Integral of $1/x^2$. I know that the integral of
$1/x^2$ is $(-1/x +C)$
Can we split $(1/x^2)$ as $(1/x)(1/x)$ and say that the integral of $(1/x^2)$ is $\ln x\cdot\ln x$?
PS: I am new to high school. And this is my first question on Stack Exchange.

It is good to ask no problem. The integral behaves nicely with addition and subtraction , I mean, if $\int f(x) dx$ and $\int g(x)  dx$ exist then $$\int(f(x)+g(x) dx=\int f(x) dx+\int g(x) dx$$ The same for subtraction. But in general , we can NOT say $$\int f(x) g(x) dx=\int f(x) dx \times \int g(x) dx$$
I hope this helps you.
