Exact number of events to get the expected outcoms Suppose in a competition 11 matches are to be played, each having one of 3
distinct outcomes as possibilities. How many number of ways one can predict the
outcomes of all 11 matches such that exactly 6 of the predictions turn out to
be correct?

Hint:
You have $11$ match guesses, out of which $6$ of the guesses are exactly right. So, probability of any random $6$ is $1$, so probability of predicting other $5$ games will be $0$.
So, you choose any $6$ matches out of $11$ AND other other games' possible outcomes are wrong(which have two options left). When you have AND, you multiply number of ways of both.As Andre Nicolas suggested.
