Integration question on $\int \frac{x}{x^2-10x+50} \, dx$ How would I integrate
$$\int \frac{x}{x^2-10x+50} \, dx$$
I am not sure on how to start the problem

Complete the square in the denominator:
$$x^2 - 10x + 50 = x^2 -10 x + 25 + 25 = (x-5)^2 + 5^2$$
Put $x-5 = 5\tan\theta\implies dx = 5\sec^2 x$.
