Expanding $(x-2)^3$ I was trying to expand $(x-2)^3$. This is what I did


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*Expanded the term so $(x-2)(x-2)(x-2)$

*Multiplied the first term and second term systematically through each case


The answer I got did not match the one at the back of the book, can someone show me how to do this please?

Make use of the identity: $$(x-y)^3=x^3-3x^2y+3xy^2-y^3.$$
Letting $y=2$, we obtain: $$(x-2)^3=x^3-6x^2+12x-8.$$
