Properties of Natural Logarithm I need help finding the Derivative $y=\ln(x)^2$
I am not sure why the answer would be $\frac{2\ln(x)}{x}$
I used this property "power rule" "$\ln(x^n) = n\ln(x)$
So i got $2\ln(x) $
the derivative of that using the constant multiplier rule i got 
$\frac{2}{x}$
can I use the other chain rule to $y=f(u)$ and $g=g(x)$
Am i not supposed to bring that 2 in front becuase the whole expression is getting raised not the $x$?
Any help would be great,

Apply the chain rule with $\;f(x):=x^2\;,\;\;g(x):=\log x$ :
$$(f(g(x)))'=f'(g(x))\cdot g'(x)$$
So
$$(\log x)^2=2\log x\cdot \frac1x=\frac{2\log x}x$$
