If a coin is flipped 10 times, what is the probability that it will land heads-up at least 8 times? I absolutely remember learning this is middle school, yet I cannot remember how to solve it for the life of me. Something to do with nCr, maybe? ...
Thanks for any help.

Lets split it into cases: 8 heads, 9 heads, and 10 heads. there are C(10, 8) (10 choose 8)=
45 sequences with 8, C(10, 9)= 10 sequences with 9 heads, and of course 1 case with 10.
45+10+1= 56
