Can we simplify this logarithm? if so, please provides some tips ${|x|^{11/10}} \log_{|x|^{{1/10}}}|x|$.
I only know  doing the first step, not sure if it is correct
$\log_{|x|^{{1/10}}}(|x|^{|x|^{11/10}})$
as got stuck following this proof.  Please help understand how we can get step two from step one.


Consider
$$y=x^a\log_{x^b} (x)$$ Using the laws of logarithms
$$y=\frac{x^a \log (x)}{\log \left(x^b\right)}=\frac{x^a \log (x)}{b\log \left(x\right)}=\frac 1b x^a$$
