why $\sin^{-1}(x)+\cos^{-1}(x) = π/2$ How do i  find  the  When $x$ is  ranging from $-1$ to $1$?
I want know why $\sin^{-1}(x)+\cos^{-1}(x) = π/2$
I have already tried inverse-function.
thanks.

Draw a right triangle whose hypotenuse has length $1$ and say the side of it opposite one of the angles, $\theta$ has length $x.$ Then the side of it adjacent to the other acute angle is that same side of length $x$. The other acute angle is $\pi/2-\theta.$
So $\theta = \sin^{-1} x$ and $\pi/2-\theta = \cos^{-1} x.$ Add those together.
