Finding the exact value of cot(23π/4) using Unit circle I need to find the exact value of $\cot (23π/4)$.
I am thinking that I can find $\tan(23π/4)$ first and then reciprocate it to get $\cot(23π/4)$
I am having trouble trying to represent this on the unit circle.
Is it going to be $\tan (23π/4) = \tan(4π + (7π/4))$.
And I think that the zeroes(tan) are $\{nπ: n $ is an integer$\}$ so $6π$ would be a zero, so from the unit circle, I essentially start like this?


You're almost there. First, well thought that $\;\cot x=\frac1{\tan x}\;$, then using that the tangent function has a $\;\pi\,-$ period (not $\;2\pi$ !), you get
$$\tan\frac{23\pi}4=\tan\frac{3\pi}4=\frac{\sin\frac{3\pi}4}{\cos\frac{3\pi}4}$$
and now use your knowledge of trigonometry to find the above. The number will be negative , of course (why?)
