How many times must I toss a coin in order that the odds are more than 100 to 1 that I get at least one head? How many times must I toss a coin in order that the odds are more than 100 to 1 that I get at least one head?
I believe that it is 10 times as if the coin is flipped ten times there is only ten outcomes that include only 1 head out of 1024 total outcomes. Is this correct?

The chance of getting at least one head is $1 - (\frac{1}{2})^n$
This equation has to equal $99 \%$, which gives us the following:
$$1 - \Big(\frac{1}{2}\Big)^n = 0.99$$
$$\Big(\frac{1}{2}\Big)^n = 0.01$$
$$n \log\frac{1}{2} = \log0.01$$
$$n = \frac{\log0.01}{\log\frac{1}{2}}$$
$$n = 6.6438...$$
Obviously we can't have $6.6438...$ number of tries, which means it must go up to the nearest integer, which means we must have $7$ tries to have more than $99 \%$ to get at least one head.
