Proving a relation between area of triangle and square of its rational sides Let d be a positive integer.The question is to prove that there exists a right angled triangle with rational sides and area equal to $d$ if and only if there exists an Arithmetic Progression $x^2,y^2,z^2$ of squares of rational numbers whose common difference is $d$
I tried using Heron's formula to get a relation between squares of sides and area but i failed and couldnot proceed.Is this an instance of an already known result I am unaware of?Any ideas?Thanks.

Hint:
If $y^2- d = x^2, y^2, y^2+d = z^2$, then: $z-x $ and $z+x $ are the legs of the right-angled triangle, area $= \frac {z^2-x^2}{2} = d $ and rational hypotenuse $2y $ because, $2 (x^2+z^2)=4y^2$.
