The number of integral values of $a$ for which the inequality $3- |x-a |>x^2$ is satisfied by at least one negative $x$, must be equal to 6 The number of integral values of $a$ for which the inequality $3- |x-a |>x^2$ is satisfied by at least one negative $x$, must be equal to 6.
I don't know how to solve this. Can you help?

this is the graph of x^2 and 3-|x-a|
as you can see the graph of $x^2$ and $3-|x-a|$ will intersect on negative x- axis if a<3 and a>-3.25 so that right part of inverted V shaped curve is tangent to $x^2$ 
