Probability distribution about consecutive Mangoes that are marketed by a particular orchard have masses which are normally distributed with mean mass $20.5g$ and standard deviation $4g$. The mangoes are packed into packets of $10$ mangoes per packet. 
What is the probability that $4$ consecutive packets of the $5$ packets chosen at random have exactly $6$ mangoes with masses greater than $20.1g$ ?
My attempt
I found that the probability that its mass is greater than $20.1g$ is $0.5938$, the probability that exactly $6$ mangoes from $10$ that are put into per packet have masses that are greater than $20.1g$ is $0.233$, now I don't know how to find the answer of $4$ consecutive packets of the $5$ packets chosen at random have exactly $6$ mangoes with masses greater than $20.1$

I have the same results. Only at $0.5938$  you have mixed up the numbers $3$ and $9$. . But it is only a typo, because the probability  that exactly $6$ mangoes from $10$ that are put into one packet have masses that are greater than 20.1g is indeed $0.233$
Let one packet with $6$ mangos with masses greater than $21g$ denoted as $g$. And a  packet with $6$ mangos with masses smaller than $21g$ is denoted as $s$.
Then you have the following two combinations for  $4$ consecutive packets of the $5$ packets chosen at random have exactly $6$ mangoes with masses greater than $20.1$:
$ggggs$ and $sgggg$ 
The probability for one combination is $(0.233)^4\cdot (1-0.233)$ 
And for two combinations it is twice as much. This is the asked probability.
