Find the number of distinct throws which can be thrown with $n$ six faced normal dice which are indistinguishable among themselves. Find the number of distinct throws which can be thrown with $n$ six faced normal dice which are indistinguishable among themselves.
The total outcomes will be $6^n$. But this this has many cases repeated since the dice are indistinguishable among themselves.

Consider six faces as six beggars and n identical dice to be identical coins.
Now,number of distributions is C(n+6-1,6-1)=C(n+5,5).
If a beggar(say face 6)gets no coin,then it is equivalent to anything which does not appear on the dice.
