Proving that floor(n/2)=n/2 if n is an even integer and floor(n/2)=(n-1)/2 if n is an odd integer. How would one go about proving the following. Any ideas as to where to start?
For any integer n, the floor of n/2 equals n/2 if n is even and (n-1)/2 if n is odd.
Summarize: 
[n/2] = n/2 if n = even

[n/2] = (n-1)/2 if n = odd

Working through it, I try to initially set n = 2n for the even case but am stuck on how to show its a floor...
thanks

You should set $n=2m$ for even numbers, where $m$ is an integer.  Then $\frac n2=m$ and the floor of an integer is itself.  The odd case is similar.
