The ring of idempotents Let $R$ be a commutative ring. Then its ring of idempotents $I(R)$ consists of the idempotent elements of $R$, with the same multiplication as in $R$, but with the new addition $x \oplus y := x+y-2xy$. (This addition might look a bit mysterious, but when we identify idempotent elements with the clopen subsets of $\mathrm{Spec}(R)$  via $x \mapsto D(x)$, then $I(R)$ is nothing else than the boolean algebra of clopen subsets with multiplication $\cap$ and addition $\Delta$.)
We obtain a functor $I : \mathsf{CRing} \to \mathsf{Bool}$, where $\mathsf{CRing}$ denotes the category of commutative rings and $\mathsf{Bool}$ the category of boolean rings. My question is: Does this functor $I$ have a left or right adjoint? Or does $I(R)$ have any universal property?

In a boolean ring every element is idempotent and, since the characteristic is $2$, we have $x\oplus y=x+y$. So, for a boolean ring $B$, $I(B)=B$. If $i$ denotes the embedding functor $\mathsf{Bool}\to\mathsf{CRing}_2$, the category of rings with characteristic $2$. This suggest there is an adjunction between $i$ and $I$, because $I(i(B))=B$.
In the case of characteristic $2$, the $\oplus$ operation is the same as $+$, so the adjunction is almost obvious, because it's just composing with the inclusion $I(R)\hookrightarrow R$.
There's no general adjunction of the embedding $\mathsf{Bool}\to\mathsf{CRing}$, because there are no ring morphisms from a boolean ring to a ring with, say, characteristic $0$.
