Is $\sqrt{|xy|}$ equal to  $\sqrt[4]{x^2y^2}$? This is a noob calculus question.
(1) $\sqrt{|xy|} = \sqrt[4]{x^2y^2}$, 
are the 2 expressions equal?
if yes to (1),
then why $\frac{d}{dx}\sqrt{|xy|} \neq \frac{d}{dx}\sqrt[4]{x^2y^2}$ ?
as $\frac{d}{dx}\sqrt{|xy|} =\frac{\sqrt[4]{x^2y^2}}{2x} $ 
but $\frac{d}{dx}\sqrt[4]{x^2y^2} = \frac{0.5xy^2}{(x^2y^2)^{0.75}}$
i obtained the above derivatives from wolfram alpha.
-updated- yup, i think they are just 2 different way of presentation, seems like they have the same graph, thanks for the clarification.

They are indeed equal.  This follows since
$$\begin{align}
\sqrt[n]{x^n} = \left\{
\begin{array}{ccc}
|x| & & n \text{ is even}
\\
x & & n \text{ is odd}
\end{array}
\right.
\end{align}$$
The derivatives are indeed equal (although the derivatives of neither function exist at $0$).
