why is the solution to $x^2 = 3$ the same as $x = \pm \sqrt 3$ I understand that in order to simplify $x$ in this equation:
$x^2 = 3$ we would need to get the square root  on both sides what i dont understand is the fact that it is written as $x = \pm \sqrt 3$.
I don't understand where the $±$ comes from  , this problem was a part of solving polynomials by factoring and I just want the reasoning behind why it wouldn't simply be $x = \sqrt 3$ but $x = x = \pm \sqrt 3$.
the original equation :
$2x^5+12x^3 -54x = 0$
my solutions :
$x=0 $
$x=\pm \sqrt 3$
$x = \pm 3i$

It comes from the identity $\sqrt{x^2}=|x|$. Now, solve $|x|=\sqrt{3}$. Also, $x^2=3$; $x^2-3=0$; $(x-\sqrt{3})(x+\sqrt{3})=0$
