Compute a laplace transform 
Compute $\mathcal{L} [e^{-2x} \sin x]$

So I want to do $\int_0^\infty e^{-2x} \sin x e^{-px} \, dx=\int_0^\infty e^{-(p+2)x}\sin x \, dx$
But due to the way $e$ and $\sin x$ integrates I dont know where to go from here?

Hint. One may write
$$
\int_{0}^{\infty}e^{-(p+2)x}\sin x dx=\text{Im}\int_{0}^{\infty}e^{-(p+2-i)x}\:dx=\text{Im}\:\frac1{p+2-i}=\frac1{(p+2)^2+1}, \quad p>-2.
$$
