Find the angle between hour hand and minute hand at 1:59? I have got the formula to find angle between hour hand and minute hand from   
http://en.wikipedia.org/wiki/Clock_angle_problem
The angle between the hands can be found using the formula:
$$\begin{align} \Delta\theta &= \left|\theta_{\text{hr}} - \theta_{\text{min.}}\right| \\ &= \left|\frac{1}{2}(60H + M) - 6M\right|\\ &= \left|\frac{1}{2}(60H - 11M)\right| \end{align}$$
where$    \scriptstyle H$ is the hour
  $  \scriptstyle M$ is the minute. 
According to this formula at 1:59, H=1, M=59  
$ \Delta\theta=|\dfrac{60\times 1-11\times 59}{2}|=294.5^\circ$ which is not true. What is the problem, please help.

Why wouldn't it be true? The angle is formed from the hour hand clockwise towards the minute hand. If you'd like an angle less than $180^\circ$, take
$$\min(360^\circ - \Delta \theta, \Delta \theta).$$
