How do you do partial fraction $\frac2{x^2 - 8}$? How do you do partial fraction on $\frac2{x^2 - 8}$ ? Or are there other method of doing? I tried trig substitution but could not get the answer.

$$\frac{2}{x^2-8}=\frac{2}{x^2-(2\sqrt2)^2}=\frac{2}{(x-2\sqrt2)(x+2\sqrt2)}=\frac{A}{x-2\sqrt2}+\frac{B}{x+2\sqrt2}$$
