rewrite $n \ln(\frac{1}{2 \theta^3})$ $n \ln(\frac{1}{2 \theta^3}) = n \ln (1) - 3n \ln (2\theta)$
why is this not right? 
apparently the answer is $-n \ln (2) - 3 n \ln (\theta)$

$n\ln(\frac{1}{2{\theta}^3})$ can be written as $n\ln(2^{-1}{\theta}^{-3})$.So according to the rule $$\ln(xy)=\ln{x}+\ln{y}$$, you will get the right answer.
