Need help with curve of intersection I have $16x^2+y^2=16$ and $x+y+z=7$
I need to find the length of the curve of intersection of these two. 
This is what I did:
$$\begin{align}
&x^2+\frac{y^2}{16}=1\\
&x=\cos t\\
&y = 4\sin t\\
&z = 7-\cos t - \sin t
\end{align}$$
so the vector equation is 
but it shows that this is not correct, because the plot doesn't work.Please let me know what went wrong. 

You should have
$$ z = 7 - x - y = 7 - \cos t - 4 \sin t.$$
