I want to find if 'N' numbers are even or odd in the fastest way possible.Here's the following code which produces the desired output, but I do not know how efficient it is. int main() {int N,x;scanf(%d,&N);while(N--){   scanf(%d,&x);    x&1 ? cout << No << endl : cout << Yes << endl;}return 0;Can this code be improved in any way to get faster results?
Fastest way to find if N numbers are even or odd
c++;algorithm