Integration question on $\int \frac{x}{x^2-10x+50} \, dx$ How would I integrate
$$\int \frac{x}{x^2-10x+50} \, dx$$
I am not sure on how to start the problem

I would complete the square in the denominator first. 
$$ \displaystyle \int \dfrac{x}{x^2-10x+25+25}dx = \int \dfrac{x}{(x-5)^2+25}dx  $$
Let $u=x-5$, 
$$ \displaystyle \int \dfrac{u+5}{u^2+25}du = \int \dfrac{u}{u^2+25}du + \int \dfrac{5}{u^2+25}du$$
the first integral you can solve by doing one more substitution, the second is just arctangent. 
