Find the kernel of a linear transformation of $P_2$ to $P_1$ For some reason, this particular problem is throwing me off:
Find the kernel of the linear transformation:
$T: P_2 \rightarrow P_1$  $T(a_0+a_1x+a_2x^2)=a_1+2a_2x$
Since the kernel is the set of all vectors in $V$ that satisfy $T(\vec{v})=\vec{0}$, it's obvious that $a_0$ can be any real number. What matters, if I understand correctly, is that $a_1$ and $a_2$ should equal 0 in order to satisfy the zero vector (i.e. $0+2(0)x$). 
Granted that what I stated is correct, why would my book say that the $\ker(T)=\{a_0: a_0 \; \text{is real}\}$? 
Yes, $a_0$ can be any real number, but what must $a_1$ or $a_2$ equal? I don't see it specified within the set. Perhaps it's implied - I'm not sure. 
Let me add some more detail:
Again, if I understand correctly, I could make a system of equations as such:
$a_1 = 0$ 
$2a_2 = 0$ 
From that I can translate it into a matrix and find that $a_1$ and $a_2$ really does equal zero.

Your argument is totally correct. Your book means that $\ker(T)=\{a_0+0\cdot x+0\cdot x^2|a_0\in \mathbb{R}\}$, i.e. $a_1=0$ and $a_2=0$, which is the same as you proved.
