Find the area of the parallelogram with vertices $K(1, 3, 1), L(1, 6, 3), M(6, 12, 3), N(6, 9, 1)$. 
Find the area of the parallelogram with vertices $K(1, 3, 1), L(1, 6, 3), M(6, 12, 3), N(6, 9, 1)$.

I know that I need to get is an equation of the form (a vector) x (a second vector)
But, how do I decide what the two vectors will be from the points provided (since you cannot really draw it out accurately)?
I know you need to pick one point as the origin of the vector and then find the distance to each point, but which point would be the origin?

Given a parallelogram with vertices $A$, $B$, $C$, and $D$, with $A$ diagonally opposite $C$, the vectors you want are $A-B$ and $A-D$. 
