Integrability of $\int_{\mathbb{R}} 1/(1+|x|)^p d\mathcal{L}(x)$ Let $p>0$. For which $p$ is the integral $\int_{\mathbb{R}} \frac{1}{(1+|x|)^p} d\mathcal{L}(x)$ finite?
I assume $f(x)= \frac{1}{(1+|x|)^p}$ is integrable for $p>1$, but how exactly can I show this?

You can do the following: split the integral al $2$ then
\begin{align*}\int_{\mathbb{R}}\frac{1}{(1+|x|)^p}\,d\mathcal{L}&=2\left( \int_{0}^2\frac{1}{(1+x)^p}\,d\mathcal{L}+ \int_{2}^\infty\frac{1}{(1+x)^p}\,d\mathcal{L}\right)\\
&=2\left( \int_{0}^2\frac{1}{(1+x)^p}\,d\mathcal{L}+ \int_{\color{red}3}^\infty\frac{1}{x^p}\,d\mathcal{L}\right).\end{align*}
The first integral is finite and smaller than $2$ and the convergence of the second depends on $p$ as you said, but the antiderivative is now easy to compute.

Previous reasoning:


*

*For $|x|\leq c$ (c any constant) the integrand is finite so the intergral cannot diverge.

*For $|x|\gg 1$ $\frac{1}{(1+|x|)^p}\approx \frac{1}{|x|^p}$ which is easy to integrate.
