Finding the antiderivative of $f(x)=\sqrt[3]{x^2+2x}$ $$f(x)=\sqrt[3]{x^2+2x}$$. 
Let $g(x)$ be an antiderivative of $f(x)$. If $g(5)=7$, then what is the value of $g(1)$? 
I tried doing integrating by parts repeatedly, but no success. Wolfram Alpha also gives something in a different type of function which I don't know. 
Please help?

If you are confident with a numerical solution , here is it :
Because of 
$$g(5)-g(1)=\int_1^5 (x^2+2x)^\frac{1}{3}dx=9.729162187801335050406060297$$
we get
$$g(1)=g(5)-9.729162187801335050406060297=-2.729162187801335050406060298$$
