Derive the Quadratic Equation Find the Quadratic Equation whose roots are $2+\sqrt3$ and $2-\sqrt3$.
Some basics:


*

*The general form of a Quadratic Equation is $ax^2+bx+c=0$


*In Quadratic Equation, $ax^2+bx+c=0$, if $\alpha$ and $\beta$ are the roots of the given Quadratic Equation, Then,
$$\alpha+\beta=\frac{-b}{a}, \alpha\beta=\frac{c}{a}$$

I am here confused that how we can derive a Quadratic Equations from the given roots

$$
0 = \left(x-\alpha\right)\left(x-\beta\right)=x^2 -\left(\alpha+\beta\right)x + \alpha \beta
$$
