Evaluating: $\lim_{n \to 0} \prod_{\substack{i=nk \\k \in \Bbb Z_{\geq 0}}}^{2-n} \left( 2-i \right) $ How would we evaluate:
$$\lim_{n \to 0} \prod_{\substack{i=nk \\k \in \Bbb Z_{\geq 0}}}^{2-n} \left( 2-i \right) $$
Is it possible to evaluate this manually? Or do we have to make a program to get an approximation? 
EDIT:
Since people are getting confused in the comments, here is an example:
If we take n=0.5:
$$\prod_{\substack{i=nk \\k \in \Bbb Z_{\geq 0}}}^{2-n} \left( 2-i \right) = \prod_{\substack{i=0.5k \\k \in \Bbb Z_{\geq 0}}}^{1.5} \left( 2-i \right)=(2-0)(2-0.5)(2-1)(2-1.5) $$
Hopes this clears up the misunderstanding.  

The product can be written in an equivalent form as:
$$\Pi(n)=\prod_{k=0}^{\frac{2-n}{n}} (2-kn)=\prod_{k=0}^{\frac{2-n}{n}} -n(k-\frac{2}{n})=\prod_{k=0}^{\frac{2-n}{n}} -n\prod_{k=0}^{\frac{2-n}{n}} (k-\frac{2}{n})=$$
$$=2(-n)^{\frac{2-n}{n}} \left(\frac{n-2}{n}\right)_{\frac{2-n}{n}}$$
This may be helpful.
