French playing cards, probability to have a four (of a kind) We have a "French playing cards" composed of $52$ cards. Each kind of cards (Ace, King, Queen, ...) is composed of $4$ cards :  There are $4$ Ace, $4$ Jack, etc. We pull $5$ cards among the $52$ cards.
We are a four (of a kind) if among the $5$ cards pulled, there are the $4$ of a same value ($4$ cards Ace, or King, or 2, or 3......).

What is the probability to have a four (of a kind) if the first card pulled is an Ace, and the fifth card pulled is a King ?
I hope you understand, it's very difficult for me to translate that. Thank you for help in advance.

Here is a hint:
Given that you have drawn one ace and one king, you will need either to draw the remaining three aces, or draw the remaining three kings, from the remaining $50$ cards.
Can you continue from this point?
(Spoiler answer)

 There are two winning ways to draw the remaining three cards, and ${50 \choose 3}$ total ways to draw the remaining three cards, so the probability is $2/{50 \choose 3}$.

