Pumping water out of a truncated cone using integration. So the issue I'm stuck with, is that I can do a cone, but I have no idea where to start with a cone that is truncated.
I have a truncated cone that has a base with radius of 3 meters and a top with a radius of 4 meters It's height is 4 meters and I want to pump the water out of a pipe that expands 1 meter above the truncated cone. I need to calculate the work required to pump out all the water.
I did a cylinder earlier and a cone, but I just can't seem to figure out this truncated cone.
Any advice on where to start with a problem like this?

Suppose you had a tank in the shape of an inverted cone with a height of $16$ and radius $4$ on the top surface. Suppose you had to pump water out of that tank, but stop pumping when the depth of water is $12.$
In this modified problem, you will have pumped the water out of a truncated cone of height $4$ with top radius $4$ and bottom radius $3.$ This is just like the problem you were given, except that when you stop pumping, the surface is made of water rather than the solid material of the tank.
Can you solve the modified problem?
