find the equations of the tangents at the points P and Q The curve ${y = (x -1)(x^2 + 7)}$ meets the x-axis at P and the y-axis at Q.
Find the equations of the tangents P and Q.
I am not looking for the answer but just some hints to get me started.
I am not sure how to being.

Hints:


*

*$P$ is where $y=0$, so either $x-1=0$ or $x^2+7=0$.

*Similarly, $Q$ is where $x=0$, in which case $y=(0-1)(0+7) = -7$.

*The tangents will be of the form $y=mx+b$. Since the line is tangent to the curve, you must evaluate the derivative at $P$ and $Q$. Whatever you get for the derivative will be the slope $m$.

