Find the volume of the function $y=\frac{6}{x}$ Consider the function $y=\frac{6}{x}$ bounded by $y=0$, $x=1$,and $x=3$ and is rotated around the $x$-axis.
Using the disk method I setup the integral as 
$$\pi\int_1^33^2-\left(\frac{6}{x} \right)^2dx $$
solving gave me $42\pi$ but the answer should be $24\pi$, my question is where did I mess up?

The integrand is incorrect. It should be just $(\frac{6}{x})^2$. There's no reason to subtract this from $3^2$.
