I have the following in a filedescription: '''        This rule forbids throwing string literals or interpolations. While        JavaScript (and CoffeeScript by extension) allow any expression to        be thrown, it is best to only throw <a        href=https://developer.mozilla.org        /en/JavaScript/Reference/Global_Objects/Error> Error</a> objects,        because they contain valuable debugging information like the stack        trace. Because of JavaScript's dynamic nature, CoffeeLint cannot        ensure you are always throwing instances of <tt>Error</tt>. It will        only catch the simple but real case of throwing literal strings.        <pre>        <code># CoffeeLint will catch this:        throw i made a boo boo        # ... but not this:        throw getSomeString()        </code>        </pre>        This rule is enabled by default.        '''with several other things in this file.I extract this part in my shell script via sed -n /'''/,/'''/p $1 (where $1 is the file).This gives me a variable with the content as one linerdescription: ''' This rule forbids throwing string literals or interpolations. While JavaScript (and CoffeeScript by extension) allow any expression to be thrown, it is best to only throw <a href=https://developer.mozilla.org /en/JavaScript/Reference/Global_Objects/Error> Error</a> objects, because they contain valuable debugging information like the stack trace. Because of JavaScript's dynamic nature, CoffeeLint cannot ensure you are always throwing instances of <tt>Error</tt>. It will only catch the simple but real case of throwing literal strings. <pre> <code># CoffeeLint will catch this: throw i made a boo boo # ... but not this: throw getSomeString() </code> </pre> This rule is enabled by default. '''How can I now extract the part between the ''' ?Or is there even a better way to retrieve it from the multiline file ?I'm on Mac El Captain 10.11.2 and GNU bash, version 3.2.57(1)-release (x86_64-apple-darwin15)
Extract text between three single quotes
shell script;text processing
perl -l -0777 -ne print for /'''(.*?)'''/gs filewould extract (and print followed by a newline) the part between each pair of '''.Beware that perl slurps the whole file in memory before starting processing it so that solution may not be appropriate for very large files.