How to prove $|z - z_0|^{-1 + \epsilon}$ is bounded This is the question from Stein and Shakarchi Complex Analysis. 

Suppose that $f(z)$ is holomorphic in a punctured disc $D_r (z_0) - \{z_0 \}$. Suppose also that $|f(z)| \leq A |z - z_0|^{-1 + \epsilon}$ for some $\epsilon > 0$, and all $z$ near $z_0$. Show that the singularity of $f$ at $z_0$ is removable. 

My instinct is to use Riemann's theorem on removable singularities and show that $f$ is bounded near $z_0$. My guess is that's why the inequality is given in the question, but $|z - z_0|^{-1 + \epsilon}$ doesn't seem to be necessarily bounded? As a real function at least it definitely isn't if $\epsilon = 0.5$.  

Hint: Multiply both sides by $|z-z_0|$ and take the limit as $z$ tends to $z_0$.
