Evaluating the integral $\int\frac{3x^{2}-x+2}{x-1}\;dx$ As the title suggests, the following integral has been given to me 
$$\int\frac{3x^{2}-x+2}{x-1}\;dx$$
Yet I still get the wrong answer every time.
Can someone calculate it step-by-step so I can compare it to my own answer?

HINT:
$$\frac{3x^2-x+2}{x-1}=\frac{(x-1)3x+(x-1)2+4}{x-1}=3x+2+\frac4{x-1}$$
