Finding the intersection of a line with $x,y,z$ coordinate planes How do I find the points at which the line given by the symmetric equation:
$$
\frac{-x - 1}{-1} = \frac{y + 5}{2} = \frac{z - 6}{-3}
$$
intersects the coordinate planes $xz$, $yz$, $xy$?

Hint: Just do it. For example, the intersection with the coordinate plane $xz$ means that $y=0$, which gives 
$$ \frac {-x-1}{-1} = \frac {0 + 5}{2} = \frac {z-6}{-3}. $$
