Find angle of a right triangle. Ok, so this question is from a practice exam. Looks very simple and basic, but I'm not very good at math, so I'm having trouble setting up the problem. 
One acute angle of a right triangle is not less than 30° more than twice the other acute angle. What are the possible measures of the larger angle? 
I know that the sum of all angles equal to 180° and that one side equals 90° so there is a 90° left for the other two remaining angles but I don't know how to divide it. To be honest I don't  I understand the problem where it says "less than 30° more than twice" if someone can put it in different words or explain. I need a hint. Thanks

$$A+B+C=180°$$
$$B=90°$$
$$A>=2C+30$$
Hence,
$$A+C=90°$$
$$A>=2C+30°$$
Let us set $A=2C+30°$, getting $2C+30°+C=90°$, so $C=20°$ and $A=70°$.
If $C$ is decreased then $A$, will still meet the equals below "Hence," so $A>=70°$.
