Solve $4^{9x-4} = 3^{9x-4}$ I am having some trouble trying to solve 
$$4^{9x-4} = 3^{9x-4}$$
I tried to make each the same base but then I'm becoming confused as to what to do next.
These are the steps I took:
$$\begin{align}
4^{9x-4} &= 3^{9x-4} \\
\log_4(4^{9x-4}) &= \log_4(3^{9x-4}) \\
\end{align}$$
Where do I go from there?
Thanks!

Note you can take logs to any base for this (provided it is the same both sides).
You get $$(9x-4)\log 4 = (9x-4)\log 3$$
which you can rewrite as $$(9x-4)(\log 4-\log 3)=0$$
