What is the probability that some random event won't happen in the next 10 minutes given it happened exactly twice in the last 120 minutes? The title says pretty much all. The event is fully random, it has the same chance any minute, it can happen multiple times at the same minute. How is it possible to calculate that?
I made a simulation code in c++, which says 78%, is that good answer?
https://gist.github.com/bakaiadam/4f4732f4147fc3a5c68f121bf57b919f
Edit: since people say it's not clear what I mean and I'm not really familiar with random distribution types, I tell you the concrete example that I was thinking about: My idea came from seeing group of people passing in a forest path. Let's say i have been there for 2 hours and saw 2 group of people. What is the probability that i will see at least 1 group of people in the next 10 minutes? Obviously there can be more than one group of people passing at the same minute, and obviously their chance  to be there is independent from each other.


I'm not really familiar with random distribution types

You need to get a grasp of probability distributions to understand the problem and solution. 
You can think of the time between the events i.e. some one passing through the path that you are looking at as a random variable.  It could be 1 minute or 8 minutes or 10 seconds etc. To get a handle on the randomness of this variable you need a mathematical function that gives you the probability that this random variable is less than some value or greater than some value or is in some interval, etc. Exponential distribution is the mathematical function that will give us that facility. 

What is the probability that some random event won't happen in the next 10 minutes given it happened exactly twice in the last 120 minutes?

In your example you say that the event occured twice in the last 120 minutes. So, the rate at which it occurs is 120/2 i.e. 1 event per 60 minute. Let $X$ denote the time between the first event the next $10$ minutes. 
So, the desired probability is $P[X>x] = \exp^{-(\lambda*x)}$. Here $\lambda$ is the rate parameter which is nothing but $1/60$ i.e. the number of events happening per minute. And $x$ is the time till the event. 
So, plugging the numbers you get $P[X>10] = \exp^{-(10/60)}$.
