2 of 3 dice are selected randomly and thrown. What is the probability that one of the dice shows 6 1 red die with faces labelled 1, 2, 3, 4, 5, 6.
2 green dice labelled 0, 0, 1, 1, 2, 2.
Answer: 1/9
Please can you show me how to get the answer. I'm confused about joining the events of choosing 2 of 3 dice vs. getting the probability that one of the dice chosen will get a 6 when rolled.
Note: There is an equi-probable chance of getting any of the six sides on a given die.

Out of the three possible choosings, two contain the die with a $6$. (Chance $2/3$)
If the die is selected, then there is a chance in six to get a six. (Chance $1/6$)
The total chance is:
$$\frac{2}{3}·\frac{1}{6} = \frac{2}{18} = \frac{1}{9}$$
