Equations - Solving for x I have this problem:
$$9x^3 - 18x^2 - 4x + 8 = 0$$
However, I'm not sure how to find the values of $x$. I moved the 8 over and factor out an $x$, but the trinomial it created can't be factored. Could someone enlighten me?

Factor the function.
$9x^3-18x^2-4x+8=9x^2(x-2)-4(x-2)=(x-2)(9x^2-4)=(x-2)(3x-2)(3x+2)$
$(x-2)(3x-2)(3x+2)=0$
$x=2$ or $2/3$ or $-2/3$
