Find the limit of $(\tan(x) + \sec (x))^{1/\sin(x)}$ $$ \lim_{x \rightarrow 0} [\tan(x) + \sec(x)]^{\csc(x)} = e $$
how to arrive at e, according to wolfram alpha, that this is the answer?

$$(\sec x+\tan x)^{\csc x}=\left(\left(1+\sec x+\tan x-1\right)^{1/(\sec x+\tan x-1)}\right)^{(\sec x+\tan x-1)/\sin x}$$
Use https://en.m.wikipedia.org/wiki/Tangent_half-angle_substitution#The_substitution for the outer exponent
