An airplane is heading due south at a speed of 500 km/h. If a wind begins blowing from the southwest at a speed of 100 km/h, calculate the velocity of the plane relative to the ground, and how far off course it will be after 10 min. if the pilot takes no corrective action.
Answer: 435 km/h, 9.36 degrees east of south
x = hypotenuse * cos(45)
x = 100 km/h * cos(45)
y = hypotenuse * sin(45)
Y = 100 km/h * sin(45)
The Attempt at a Solution
First I drew a diagram with N, E, S, W labeled. I then drew a line going NE since the wind is coming from SW. Then using the same starting point as the wind I drew 500 km/h going south to represent the airplane. I now wrote in a 45 degree angle for the wind. From this point I made a right triangle for the wind. To find the x and y I used sin and cos to get the values y = 70.71 km/h and x = 70.71 km/h. Am I on the right track or no?