Please help with derivative question Here's my question:

A metal bar is heated to a certain temperature and then the heat source is removed. At time t minutes after the heat source is removed, the temperature, x degrees Celcius, of the metal bar is given by $x = \dfrac{280}{1+0.02t}$ At what rate is the temperature decreasing 100 minutes after the removal of the heat source?

I'm guessing the chain rule needs to be employed; as in $\dfrac{dx}{dt} = \dfrac{dx}{du}\dfrac{du}{dt}$ but couldn't figure out exactly how? Help appreciated, thanks!

I guess that if you want to apply the chain rule then what you want to do is to write your function as
$$
x(t) = 280(1 + 0.02t)^{-1}
$$
and then it's derivative can be found by applying the chain rule as follows. Following your notation you can let $u = 1 + 0.02t$ and then you have $x = 280u^{-1}$. Therefore
$$
\frac{dx}{dt} = \color{green}{\frac{dx}{du}} \color{red}{\frac{du}{dt}} = \color{green}{-280u^{-2}} \color{red}{(0.02)} = \frac{-280(0.02)}{u^2} = \frac{-5.6}{(1 + 0.02t)^2}
$$
Then with the derivative in hand I guess you can figure out the rate at which the temperature is decreasing 100 minutes after.
