How to solve the exponential equation $x^{\log_x (x^2 + x - 2)}=0$ for $x$? How to solve this equation?
$x$ can never be equal to $0$ nor its exponent. Am I right?
$$\large x^{\log_x (x^2 + x - 2)}=0$$

HINT


*

*$\log_x(a)$ answers the question "$x$ to the what is $a$?"

*You are, in fact, taking it to the power of $x$

*While you solve, you should also remember the domain of the logarithm.

