Solving a non-linear Partial differential equation $px^5-4q^3x^2+6x^2z-2=0$ I have to find out the complete integral of :
$$px^5-4q^3x^2+6x^2z-2=0$$
My attempt: Let $$f(x,y,z,p,q)=px^5-4q^3x^2+6x^2z-2$$ 
So, $$f_p=x^5,f_q=-12q^2x^2,f_x=5px^4-8q^3x+12xz,f_y=0,f_z=6x^2$$
Applying Charpit's method:
$$\frac{dx}{x^5}=\frac{dy}{-12q^2x^2}=\frac{dz}{px^5-12q^3x^2}=\frac{-dp}{5px^4-8q^3x+12xz+6px^2}=\frac{-dq}{6x^2q} $$ $$\implies \frac{dy}{-12q^2x^2}=\frac{dq}{-6x^2q}$$ $$\implies q=\sqrt{(y+c)}$$

where $c$ is an arbitrary constant.
I don't see here a way to find out $p$. Please help me solve this problem. Even a hint would be much help.
I'll appreciate any help towards it. Thanks in advance.

From given pde and by using the value q, we get 
$P=\frac{4(y+c)^{\frac{3}{2}}}{x^3}-\frac{6z}{x^3}+\frac{2}{x^5}$
and subtitute the values $p$ and $q$ in $Z=pdx+qdy$ and use multiplier $e^{-\frac{3}{x^2}}$ 
and on integration we get complete required complete integral 
