I have a CSV file of approx 1000 rows, and where I'm supposed to import it, I get an error on row 700. However, the entries in this CSV contain newlines (and are quoted), and thus I cannot really quickly use awk or similar to show what is row 700.So I found Is there a robust command line tool for processing csv files?, and installed both csvfix and csvkit; however it seems none of these applications supports simply specifying a row number (or a range of rows), and outputting them. For instance:$ csvfix help echoecho input CSV data to outputusage: csvfix echo [flags] [file ...]where flags are:  -ibl      ignore blank input lines  -sep s    specify CSV field separator character  -rsep s   as for -sep but retain separator on output  -osep s   specifies output separator  -hdr s    write the string s out as a header record  -ifn      ignore field name record  -smq      use smart quotes on output  -sqf fields   specify fields that must be quoted  -o file   write output to file rather than standard output  -skip t   if test t is true, do not process or output recordI would have thought echo is what I need, as soon as I could specify which row(s) is(are) to be echoed, but when I look at http://neilb.bitbucket.org/csvfix/manual/csvfix16/csvfix.html?unique.html, only columns are described.How could I use these tools - or other tools - to simply dump say row 700 (or rows 702-705) from a 1000-row CSV to stdout?EDIT: Found (http://neilb.bitbucket.org/csvfix/manual/csvfix16/ExpressionLanguage.html) that csvfix has:csvfix find -if '$line == 407' data.csv... however, this is indeed line number and not row number; so if the row starts at line 406, then breaks to line 407, and ends at 407; then the above command will output nothing - but if you go one line back, -if '$line == 406', then the row is dumped. This is useful too, but still isn't a row number....
Extract (and dump to stdout) only certain range of rows from a CSV?
command line;csv