Simplifying $\frac{ (2x+1) (x-3) }{ 2x^3 (3-x) }$ In simplifying
$$\frac{2x^2-5x-3}{6x^3-2x^4}$$
I got this far
$$\frac{ (2x+1) (x-3) }{ 2x^3 (3-x) }$$
but there aren't same brackets to cancel out.

$\frac{(2x+1)(x-3)}{2x^3(3-x)}= -\frac{(2x+1)(x-3)}{2x^3(x-3)}= -\frac{(2x+1)}{2x^3} $
