Simplify $(3\log x) - (2\log x)$ How to simplify $(3\log x) - (2\log x)$? Would this become $(\log x )^ {\frac{3}{2}}$ or would this be just $3\log x-2\log x =\log x$? If so how to get $\log x$?
I was given this question: solve for $x$ if $\log x + \log x^2 +...+ \log x^n =n(n+1)$. But, the answer to my main question will also be enough. Thank you for trying!

Hint: $\log(ab) = \log(a) + \log(b)$. This should be enough to simplify the sum on the left-hand side.
