Given the differential equation: $\frac{dy}{dt} = (y-2)(y-5)^2$ sketch phase line and identify equilibrium I am  trying to sketch the phase line and identify equilibrium and I am getting both solutions to be unstable , where I think the upper solution has to be stable and the lower one should be unstable

a) Sketch the phase line diagram for $\frac{dy}{dt} = (y-2)(y-5)^2$
b) Identify each equilibrium solutions as stable or unstable. Sketch the solutions corresponding to $y(0) = 3$

This is what I have:

How would you do this?

Here is a direction field for your problem.
It has many initial points included, plus direction. Notice that in one case, we have points leaving and in the other we approach from one side, but leave from the other.


