How I can solve this inequality $(R\gamma^T(1/(1−\gamma))≤\epsilon)$ for $T$?! Can someone solve this inequality for $T$
$$
R\gamma^T(1/(1−\gamma))≤\epsilon
$$
In a paper it solved for $T$ and the inequation below is the result, but I can not prove how the inequation above can be the inequation below: 
$$
T≥(1/(1−\gamma))\log⁡(R/(\epsilon(1−\gamma)))
$$
May someone help me,
thanks in advanced.

We assume that $0<\gamma<1$, $R>0$, $\epsilon>0$. We multiply both sides of
$$
R\gamma^T(1/(1−\gamma))≤\epsilon
$$ by the positive real number $\displaystyle (1−\gamma)/R$ to get
$$
\gamma^T \leq\epsilon(1−\gamma)/R
$$ since $\displaystyle (\infty,0) \ni x \mapsto \log x$ is an increasing function we get
$$
T \log \gamma \leq \log \left(\epsilon(1−\gamma)/R \right) 
$$ equivalently
$$
-T \log \gamma \geq \log \left(R/(\epsilon(1−\gamma)) \right) 
$$ but how to get the desired inequality since we know that $1-\gamma \geq \log \gamma$, $0<\gamma<1$.
