Rolling die until number is greater than 100 
Possible Duplicate:
Probability of dice sum just greater than 100 

A die is rolled several times and the number appearing is summed. We stop when this sum becomes greater than or equal to 100. What value of sum in the end is the most probable (out of 100, 101, 102, 103, 104, 105)?
105 can be generated in only 1 way : 99 + 6
104 can be generated in only 2 ways: 99 + 5, 98 + 6
and so on.
Assuming that the dice rolling will reach either of numbers in range [94,99] is equally likely, 100 is the most likely. Am I correct?

Let an be the number of ways to get a sum of n:
a100 = a99 + a98 + a97 + a96 + a95 + a94
a101 = a99 + a98 + a97 + a96 + a95
a102 = a99 + a98 + a97 + a96 
a103 = a99 + a98 + a97
a104 = a99 + a98
a105 = a99
So you can see just from this that a100 is the most likely since there are more ways to get to a sum of 100.
In plain language...
In other words, you might have the opportunity to end a game at 100 by rolling a 1, 2, 3, 4, 5, or 6, but you can only end a game at 105 by rolling a 6 on your last roll.
Sum at the penultimate roll
I disagree that sums of [94,99] are all equally likely for your penultimate roll, but it doesn't matter if they are equal or not. It's the last roll that determines the total score, which is the focus here. There are still a98 + a97 + a96 + a95 + a94 more ways to get a sum of 100 than there are to get a sum of 105, for example.
