Solve for $z$ in $z^5=32$ This was the last question on my Year 11 Complex Numbers/Matrices Exam
Name all 5 possible values for $z$ in the equation $z^5=32$
I could only figure out $2$. How would I go about figuring this on paper?

We have $z^5=2^5$ or $$\left(\frac{z}{2}\right)^5=1$$ then we have the solutions are $$z=2*\large{(e^\frac{2ki\pi}{5})}$$ where $k=0,1,2,3,4.$
