binomial limit when limit approches to infinity $\displaystyle \lim_{n\rightarrow\infty}\binom{n}{x}\left(\frac{m}{n}\right)^x\left(1-\frac{m}{n}\right)^{n-x}$
solution i try 
$\displaystyle \lim_{n\rightarrow\infty}\left(\frac{m}{n}\right)^x\left(1-\frac{m}{n}\right)^{n-x}=\lim_{n\rightarrow\infty}(\frac{m}{n}+1-\frac{m}{n})^n=1$
I have edited my post 
This is wrong how i find right answer. Help me

Assuming that $x>0$
$$\displaystyle \lim_{n\rightarrow\infty}\left(\frac{m}{n}\right)^x\left(1-\frac{m}{n}\right)^{n-x}$$
$$\displaystyle \lim_{n\rightarrow\infty}\left(\frac{m}{n}\right)^x\left(1-\frac{m}{n}\right)^{n} \left(1-\frac{m}{n}\right)^{-x}=$$
$$0\times e^{-m} \times 1 =0$$
Assuming $x=0$ the limit is $$1\times e^{-m} \times 1 =e^{-m}$$
Assuming $x<0$ the limit is $$\infty \times e^{-m} \times 1 =\infty$$
