Finding the integral I've come across the following integration problem online:
$$\int{\frac{x^3}{x^4-2x+1}}\,\,dx$$
This is beyond my current knowledge of integrals, but it seems to be a very interesting integration problem.  Would anyone be able to give a tip on how to being solving the expression?
If there are any techniques, please elucidate - i.e. substitution, trigonometric identities, etc.
Thanks!

HINT:You can solve the intgral in this way:
$$\int{\frac{x^3}{x^4-2x+1}}\,\,dx=$$
$$\frac{1}{4}\int{\frac{4x^3+2-2}{x^4-2x+1}}\,\,dx=$$
$$\frac{1}{4}\int{\frac{4x^3-2}{x^4-2x+1}}\,\,dx+\frac{1}{4}\int{\frac{2}{x^4-2x+1}}\,\,dx=$$
$$\frac{1}{4}ln|x^4-2x+1|+\frac{1}{4}\int{\frac{2}{x^4-2x+1}}\,\,dx=$$
and then you have to factor the denominator.
