How can one prove that $\lim\limits_{\theta\to 0} \frac{\sin\theta}{\theta}=1$ 
Possible Duplicate:
Proving $\lim_{\theta \to 0}{\frac{\sin \theta}{\theta}}=1$ using $\frac{1}{2}r^2(\theta-\sin \theta)$ 

How can one prove that $$\lim_{\theta \to 0} \frac{\sin\theta}{\theta}=1$$
$\sin(0) = 0$

$\lim_{\theta \rightarrow 0} \frac{\sin(\theta)}{\theta} = \lim_{\theta \rightarrow 0} \cos(\theta) = 1$ by L'hopital's rule.
