I am using the following code to first split an array into 2 and then search if 2 elements Alchemist and Axe are present in each of the two split arrays.tempifs=$IFS    IFS=,    match=($i)    IFS=$tempifs    team1=( ${match[@]:0:5} )    team2=( ${match[@]:5:5} )        if [ array_contains2 $team1 Alchemist Axe ]    then    echo team1 contains        fi    if [ array_contains2 $team2 Alchemist Axe ]    then    echo team2 contains        fi  array_contains2 () {     local array=$1[@]    local seeking=$2    local seeking1=$3    local in=0    for element in ${array[@]}; do        if [[ $element == $seeking && $element == $seeking1]]    then            in=1            break        fi    done    return $in}But I am getting the following error - /home/ashwin/bin/re: line 18: [: Alchemist: binary operator expected/home/ashwin/bin/re: line 14: [: too many argumentsLines 14 and 18 are  if [ array_contains2 $team1 Alchemist Axe ] and  if [ array_contains2 $team2 Alchemist Axe ] respectively.Is the error because of IFS. If not what is the cause for the error?
Finding an elements in an array in bash
bash