Forward Euler Method Given Two Step Sizes I am attempting to compute an approximation of the solution with the forward Euler method in $[0,1]$ with step lengths $h_{1}= 0.2$, $h_{2}= 0.1$ given the initial value problem below
$$\frac{dy}{dz}=\frac{1}{1+z}-y(z)\quad y(0)=1$$
I am not sure what to do when I am given two step sizes instead of one. I know how to compute it if it was given with a step size. Am I supposed to find out the approximation for two different step sizes? Or is there anything I am missing?

The problem asks for solving the differential equation twice. Once for the step size of $h=.1 $ and once for the step size  of $h= .2$ and compare the results. 
As you know different step sizes give you different results with the smaller step size smaller error is made .  
