Speed of light, and limits From the theory of relativity there is this equation:

$$m=\frac{m_0}{\sqrt{1-(\frac{v^2}{c^2}})}$$

The problem asks to find the mass of the an object as it approaches the speed of light. I know the answer is $+\infty$, but I don't know how to write the limit. Would I just assume its like a regular function?
Assumption

$$f(v)=\frac{m_0}{\sqrt{1-(\frac{v^2}{c^2}})}$$
$$\lim_\limits{v \to c^-}(\frac{m_0}{\sqrt{1-(\frac{v^2}{c^2})}})$$
$$m_0 \lim_\limits{v \to c^-}((\sqrt{1-\frac{v^2}{c^2}})^{-1})$$

I just typically get up to there, and state that the mass, $m$ would approach $+\infty$.  Are my assumptions correct, as well as my answer?

I think the most intuitive way to do this is in pieces.
As $v\rightarrow c^-$, we get $\frac{v^2}{c^2}\rightarrow 1^-$, so $1-\frac{v^2}{c^2}\rightarrow 0^+$, $\sqrt{1-\frac{v^2}{c^2}}\rightarrow 0^+$, and finally $\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\rightarrow +\infty$.
