How many ways are there to divide 10 customers across 2 salespeople? An article quotes that "there are more than 1,000 ways to assign ten customers to two salespeople" however this is wrong! How many actual ways are there to divide these customers across the two salespeople and what is the method used to get to this number?
I believe I should use combinations to answer this question but i'm not sure if im right. My thoughts were if the combination formula is nCr = n!/(n−r)!r! then it would be 10c5 = 10!/((10-5)!5! = 252
Thank you for any help you can provide :)

If each customer can be assigned to either salesperson, the answer is $2^{10}=1024$.  That is clearly what the statement is thinking.  Each customer can be assigned $2$ ways and you use the multiplication principle to combine them.  You are assuming that each salesperson must be responsible for $5$ customers, but that is not stated in the problem.
