Inverse Laplace Transform, need help with this $\frac{s^2}{s^2+\sqrt{2}s+1}$ Inverse Laplace Transform of $\frac{s^2}{s^2+\sqrt{2}s+1}$
I transformed the denominator as $(s+\frac{\sqrt{2}}{2})^{2}$ + $\frac{1}{2}$
$\frac{s^2}{(s+\frac{\sqrt{2}}{2})^{2} + \frac{1}{2}}$ and I have no idea how to move forward because partial fraction decomposition fails.

Hint:
$$\frac{s^2}{s^2+\sqrt2\,s+1}=1-\frac{\sqrt2\left(s+\frac{\sqrt2}2\right)}{\left(s+\frac{\sqrt2}2\right)^2+\frac12}$$
