I looked into the integrated manual of the xargs command, where the -I option is explained. And though I read the few lines repeatedly, I can not make any sense of it:-I replace-str                Replace  occurrences of replace-str in the initial-arguments with names read from standard input.  Also, un                quoted blanks do not terminate input items; instead the separator is the newline character.  Implies -x  and                -L 1.Could you explain this to me with other words or give me a jump start by an example, which shows the importance of this option?
what is the purpose of the -I option of the xargs command?
command line;xargs
Here is a quick pair of examples of xargs -I in action:$ echo foo bar baz | xargs -I quux echo quuxfoo bar baz$ echo -e foo\nbar\nbaz | xargs -I quux echo quuxfoobarbaz-I means Replace this marker with the newline-separated items coming in from standard input.