Pumping water out of a truncated cone using integration. So the issue I'm stuck with, is that I can do a cone, but I have no idea where to start with a cone that is truncated.
I have a truncated cone that has a base with radius of 3 meters and a top with a radius of 4 meters It's height is 4 meters and I want to pump the water out of a pipe that expands 1 meter above the truncated cone. I need to calculate the work required to pump out all the water.
I did a cylinder earlier and a cone, but I just can't seem to figure out this truncated cone.
Any advice on where to start with a problem like this?

In this case, you need to realise that one can obtain a cone by simply revolving/rotating a linear curve about the x-axis (or y-axis). You can then use the following integral. In general, the volume given by rotating the function $f(x)$ over an interval $[a,b]$ is given by:
$V(x)=\pi \int_a^b f(x)^2 \ dx$.
Combined with having a look at the following picture, I am sure you can calculate the volume of your truncated cone. 
(from: http://www.nabla.hr/DIASurfXFig.gif)

