How to solve an Inverse differentiation problem If f is a one-to-one function where $f(3)=2$ and $f'(3)=6$, what is the value of $(f^{-1})'(2)$?
I am not even sure where to start with this question. I was hoping someone can help
$f$ of $3 =2$ and $f$ prime of $3 = 6$ we need to find the value of the derivative inverse of $f$ of $2$

Hint: 
$$(f^{-1})'(2)=\displaystyle\frac{1}{f'(f^{-1}(2))}$$
