Find the number of ways you can put fruits into drawers We have 5 fruits and 3 drawers. I need to find the number of ways I can put the fruits in them when there will be at least one fruit in the lowest drawer and the first and the second fruit won't be in the same drawer.
I tried to do it by the complementary way, I took all of the options $3^5$ and subtruct from it the bad options($2^5$ when there is no fruits in the lowest and $3^4$ when the first and the second are in the same drawer  )
I got to  $3^5-2^5-3^4 =130$ but the answer is 146. 
Thanks in advance!

5 fruit in any of 3 drawers.
$3^5$
Fruit 2 not in the same drawer as fruit 1
$3^4\cdot 2=162$
minus the cases where all of the fruit are in the top two drawers.
$-2^4\cdot 1=16$
$162-16 = 146$
