How to solve $\ln(x) = 2x$ I know this question might be an easy one. but it has been so long since I solved such questions and I didn't find a an explanation on the internet. I'd like if someone can remind me. 
I reached that $e^{2x} = x$, but didn't know how to continue from here. I remember something that has to do with bases and equalizing parameters, but how do I do that in this case? 

Draw a graph. $\log x < 2x $
A proof is by noting that $\log x < 2x$ for $x < 1$ and then differentiating both sides to see that the LHS grows slower than the RHS.
Equivalently, $e^{2x} > x$
