(Highschool Pre-calculus) Solving quadratic via completing the square I'm trying to solve the following equation by completing the square:
$x^2 - 6x = 16$ 
The correct answer is -6,1. This is my attempt:
$x^2 - 6x = 16$
$(x - 3)^2 = 16$
$(x - 3)^2 = 25$ 
$\sqrt(x -3)^2 = \sqrt(25)$
$x - 3 = \pm5$
$x =\pm5 - 3$
$x = -8,2$
I did everything according to what I know,but my answer was obviously wrong. Any help is appreciated. Thanks

no ,no,what do you need is following
we have
$x^2-6*x=16$
$x^2-6*x+9=16+9$
$(x-3)^2=25$
now $x-3=5$ or  $x=8$
and $x-3=-5$  or $x=-2$
there is no mistake,why is answer $-6$?
$(-6)^2-6*(-6)=36+36=72$
