I try to learn (flat-, FASM-) Assembly currently. For to become more familiar with the concept of branching I made a tiny program. Inspired by an exercise I had to do once in school when learning PHP.Write a program which takes an integer given by the user. The program then calculates and prints the square numbers from 1 to the given number.Here my source code.I have added comments in the code. Trying to explain my thoughts and motivations.format PE consoleentry startinclude 'win32a.inc' ; ===========================================; = Displays the square number from 1 until =; =  number n. n is given by the user.      =; = @param [ integer ] n - The upper        =; =  limit. The last integer to calculate   =; =  the square number of.                  =; ===========================================; - Example --------------------------------; 100 // User have entered 100.; 1; 4; 9; 10  // 16 in base 10; 19  // 25 in base 10; 24  // 36 in base 10; 31  //   ...; 40; 51; 64; 79section '.text' code readable executablestart:    call    read_hex ; Provided by teacher. Reads in a hexadecimal number from stdin.    mov     ecx, eax    mov     ebx, 1 ; First number ...    cmp eax, 1000000 ; When the number received is smaller the upper limit ...    jle createSquareNumbers ; ... then you do not have to override it.    mov     ecx, ebp ; ... otherwise you override it with the upper limit.createSquareNumbers:    mov edx, 0    mov eax, ebx    mul ebx ; Multiply the number with itself.    call print_eax ; ; Provided by teacher. Prints eax to stdin.    inc ebx ; Go to the next integer.    cmp ebx, ecx    jle createSquareNumbers    push    0    call    [ExitProcess]include 'training.inc'It seems to work as expected.But I'm sure there's a lot of room for improvements ...So therefore: Hints and comments from more experienced Assembly programmers very appreciated. :)
Assembly beginner exercise: Calculate the square numbers from 1 to n
beginner;assembly
cmp eax, 1000000 ; When the number received is smaller the upper limit ...jle createSquareNumbers ; ... then you do not have to override it.mov     ecx, ebp ;I suspect that the upper limit is in the ebp register. (Why else would you move it to ecx when the input is too large?) Then it would be better to not use the immediate value and just write:cmp  eax, ebpcreateSquareNumbers:mov edx, 0Prior to the multiplication it is not necessary to zero the edx register. It's the division that needs this. This way you'll shave off some bytes.You should test for overflow on the multiplication! You are printing results from the EAX register only, but look what happens when the square exceeds the 32 bits of EAX. You should use this overflow (EDX <> 0) as an extra reason to exit the loop.You should write in a more readable fashion.I suggest you make all the instructions, operands, and comments start in their own columns.start:    call    read_hex            ; Provided by teacher. Reads in a hexadecimal number from stdin.    mov     ecx, eax    mov     ebx, 1              ; First number ...    cmp     eax, ebp            ; When the number received is smaller the upper limit ...    jle     createSquareNumbers ; ... then you do not have to override it.    mov     ecx, ebp            ; ... otherwise you override it with the upper limit.