A question on roots of a Quadratic. If roots of the equation ${ax}^2+bx+c=0$ are of the form $$\frac{\alpha}{\alpha-1},\frac{\alpha+1}{\alpha}$$
Then the value of $$({a+b+c})^2$$
I have no clue how to approach this one, any help is appreciated!

From the form:
$\frac{1}{x} + x = 2$ => $x^2 + x -2 = 0$, and first equation is $kx^2 + kx - 2k = 0$.
So, $(a+b+c)^2=0$
