The derivative of $ \ln\left(\frac{x+2}{x^3-1}\right)$ I know it is a simple question, but what would be the next few steps in this equation to find the derivative?
$$f(x)= \ln\left(\frac{x+2}{x^3-1}\right)$$

For $$f(x)= \ln\left(\frac{x+2}{x^3-1}\right)$$
Start by re-writing the logarithm as
$$\frac{d}{dx}\left(\ln\left(\frac{x+2}{x^3-1}\right)\right)=\frac{d}{dx}\left(\ln({x+2})-\ln({x^3-1})\right)$$$$=\frac{d}{dx}\left(\ln({x+2})\right)-\frac{d}{dx}\left(\ln({x^3-1})\right)= \color{blue}{\frac{1}{x+2}-\frac{3x^2}{x^3-1}}$$
