A pure ALOHA Network transmit 200 bit frames using a shared channel with 200 Kbps bandwidth. If the system (all stations put together) produces 500 frames per second, then the throughput of the system is$0.384   $$0.184$$0.286   $$0.586$My attempt:Well, this question is from UGC-NET-16-CS-3 paper(see question no.- 27 on page no.-6). Throughput should be $ 500  0.184 = 92$, but no option matched.(As, explained on example 12.3 on page no.-8). $0.184$ is efficiency of pure ALOHA.Official key is given option $(2)$ (see ans.no.-27 on page no.-71). But, $0.184$ is efficiency of pure ALOHA but not throughput. Are given options correct? Can you explain it, please?
Throughput of pure ALOHA
efficiency;computer networks;performance;communication protocols;protocols