How can I solve this limit without L'Hopital rule? I have found this interesting limit and I'm trying to solve it without use L'Hopital's Rule.
$$\lim\limits_{x\rightarrow 0}\frac{\sinh^{-1}(\sinh(x))-\sinh^{-1}(\sin(x))}{\sinh(x)-\sin(x)}$$
I solved it with L'Hopital's rule and I found that the solution is $1$. But if I try without this rule, I can't solve it. Any ideas?  

Let $\sin x = y $ , $ \sinh x =  y + z$
Then $L = \lim_{x\rightarrow 0}\frac{\sinh^{-1}(y+z) - \sinh^{-1}(y)}{z} = {\sinh^{-1}}' (0)  = 1 $
($z \rightarrow 0 $ as $ x \rightarrow 0$)
