How to find the limit $\lim_{n\to \infty}\frac{n}{2^n-1}$? I've been trying to find and prove the 
$$\lim_{n\rightarrow\infty}\frac{n}{2^n-1}$$
but I haven't even figure out the limit, could anyone help?

$$\lim_{n\to\infty}\frac{n}{2^n-1}=\lim_{n\to\infty}\frac{1}{2^n\ln2}=\dfrac{1}{\ln{2}}\lim_{n\to\infty}2^{-n}=\dfrac{1}{\ln{2}}\cdot0=0$$
