How to solve: $\frac{3·x-5}{8·x-2}<6$ I'm trying to solve $\frac{3x-5}{8x-2}<6$ ?
I'm not sure which first step to take. I mean if I multiply both sides by $8x-2$ then I'm not sure if the sign would switch, as this could be positive or negative depending on $x$.

Assume $8x-2>0$ (i.e. $x>\frac14$) and multiply both sides: $3x-5<48x-12$, or $x>\frac7{45}$.
Symmetrically, when $x<\frac14$ you get $x<\frac7{45}$.
Combined, $x>\frac14\lor x<\frac7{45}$.
