Are the square roots of all non-perfect squares irrational? I was asked to define a non-perfect square. Now obviously, the first definition that comes to mind is a square that has a root that is not an integer. However, in the examples, 0.25 was considered a perfect square. And the square itself + its root were both not integers.
Is it that all non-perfect squares have irrational roots, e.g. $\sqrt{2}$?

In the integers, a perfect square is one that has an integral square root, like $0,1,4,9,16,\dots$  The square root of all other positive integers is irrational.  In the rational numbers, a perfect square is one of the form $\frac ab$ in lowest terms where $a$ and $b$ are both perfect squares in the integers.  So $0.25=\frac 14$ is a perfect square in the rationals because both $1$ and $4$ are perfect squares in the integers.  Any rational that has a reduced form where one of the numerator and denominator is not a perfect square in the integers is not a perfect square.  For example, $\frac 12$ is not a perfect square in the rationals.  $1$ is a perfect square in the integers, but $2$ is not, and there is no rational that can be squared to give $\frac 12$
