How does expected value work with multiple probabilities? I'm familiar with how expected value works normally (EV = probability * value of event) but I'm not sure how to handle a situation with multiple probabilities.
As a simple example, let's say that I'm trying to calculate how much time I will take to park a car. I can either park at the end of the road, which takes only 1 minute or I can park in a big parking garage but that will take me at least 10 minutes of driving around in circles and riding the elevator.
Due to the time of day, there's an 80% chance that I'll snag a spot at the end of the road. The parking garage is huge so there's a 100% chance of getting a spot there.
How would this work?
Feel free to ask for additional information.

I assume you mean that you take the spot at the end of the road if it is available, and checking whether this is available takes no time; if this spot is not available, you go to the parking garage.  So if $X$ is the time you take, $X=1$ with probability $0.8$ and $X=10$ with probability $0.2$ (you did say "at least $10$", but we don't know how much more than $10$, so without further information this might be a reasonable assumption).
