Graph of $\log(3-x)$ So if $y=\log(3-x) = \log(-x+3)$ then you reflect $\log(x)$ in the $y$ axis to get $\log(-x)$.
Then because it is $+3$ inside brackets you then shift to the left by $3$ giving an asymptote of $x=-3$ and the graph crossing the $x$ axis at $(-4,0)$. 
However this does not work. The answer shows the $+3$ in the bracket shifting the curve to the right by $3$ giving an asymptote of $x=3$ and the curve crossing the $x$ axis at $(2,0)$. 
Why does it do this? Can anyone please explain?

Note that


*

*$3-x$ put the origin in x=3 (right translation) and reverse axis direction

*thus the vertical asympthote is at $x=3$ and the root is at $x=2$

