Two riders and their distance Two riders have distance between them $118$ km and they are moving   towards each other to meet . B starts an hour later by A. A travels $7$km in hour while B travels $16$km every three hours. How many kilometers(km) will A have already traveled, once they meet each other?
Could anyone help me with this puzzle?

Let us assume the time taken by them to meet for A=$x$ and for B=$y$. So now we know speed.time=distance so now we can generate 2 equations $7x+\frac{16y}{3}=118$...(1) and B starts 1 hour late $x-y=1$ ..(2) solving them we get $x=10,y=9$ . Hope its clear.so distance travelled by $A=7.t=7.10=70km$
