Solve $x-1 \ge \sin(x)$ I got as far as $-1 = \sin(x)-x$.
I don't know what to do next. Pretty sure I am forgetting some simplification rule.

It seems analytic solution is more subtle .so,by numerical methods ,You can try Newton-Rephson method ,


*

*F(X)=sinx-x+1=0.

*X2=x1-(f(x1)/f'(x1)). X1 is initial point.

*x1 =(a+b)/2, where f(a)*f(b)<0.

*as per required accuracy iteration can be done.

