What is the sum of the solutions to $6x^3+7x^2-x-2=0$ What is the easy way to solve the problem? 

The sum of the solutions to $6x^3+7x^2-x-2=0$ is:
  $$A) \ \frac{1}{6}$$ $$B) \ \frac{1}{3}$$ $$C) \ \frac{-7}{6}$$ $$D) -2$$ $$E) \text{ none of above}$$


Constant is -2.
Using remainder theorem
So you have 1,-1,2,-2.
By putting-1 in x you get to know that -1 satisfies the solution. 
So -1is a solution and x+1 is a factor of above equation. 
After dividing 6x^2+7x^2-x-2 by x+1 we get,
6x^2 +x-2 as quotient.
Solving this quadratic equation you get 1/2 and -2/3 as solutions. 
So -1 + 1/2 + -2/3= -7/6 none of the above.
