How do I solve this $\lim\limits_{s\to \infty}\frac{2s^2}{s^2-4}$ How do I solve this  $$\lim_{s\to \infty}\frac{2s^2}{s^2-4}$$ .
I have tried partial fraction, but it does not give me a constant. And I know the answer is 2.

As an alternative
$$\frac{2s^2}{s^2-4}=2+\frac{8}{s^2-4} \to 2+0=2$$
