In how many ways can a group of 5 boys and 5 girls be seated in a row of 10 seats? In how many ways can a group of 5 boys and 5 girls be seated in a row of 10 seats?
Still having some confusion with the difference between combinations and permutations. I have tried this problem using both combination and permutation with the formulas and my calculator and neither were correct answers. 

Instead of the rigid formulas, try to use your own logic.
10 human can sit on 10 seats in 10! ways.
But, we are only curious only for the boy-girl ordering, thus if only the ordering of the boys, or the ordering of the girls differ, it is the same case.
The 5 boys can seat 5! ways (between the girls) and the 5 girls can seat also 5! ways (between the boys).
Thus, we calculated every case 5!*5! times into this 10! result.
Thus, the real result is $\frac{10!}{5! \cdot 5!}=252$.
