Why outer measure of Vitali set is greater than 0 or equals to 0? In the following conservation (link below)
https://www.researchgate.net/post/Bounds_on_the_outer_measure_of_Vitali_Set_in_0_1
There is a person who said that outer measure of the Vitali set on $[0,1]$ is greater than 0. Anyone can tells me why?

*

*$m^{\star}(A) \ge 0$


*$m^{\star}(A) =0$ implies $A$ is measurable.
Let $\mathcal{V}$ denote the Vitali set.
If $m^{\star} (\mathcal{V}) \not >0$ , then $m^{\star}(\mathcal{V}) =0$ implies $\mathcal{V}$ is measurable.
But $\mathcal{V}$ is non measurable.
Infact $\mathcal{V}$ has full outer measure.
( See here)
