My query is to extract the value between double quotes . Sample input is:10.219.41.68 - - - [11/Jun/2014:10:23:04 -0400] Sec:0 MicSec:1797 GET /balancer-manager HTTP/1.1 200 28980 - curl/7.15.5  (i386-redhat-linux-gnu) libcurl/7.15.5 OpenSSL/0.9.8b zlib/1.2.3  libidn/0.6.5I have large log files, so values can be vary for each line, need to extract the value between first occurrence of double quotesExpected output:GET /balancer-manager HTTP/1.1Anyone have any idea then please suggest.
Extract value between double quotes
awk