Solve $4^{9x-4} = 3^{9x-4}$ I am having some trouble trying to solve 
$$4^{9x-4} = 3^{9x-4}$$
I tried to make each the same base but then I'm becoming confused as to what to do next.
These are the steps I took:
$$\begin{align}
4^{9x-4} &= 3^{9x-4} \\
\log_4(4^{9x-4}) &= \log_4(3^{9x-4}) \\
\end{align}$$
Where do I go from there?
Thanks!

So you thought @fasttouch was complex?
Adapted from Mathematica:
$$x =  \frac{4\log\frac{4}{3}- 2 \pi ni}{9 \log \frac{4}{3}},   n \in \Bbb Z$$
