Permutations and Combinations Heads/Tails Out of all of the potential sequences of 73 Heads/Tails games, each being Heads or Tails, how many sequences contain 37 tails and 36 heads? 
Express the output in terms of factorials. 
Because there are sequences of 73 games my initial thought is, that the answer would be $\frac{73!}{36!\cdot 37!}$. 
Would this be correct?

You are correct. The number of coin flip sequences of length $n$ with exactly $k$ heads is $$\binom{n}{k} = \frac{n!}{k!(n-k)!},$$ because that is the number of ways to choose the $k$ positions in which the heads appear. Letting $n = 73$ and $k = 36$ gives you your answer.
