Find a formula a_n Find a formula an for the nth term of the arithmetic sequence whose first term is $a1=1$ such that $a_{n+1} - a_n=17$ for $n≥1$.
I am not sure on the process for solving this. Is it simply solving for $a_n$ so it would give me the result $a_n = a_{n-1} + 17$

Observe that
$$
a_n=a_1+\sum_{k=1}^{n-1} (a_{k+1}-a_k) \quad (n>1)
$$
by telescoping sum whence
$$
a_n=1+17(n-1)\quad (n>1)
$$
