Is it possible to evaluate $232^2-62^2\times14$ by factoring or using identities or...? The expression $232^2-62^2\times14$ can be calculated directly ($53824-3844
\times14=8$). But is it possible to evaluate it for example by factoring or using identities?
Here is what I have tried,
$$(58\times4)^2-62^2\times14=58^2\times16-62^2\times14=(60-2)^2(15+1)-(60+2)^2(15-1)$$
Or
$$58^2\times16-62^2\times14=29^2\times64-31^2\times56=(30-1)^2\times8^2-(30+1)^2(8\times7)$$
But I can't see an elegant way to get $8$ from either of the calculatins.

Using a prime decomposition
$$
\begin{align}
232^2-62^2\times14 &= \\
(2^3 \times 29)^2-(2\times31)^2\times2\times7 &= \\
2^3(8\times29^2-(29+2)^2\times7)&= \\
2^3(29^2-28\times29-28) &= \\
2^3(29-28) &= 8
\end{align}
$$
Line 3 above used $31=29+2$ to facilitate further simplification.
