Find the probability of winning at this lottery. So, the problem I found goes like this:

You have $n$ different numbers, numbered from $ 1 $ to $n$. You can
  randomly choose $m$ (different) of them. The computer also randomly
  selects $m$ (different) of them. If you and the computer have exactly
  $k$ common numbers, then you win a certain amount of money.

The problem asks us to find the probability of winning.
I have solved some easier problems involving probabilities. But here, the only thing I could think of was that the probability for a certain sequence of $m$ numbers to emerge is:
$$ \frac{1}{\dbinom{n}{m}} $$
How do you solve it? I'm on my way of getting used to this type of problems and I could really use some help.

Let us assume you have picked your $m$ numbers. Now it's the computer's turn. It has to match $k$ of your numbers.  Which $k$? These can be chosen in $\binom{m}{k}$ ways. Then it has to produce $m-k$ numbers which do not match any of yours. This can be done in $\binom{n-m}{m-k}$ ways.
So the number of ways the computer can match $k$ of your numbers is $\binom{m}{k}\binom{n-m}{m-k}$.
For the probability, divide $\binom{m}{k}\binom{n-m}{m-k}$ (the number of "favourables,")  by the number of (equally likely) choices the computer can make. This is $\binom{n}{m}$. 
