If $ f(x)=x^2-3x+1$ then $ f(x-2) = ?$ If $ f(x)=x^2-3x+1$ then $ f(x-2) = ?$
I'm not sure how to properly deal with this function and solve for $f(x-2)$.

Hint: You have $f(x)=x^2-3x+1$, now instead of $x$ just put $x-2$ and evaluate: $$f(x-2)=(x-2)^2-3(x-2)+1.$$
In general, if you have $f(x)$ and you want to find $f(m)$ just replace all the $x$ with $m$. 
