Interpretation of Einstein notation for matrix multiplication Consider the matrix product $C = AB$ where  $A \in \mathbb{R}^{m \times n}, B \in \mathbb{R}^{n \times p}$. The Einstein summation notation for this is
$$
c_{ik} = a_{ij}b_{jk}.
$$
Is there any example from math, physics, engineering, statistics etc. where each term in the sum $a_{ij}b_{jk}$ has a meaningful interpretation?
Equivalently, I guess: suppose we did not use Einstein summation notation, and instead defined $D \in \mathbb{R}^{m \times n \times p}$ as:
$$
D_{ijk} = A_{ij}B_{jk}.
$$
Would the elements of $D$ mean anything with respect to $A, B, C$ or the linear transformations represented by these matrices? Obviously $C_{ik} = \sum_{j} D_{ijk}$, but what does this mean?
Or suppose, instead of summing over the second index of $D$ to get $C$, we instead summed over the first index of $D$ to get $E \in \mathbb{R}^{n \times p}$:
$$
E_{jk} = \sum_{i} D_{ijk}.
$$
Obviously this cannot be represented in Einstein notation. So does this not have meaning as a tensor contraction, and unlikely to have a physical interpretation?
Edit: For the powers of adjacency matrices (eg $C = A^2 = AA$), the terms do have an interpretation. Iff $a_{ij}b_{jk} = 1$ (not using Einstein notation), then there is a path from node $i$ to node $k$ through node $j$.

Define a third order tensor whose components are equal to zero unless all three indices are equal 
$${\cal H}_{ijk} = \begin{cases}
1 \quad{\rm if}\; i\!=\!j=\!k \\
0 \quad{\rm otherwise} \\
\end{cases}
$$
Then you can use Einstein notation to write
$${\cal D}_{ijk} = A_{ip}{\cal H}_{pjs}B_{sk}$$
This tensor is a useful addition to standard matrix algebra. 
It can be used to generate a diagonal matrix $A$ from a vector $a$ (using a single-dot product) 
$$A = \operatorname{Diag}(a) = {\cal H}\cdot a 
\quad\implies A_{ij} = {\cal H}_{ijk}\,a_k$$
or to create a vector $b$ from the main diagonal of a matrix $B$ (using a double-dot product)
$$b = \operatorname{diag}(B) = {\cal H}:B 
\quad\implies b_{i} = {\cal H}_{ijk}\,B_{jk}$$
or simply as a way to write ${\cal D}$ without resorting to index notation
$${\cal D} = A\cdot{\cal H}\cdot B$$
