How to prove a Banach normed vector space is NOT a Hilbert space? We know that the Banach space $\big(\Bbb R^n,\|\cdot\|_2\big)$ is a Hilbert space with inner product $\langle x,y\rangle := \sum_{k=1}^n x_ky_k$. However, how to prove that $\big(\Bbb R^n,\|\cdot\|_3\big)$ is NOT a Hilbert space where $\|v\|_3 := \left(\sum_{k=1}^n|v_k|^3\right)^{1/3}$?
More generally is there a characterization of Hilbert spaces other than the existence of an inner product? And supposing $(V,\|\cdot\|_V)$ satisfies this characterization, how can we build an associated inner product?

It's possible to prove that norm comes from inner product if only if Parallelogram law holds, that means:
$$2\|x\|^2+2\|y\|^2=\|x+y\|^2+\|x-y\|^2$$
For all $x,y \in \mathbb{R}^n$.
For example, let $x=(1,0,0,0,\ldots)$, $y=(0,1,0,0,\ldots)$ , then:
$$\|x\|^2=\|y\|^2=1$$
$$\|x+y\|^2=(2)^{\frac{2}{3}}$$
$$\|x-y\|^2=(2)^{\frac{2}{3}}$$
So Parallelogram law doesn't hold.
