What is the value of $x$ in $222^x−111^x∗7=111^x$? Can anyone help me on this? It is for a 8th grader.

What is the value of $x$ in $222^x-111^x*7=111^x$?

I know the equation can be rearranged as $222^x=111^x*7-111^x=6*111^x$. Then what is next?

$$222^x-111^x\cdot7=111^x$$
$$\implies(2\times111)^x-111^x\cdot7=111^x$$
$$\implies2^x\cdot111^x-7\cdot111^x=111^x$$
$$\implies111^x(2^x-7)=111^x$$
$$\implies2^x-7=1$$
$$2^x=8$$
$$\implies x=3$$
