Find the numbers in A.P. those sum is $24$ and product is $440$ 
If the sum of three numbers in A.P. is $24$ and their product is $440$, find the numbers.

My Approach: Let the numbers be $a,a+d,a+2d$ 
So, according to question $$3a+3d=24$$ $$a+d=8$$ and $$a(a+d)(a+2d)=440$$ $$8a+ad=55$$ I can’t proceed from here. 
Please help.

Let the numbers be : $a-d, a, a+d$ 
Then According To Question.  $$a-d+a+a+d=24$$ $$a=8$$ and $$(a-d)(a)(a+d)=440$$ $$(8-d)(8)(8+d)=440$$ $$(8-d)(8+d)=55$$ $$64-d^2=55$$ $$-d^2=-9$$ $$d=\pm3$$ $\therefore$ the A.P. is $$5,8,11$$ $$**OR**$$ $$11,8,5$$
