$$
I need the inverse function for some other problem, but I just can't find it.
Could you please point me the steps to solve this?
Thanks

$y=\sqrt{2x-x^2}$
$y^2=2x-x^2$
$y^2-1=-1+2x-x^2$
$1-y^2=x^2-2x+1$
Becoming visible now?
$\sqrt{1-y^2}=x-1$
$x=1+\sqrt{1-y^2}$
But our INVERSE is obtained by switching $x$ and $y$ to get $\boxed{y=1+\sqrt{1-x^2}}$.
