How to calculate simple trigonometric problem I tried for an hour or so to solve this but I can't show the way to the solution. How does one solve the below problem?
$\tan(\sin^{-1}(1/3))$?
Is the solution periodic because it is a tangent?

Here is how you would do it if you didn't have Wikipedia.
$$\tan\left(\arcsin\left(\frac{1}{3}\right)\right)
=\frac{\sin\left(\arcsin\left(\frac{1}{3}\right)\right)}{\cos\left(\arcsin\left(\frac{1}{3}\right)\right)}
=\frac{\sin\left(\arcsin\left(\frac{1}{3}\right)\right)}{\sqrt{1-\sin^2\left(\arcsin\left(\frac{1}{3}\right)\right)}}
=\frac{\frac{1}{3}}{\sqrt{1-\left(\frac{1}{3}\right)^2}}=\frac{\sqrt{2}}{4}$$
