What is the value of $x$ in $222^x−111^x∗7=111^x$? Can anyone help me on this? It is for a 8th grader.

What is the value of $x$ in $222^x-111^x*7=111^x$?

I know the equation can be rearranged as $222^x=111^x*7-111^x=6*111^x$. Then what is next?

Actually you got the first step backwards.
$222^x - 7 \cdot 111^x = 111^x$
$222^x = 8 \cdot 111^x$
$(2 \cdot 111)^x = 8 \cdot 111^x$
$2^x \cdot 111^x = 8 \cdot 111^x$
$2^x = 8$
$x = 3$
