Interpreting Division as subtraction Basically, Division is the inverse of multiplication, see this instance:  
5  × 4,
This basically means, adding five four times,
5, 5, 5, 5 added together is 20; 
If division is the inverse of multiplication and multiplication comes from repeated addition, how can we interpret division as repeated subtraction?
Consider:
20/4;
How can we interpret this as the statements in bold above?  
That's the level 1 of confusion, the next is, while taking the word PEPPER:
Total arrangement is given by the formula:    
6!/(3!2!)
How can we interpret the result as above, i.e. with the division interpreted as a series of repeated subtraction?
EDIT: And how do we relate this with the fact that division is breaking things up equally with respect to the denominator? And in this case:
Why isn't 6!-(3!2!)used?

If you want to interpret "$20$ divided by $4$" in terms of repeated subtraction, what you would do is repeatedly subtract $4$ from $20$ until you get $0$:
$$16, 12, 8, 4, 0$$
The number of times you had to subtract $4$ is exactly the quotient $\frac{20}{4}$.  This same principle carries over to the quotient $\frac{6!}{3!2!}$: you repeatedly subtract $3!2!$ from $6!$ until you get zero, and the number of times you subtracted it is the quotient.
The same principle sort of works when $a, b$ are positive integers, but $\frac{a}{b}$ is not an integer.  Let's say you want to interpret the division of $27$ by $4$ as repeated subtraction.  What you would do is repeatedly subtract $4$ from $27$, until you eventually get a number between $0$ and $3$.  The number of times $q$ that you subtracted $4$ to get to that point, and the number $r$ between $0$ and $3$ that you get, satisfy $q = 6$ and $r = 3$.  Then 
$$q + \frac{r}{4} = 6 + \frac{3}{4}$$
is equal to the quotient $\frac{27}{4}$.
