Integrating $x/(x-2)$ from $0$ to $5$ How would one go about integrating the following?
$$\int_0^5 \frac{x}{x-2} dx$$
It seems like you need to use long division, split it up into two integrals, and the use limits. I'm not quite sure about the limits part.

$\displaystyle \int$$\displaystyle {\frac{{dx}}{{ax + b}}}$ = $\displaystyle {\frac{{1}}{{a}}}$$\displaystyle \int$$\displaystyle {\frac{{dt}}{{t}}}$ = $\displaystyle {\frac{{1}}{{a}}}$ $\ln| t| + C =$ $\displaystyle {\frac{{1}}{{a}}}\ln| ax + b| + C$. 
where
$ax + b = t$
