5 odd-numbered taxis out of 9 to 3 airports 
A fleet of 9 taxis must be dispatched to 3 airports: three to airport A, five to B and one to C. If the cabs are numbered 1 to 9, what is the probability that all odd-numbered cabs are sent to airport B?

What I have have come up with so far:


*

*Probability the cabs are odd is $\frac59$

*Probability they are sent to only airport B is $\frac13$

*$\frac59 + \frac13 = \frac89$


Is this the right answer?

There is only $1$ way to send all $5$ odd numbered cabs to $B$,
against an unrestricted distribution of $\binom95 = 126$
Thus $Pr = \dfrac1{126}$
