Two riders and their distance Two riders have distance between them $118$ km and they are moving   towards each other to meet . B starts an hour later by A. A travels $7$km in hour while B travels $16$km every three hours. How many kilometers(km) will A have already traveled, once they meet each other?
Could anyone help me with this puzzle?

Note that
$$\mbox{speed·time = distance}$$
So, the distance $d$ by A after time $t$ is
$$d = 7t.$$
Since both A and B have to meet and B started 118km away an hour later, the position of B will be given by
$$118 - d = \frac{16}{3}(t-1).$$
Thus, you now have a system of two equations and two unknowns, I guess you can continue from there.
