A question of chance. I'm having a bit of trouble with this problem.
Three cards are drawn from a pack of regular playing cards. What's the probability of getting different suits, as well as different denominations (number, face, etc.)?
Bonus question. In the above case, it isn't specified whether the cards are drawn simultaneously, or one by one. Would it make a difference?

first one is 'any card' P = 1
2nd drawing has to be 12 denominations out of 3 suits, so it is 36 out of 51 remaining p2 = 36 / 51
3rd drawing 11 denominations from 2 suits, 22 / 50
answer = (36 / 51) (22 / 50) = 132 / 425

bonus question - drawing method makes no difference, unless there is replacement and a reshuffle after each card, which changes things, it would make the denominator go back to 52 in each fraction, since you could redraw the same card - but I don't think they mean that - with my method you could take 3 straight off the top and check them, or deal them one-by-one, it makes no difference
