Help With SAT Maths Problem (Percentages and Numbers) I usually solve SAT questions easily and fast, but this one got me thinking for several minutes and I cannot seem to find an answer.
Here it is:

In 1995, Diana read $10$ English and $7$ French books. In 1996, she read twice as many French books as English books. If 60% of the books that she read during the 2 years were French, how many English and French books did she read in 1996?
(A) $16$, (B) $26$, (C) $32$, (D) $39$, (E) $48$

Could you please help me by either giving hints or explaining how to solve the problem?
I cannot find, in any way, the number of books of any language she read in 1996. I have tried a lot of operations with percentages, but no results.
Sorry for this question, as I am not very good at Maths.
Thank you.

Total English books: $x=10+E$
Total French books: $y=7+F$
Where $E$ and $F$ are English and French books in 1996.
We know $F=2E$
Thus:
Total books: $T=x+y=17+E+F$
We know that $0.6t=y$ that is 
$0.6(17+E+F)=7+F\implies 0.6(17+3E)=7+2E$ - solve this for $E$
Which is sufficient to work it out :)
