In zsh, there is the [m,n] glob qualifier which works as follows:[beg[,end]]specifies which of the matched filenames should be included in the  returned list. The syntax is the same as for array subscripts. beg and  the optional end may be mathematical expressions. As in parameter  subscripting they may be negative to make them count from the last  match backward. E.g.: *(-OL[1,3]) gives a list of the names of the  three largest files.So for example, if I type:print *([2,10]) it will return the elements 2 to 10 matched by *.My question is: How can I ask zsh to return the matched elements starting from element X to the end of the list?For example say I have 2500 files in one folder, BUT I don't know this number, and I would like to match all files starting from file 160.I have tried:1) print -l *([160]) -> only matches file # 160. 2) print -l *([160,]) -> No matches found3) print -l *~*([1,160])-> No matches found
List all the matched files starting from an index
zsh;wildcards
A negative number counts from the end. The last element is -1.print -l *([160,-1])If you wanted the last 42:print -l *([-42,-1])