I want to, from a bash shell script, present the user with a menu of choices to pick from. The selection should then be stored in an environment variable for further use later.If I run from the command line:dialog \    --backtitle Make a choice \    --menu Take a pick \    10 40 3 \    choice1 First choice \    choice2 Second choicethen everything works fine; I get the menu that I want, and choice1 or choice2 is printed back at me. However, if instead I run:SELECTION=$( dialog \    --backtitle Make a choice \    --menu Take a pick \    10 40 3 \    choice1 First choice \    choice2 Second choice \)then it no longer works the way I want to.No menu is displayed, although (as far as I can tell) dialog exits when I press EnterWhen I exit the non-displayed menu by pressing Enter, the tag of the selection appears on the terminal rather than being stored into $SELECTIONI have tried adding 2>&1 to redirect stderr to stdout, in case it really was being printed to stderr instead. The only noticable effect of that is that now, nothing is returned, either from the command substitution expression or printed to the terminal.On my system, dialog is cdialog 1.1-20120215. The dialog man page says about --menu that On exit the tag of the chosen menu entry will be printed on dialog's output. This seems like it should work fine with something like the above, but it doesn't for me.I want the menu to be displayed, allowing the user to pick between the available choices, and when the user accepts, the tag (for example, choice2) for the selected choice to be stored in the environment variable $SELECTION. If the user cancels, there should be clear indication of that (ideally, $SELECTION would be undefined or a zero-length string).How can I do that? What piece of the puzzle am I missing?Solutions suggesting alternatives to dialog are also acceptable, as long as they present a nice menu to choose from and ideally the software suggested isn't too exotic (availability in the Debian Stable main repository is a requirement).
Why doesn't `dialog` display the menu (but accepts acceptance) when started through a command substitution expression?
bash;dialog
Try with the --stdout option:$ SELECTION=$( dialog --stdout \    --backtitle Make a choice \    --menu Take a pick \    10 40 3 \    choice1 First choice \    choice2 Second choice \)