2 of 3 dice are selected randomly and thrown. What is the probability that one of the dice shows 6 1 red die with faces labelled 1, 2, 3, 4, 5, 6.
2 green dice labelled 0, 0, 1, 1, 2, 2.
Answer: 1/9
Please can you show me how to get the answer. I'm confused about joining the events of choosing 2 of 3 dice vs. getting the probability that one of the dice chosen will get a 6 when rolled.
Note: There is an equi-probable chance of getting any of the six sides on a given die.

Two ways to select a die: (Red,Green) or (Green,Green), out of which only (Red,Green) can show a 6.
Now total ways are: 
$$\begin{array}{|c|c|}\hline(Red,Green)&6\times3=18\\\hline(Green,Green)&3\times3=9\\\hline\end{array}$$ Total=27, Now for 6, ways are (Red,Green)$1\times3=3$;so probability is $3/27=1/9$
