Find the correlation coefficient between $2$ variables Value $A$ is the product of $2$ integers $X$ and $Y$. Each of the last two integers takes values from the set {$1,2,5$} with probabilities: $0.2$, $0.5$, $0.3$. Determine the correlation coefficient between $X$ and $A$.   
Any ideas on how to solve this? I would appreciate any help.

We have
\begin{align}
\mathbb P(X = 1) &= \frac15\\
\mathbb P(X = 2) &= \frac12\\
\mathbb P(X = 5) &= \frac3{10}\\
\mathbb P(A = 1) &= \frac1{25}\\
\mathbb P(A = 2) &= \frac15\\
\mathbb P(A = 4) &= \frac14\\
\mathbb P(A = 5) &= \frac3{25}\\
\mathbb P(A = 10) &= \frac3{10}\\
\mathbb P(A = 25) &= \frac9{100},
\end{align}
and so
$$
\mathbb E[X] = 1\cdot\frac15 + 2\cdot\frac12+5\cdot\frac3{10} = \frac{27}{10},
$$
$$
\mathbb E[X^2] = 1^2\cdot\frac15 + 2^2\cdot\frac12+5^2\cdot\frac3{10} = \frac{97}{10} 
$$
and
$$
\mathrm{Var}(X) = \mathbb E[X^2] - \mathbb E[X]^2 = \frac{97}{10} - \frac{729}{100} = \frac{241}{100}.
$$
Similarly,
$$
\mathbb E[A] =  \frac{729}{100}, \quad \mathbb E[A^2] = \frac{9409}{100},\quad \mathrm{Var}(A) = \frac{9409}{100} - \left(\frac{729}{100}\right)^2 = \frac{409459}{100000}.
$$
Moreover,
\begin{align}
\mathbb E[XA] &= \mathbb E[X^2Y]\\
&= \mathbb E[X^2]\mathbb E[Y]\\
&= \frac{241}{100}\cdot \frac{27}{10}\\
&= \frac{6507}{1000}.
\end{align}
It follows that
\begin{align}
\rho(X,A) &= \frac{\mathrm{Cov}(X,A)}{\sigma(X)\sigma(A)}\\
&= \frac{\mathbb E[XA] - \mathbb E[X]\mathbb E[A]}{\sqrt{\mathrm{Var}(X)}\sqrt{\mathrm{Var}(A)}}\\
&=\frac{\frac{6507}{1000} - \frac{27}{10}\cdot\frac{9409}{100}}{\sqrt{\frac{241}{100}}\sqrt{\frac{409459}{100000}}}\\
\end{align}
There is an error in my computations as this value is not between $-1$ and $1$, but the method should be correct.
