Negate the following statements 1) For every shape A, there is a circle D, such that D surrounds A
2) There is a circle C, such that for every line l, l intersects C
This is what I got are my answers correct
1) There is at least one shape of A that no circle D surroundings.
2) There is at least one line I which does not intersect this circle C.

The negation of 1) is correct. The negation of 2) is: For every circle C, there exists a line L which does not intersect C.
One might take this occasion to mention that there is an automatic procedure to negate logical sentences. Let me give an example. Let $f:\mathbb R\to\mathbb R$ denote a function. The assertion that $f$ is continuous can be written as:
$$
\forall\varepsilon\in\mathbb R_+^*,\ \forall x\in\mathbb R,\ \exists\delta\in\mathbb R_+^*,\ \forall y\in\mathbb R,\ |x-y|\leqslant\delta\implies|f(x)-f(y)|\leqslant\varepsilon.
$$
How to negate this? One can work sequentially, starting from the leftmost end of the formula, and making its logical structure apparent. The original formula is:
$$
\color{red}{\forall}\varepsilon\in\mathbb R_+^*,\ \color{red}{\forall} x\in\mathbb R,\ \color{red}{\exists}\delta\in\mathbb R_+^*,\ \color{red}{\forall} y\in\mathbb R,\ P(x,y,\delta,\varepsilon),
$$
for some logical assertion $P(x,y,\delta,\varepsilon)$. Thus its negation is:
$$
\color{red}{\exists}\varepsilon\in\mathbb R_+^*,\ \color{red}{\exists} x\in\mathbb R,\ \color{red}{\forall}\delta\in\mathbb R_+^*,\ \color{red}{\exists} y\in\mathbb R,\ \color{red}{\lnot} P(x,y,\delta,\varepsilon),
$$
That is, starting from the left, one replaces each $\forall$ by $\exists$, and vice versa. Finally, one should negate $P(x,y,\delta,\varepsilon)$, but perhaps you already know how to do this?
