acceleration formula of parametric curve? I have a parametric curve as follows:
x(t)= 0.236t³-0.645t²+0.909t+0

y(t)= 0.189t³-0.792t²+0.603t+0
which looks like:

Now, I want to find the acceleration of this curve, from when it starts at 0,0 and ends at .5,0. HOW would I do this? It has been years since i took a math course, and I have spent hours and hours on  google trying to figure this out but I cant. can someone please help me in lehmans terms?? thanks in advance!

Hint: The acceleration is the second derivative of position. As such, the acceleration in the x direction would be x''(t), and the acceleration in the y direction would be y''(t). 
