Find 3rd side, given two sides and bearings The bearing from A to B is N $42^\circ$ E. The bearing from B to C is S $44^\circ$ E. A small plane traveling $65$ miles per hour, takes $1$ hour to go from A to B and $2$ hours to go from B to C. Find the distance from A to C.

You have $<ABC = 42+44 = 86^\circ$, and $AB = 65$, $BC = 130$. Use law of cosine to get the answer.
