How do i find P(2)? Let $P(x)$ be the polynomial of least degree with real coefficients such that $P(i)=P(1+i)=0$ and $P(1)=4$. Find $P(2)$.
Here i is the complex number. I have done such questions with real numbers but I don't know why I am not getting it.

Hint: $P$ has real coefficients.  So, if $P(i) = 0$, then $P(-i) = 0$.  If $P(1+i) = 0$, then $P(1 - i) = 0$.
Can you construct the smallest complex polynomial that has these zeros?
