Find the range of values which has no real solutions I would like to know how to solve the following problem:

Find the range of values of the parameter $m$ for which the equation $2x^2 - mx + m = 0$ has no real solutions.

I know I have to use the quadratic formula and the response is $0 < m < 8$.
But what I don't know is how to proceed to find this answer. Thanks for your help.

If you rearange equation like this $$m= {2x^2\over x-1}$$ you must figer out for witch $m$ graph of $f(x) = {2x^2\over x-1}$ does not cuts the line $y=m$ ?

