Counting outcomes of flipping coins I know this is an extremely basic question, but I have a slight misunderstanding (?) regarding this question:

How many possible outcomes are there when flipping two coins?

At first glance, this is a really easy problem: 2 x 2 = 4!
But if I list all the possible outcomes:
{H, H}
{H, T}
{T, H}
{T, T}

I noticed that there are really three "distinct" outcomes:
{H, H}
{H, T}
{T, T}

Is it wrong to consider {H, T} and {T, H} the same? Why or why not?

You can understand it by assuming that 1 coin is red and the other is black. In this case there are exactly 4 outcomes when you flip these 2 coins, that is HH, HT, TH or TT.
