Examples of when Newton's Method will fail? I'm currently working on Newton's Method, and my instructor gave four instances where Newton's Method will fail.
(A) Newton's method converges to another solutions x=b such that f(b)=0 instead of converging to the desired solution x=a.
(B) Newton's method eventually gets into the never ending cycle, bouncing between the same two approximations $x_i$ and $x_{i+1}$.
(C) Eventually, each next approximation $x_{i+1}$  falls further from desired solution $x_a$ than the previous approximation $x_i$  determined by the Newton's method.
(D) Newton's method is not able to find the next approximation $x_{i+1}$  because f'($x_i$)=0 or f'($x_i$) Does Not Exist.
However, there aren't any examples of when this happens. Would anyone be willing to provide examples of these instances?

For $A$, suppose you have a function with multiple zeros like $f(x) = \sin x$. Depending on your starting point, you will see that you could converge to any of the roots ($x = n\pi$), even if you want it to converge to a particular $x = \pi$ for example - say you start with $x_0 = 7\pi / 4$
For $B$, imagine a function whose gradient is very sharp - almost vertical. Then there is a chance that the tangent will cut at a point beyond the root, and then when you repeat at the new point, it will come back to the original point (Something like $f(x) = \arctan x$ at $x = 0$)
For $C$, if your starting point is too close to a stationary point, the next point is very far away, and will keep pushing the point further and further from the root
