Evaluate $\lim_{x\to49} \frac{x-49}{\sqrt{x}-7}$ Evaluate $\lim_{x\to 49} \frac{x-49}{\sqrt{x}-7}$ 
I'm guessing the answer is 7 but again that is only a guess. I don't know how to solve this type of problem.
Please help.

Since both numerator and denominator go to $0$, you can apply L'Hospital's Rule.
Since the answer hasd been given, I guess it is safe to demonstrate:
$$
\begin{align}
\lim_{x\to49}\frac{x-49}{\sqrt{x}-7}
&=\lim_{x\to49}\frac{1}{\frac1{2\sqrt{x}}}\\
&=\lim_{x\to49}2\sqrt{x}\\
\end{align}
$$
