Another limit task, x over ln x, L'Hôpital won't do it?  $$\lim_{x\to 0 } \frac{x}{\ln x}.$$
This was wrong, I got a big red wrong! Why doesn't L'Hôpital work on this one? 
The problem is that $\ln$ is not defined for 0. It needs to be rewritten?
(Thanks to everyone helping me out with my homework, due anxiety I'm not able attend the class workshops.) 
Edit: I did get the correct limit ($0$), but that was a coincidence.

L'Hopital's rule is best forgotten about. Of course as $x\to0^+$,
$\log x\to-\infty$ and so $1/\log x\to0$. A fortiori
$x/\log x\to 0$.
A better problem is to find $\lim_{x\to0^+}x\log x$.
