Texas hold 'em odds If I have a $6,7$ spades in my hand, and the flop shows $4$ clubs, $5$ spades and $Q$ spades. What is the probability I will hit my straight or flush with $2$ cards still to come?  I see $15$ cards that help me with $32$ that don't help me. So about $32\%$ with one card. But with $2$ yet to come?

To do this, let's find the chances of missing your draw first, because that's actually easier. Let's break this entire scenario down into three situations: either the first card helps, so the second card doesn't matter (good); the first card doesn't help but the second card does (also good); or neither card helps (bad). The chances of the first card not helping are $32\over47$ (number of cards not helping over total number of cards available at this point); this would rule out the first scenario but leaves open the second. Given this, the chances of the second card also not being helpful is $31\over46$, to rule out the second scenario. Thus, the chances of missing your draw are $32\times31\over47\times46$, making the chances of hitting your draw $1-\frac{32\times31}{47\times46}$, or about 54.12%.
