Algebra rearrangement, solve for x How do I solve this equation for x?
$$1.43 = \frac{x}{0.99x+5.21\times10^{-5}}$$
I have tried rearranging it, but can't seem to get a positive number.

Let $A = 1.43, B=0.99, C = 5.21 \times 10^{-5}$
The equation is $A = \frac{x}{Bx + C}$
Rearranging,
$ABx + AC = x$
$x(AB-1) = -AC$
$x = \frac{AC}{1-AB}$
which evaluates to approximately $x = -1.792 \times 10^{-4}$, indeed a negative real number.
