Factoring over a set of complex numbers  Ahem. I can only now laugh at how blind I am to not see such a simple answer, LMAO. Thanks to Isaac ♦, Paul VanKoughnett, and Bill Dubuque! 
Case closed!
How would you factor  $6x^2 + 18x - 60$  over a set of complex numbers?
When I did it myself, I had  $6(x - 1.5 + 3.25i)(x - 1.5 - 3.25i)$ .
I am not 100% sure about my answer, so I am asking anyone who knows how to do this to help me confirm the answer! (:
- EDIT -
Well, first thing that I did was to factor out 6.
$6(x^2 + 3x - 10)$ , then I changed the expression into a perfect square, so : 
$6(x^2 - 3x + 2.25) - 12.25$ . 
After that:  $6(x - 1.5)^2 + (-12.25)$ .
Then I took the square roots of that, so I got:
$6(1 - 1.5)^2 + 3.5i)$  .
Thus my answer:  $6(x - 1.5 + 3.25i)(x - 1.5 - 3.25i)$
And I see that it is wrongggggg~
My teacher did not go over it much; she was rushing throughout the whole lesson and her accent does not make it any easier. The textbook does not have anything on it. I looked around the index and there is nothing. -_____-

The answer is wrong since $\rm\ 3.25^2 \ne 10\:\ $ It appears that you made the error of computing the discriminant as $\rm\ 9^2 - 24\cdot 60\ = 39^2\ $ instead of $\rm\ 18^2 -24\cdot 60 = 42^2\:$.
Simpler: apply the quadratic formula to $\rm\ p(x)/6 = x^2 + 3x -10\:$, or apply the Rational Root test.
