I have a task to join two bezier curves, so that the resulting curve is two-times continuously differentiable.I have the cubic bezier Curve C with control points:c0 = (1,1)c1 = (3,4)c2 = (7,5)c3 = (8,2)I shall continue this curve C with Curve D from control point c3 to a control point d3 = (12,1) so that this curve is two-times continuously differentiable.First Task: Determine control points d0, d1, d1 for the new curve.Second Task: Specify a pecewise defined formula for the new curve G(v) with v out of [0,1] that passes through c0,c3 and d3. Thus connect curves C and D in v = 1/2.Third Task: Prove by calculation that the transition between C and D is two-times continuously differentiable.Regarding first task: I don't know how to determine the points. Can someone help to do this? The rest of the tasks is then maybe something easier to do for me.
Join two bezier curves so that the result is two-times continuously differentiable
bezier curve