Solving for x with exponents (algebra) So I am trying to help a friend do her homework and I am a bit stuck. 
$$8x+3 = 3x^2$$
I can look at this and see that the answer is $3$, but I am having a hard time remembering how to solve for $x$ in this situation. 
Could someone be so kind as to break down the steps in solving for $x$.
Thanks in advance for replies. 

Rewrite the equation as $3x^2-8x-3=0$ and then use the quadratic formula with $a=3,b=-8,c=-3$.
$$
x=\frac{8\pm\sqrt{64+4*3*3}}{2*3} = \frac{8\pm 10}{6} = 3,-\frac{1}{3}
$$
