Area of a trapezoid without the height How would I find the area of a non-iscoceles trapezoid and without the height? The trapezoid's bases are $30$ and $40$, and the legs $14$ and $16$. Thanks

Area of a trapezium without knowing the height:
(a+c) / 4(a-c) * √(a+b-c+d)(a-b-c+d)(a+b-c-d)(-a+b+c+d)
Where a>c and 'a' is parallel to 'c'. 'b' and 'd' are the 'diagonals'.
Therefore,
(40+30) / 4(40-30) * √(40+14-30+16)(40-14-30+16)(40+14-30-16)(-40+14+30+16)
70 / 40 * √(40)(12)(8)(20)
7/4 * 277.128129...
484.974
