Struggling with BIDMAS. This question came up an I'm not sure about it:
You need to simplify leaving  the answer in standard form:
$\dfrac{2((3-3^2)^2)}{3+\sqrt{4^2-7}}$
I struggle to work it out myself. When I used a calculator it said 12. But you only get 12 if it's $3.464101614^2$. What do you think and how you worked it out.

Assuming your expression is:
$$2\left(\frac{(3-3^2)^2}{3+\sqrt{(4^2-7)}}\right)$$
Simplifying we get:
$$2\left(\frac{(3-9)^2}{3+\sqrt{(16-7)}}\right)$$ 
$$2\left(\frac{36}{3+\sqrt{(9)}}\right)$$ 
$$2\left(\frac{36}{3+3}\right)$$
$$2\left(\frac{36}{6}\right)=12$$
