Determine if improper integral is convergent or divergent Determine if $$\int_1 ^\infty \frac {dx}{x^2+x} $$ is divergent or convergent. If convergent: determine its value.
Tip: When $ x\ge1  $ is $ \frac 1 {x^2} \ge \frac 1 {x^2+x} = \frac 1 {x} - \frac {1} {x+1} $
Don't really know where to start here. Finding convergence/divergence really difficult so any tips on how to tackle questions like this one is appreciated. 

HINT
Note that for $x\to \infty$
$$\frac {1}{x^2+x}\sim \frac{1}{x^2}$$
then use limit comparison test with $\int_1 ^\infty \frac {1}{x^2}dx$.
