Solving Boolean expression (A+C+D)(A+C+D’)(A+C’+D)(A+B’)
This is my first attempt on solving four algebraic terms using boolean expression. I am stuck,please help me. I have a test tommorow. 
Thanks! 

Hint: Simplify bracket by bracket. For example $$(A+C+D)(A+C+D') = AA+AC+AD'+CA+CC+CD'+DA+DC+DD' \\ = A+AC+AD'+CA+C+CD'+DA+DC \\= A+AC+AD'+C+CD'+DA+DC \\= A+AC+C+A(D+D')+C(D+D') \\= A+AC+C+A+C=A+C+AC=A+C$$
Now you can put this expression in the place of the first two brackets and solve again, keeping the rules of simplifying in mind. 
