I've been reviewing C programming and there are just a couple things bothering me.Let's take this code for example:int myArray[5] = {1, 2, 2147483648, 4, 5};int* ptr = myArray;int i;for(i=0; i<5; i++, ptr++)    printf(\n Element %d holds %d at address %p, i, myArray[i], ptr);I know that an int can hold a maximum value of positive 2,147,483,647. So by going one over that, does it spill over to the next memory address which causes element 2 to appear as -2147483648 at that address? But then that doesn't really make sense because in the output it still says that the next address holds the value 4, then 5. If the number had spilled over to the next address then wouldn't that change the value stored at that address?I vaguely remember from programming in MIPS Assembly and watching the addresses change values during the program step by step that values assigned to those addresses would change. Unless I am remembering incorrectly then here is another question: If the number assigned to a specific address is bigger than the type (like in myArray[2]) then does it not affect the values stored at the subsequent address?Example: We have int myNum = 4 billion at address 0x10010000. Of course myNum can't store 4 billion so it appears as some negative number at that address. Despite not being able to store this large number, it has no effect on the value stored at the subsequent address of 0x10010004. Correct?The memory addresses just have enough space to hold certain sizes of numbers/characters, and if the size goes over the limit then it will be represented differently (like trying to store 4 billion into the int but it will appear as a negative number) and so it has no effect on the numbers/characters stored at the next address.Sorry if I went overboard. I've been having a major brain fart all day from this.
If a number is too big does it spill over to the next memory location?
architecture;c;memory;hexadecimal