Indefinite integral $\int{3x^2\over (x^3+2)^4}dx$ Question:

How to solve this indefinite interal $$\int{3x^2\over (x^3+2)^4}dx$$

Attempt:
$3\int x^2{1\over (x^3+2)^4}dx$
Let $u=x^2$ then $du={1\over (x^3+2)^4}dx$.
Am I on the right track or going about it the wrong way? 
ok so I make $du=3x^2dx$ but what do I do with this? Does it just disappear?

Your option $u=x^2$ seems to be a bad one. Indeed, $du=2x\,dx$ doesn't mate very well with the given numerator, and the denominator will turn to the unappetizing $(\sqrt u^3+2)^4$.
It is much more appealing to notice that $3x^2$ is the derivative of $x^3$, so that a substitution $u=x^3$ will yield $du$ at the numerator and $(u+2)^4$ at the denominator, a much more tractable result.
