Compute the expression $(a^2 + 4b - 1)(b^2 + 4a - 1)$ without calculating the roots of $x^2 - x - 5 = 0$ Let $a$ and $b$ be the roots of this equation:
$$x^2 - x - 5 = 0$$
Find the value of
$$(a^2 + 4b - 1)(b^2 + 4a - 1)$$
Without calculating the values of a and b.
I saw this on a problems site and tried it but I got 100 and I don't think that's correct.

Hint:
$$
a^2 + 4b - 1 = a^2 - a - 5 + 4b + a + 4 = 4b + a + 4
$$
