Solving complex number equations I haven't been able to find any help about this and my math book is not helping at all. I need to solve this equation:
z+1 = iz 
Any help would be greatly appreciated

Assume that $z=a+bi$ then we have for the equation.
$$a + bi + 1 -ai +b=0$$
$$(a+b+1) + (b-a)i=0$$
Now set $a+b+1=0$ and $a-b=0$ to get $a=b=-\frac 12$, hence $z = -\frac 12 - \frac i2$
