What is $\int_0^3 x^2e^{-x}\ dx$? Getting a different answer. So I was solving some papers and I came across this problem. The answer is supposed to be $2-17/e^3$, but I'm getting $1/e^3 + 2$. I'm not familiar with the formatting and am in a hurry so please excuse the poor formatting. Thanks in advance!

HINT Integration by parts 2 times, each time differentiate the polynomial and integrate the exponential function.
