I have a set of three coupled autonomous equations:${y_{1}}\prime = y_{1}(\frac{\Omega_{m}}{y_{1}^3} + \frac{y_{3}^2}{6.0} + \frac{V(y_{2})}{2.H_{0}^2})$$y_{2}\prime = y_{3}$$y_{3}\prime = -3\frac{y_{1}\prime}{y_{1}}y_{3} - \frac{1}{H_{0}^2}\frac{\partial v(y2)}{\partial y_{2}}$And I have used the following code to solve it using scipy.odeint:  def f(y,t):    Xi = y[0]    Yi = y[1]    Zi = y[2]    f0 = Xi*(onr/(Xi**3) + (H**2)*(Zi**2)/(2.0*rho_c) + (v0*np.exp(-l*Yi*k))/(rho_c))**(1.0/2.0)    f1 =  Zi    f2 =  -3*Zi*(H**2)*(onr/(Xi**3) + (H**2)*(Zi**2)/(2.0*rho_c) + (v0*np.exp(-l*Yi*k))/(rho_c))**0.5 + (l*k*v0*np.exp(-l*Yi*k))/(H**2)    return [f0,f1,f2]X0 = [1.0]Y0 = [1.0]Z0 = [c]y0 = [X0,Y0,Z0]t = np.linspace(start=1.0,stop=0.0,num=10001)soln = odeint(f,y0,t)X = soln[:,0]Y = soln[:,1]Z = soln[:,2]  But when I run it ValueError: Initial condition y0 must be one-dimensional shows up. What should I do? I am new to python and this is the first time I am using this. Any help or explanation here would be great.
Using scipy.odeint to solve coupled equations
numerical analysis;python;ode;scipy;integration
You shouldnt have defined X0, Y0, and Z0 as lists. As it stands, y0 is a list of lists  i.e., two-dimensional. You can solve this by replacing the respective lines with:X0 = 1.0Y0 = 1.0Z0 = c