Linear algebra help! Find parametric equations for the line
$$x − 2y + 3z = 4, 2x + y − z = −2$$
I know that the first thing you do is cross the vectors perpendicular to the planes, but I'm having a little trouble finding the point of intersection - can I just set $x, y,$ or $z$ to $0$ and take it from there?

Points on the line that is the intersection of the two planes will satisfy the system of linear equations
$$x-2y+3z=4\\2x+y-z=-2$$
which has as it's solution
$$x=-t/5\\
y=-2+7t/5\\
z=t$$
where $t$ is a parameter which maps out the intersection line as it varies over $\mathbb{R}$.
