Packing $8$ identical DVDs into $5$ indistinguishable boxes I am trying to solve this question:

How many ways are there to pack eight identical DVDs into five indistinguishable boxes so that each box contains at least one DVD?

I am very lost at trying to solve this one. My attempt to start this problem involved drawing 5 boxes, and placing one DVD each, meaning 3 DVDs were left to be dropped, but I am quite stuck at this point.
Any help you can provide would be great. Thank you.

5 boxes 8 dvds ... 
firstly you put one dvd in each box .
and now you solve no. of ways of placing 3 dvds in 5 boxes.
which is same as no of solution to the equation 
    b1 + b2 + b3 + b4 + b5 = 3  i.e., 
$ (5+3-1)\choose (3)$ = 35 .  .... [solution to the equation a1+a2+a3+...an = r is $ (n+r-1) \choose n $ which can easily be proved]
 so 35 ways
