Find the area of the region bounded by lines I have two similar problems, finding the area of the region bounded by lines:


*

*$y=x, y=2-x$ and $y=0$

*$y=x+1$ and $y=\frac{x}{2}$, $x=0$ and $x=4$
I remember (not sure) I should equate the two equations for each number but I'm not sure if I'm correct. 
For example in problem #1, $x=2-x$ thus $ x=1 $. 
But I don't know how to proceed for it. Are the points of intersection in the first problem $(1,1)$ and $(0,0)$?

1.This is a triangle, with height $h=1$ and basis $b=2$. $S=\dfrac{bh}{2}=1$

2.This is a trapezoid, with upper base $b_u=1$ lower base $b_l=3$ and height $h=4$. $S = \dfrac{b_u + b_l}{2} h=8$

