how to solve this gamma function i know that $\Gamma (\frac {1}{2})=\sqrt \pi$ But I do not understand how to solve these equations
$$\Gamma (m+\frac {1}{2})$$
$$\Gamma (-m+\frac {1}{2})$$
are there any general relation to solve them
for example:
$\Gamma (1+\frac {1}{2})$
$\Gamma (-2+\frac {1}{2})$

By the functional equation $$\Gamma(z+1)=z \, \Gamma(z)$$ (which is easily proved for the integral definition of $\Gamma$ by parts, and may be used to analytically continue the function to the negative numbers) we find $$\Gamma(1 + \frac{1}{2}) = \frac{1}{2} \Gamma(\frac{1}{2})$$ and $$\Gamma (-2+\frac {1}{2}) = \frac{1}{-1+\frac {1}{2}}\Gamma (-1+\frac {1}{2}) = \frac{2}{-1+\frac {1}{2}}\Gamma (\frac{1}{2})$$
