$e^{\large\frac{-t}{5}}(1-\frac{t}{5})=0$ solve for t I'm given the following equation an i have to solve for $"t"$ This is actually the derivative of a function, set equal to zero:
$$f'(t) = e^\frac{-t}{5}(1-\frac{t}{5})=0$$
I will admit im just stuck and im looking for how to solve this efficiently.
steps $1,\;2$ - rewrote the equation and distributed:
$$\frac{1}{e^\frac{t}{5}}(1-\frac{t}{5}) \iff \frac{1-\frac{t}{5}}{e^\frac{t}{5}} $$
steps $3, \;4$ - common denominator of 5,  multiply by reciprocal of denominator:
$$ \frac{\frac{5-t}{5}}{e^\frac{t}{5}}\iff\frac{\frac{5-t}{5}}*\frac{1}{e^\frac{t}{5}}  = \frac{5-t}{5e^\frac{t}{5}}  $$
step 5, set  this is where I,m stuck:
$$f'(t) = \frac{5-t}{5e^\frac{t}{5}}=0$$
How do i go from here? And am I even doing this correctly? Any help would be greatly appreciated.
Miguel

$e^{\dfrac{-t}{5}}\neq0$. (Cause: $\frac{1}{e^\frac{t}{5}}$ is a real number)
Therefore, the other term has to be zero.
Now you can solve it !
