Find volume of the solid generated by revolving Find volume of the solid generated by revolving the region bounded by the parabola
$ =^2+1 ,=0 $ and the line =3 about the line =3
Using Disk method,I found the answer to be 9.4

$$V=\pi \int_{y_0}^{y_1} (R(y))^2dy$$ $$=\pi \int_{0}^{\sqrt{2}} (3-(y^2 +1))^2dy$$ $$=\frac{32\sqrt{2}\pi}{15}\approx 9.478$$
You're correct.
