Solve inequality: $\frac{2x}{x^2-2x+5} + \frac{3x}{x^2+2x+5} \leq \frac{7}{8}$ Rational method to solve $\frac{2x}{x^2-2x+5} + \frac{3x}{x^2+2x+5} \leq \frac{7}{8}$ inequality?
I tried to lead fractions to a common denominator, but I think that this way is wrong, because  I had fourth-degree polynomial in the numerator.

HINT:
As $\displaystyle x^2\pm2x+5=(x\pm1)^2+4\ge4>0$ for real $x$
we can safely multiply out either sides by $(x^2+2x+5)(x^2-2x+5)$
Then find the roots of the Quartic Equation 
