I can't find the critical points for this function. I showed my work :) So, I have to find Critical Points of $y=\frac{1}{(x^3-x)}$
I know the derivative.
Derivative = $(3x^2-1)/(x^3-x)^2$
To find Critical Points I equal to $0$.
$x=1/\sqrt3$ and $x=-1/\sqrt3 $
But Critical points are the Max and Min value of your graph... and the graph is a little tricky... I don't know what to do... Because in my opinion, there are no critical points. It goes to infinity and -infinity.
Opinions? Help please!


The points you found are just local extrema. Regarding the + and - $\infty$, you can simply note that those are local maxima of the function.
