Why is there no solution set for $|x-7|<-4$? I am asked to find the solution set fot $|x-7|<-4$.
I arrived at $(-\infty, 3)\cup(11, \infty)$
For $x - 7 > 0$:
$x-7<-4$ 
=> $x<3$
For $x-7 < 0$: 
$-(x-7)<-4$ 
=> $-x+7<-4$ 
=> $-x<-11$ 
=> $x>11$
So, I arrive at a solution set of:
$(-\infty, 3)\cup(11, \infty)$
However, my textbook says "no solution". Why is there no solution?

If you graph the solution on a x-y plane you get...
As you can see if you graph all of these according to y, $|x-7|$ can never reach -4, hence, no solution. :))
