Calculus: Area Between Two Curves Find the area between the two curves $y = x^2 + ax$ and $y = 2x$ between $x=1$ and $x=2$, given that $a>2$
I found the antiderivative of $x^2+ax-2x$ and included the area between $x=1$ and $x=2$ which is $\dfrac{3a-4}{6}-\dfrac{6a-4}{3}$. I don't understand what $(a>2)$ means in the problem.

Hint:  the area between two curves $f(x)$ and $g(x)$ can be found by the formula 
$$A=\int_c^d{[f(x)-g(x)]dx}$$
It seems the reason it's asking you for $a>2$ is it will cancel the $2x$ if $a=2$.  Perhaps you should plot the graphs for different values of $a$.
