Find Laplace transform of $(sin^2 2t)$ Find Laplace transform of $(\sin^2 2t)$
How do I go about this ? 
do I spilt them up like 
$ L ( \sin 2t) \cdot L (\sin 2t) $ ?

Given $\sin^22t$
$$\sin^22t=\dfrac{1-\cos4t}{2}$$
$$L(\sin^22t)=\dfrac{L(1)-L(\cos4t)}{2}=\dfrac{1}{2s}-\dfrac12\left(\dfrac{s}{s^2+16}\right)$$
