Find convergence in probability for variance that changes I'm preparing for my exam and was trying out this question:

Let $X_1, X_2,\dots,X_n$ be independent random variables with $E(X_i) =\mu, V(X_i) = \begin{cases} 2 & \text{ if } i \text{ is odd} \\ 3 & \text {if } i \text{ is even}\end{cases}$. Show that $\bar{X} \stackrel{\Bbb{P}}\to \mu$ as $n \to \infty$.

Here is my working:
$$\Bbb{P}(|\bar{x}-\mu| \geq \epsilon) \leq \frac{\operatorname{\rm Var}(\bar{x})}{\epsilon^2}=\frac{2}{n\epsilon^2} \text{ or } \frac{3}{n\epsilon^2} \to 0 \text{ as } n \to \infty,$$
so as $n \to \infty,\bar{X} \stackrel{\Bbb{P}}\to \mu $.
I have a feeling that it is not correct. Anyone can help point out where I did wrong?

$$\text{Var}(\bar{X}_n) = \frac{1}{n^2} \sum_{i=1}^n \text{Var}(X_i) \le \frac{3}{n}.$$
