I'm wanting to prepend the epoch time to a single line of arguments. My desired output is:$ echo foo bar baz | some_bash_awk_sed_date_program_or_something_else1491146539 foo bar bazThe actual output I'm getting can be seen below:$ echo foo bar baz | awk -f time_stamper.awk14911465390 foo bar bazMy time_stamper.awk:BEGIN { OFS= printf %s , system(date +'%s')}{ print }I think the leading 0 is coming from the return value from date +'%s'. I was expecting setting the OFS=  would at least return 1491146539 0 foo bar baz changing the newline to space.Some questions about my current attempt:What is wrong with my usage of the OFS built-in variable?Why is the 0 printing in front of foo bar baz?More importantly, I'm not sure if awk is the right tool for the job. Maybe I should use sed, date or some other utility. How do I print the desired output?Note: This question is more specific and therefore different from this question. Also, the answer requires the installation of moreutils which seems like an interesting addition the Unix toolset; however, I'd rather stick with more traditional Unix utilities to perform my task.
How do I prepend a line read from STDIN with an epoch timestamp?
bash;text processing;awk;date