Find the volume of the function $y=\frac{6}{x}$ Consider the function $y=\frac{6}{x}$ bounded by $y=0$, $x=1$,and $x=3$ and is rotated around the $x$-axis.
Using the disk method I setup the integral as 
$$\pi\int_1^33^2-\left(\frac{6}{x} \right)^2dx $$
solving gave me $42\pi$ but the answer should be $24\pi$, my question is where did I mess up?

The integral should be
$$\pi\int_1^3 \left(\frac{6}{x} \right)^2dx =24\pi $$
where $6/x$ is the radius of the disk at $x$. Also note the volume revolves around $x$-axis, not $y$.
