How to pronounce Stirling Numbers of Second Kind ${n\brace k}$? The Stirling Numbers of the Second Kind, ${n\brace k}$, count the number of ways to partition an $n$-element set into $k$ unlabeled non-empty parts and are rather useful for several introductory questions in combinatorics alongside the other earlier taught binomial coefficients $\binom{n}{k}$ and factorials, and so on.
The binomial coefficients have a standardized way of reading them aloud in English, being "$n$ choose $k$."  Is there anything similar for Stirling Numbers of the Second Kind?  Or for the Stirling Numbers of the First Kind?
In my head, when typing them out or thinking of them, I often read them with the TeX commands as "n brace k"... but if I were to try to use a more suggestive phrase that helps imply the meaning of the notation I might prefer "$n$ partition $k$" or "Second Stirling $n$ $k$."
I am curious how other people read this aloud in a classroom setting or in their own head.

The book Concrete Mathematics by Graham, Knuth & Patashnik suggests “$n$ subset $k$” for ${n\brace k}$ and “$n$ cycle $k$” for ${n \brack k}$ (pp. 258–259 in the second edition).
