Why is $ \lim_{x \to \infty} \ x^{2/x} = 1$ Why is $\displaystyle \lim_{x \to \infty} \ x^{2/x} = 1$ since this is an indeterminate form $\infty^{0}$ and I can't see any manipulation that would suggest this result?

$$x^{2/x} = (e^{\log(x)})^{2/x} = \exp(\frac{2 \log(x)}{x}) \rightarrow \exp(0) = 1 \quad \textrm{as} \quad x \to \infty$$
where in the limit I use the fact that $x$ dominates $\log(x)$ as $x \to \infty$. 
