Solve for $x$ in $2\log(x+11)=(\frac{1}{2})^x$ Solve for $x$.
$$2\log(x+11)=(1/2)^x$$
My attempt:
$$\log(x+11)=\dfrac{1}{(2^x)(2)}$$
$$10^{1/(2^x)(2)}= x+11$$
$$x=10^{1/(2^x)(2)}-11$$
I'm not sure what to do next, because i have one $x$ in the exponent while the other on the left side of the equation.

Hints:
$$2\log(x+11)=\frac14\implies \log(x+11)=\frac18\implies \color{red}{x+11=e^{1/8}}\ldots$$
