What is the "determinant" of two vectors? I came across the notation $\det(v,w)$ where $v$ and $w$ are vectors. Specifically, it was about the curvature of a plane curve:
$$\kappa (t) = \frac{\det(\gamma'(t), \gamma''(t)) }{\|\gamma'(t)\|^3}$$
What is it supposed to mean?

In general, the determinant of $n$ vectors $v_1$, $v_2$, $\dots$, $v_n$ in $\mathbb R^n$ is the determinant of the matrix whose columns are $v_1$, $\dots$, $v_n$ (in that order).
Seen as an application whose inputs are vectors, the determinant has nice properties: 


*

*multilinear, that is linear in each variable: 
$$\det(v_1,\dots, a v_j+b w_j,\dots,v_n)
=
a \det(v_1,\dots, v_j,\dots,v_n)
+ b\det(v_1,\dots, w_j,\dots,v_n)$$

*alternating: switching two vectors transforms the determinant in its opposite
$$\det(v_1,\dots, v_i, \dots, v_j,\dots,v_n) = \det(v_1,\dots, v_j, \dots, v_i,\dots,v_n)$$


*The value on the canonical basis $(e_1,\dots,e_n)$ of $\mathbb R^n$ is $1$.


$$\det(e_1,\dots,e_n) = 1 $$
Actually, it can be proved that the determinant is the unique alternating multilinear form whose value on the canonical basis is $1$. Many (most?) Linear Algebra books use this as a definition of the determinant (before extending the definition to matrices and then linear applications). I think it is equivalent but more satisfying than introducing the determinant by the strange "expansion along a row" formula most PreCalculus textbook use.
