Geometry Inequality Proof: show one side greater than another 
Can someone refresh my memory how to prove this. I am going to be tutoring a high school student. I know $\angle 1 = \angle 2$ and $EG$ is congruent to itself but where do I go from there?

Hint:
Angle $3$ is an exterior angle of triangle EFG, hence angle $3$ > angle $2=$ angle $1$. Then apply the law of sines.
This works directly if angle $3$ is acute. If it is obtuse, angle $FEG$ is acute, and $>$ angle $1=$ angle $2$…
