I have a files multiple file path for backup purpose ,now i want to filter it based on .csv  fromat. I have tried this.filesall=(/home/abc/allfiles/*)files=$((${filesall[@]}|grep -F .csv))files=$(${filesall[@]}|grep -oe *.csv)but unable to extract .csv files from $filesall . I know i can achieve it like this files=(/home/abc/allfiles/*.csv)any suggestion ,how can i get all .csv files from filesall.Thanks.
Extract csv files from path to multiple files in bash
bash;shell;files;sed;grep