How to draw the graph of $x^6 = y^3$ and $3y = (\log x)^2$? For example, if the equation is $x^4 = y^2$ then I can separate this to get the two equations $y = x^2$ and $y = - x^2$ , hence I can plot the two graphs. But how do I simplify the given equation?
I have understood how to draw the graph if the first equation, could you please help me with the second graph?

Fortunate you, there will arise only one case while solving $y^6=x^3$, since you're having cube over $x$, hence the expression will simply reduce to

$y^2=x$


