Finding Anchor and Reference Point of a Cube Root Function. My brother sent me a question from his Pre-Calculus Study Guide. I have been studying math for $4$ years and don't ever recall seeing a question like this. 
The question: 
Graph $f(x) = (-1/2)(x+1)^{1/3} - 2$ on the axis provided. You must include the anchor and reference point to receive full credit. 
Any advice on how to approach would be appreciated. 

First plot
$x^{1/3}$.
It goes through the origin.
The change to
$(x+1)^{1/3}$
moves it $1$ to the left
so it goes through
$(-1, 0)$.
The change to
$-\frac12(x+1)^{1/3}$
turns it upside-down
and compresses is vertically
by a factor of $2$.
The final change to
$-\frac12(x+1)^{1/3}-2$
moves it down by 2.
And that's the way it is.
