I have a csv file that has many lines of timestamps in following format HH:MM:SS:MSFor example:00.00.07.38    00.00.08.13    00.00.08.88The hour is not relevant to me so I would like to cut it out. How do I remove HH from every line in file with bash.I can read line by line from the filewhile IFS=, read col1do    #remove HH from every line    #awk -F '[.]' '{print $1}' <<< $col1 #only prints one portion of time    #echo $col1 | cut -d. -f2 | cut -d. -f3 | cut -d. -f4done < $fileI have been playing around with awk and cut but was only able to print a specific position ex HH etcBut how to remove just the HH from the line without creating a new file?
Remove a specific portion of line
bash;sed;awk;cut