How to calculate $\lim_{x \to - 1} \frac{2}{(x+1)^4}$ Calculate $$\lim_{x \to - 1} \frac{2}{(x+1)^4}$$
a) $0$
b) $\infty$
c) $-\infty$
d) $2$
I am able to see that it is equivalent the limit as $x$ approaches $-1$ of $\frac{2}{(x^2+2x+1)^2}$. 
I know that when doing limits to infinity this would be $0$ because the denominator has the highest exponent, but I am confused for $x$ approaches $-1$.
Is this a limit from the right and left kind of thing? Would the process be the same if I changed $-1$ to another number?

Consider the easier function $\frac{1}{(x+1)^{2}}$. What would be it's value if $x$ approach -1 ?
