Prove $\sin \left(1/n\right)$ tends to $0$ as $n$ tends to infinity. I'm sure there is an easy solution to this but my mind has gone blank! Any help on proving that $\sin( \frac{1}{n})\longrightarrow0$ as $n\longrightarrow\infty$ would be much appreciated.
This question was set on a course before continuity was introduced, just using basic sequence facts. I should have phrased it as:
Find an $N$ such that for all $n > N$ $|\sin(1/n)| < \varepsilon$

Hint
$$\quad0 \leq\sin\left(\frac{1}{n}\right)\leq \frac{1}{n}$$
