Simple algebra question $$\dfrac{\qquad\dfrac{5p+10}{p^2-4}\qquad}{\dfrac{3p-6}{(p-2)^2}}$$ 
Im all confused about this question. Can someone go through it step by step. Can you please list when I can cancel numbers. Thanks. 

$$\frac{{5p + 10}}{{p^2  - 4}}\bigg/\frac{{3p - 6}}{{(p - 2)^2 }} = \frac{{5p + 10}}{{p^2  - 4}}\frac{{(p - 2)^2 }}{{3p - 6}} = \frac{{5(p + 2)}}{{(p + 2)(p - 2)}}\frac{{(p - 2)(p - 2)}}{{3(p - 2)}} = \frac{5}{3}$$
