Find the Derivative: This problem for my Calculus 1 class has got me stumped. I am not sure on where to start for this problem. Any help would be much appreciated. 
$y=x\tanh^{-1}(x) + \ln(\sqrt{1-x^2})$

HINTS:
$$\text{arctanh}(x)=\frac12\log\left(\frac{1+x}{1-x}\right)$$
Then, use the product rule along with the chain rule.
Can you proceed now?
