Limit of $\frac{\pi^h-1}{h}$ as h approaches zero Can someone help me find this limit here. I only know how to use L'Hospital's rule but I want to be able to evaluate this limit without using differentiation.
$$\lim \limits_{h \to 0} \frac{\pi^h-1}{h}$$
The reason I want this limit is because just like $e$ can be expressed as $\sum_{n=0}^{\infty}\frac{1}{n!}$ I want to find a way to do the same with $\pi$ so i want to find the dervivative of $\pi^x$ without having $\pi$ in the result.

$$\lim_{x\to 0} \frac{e^{hln\pi}-1}{h} = (H) = $$
$$\lim_{x\to 0} \frac{ln{\pi} * lne^{hln\pi}}{1} = ln \pi $$
