Why is $\lim_{x \to \infty}\ln\left(\frac{x}{x+1}\right) = 0$? This equation goes like this: $$\lim_{x \to \infty}\ln\left(\frac{x}{x+1}\right) = 0$$
Can you help me understand the logic behind the above equation?

The logarithm function is continuous (so that the limit of the logarithm is the logarithm of the limit) and its argument tends to $1$ (because the inverse, $1+1/x$, tends to $1$).
