If $2^{2013}-2^{2012}-2^{2011}+2^{2010} = k \cdot 2^{2010}$, find $k$ Hey this is just a question i was having fun with but couldnt solve for some reason. Would love if you can help me solve it thankyou!:
If $2^{2013}-2^{2012}-2^{2011}+2^{2010} = k\times2^{2010}$.  find k

Let $a=2^{2010}$ and just bring down some of the exponents:
$$2^{2013}-2^{2012}-2^{2011}+2^{2011} = 8a - 4a -2a +a$$
$$= 3a = 3\times 2^{2010}$$
So $k=3$.
