Area triangle (possible) The area of a right triangle is an integer greater than $ 85 $. If the hypotenuse measures $ 20 $, what is the area of this triangle?
It’s just a 3-4-5 right triangle, so the area is $\boxed{96}$.
This is true? If so, how to prove it?
But he said the area is integer, not the sides
Can you use Weitzenbock inequality in this problem? 

If the hypotenuse is $20$, the ratio is then $4$ times that of a $3-4-5$ triangle or $12:16:20$. Now the area is $\frac{1}{2} \times 12 \times 16 = 96$ which is indeed greater than $85$.
