Vector question regarding plane and area How do i find the area enclosed within the $3$ points when the plane intersects the $x, y$ and $z$ axis and 
The plane is $ax+by+cz=1$
Need help on solving this as it has been bothering me for some time

The points are $X=(\frac 1a,0,0), Y=(0,\frac 1b,0), Z=(0,0,\frac 1c)$
You can either compute the lengths of the sides of the triangle using pythagoras, and then the area using Heron's formula. Or compute the magnitude of the vector product $(Y-X)\times (Z-X)$ which may be computationally simpler.
