I'm connecting to a VPN service using OpenVPN and everything works fine.Once I connect these are the rules that automatically are set:root@linux:~# ifconfigeth0      Link encap:Ethernet  HWaddr 00:AA:1B:01:AC:FB            inet addr:192.168.1.201  Bcast:192.168.1.255  Mask:255.255.255.0          UP BROADCAST RUNNING MULTICAST  MTU:1500  Metric:1          RX packets:46867 errors:0 dropped:0 overruns:0 frame:0          TX packets:29742 errors:0 dropped:0 overruns:0 carrier:0          collisions:0 txqueuelen:1000           RX bytes:37977382 (36.2 MiB)  TX bytes:5098121 (4.8 MiB)          Interrupt:16 tun0      Link encap:UNSPEC  HWaddr 00-00-00-00-00-00-00-00-00-00-00-00-00-00-00-00            inet addr:10.7.7.126  P-t-P:10.7.7.125  Mask:255.255.255.255          UP POINTOPOINT RUNNING NOARP MULTICAST  MTU:1500  Metric:1          RX packets:23284 errors:0 dropped:0 overruns:0 frame:0          TX packets:5817 errors:0 dropped:0 overruns:0 carrier:0          collisions:0 txqueuelen:100           RX bytes:31366374 (29.9 MiB)  TX bytes:308591 (301.3 KiB)root@linux:~# routeKernel IP routing tableDestination     Gateway         Genmask         Flags Metric Ref    Use Ifacedefault         10.7.7.125      128.0.0.0       UG    0      0        0 tun0default         192.168.1.1     0.0.0.0         UG    0      0        0 eth05.120.121.114   192.168.1.1     255.255.255.255 UGH   0      0        0 eth010.7.7.1        10.7.7.125      255.255.255.255 UGH   0      0        0 tun010.7.7.125      *               255.255.255.255 UH    0      0        0 tun0128.0.0.0       10.7.7.125      128.0.0.0       UG    0      0        0 tun0192.168.1.0     *               255.255.255.0   U     0      0        0 eth0Here is what I understand:my local IP address is 192.168.1.201local gateway is 191.168.1.15.120.121.114 is the VPN public iptun0 is the VPN tunnel, my machine has 10.7.7.126 as address10.7.7.125 is the p-t-p address I understand is the other end of the VPNRegarding the routing table I understand that:by default all traffic is sent via 10.7.7.125 on interface tun0 (but why that mask?)10.7.7.1 is reachable via tun0public ip of vpn is reachable via eth0I don't understand the second default gateway, this is the default when the vpn is not active, is it simply bypassed?What about the 10.7.7.1? looks like it is the gateway of the vpn...Why the destination 128.0.0.0?OpenVPN automatically creates all these rules. But based on what are those created?I cannot control the server side of the VPN but only the client configuration.Now what if I would like to:force all traffic to 216.58.213.174 to go via VPN tun0 and have all the rest going through eth0?can I have it established automatically when starting the VPN?Thank you for your suggestion and support in understanding this.KR, dkEDIT:root@linux:~# ip route list0.0.0.0/1 via 10.7.7.125 dev tun0 default via 192.168.1.1 dev eth0 5.152.210.249 via 192.168.1.1 dev eth0 10.7.7.1 via 10.7.7.125 dev tun0 10.7.7.125 dev tun0  src 10.7.7.126 128.0.0.0/1 via 10.7.7.125 dev tun0 192.168.1.0/24 dev eth0  src 192.168.1.201 
OpenVPN - Understand the routing table + How to route only the traffic to a specific ip via the VPN
routing;openvpn