Alan B. Pearce email (remove spam text)
>> Umm, wrong. The magnetic field induces a current in the coil,
>> and the voltage you get out of that will depend on what resistor
>> you put across the coil.
>What you are saying is that magnetic field induces a current in the
>coil and the coil becomes an ideal current source ?
The coil will never be an ideal current source because of leakage inductance
and other loss effects, but within the useful range of load resistance that
will be essentially how you need to treat it.
Don't forget that the load resistance you put on the secondary will be
reflected back to the primary causing a finite, but small, voltage drop in
the wire that forms the primary winding.
But you still haven't said what current range you are looking to measure.
See also: www.piclist.com/techref/microchip/devices.htm?key=pic
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