the New Year will be 2017: how many pairs of integer solutions to $x^2 + y^2 = (2017)^3$? We're almost in 2017. I wonder how many pairs of integer solutions has the following diophantine equation:
$$x^2 + y^2 = (2017)^3$$
Thanks in advance.

I want to share with everyone that I just found an algebraic method to calculate primitive triples in my specific case of raising to the third power:
$$[x(x^2-3y^2)]^2+[y(3x^2-y^2)]^2=n^3$$
I do not know why but on specialist internet sites this is not often found.
Happy new year for all.
