Bernoulli differential equation help? We have the equation $$3xy' -2y=\frac{x^3}{y^2}$$ It is a type of Bernouli differential equation. So, since B. diff equation type is 
$$y'+P(x)y=Q(x)y^n$$
I modify it a little to:
$$y'- \frac{2y}{3x} = \frac{x^2}{3y^2}$$
$$y'-\frac{2y}{3x}=\frac{1}{3}x^2y^{-2}$$
Now I divide both sides by $y^{-2}$. What should I do now?

Note that in any Bernoulli OE, $$y'+p(x)u=q(x)y^n,~~n\neq1,0$$ you can set $w=y^{1-n}$ and then you have to solve the following linear OE instead: $$w'+(1-n)p(x)w=(1-n)q(x)$$
