Propositional logic and distributive law I am having trouble trying to understand how this question passes from this point
$$
( ( p\vee q )\wedge  (p \vee \neg r  )  \wedge (\neg q \vee \neg r ) ) \vee  ( \neg p \vee r  ) 
$$
to this
$$
(p\vee q \vee \neg p \vee r)\wedge(p \vee \neg r \vee \neg p \vee r)\wedge(\neg q \vee \neg r \vee \neg p \vee r)
$$
$$
T \wedge T \wedge T = T
$$
I'm sure it has to do something with the distribution law ($p\vee(q \wedge r) =(p\vee q)\wedge(p \vee r)$) but I'm confused on how it is applied. Can anyone give me a heads-up on where and how I should start expanding?

The first formula is of the form
$$(A\land B\land C)\lor D$$
while the second one is
$$(A\lor D)\land(B\lor D)\land(C\lor D)\,.$$
