How can you solve this convolution? Let $c$ be a positive constant and let $f(t)=\delta(t-c)$. Compute $f*g$. So setting up the integral, I get $$ (f*g) = \int_0^t \delta (t-\tau-c) g(\tau) d\tau$$ I am unsure of how to take the integral of the delta function. Any help would be greatly appreciated. 

If you want compute $f*g$, that is $$(f*g)(t) = \int_{-\infty}^{+\infty}\delta(t-c-\tau)g(\tau)d\tau=g(t-c)$$
