find $\frac{ax+b}{x+c}$ in partial fractions $$y=\frac{ax+b}{x+c}$$ find a,b and c given that there are asymptotes at $x=-1$ and $y=-2$ and the curve passes through (3,0)
I know that c=1 but I dont know how to find a and b?
I thought you expressed y in partial fraction so that you end up with something like $y=Ax+B+\frac{C}{x+D}$ 

$c=1$, and since the curve passes through (3,0), we have $b = -3a$.
So $y=a\frac{x-3}{x+1} = a(1-\frac{4}{x+1})$ which converges to a when x goes to infinity. So $a=-2$
