I'm currently in the process of creating a online work schedule for internal use. For this, the client needs to show the days of a single week.I pass a week number and a year.From that I get the first day of that week, by using strtotime() passing an argument in the format [year]-W[weekno]-[dayofweek]. Example: strtotime('2011-48W-1');With that function I create my table as mentioned earlier:<table class=weekly>    <thead>         <tr>            <?php for($i = 1; $i <= 7; $i++): ?>            <th><?php echo $dage[$i] .  . date(j/m, strtotime($year.'-W'.$week.'-'.$i)); ?></th>            <?php endfor; ?>                    </tr>    </thead>    <tbody>                 <tr>            <?php for($i = 1; $i <= 7; $i++): ?>            <td<?php if($i == 7) { echo ' class=last'; } ?>>                <?php                $day = date(Y-m-d, strtotime($year.'-W'.$week.'-'.$i));                if(isset($entries[$day])):                foreach($entries[$day] as $entry):                ?>                      <div class=workEntry title=<?php echo $entry->note; ?>>                    <span>                        <?php echo date(H:i, strtotime($entry->workStart)); ?>                        <?php if($entry->workStart != 0000-00-00 00:00:00) { echo  - .date(H:i, strtotime($entry->workEnd)); } ?>                    </span>                    <span>                    <?php if($entry->userId == 0): ?>                    Unspecifed                    <?php else: ?>                    <?php echo $entry->name; ?>, <?php echo $entry->pgroup; ?>                    <?php endif; ?>                    </span>                                     </div>                              <?php endforeach;                endif; ?>            </td>            <?php endfor; ?>                    </tr>       </tbody></table>Well, it works, but I'm pretty sure that I'm reinventing the wheel, and doing a pretty bad job at it too. I'd like to know what you think and to hear any suggestions.
Show days of single week
php;html;datetime