Simplifying $\frac{ (2x+1) (x-3) }{ 2x^3 (3-x) }$ In simplifying
$$\frac{2x^2-5x-3}{6x^3-2x^4}$$
I got this far
$$\frac{ (2x+1) (x-3) }{ 2x^3 (3-x) }$$
but there aren't same brackets to cancel out.

$$\dfrac{2x^2-5x-3}{6x^3-2x^4}=\dfrac{(2x+1)(x-3)}{2x^3(3-x)}=\dfrac{(2x+1)(x-3)}{2x^3[-(x-3)]}=\dfrac{(2x+1)(x-3)}{-2x^3(x-3)}=\dfrac{2x+1}{-2x^3}$$
