Numerical Value for $\lim \limits_{n \to \infty}\frac{x^n}{1+x^n}$ 
Let $$f (x) := \lim \limits_{n \to \infty}\frac{x^n}{1+x^n}$$
Determine the numerical value of $f(x)$ for all real numbers $x \ne -1$. For what values of $x$ is $f$ continuous?

I honestly do not know how to find the numerical value.  I don't even know what this means as the teachers notes do not seem to cover this topic directly.
For the second part the answer seems too obvious, so I feel like my thinking is off.
$f$ is continuous for all values of $x$ except for $x=-1$ and where $n$ is not odd.
Any assistance on this is greatly appreciated.

In general you have for $f(x)=\frac{x^n+P(x)}{x^n+Q(x)}$ that $\lim \limits_{n \to \infty}f(x)=1$ if $P$ and $Q$ are polynomials both of degree less than $n$ (divide numerator and denominator by $x^n$ to see this).
With your function $f(x)=\frac{x^n}{x^n+1}$ you have no discontinuity when $n$ is even (because the denominator never is zero)  and just one discontinuity at $x=-1$ when $n$ is odd (because the denominator becomes zero).
