Greatest possible measure of $\angle A$ in an isosceles triangle $ABC$ I am a high schooler studying for the SAT, and I came across this question.

In isosceles triangle $ABC$, side $\overline{BC}$ is longer than the other two sides. If the degree measure of $\angle A$ is a multiple of 22, calculate the greatest possible measure of $\angle C$.
(A) 78
(B) 88
(C) 75
(D) 86
(E) 79

The correct answer according to the study guide is (E) 79.
But in the very first sentence of the question, it is stated that side $BC$ is longer than the other two sides, and we know that sides $BA$ and $AC$ are equal in length because this is an isosceles triangle.
That means that $\angle A > 60°$.
Were they just throwing in the part about $BC$ being longer to confuse me?

If BC is longer than the other 2 sides, then the other 2 sides must be equal because the triangle is isosceles. If indeed they claim that the answer is E, that implies that angle C (79°) is bigger than angle A and thus side AB must be bigger than side BC.
So this is clearly incorrect.
This is not the first time I have come across such a question from ACT, SAT
