I have a function defined in my .bashrc that I would like to bypass:function func() {   // func}export -f funcWhen I run env -i func I can access the func command without the function in the way, but if I try func or \func then I don't have any luck.I read on another post that \ should work to bypass bash functions, is this true? If so, is there any reason that I am not able to use it in this case?
Does \ work for escaping functions?
bash;shell;function
The official way to prevent function definitions from being used by the shell is to call:command funcSee: http://pubs.opengroup.org/onlinepubs/9699919799/utilities/command.html