A fair die is rolled three times, find the probability of the following events: a. All rolls show an even number of dots
b. the last two rolls show an even number of dots
c. the third roll shows an even number of dots
d. every roll shows a single dot
e. every roll shows the same number of dots
what Ive done so far:
I know that the probability will always be out of 216 because you roll the die 3 times and there are 6 possibilities. 
I think I am overthinking things. For e, would it just be 6/216 or would it be 1/216 ->( (1/6) * (1/6) * (1/6))? 
Please show me how/where you got the answers from. Thanks! 

Hint A: What's the probability of rolling an even, $P(even)$? You want this to happen all three times.
Hint B: We don't care about the first roll.
Hint C: We don't care about the first two rolls.
Hint D: What's the probability of rolling a 1, $P(1)$? You want this every time.
Hint E: The first roll doesn't matter. You just want to match it the second and third time.
