Is it correct? $n^{(\log\,x)} = x^ {(\log\,n)} $? Is it correct?
$$n^{(\log\,x)} = x^ {(\log\,n)} $$
Can you proof and describe that, for any base?
Please explain completely.
Thank you.

$
n^{(\log x)} = (e^{\log n})^{(\log x)} = e^{(\log n)(\log x)} = e^{(\log x)(\log n)}= (e^{\log x})^{(\log n)} =  x^{(\log n)}
$
If you use $\log$ to a different base $b$, then use $b$ instead of $e$.
