Integrating $x/(x-2)$ from $0$ to $5$ How would one go about integrating the following?
$$\int_0^5 \frac{x}{x-2} dx$$
It seems like you need to use long division, split it up into two integrals, and the use limits. I'm not quite sure about the limits part.

Shashwat, the antiderivative of $1/x$ is not $\ln(x)$, but $\ln|x|$.
So in the computation there wouldn't be any natural log of $-2$.
The reason that this integral does not exist, is as stated earlier, the discontinuity issues at $x=2$.
