Find : $ dy/dx, y=\sqrt{4x^2 - 7x - 2}$ The problem says Find $dy/dx,  y=\sqrt{4x^2 - 7x - 2}$
So far I changed it to $(4x^2 - 7x - 2)^{1/2}$
I don't know where to go from there.

hint: Use the chain rule: $\sqrt{u(x)}' = \dfrac{u'(x)}{2\sqrt{u(x)}}$
