What is wrong in $(\frac{1}{8})^{-\frac{1}{3}}$? I tried this:
$$\biggl (\frac{1}{8}\biggr)^{-\frac{1}{3}}= \frac{1^{-\frac{1}{3}}}{8^{-{\frac{1}{3}}}}=\frac{-\sqrt[3]{1}}{-\sqrt[3]{8}}=\frac{-1}{-2}$$
Also, is it possible to see what I don't understand here or are there maybe several things..

$$(1/8)^{-1/3}=((1/8)^{1/3})^{-1}=(1/2)^{-1}=2$$
