logarithm properties problem The problem in question is:
$3^{x+3} = 5e^{7x}$
I have tried:
$(x+3) *ln(3) = 7x *ln(5)$
$ln(3)/ln(5) = 7x/(x+3)$
And that is where I stall out. I assume it is because I made an error somewhere along the way. Would anyone mind pointing it out?

$$ 3^{x+3} = 5e^{7x} $$
$$ (x+3)\ln 3 = \ln(5e^{7x}  ) = \ln 5 + 7x $$
$$ x\ln 3 - 7x = \ln 5 - 3\ln 3 \Rightarrow x(\ln 3 - 7) = \ln 5 - 3\ln 3 \Rightarrow x = \frac{\ln 5 - 3\ln 3}{\ln 3 - 7} $$
