Prove that $x^2 + 3 > 2x + 1$ for all values of $x$ how would I go about proving this:
$x^2 + 3 > 2x + 1$
I know that I have to complete the square but do I bring everything to one side and convert it to an equation or do I simply complete the first side?
Sorry if this seems nooby

With Analysis:
Just to show there isn't a single way to prove inequalities. 
The tangent to the parabola with equation $y=x^2+3$ at point $A=(1,4)$ has equation 
$y=2(x-1)+4=2x+2$.
Now the function is convex, i.e. its graph is above each of  its tangents, so for all $x$,
$$x^2+3\ge 2x+2~(>2x+1).$$
