Find the value of $x$ which is correct I have one exercise which is $$(x+2013)(x+2014)(x+2015)(x+2016)+1=0$$
I tag $A=x+2013$ or other for many ways but still can not find the first $x$ value. please help.

$a(a+1)(a+2)(a+3)+1=0$ thus $(a^2+3a)(a^2+3a+2)+1=0$ thus let $a^2+3a=x$ thus $b^2+2b+1=0 so b=-1,-1$ thus $a^2+3a+1=0$ thus $a=\frac{-3\pm(\sqrt{5})}{2}$ and accordingly $x$ will be approximated 
