Area of rectangle knowing diagonal and angle between diagonal and edge I found on the web that the area of a rectangle with the diagonal of length $d$,  and inner angle (between the diagonal and edge)  $\theta$ is $d^2\cos(\theta)\sin(\theta)$. However, I wasn't able to deduce it myself. I tried applying law of sines or generalised Pythagorean theorem but I couldn't derive the area using only the length of the diagonal and the angle between diagonal and edge. How might I get to this result ?

If you use the formulas for sine and cosine in right-angled triangles, the formula can be proved rather easily: If the width and the height of the rectangle are resp. $w$ and $h$, then the formulas say $\cos(\theta)=w/d$ and $\sin(\theta)=h/d$. If you isolate $w$ and $h$ in these formulas and substitute in the formula "area $=wh$", then the formula you mention appears.
