Function linear in one variable and quadratic concave on another, is concave in jointly? I have a function $f(x,y,z)$. $f$ is convex with respect to $x$, and linear with respect to $y$. Also, it is quadratic concave with respect to $z$. I want to solve the following optimization problem: 
\begin{align}
    \min_{x\in C} \max_{y\in D_y} \max_z f(x,y,z)
\end{align}
My question is can I assume that this problem is concave with respect to $(y,z)$?
Let $g(y,z) = \min_{x\in C} f(x,y,z)$. Function $g(u)$, where $u=(y,z)$ is concave? 
What if $f(x,y,z) = f_1(x,y) + f_2(x,z)$?

No, you may not. Suppose $f(x,y,z) = -yz^2$, with $D_y = \mathbb{R_+}$, then the Hessian is:
$$\begin{pmatrix}0 & -2z \\ -2z & -2y\end{pmatrix}$$
which is indefinite for $z \neq 0$, since the eigenvalues are $-y \pm \sqrt{y² + 4z²}$
