probability question P(A/B) Let's suppose that we have  $\mathbb{P}(A|B)=0.4$ and $\mathbb{P}(B)=0.5$. I have to find $\mathbb{P}( A' \cap B)$ ..I know how to find $\mathbb{P}( A \cap B)$ which is related to $\mathbb{P}(A \setminus B)=\mathbb{P}(A \cap B) \setminus \mathbb{P}(B) $..and here I find $\mathbb{P} (A \cap B)$ but how to find $\mathbb{P}(A' \cap B)$..?

$P(A^{c} \cap B)=P(A^{c} | B)P(B)=[1-P(A|B)]P(B)=[1-0.4](0.5)=0.3$
