How can I trim a file (well input stream) so that I only get the lines ranging from the first occurrence of pattern foo to the last occurrence of pattern bar?For instance consider the following input :A linelikefoothis foobarsomethingsomething elsefoobarandtherestI expect this output:foothis foobarsomethingsomething elsefoobar
How to get all lines between first and last occurrences of patterns?
text processing;sed
sed -n '/foo/{:a;N;/^\n/s/^\n//;/bar/{p;s/.*//;};ba};'The sed pattern matching /first/,/second/ reads lines one by one. When some line matches to /first/ it remembers it and looks forward for the first match for the /second/ pattern. In the same time it applies all activities specified for that pattern. After that process starts again and again up to the end of file.That's not that we need. We need to look up to the last matching of /second/ pattern. Therefore we build construction that looks just for the first entry /foo/. When found the cycle a starts. We add new line to the match buffer with N and check if it matches to the pattern /bar/. If it does, we just print it and clear the match buffer and janyway jump to the begin of cycle with ba.Also we need to delete newline symbol after buffer clean up with /^\n/s/^\n//. I'm sure there is much better solution, unfortunately it didn't come to my mind.Hope everything is clear.