Coordinate vector from a Basis of a subspace I'm having difficulty with this question:
Let V be a subspace of $\mathbb R^4$ spanned by the set $U = {(1, -1, 3, 1), (2, 1, -1, 2), (-1, 3, 0, 2)}$. Show that U is a basis of V and determine whether the vector $t = (-3, 6, 7, 6)$ belongs to space V in order to find the coordinate vector of $t$ relative to basis $U$.
My problem is that although the vectors are linearly independent with the trivial solution $c$1 = $c$2 = $c$3 = $0$, I did not think it was possible to span $\mathbb R^4$ with only 3 vectors.
I assume $t$ can be found by equating the vectors in $U$ to $t$ for the $b$ column of the matrix, but how can a coordinate vector be found if it seems that $U$ is not a basis of $V$?
Or have I made a wrong assumption?

You are correct that it is not possible to span $\mathbb R^4
$ with only $3$ vectors,
but the question stipulates that $V$ is a subspace of $\mathbb R^4$ spanned by the $3$ vectors in $U$.
In fact, $t=2(1,-1,3,1)-(2,1,-1,2)+3(-1,3,0,2)$ is in $V$, though not every vector in $\mathbb R^4$ is.
