Laurent polynomials $ \mathbb C[t,t^{-1}]$ is the localization of $\mathbb {C}[t].$ I want to prove this question:
Show that the ring of Laurent polynomials $ \mathbb C[t,t^{-1}]$ is the localization of the polynomial ring $\mathbb {C}[t].$
Localization is defined as follows: Let $R$ be a commutative, $S\subset R$ multiplicatively closed. Define $\sim $ on $ S \times R $ by $\frac{r}{s} \sim \frac{r'}{s'}$ which is equivalent to $t(rs' - r's) = 0$ for some $t \in S$ then $S^{-1}R$ is a commutative ring.
Still, I do not know how to prove this localization, do I have to find an isomorphism? or what?

"Show that the ring of Laurent polynomials $\mathbb C[t,t^{-1}]$ is the localization of the polynomial ring $\mathbb C[t]$."
The problem does not make sense as you state it because, as others have pointed out in the comments, there are many localizations of $R =\mathbb C[t]$.  Each localization is done with respect to a multiplicatively closed subset $S$ of $R$.  You must choose a suitable multiplicatively closed subset $S$ so that $S^{-1}R = \mathbb C[t,t^{-1}]$.
By the way, the abstract definition you have provided of localization is not at all necessary here.  The following observation will make the problem much more tractable:
What does a localization of an integral domain look like? If $A$ is an integral domain, and $K$ is its field of fractions, any localization $S^{-1}A$ of $A$ is a ring which contains $A$ and which is contained in $K$.  Indeed, $$A \subseteq S^{-1}A = \{ \frac{a}{s} : a \in A, s \in S\} \subseteq K.$$
The abstract definition of $S^{-1}A$ as the set of equivalence classes of pairs in $S \times A$ is not necessary here and will only confuse you.  Sending the class of $(s,a)$ to $as^{-1} \in K$ gives an isomorphism between the formal definition of $S^{-1}A$ and the definition I just provided, as a subring of the field $K$.
What multiplicatively closed set $S$ should I pick to obtain $\mathbb C[t,t^{-1}]$?
The set should obviously contain $1$ and $t$, as you will want $t$ to be invertible in the localization.  What other elements does $S$ need to contain to be closed under multiplication?
