Related Rates - Finding dx/dt I've attempted this problem 11 times now using veriest resources and I can't get it. Here's the problem I'm trying to solve: 
Suppose that x = x(t) and y = y(t) are both functions of t. If 

     y^2 + xy -3x = 5

and dy/dt = 1 when x = -1 and y = -1, what is dx/dt?

I'm trying to start by converting the above into this: 
2y + x (dx/dy) * y (dy/dt) - 3 = 0

but it never comes out to the correct answer once I plug in the values so now i'm completely lost. 
Thanks for your help!

By taking the derivative of $y^2 + xy -3x = 5$ with respect to $t$, we  get
$$2y\frac{dy}{dt}+x\frac{dy}{dt}+\frac{dx}{dt}y-3\frac{dx}{dt}=0.$$
By substitution,
$$-2-1-\frac{dx}{dt}-3\frac{dx}{dt}=0,$$
implying that
$$\frac{dx}{dt}=-\frac34\cdot$$
