Difficult Ordinary Differential Equation? I was wondering how to solve the following ODE:
Find $y(1)$ given $y(0)=1$ and
$\frac{dy}{dx}=2ye^{-5x^2}$
So far I got:
$\int \frac{1}{y} dy = 2 \int e^{-5x^2} dx$
On the left hand side I got $\ln|y|$ but did not know how to continue on the right hand integral. Any help would be greatly appreciated.

Following Robert Israel's guidance the solution has the form
$$y(x) = c_{0} \, \exp\left[\frac{\pi}{\sqrt{5}} \, \operatorname{erf}(\sqrt{5} \, x)\right].$$
Since $y(0) = 1$ and $\operatorname{erf}(0) = 0$ then
$$y(x) = \exp\left[\frac{\pi}{\sqrt{5}} \, \operatorname{erf}(\sqrt{5} \, x)\right].$$
Now,
$$y(1) = e^{\frac{\pi}{\sqrt{5}} \, \operatorname{erf}(\sqrt{5})} = 4.066422474604290915236336...$$
