Problem involving combinations. In how many ways can $42$ candies (all the same) be distributed among 6 different infants such that each infant gets an odd number of candies?
I seem to think that we have 42 different objects, and 6 choices. So it should be 42C6. However, I'm not factoring in the "odd number of candies" part of the question, so I'm sure it's wrong. Any help is appreciated.

Each infant must get at least one candle, so you have 36 candles to give out in pairs to 6 infants.  Hence you have 18 pairs to give out to 6 infants.  Can you take it from there?
