Probability of winning a game 
$A$ and $B$ play a game. 
  
  
*
  
*The probability of $A$ winning is $0.55$. 
  
*The probability of $B$ winning is $0.35$. 
  
*The probability of a tie is $0.10$. 
  
  
  The winner of the game is the person who first wins two rounds. What is the probability that $A$ wins?

The answer is $0.66$. I don't know how it's coming $0.66$. 
Please help.
EDIT :
The right combinations according to me are
{null,T,TT,TTT....}A{null,T,TT,TTT....}A
{null,T,TT,TTT....}A{null,T,TT,TTT....}B{null,T,TT,TTT....}A
{null,T,TT,TTT....}B{null,T,TT,TTT....}A{null,T,TT,TTT....}A

Ties don't count, don't record them. So in effect we are playing a game in which A has probability $p=\frac{0.55}{0.90}$ of winning a game, and B has probability $1-p$ of winning a game. 
Now there are several ways to finish. The least thinking one is that A wins with the pattern AA, or the patterns ABA, or BAA.   
