2 of 3 dice are selected randomly and thrown. What is the probability that one of the dice shows 6 1 red die with faces labelled 1, 2, 3, 4, 5, 6.
2 green dice labelled 0, 0, 1, 1, 2, 2.
Answer: 1/9
Please can you show me how to get the answer. I'm confused about joining the events of choosing 2 of 3 dice vs. getting the probability that one of the dice chosen will get a 6 when rolled.
Note: There is an equi-probable chance of getting any of the six sides on a given die.

You can select the dices r,g1 and g2 in following combinations:
(r,g1);(g1,g2);(r,g2) Each combination has the probability of 1/3.
There are two combinations, which can show a 6:(r,g1);(r,g2).
Each of this two combination has a probability of 1/6 showing a 6.
All together it is: $\frac{1}{3}\cdot \frac{1}{6}+ \frac{1}{3}\cdot \frac{1}{6}=\frac{2}{18}$
