Prove that $Z_{14}/(7)$ ≅ $Z_7$ Prove that $Z_{14}/(7)$ ≅ $Z_7$.
I understand that I have to show that there exists a surjective function relating the two and use the morphism theorem, but I'm not sure how in this case. Any help would be great, thank you in advance!

Hint: There is one specific, very natural, surjective homomorphism $\Bbb Z_{14}\to\Bbb Z_7$ (it exists because $7$ divides $14$). Its kernel is $(7)$. And the image of any homomorphism is isomorphic to the domain divided by the kernel.
