Solve $\log_7 3 = y$; $\log_7 2 = z$; $x = \log_3 2$ I am trying to figure out they logarithmic equation but it has 3 semicolons and I can not find out what they mean. How do I go about solving it? 
I have to solve for $x$.  The answer should be $z/y$.
$\log_7 3 = y$; $\log_7 2 = z$; $x = \log_3 2$ 

Note that the 3 equations are equivalent to 
$$7^y =3, 7^z=2, \mbox{ and } 3^x=2.$$
Replace the $3$ in the last equation with $7^y$, by dint of the first equation.  And replace the $2$ in the last equation with $7^z$ per the second equation,
and you have
$$(7^y)^x = 7^z$$
or 
$$7^{xy} = 7^z.$$
Therefore $xy = z$ and so $x=z/y.$
