$ \int \frac{x^2-x}{x+\sqrt {x}}\, \mathrm{d}x$ My problem, is how to find the integral of $$ \int \frac{x^2-x}{x+\sqrt {x}}\, \mathrm{d}x$$
And I don't even know where to start. I tried factoring out x, but I don't get anything useful. I need some suggestions please. 
I appreciate your help!

Observe that $x^2-x=(x+\sqrt{x})(x-\sqrt{x})$
