Simple integration I'm currently learning calc 2 and feel I'm making a very silly, obvious mistake with solving the integral $\int\frac{-5\sqrt[3]{x^2}}3 dx$
I guess I'm making an algebraic mistake somewhere, this is how I went about solving it:
$$\int\frac{-5x^\frac{7}3}3 dx$$
$$\int-5x^\frac{-2}3 dx$$
$$\frac{-5x^\frac{1}3}{\frac13} = -15x^\frac{1}3 + C$$
But the actual answer is $-x^\frac{5}3$ + C

$$\int \frac{-5x^{\frac{2}{3}}}{3}dx=-\frac{5}{3} \int x^{\frac{2}{3}} dx=-\frac{5}{3} \cdot \frac{3}{5} x^{\frac{5}{3}}+c=-x^{\frac{5}{3}}+c$$
