Permutations and Combinations Heads/Tails Out of all of the potential sequences of 73 Heads/Tails games, each being Heads or Tails, how many sequences contain 37 tails and 36 heads? 
Express the output in terms of factorials. 
Because there are sequences of 73 games my initial thought is, that the answer would be $\frac{73!}{36!\cdot 37!}$. 
Would this be correct?

Yes that is correct.
You can basically assume that you have 73 boxes and you have to fill 36 boxes with heads and 37 boxes with tails. Thus you can fill heads first and then fill the remaining ones with tails. Thus the answer is $\dbinom{73}{36}$.
