Trigonometric Identities Need Help I'm struggling with this. Can someone help me?
I need to make $$-\sin(x)$$ into $$(\cot(x)-\csc(x))(\cos(x)+1)$$
Does anyone know the solution?
Thank you.

$$\sin x=\frac{\sin^2 x}{\sin x} $$
$$\frac{\sin^2 x}{\sin x} = \frac{1- \cos^2 x}{sin x} = \frac{(1- \cos x)(1+\cos x)}{sin x} = {(\csc x- \cot x)(1+\cos x)} $$
So
$$-\sin x = {(\cot x - \csc x)(1+\cos x)} $$
