I'm writing some scripts for testing an API. I'm interested in the JSON response as well as the HTTP status code of the request. I definitely want to pretty-print the JSON response in order to make it easier to read.I'm using curl to perform the request and want to use python -m json.tool to pretty-print the json result.Curl has a nice option -w that can be used to surface information about the request, like %{http_code}. Unfortunately, that information prints to stdout and confuses python -m json.tool. It seems it isn't possible to configure it to ignore trailing non-json data.When I docurl \'--silent' \'--insecure' \'-L' \'-w' \'\n%{http_code}\n' \'--user' \<REDACTED> \'-X' \'GET' \'--' \'https://somecompany.com/some_api_endpoint' \| python -m json.toolI get$ bash call_api_endpoint_script.sh Extra data: line 2 column 1 - line 3 column 1 (char 203 - 207)Exit 1Is there a way to configure curl to write the status code to a file? The -w option in the man page doesn't seem to mention the possibility of redirecting this information elsewhere.
curl write http code to stderr or to file
curl