Evaluate:$\int_{l}(z^2+\bar{z}z)dz$ 
Evaluate:
  $\displaystyle=\int_{l}(z^2+\bar{z}z)dz\,\,\,\,\,\,\,\,\,\,l:|z|=1,0\leq\arg z\leq\pi$

My try:
$$\int_{l}(z^2+\bar{z}z)dz=\int_{0}^{\pi}(r^2e^{2i\theta}+re^{i\theta}???)dz$$
I'm stuck here, hints?

Hint : $z \bar z =|z|^2$ $$\Rightarrow \int_{l} z^2dz+|z|^2\int_{l}dz$$
