Finding the probability of a selecting at least 1 of an element. If there are 18 red and 2 blue marbles what is the probability of selecting 10 marbles where there is either 1 or 2 blue marbles in selected set.
Also, it seems intuitive that the probability should be twice that of selecting a single blue marble in a set of 10 from 19 red and 1 blue, but I'm not sure.

Another approachment is through hypergeometric distribution.


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*The probability that there is exactly one blue ball in the selected set is:
$$P(A_1)=\dfrac{\color{blue}{\dbinom 2 1}\cdot \color{red}{\dbinom {18} {10-1}}}{\dbinom {20}{ 10} }$$

*The probability that there are exactly  2 blue balls in the selected set is:
$$P(A_2)=\dfrac{\color{blue}{\dbinom 2 2}\cdot \color{red}{\dbinom {18} {10-2}}}{\dbinom {20}{ 10} }$$
So, the probability you are looking for is $P(A_1)+P(A_2)\approx 0.763 $
