Find $\frac{y}{x}$ from $3x + 3y = yt = xt + 2.5x$ I need to find the ratio of
 $$\frac{y}{x}$$
If given that
$$3x + 3y = yt = xt + 2.5x$$
So what I tried is:
$$t = \frac{3x + 3y}{y}$$
And then put it in the equation
$$\frac{x(3x + 3y)}{y} + 2.5x = \frac{(3x + 3y)}{y}y$$
$$\frac{x(3x + 3y)}{y} + 2.5x = 3x + 3y$$
$$\frac{3x^2}{y} + \frac{3yx}{y} + 2.5x = 3x + 3y$$
$$\frac{3x^2}{y} + 3x + 2.5x = 3x + 3y$$
$$\frac{3x^2}{y} + 2.5x = 3y$$
Here I got stuck. I didn't know how to find the ratio. Can someone help me?

Solve to get 
$$t = \frac{5x}{2y-2x} = \frac{3(x+y)}{y}$$
This gives the quadratic equation:
$$ 6x^2 - 5xy - 6y^2 = 0 $$
Factorize to get:
$$(3x + 2y) (2x - 3y) = 0$$ 
yielding 
$$\frac{y}{x} = \frac{-3}{2} \,\,\,\text{or} \,\,\,\frac{2}{3}$$ 

Thus unless some sort of restriction is placed on $x$ or $y$ 
(for e.g both > $0$), $\frac yx$ can assume $2$ distinct values.
