Find the symmetric difference of two finite sets Find the symmetric difference, $A \triangle B$, where $A=\{6,7,8,9,10\}$, and
$B$ is the set of odd integers between $5$ and $10$. The end points are exclusive.
I think the only answer it could be is $10$. If it is not can someone point me into the right direction?

$A\Delta B = (A -B)\cup(B-A)=(A-B)\cup \emptyset=A-B=\{6,8,10\}$  

 For "$A\Delta B = (A -B)\cup(B-A)$", see here.

