imaginary equation of second degree I have the follow equation:
$$ix^2−x+2i=0$$
After resolve it with mathway (a web that resolves the equation step by step) I can't understand the last step.
Having:
$$x=\dfrac{1\pm3}{2i}$$
I take $+2i,-i$ from "$4/2i$" and "$-2/2$". But the app say that the answer is $-2i,1$.
What I'm doing wrong?

There's a simple fact I think you are missing, that is that $\cfrac{1}{i} = -i$.
Hence the two solutions are $\cfrac{4}{2i} = \cfrac{2}{i} = -2i$ and similarly $\cfrac{-2}{2i} = \cfrac{-1}{i} = i$.
To understand why $\cfrac{1}{i} = -i$ take $\cfrac{1}{i}$ and multiply by $\cfrac{i}{i} = 1$.
