Graphing Parabolas ( finding area) Find the area of the triangle formed by the origin and the points of intersection of parabolas $y=−3x^2+20$ and $y=x^2−16$.
I tried graphing it. I could figure out what it meant when it's said formed by the origin. Please help.
Could someone also please post a picture of the two graphs using online because I don't know how to do it.


Find solutions to $$\begin{cases}
y=-3x^2+20\\
y=x^2-16
\end{cases}$$
$$-3x^2+20=x^2-16$$
$$36=4x^2$$
$$9=x^2$$
$$x=\pm 3\implies y=9-16=-7$$
So the solutions are $(3,-7)$ and $(-3,-7)$. The area is equal to 
$$S=\frac{6\cdot 7}{2}=21$$
