How to solve $\ln(x) = 2x$ I know this question might be an easy one. but it has been so long since I solved such questions and I didn't find a an explanation on the internet. I'd like if someone can remind me. 
I reached that $e^{2x} = x$, but didn't know how to continue from here. I remember something that has to do with bases and equalizing parameters, but how do I do that in this case? 

This equation has no solution. To see it, note that $\ln(x)<x$$<2x$ for every $x>0$.
