Help finding $(fg)(-2)$ So I just need a confirmation really, as my friend and I don't agree on the answer.
Problem: let $f(x)= \frac{x^2}{1-x^2}$ and $g(x)=log_3 (x+3)+1$
Find $fg(-2)$
$f(-2)\cdot g(-2)$
$-4/3\cdot 1= -4/3$
But my friend got 1. Don't you have to find $f(-2)$ and $g(-2)$ first and then perform the multiplication or what?

I am assuming that you mean $f \circ g(-2)$ ... which means you first find $g(-2)$ which is 1, and then find $f(1)$, which is  $\infty$ ... so I'm not really sure what method you are using but both the answers seem wrong
