Probably that an $80\%$-truthful person actually rolled a $6$ A person, $A$, speaks the truth $4$ out of $5$ times. The person throws a die and reports that he obtained a $6$. What is the probability that he actually rolled a $6$?
I know there is a similar question like this 
but my doubts are different from it and also I want to identify and solve total probability theorem questions so I posted a side doubt also.
In my attempt, I defined the events
\begin{align*}
 E_1&: \text{The person tells the truth.} \\
 E_2&: \text{The person lies.} \\
 E_3&: \text{The person reports that the die landed on a 6.} 
\end{align*}
I noted that $P(E_1)=\frac{4}{5}$, $P(E_2)=\frac{1}{5}$, $P(E_3|E_1)=6^{-1}$ and
$P(E_3|E_2)=0$ and obtained
\begin{align*}
 P(E_3) = \frac{4}{5} \cdot \frac{1}{6} + \frac{1}{5} \cdot 0 = \frac{2}{15}.
\end{align*}
However, the correct answer is, $\frac{4}{9}$. What did I do wrong?
Side doubt: Even though the first experiment (truth and lying) is different from the second experiment, can we still apply total probability theorem? In my book the dependent experiment lies inside the sample space associated with the mutually and exhaustive events.

Your error would appear to be in P(E3|E2)=0
You are missing out the fact that the user may report a 6 being throw when in fact one has not
In fact your use of E3 is not helpful as it covers two scenarios.
What you are interested in is
User throws a six AND tells the truth
User lies AND reports that they threw a 6.
