For the polynomial For the polynomial, -2 is a zero. $h(x)= x^3+8x^2+14x+4$. Express $h(x)$ as a product of linear factors. 
Can someone please explain and help me solve? 

Okay, the first thing to do is polynomial division (or synthetic division, whichever you prefer).
Since -2 is a 0, we know that $(x+2)$ is a factor of $h(x)$. We then divide $h(x)$ by $(x+2)$
Dividing: $$\frac{x^3 + 8x^2 + 14x + 4}{x+2} = x^2 + 6x + 2$$
So $h(x)$ becomes: $$(x+2)*(x^2+6x+2)$$
Now you must use the Quadratic formula to find the root of $x^2 + 6x +2$
$$x = \frac{-6 +/- \sqrt{28}}{2}$$
$$x = -3 +/- \sqrt{7}$$
So $h(x)$ is $$(x+3+\sqrt{7})(x+3-\sqrt{7})(x+2)$$
