Finding the plane that contains both a given point and every point of a line. I'm not sure how to begin with this question as I've just started with linear algebra and its starting to become overwhelming.
Given this problem:
Let L denote the line consisting of all points of the form (t, 0,2), where t can be any real number.
Let v denote the point (-1,2,2).
Which of the following planes contain both v and every point of L?
a) x=-1, y,z are any real numbers 
b) z=2, x, y are any real numbers 
c) y=2, x,z are any real numbers 
The answer is apparently (b):  $z=2, x, y$ are any real numbers 
What are the steps that I need to approach to get to this answer?

All of the answer choice planes contain $v$ so that isn't an issue.
For the line, we know that $c$ is not the correct option because it doesn't contain $y=0$.
We also know that $a$ is not the correct option because the line is parallel to the $x$ axis, and this plane only contains one $x$-value.
The correct answer is $b$ because $x$ and $y$ are allowed to vary, and then $z=2$ which agrees with the line. 
