Find all the equilibrium points of this second-order equation $x''+2x'=3x-x^3$ Find all the equilibrium points of this second-order equation $x''+2x'=3x-x^3$
I know that you must the roots of the equation, but when the equation isn't equal to $0$ I am confused on where to begin, thank you for any help!
edit: sorry, i did leave out a prime in there.  It is fixed now

The equilibrium points are such that $x'=x''=0$. Hence $x=0,\pm\sqrt3$.
