Limit of $[\ln (3+x^2) - \ln (2+x)]$ as $x$ approaches $\infty$ I got an answer as $\infty$ but I need more clear explanation.
Please help me!

$$\lim_{x \to \inf}ln(3+x^2) - ln(2+x)$$ can be symplified as $$\lim_{x \to \inf}ln( \frac{3+x^2}{2+x})$$
So, we can use this as a truth.
$$\lim_{x \to \inf} \frac {1}{x} = 0$$
And we will have
$$\lim_{x \to \inf}ln( \frac{x^2( \frac{3}{x^2}+1)}{x (\frac{2}{x}+1)})$$
As you see, you’ll have $x$ left so the answer is $\inf$
