Simple trigonometry question (angles) I am starting again with trigonometry just for fun and remember the old days. I was not bad at maths, but however I remember nothing about trigonometry...
And I'm missing something in this simple question, and I hope you can tell me what.

One corner of a triangle has a 60º angle, and the length of the two
  adjacent sides are in ratio 1:3. Calculate the angles of the other
  triangle corners.

So what we have is the main angle, $60^\circ$, and the adjacent sides, which are $20$ meters (meters for instance). We can calculate the hypotaneous just using $a^2 + b^2 = h^2$. But how to calculate the other angles?
Thank you very much and sorry for this very basic question...

This is indeed a very basic question. The information you have is "Side-Angle-Side (SAS)", which is enough to classify your triangle. (You may assume that one side has length 1 and the other has length 3 or just keep it as a variable x and 3x). Then you essentially have to apply the law of cosines, see this page for a detailed solution, or just google for SAS.
