How do you factorize quadratics when the coefficient of $x^2 \gt 1$? So I've figured out how to factor quadratics with just $x^2$, but now I'm kind of stuck again at this problem:
$2x^2-x-3$
Can anyone help me?

You can get a monic polynomial out of his by putting $y=2x$. The expression becomes
$$\frac12(y^2-y-6)$$
which you can easily factorise as
$$\frac12(y-3)(y+2)$$
Substituting back gives
$$(2x-3)(x+1)$$
