Probability of drawing balls from a box There are four red and six blue balls in a box. Three balls are drawn from the box randomly. What is the probability of drawing at least two red balls?
This seems pretty simple but I can't seem to find the right answer for some reason.

Three balls can be drawn from the box in a total $\binom{10}{3}$ ways. Now, the no. of ways the three balls can have at least $2$ red balls is $\binom{4}{2}\binom{6}{1}+\binom{4}{3}$. The first factor is due to $2$ red one blue and the next factor is due to all three red.
So, probability is $$\frac{\binom{4}{2}\binom{6}{1}+\binom{4}{3}}{\binom{10}{3}}$$
