$\lim\inf a_n = 0$ as $n$ goes to infinity Let $(a_n)$ be a sequence of positive numbers such that for every $m$ in the natural numbers there is $n$ in the natural numbers such that $a_n = \frac{1}{m}$.
Prove $\lim\inf a_n = 0$ as $n$ goes to infinity.
I want to some suggestions on how to "approach" this problem because as it is all that i am seeing is that infact there is no n for the expresion a_n i double checked with other peers and there is no miscopy this leaves me kind of distraught.
i need to understand how to approach this in general if there is any advice for this i would greatly appreciate it!

For any $\epsilon > 0 $ and $N \in \mathbb{N}$ for how many $n>N$ can you find $0 < a_n < \epsilon$?
