Differentiating this problem $\frac{2t^{3/2}}{\ln(2t^{3/2}+1)}$ How does one differentiate the function
$$y(t)=\frac{2t^{3/2}}{\ln(2t^{3/2}+1)}.$$
I am still tying to understand MathJaX and not sure what is wrong with the expression.
Anyways,
How do I start/process solving this? Do i take the ln of both side? If so I get the log of the top - the log of the bottom. which is the log of a log? If I do the quotient rule right away, i get the log expression in the bottom squared. Help please?

In this case the quotient rule is probably the best option. The symmetry of the $2 t^{2/3}$ in the top and bottom makes me suspect that some things might end up canceling out.
