When is implication true? If we have $p\implies q$, then the only case the logical value of this implication is false is when $p$ is true, but $q$ false.
So suppose I have a broken soda machine - it will never give me any can of coke, no matter if I insert some coins in it or not.
Let $p$ be 'I insert a coin', and $q$ - 'I get a can of coke'.
So even though the logical value of $p \implies q$ is true (when $p$ and $q$ are false), it doesn't mean the implication itself is true, right? As I said, $p \implies q$ has a logical value $1$, but implication is true when it matches the truth table of implication. And in this case, it won't, because $p \implies q$ is false for true $p$ (the machine doesn't work).
That's why I think it's not right to say the implication is true based on only one row of the truth table. Does it make sense?

The fact some specific values satisfy the formula doesn't mean the formula is true in general. "It is noon now and it rains" is true right now and right here, but at other place or in other time this will appear false.
Your implication will turn out true if you check it keeps satisfied by any possible combination of its components values.
