Probability that 3 randomly selected elements of a set are equal check I have the following question:
Let A = {1, 2, 3, . . . , 100}. Let x, y, and z be elements in A that are chosen independently
and uniformly at random. What is the probability that x = y = z?
Because if x is chosen first, only y and z have to be equal to it, would this mean that the answer is $\frac{1}{100 \cdot 100}$? 

Yes, you are exactly right. This should be a comment however I don't have enough reputation to put a comment.
If number is picked without replacement, how can they be equal?
