Log function solve for x The function is defined by $y=f(x)=3e^{{1\over3}x+1}$
Solve for $x$ in terms of $y$
My answer:
$$x={\ln({y\over3})-1\over3}$$
Is this the correct way to go about this question?
Update. Finding the inverse and range.
Would the inverse of this function be:
$$f^{-1}(x)=3(\ln({x\over3})-1)$$
and its domain $x>0$

The steps are right. Just don't put the 3 in the denominator at last, multiply 3.
