Solving $y'(x) = \frac{y(x)}{3x-y^2(x)}$? Solving $y'(x) = \frac{y(x)}{3x-y^2(x)}$ ? I'm trying to solve this first order non-linear equation. I've tried to plug in a couple of different things and would appreciate if anyone could point me in the right direction. 

$\dfrac{dy}{dx} = \dfrac{y}{3x-y^2}\implies \dfrac{dx}{dy}=\dfrac{3x-y^2}{y}\implies \dfrac{dx}{dy}= \left(\dfrac{3}{y}\right)x-y$
