Help in understanding the Maple answer I tried to find the definite integral of an equation using Maple. It returns the answer to me as a limit. Specifically, it is giving me
$$\lim_{r\to \infty} G(r)$$
What does this answer mean? Do I need to put the limit myself to get the final answer?
Regards.

(incorporating comment into this question)
This is the maple code:
int(2*Pi*lambda*alpha*r*exp(-Pi*r^2*(lambda*alpha-D*ln(Y)))*(1-exp(-Pi*lambda*alpha*(-R^2+r^2))), r = R .. infinity)

Can you please let me know what to do with this answer?

Hint: Using a version with simplified expressions (i.e. straightforward combinations of your parameters) I get with Maple 7
$$G(r) = \int r \exp(-b r^2) \left(1-\exp\left(-c \left(-R^2+r^2\right)\right)\right) d\,r \\
=-\frac{1}{2b\exp(br^2)}+\frac{\exp\left(-(b+c)r^2+cR^2\right) }{2(b+c)}
$$
where you can see that the convergence $r\rightarrow \infty$ depends on the sign of $b$ and $b+c-\;$ If both are positive the limit should be 0 and the integral
would be 
$$-G(R) = \frac{ce^{-R^2 b}}{2b(b+c)}$$
