In Java there are no virtual, new, override keywords for method definition. So the working of a method is easy to understand. Cause if DerivedClass extends BaseClass and has a method with same name and same signature of BaseClass then the overriding will take place at run-time polymorphism (provided the method is not static).BaseClass bcdc = new DerivedClass(); bcdc.doSomething() // will invoke DerivedClass's doSomething method.Now come to C# there can be so much confusion and hard to understand how the new or virtual+derive or new + virtual override is working. I'm not able to understand why in the world I'm going to add a method in my DerivedClass with same name and same signature as BaseClass and define a new behaviour but at the run-time polymorphism, the BaseClass method will be invoked! (which is not overriding but logically it should be). In case of virtual + override though the logical implementation is correct, but the programmer has to think which method he should give permission to user to override at the time of coding. Which has some pro-con (let's not go there now).So why in C# there are so much space for un-logical reasoning and confusion. So may I reframe my question as in which real world context should I think of use virtual + override instead of new and also use of new instead of virtual + override?After some very good answers especially from Omar, I get that C# designers gave stress more about programmers should think before they make a method, which is good and handles some rookie mistakes from Java. Now I've a question in mind. As in Java if I had a code likeVehicle vehicle = new Car();vehicle.accelerate();and later I make new class SpaceShip derived from Vehicle. Then I want to change all car to a SpaceShip object I just have to change single line of codeVehicle vehicle = new SpaceShip();vehicle.accelerate();This will not break any of my logic at any point of code.But in case of C# if SpaceShip does not override the Vehicle class' accelerate and use new then the logic of my code will be broken. Isn't that a disadvantage?
Why was C# made with new and virtual+override keywords unlike Java?
java;c#;language design;implementations
Since you asked why C# did it this way, it's best to ask the C# creators. Anders Hejlsberg, the lead architect for C#, answered why they chose not to go with virtual by default (as in Java) in an interview, pertinent snippets are below.Keep in mind that Java has virtual by default with the final keyword to mark a method as non-virtual. Still two concepts to learn, but many folks do not know about the final keyword or don't use proactively. C# forces one to use virtual and new/override to consciously make those decisions.There are several reasons. One is performance. We can observe that as  people write code in Java, they forget to mark their methods final.  Therefore, those methods are virtual. Because they're virtual, they  don't perform as well. There's just performance overhead associated  with being a virtual method. That's one issue. A more important issue is versioning. There are two schools of thought  about virtual methods. The academic school of thought says,  Everything should be virtual, because I might want to override it  someday. The pragmatic school of thought, which comes from building  real applications that run in the real world, says, We've got to be  real careful about what we make virtual. When we make something virtual in a platform, we're making an awful  lot of promises about how it evolves in the future. For a non-virtual  method, we promise that when you call this method, x and y will  happen. When we publish a virtual method in an API, we not only  promise that when you call this method, x and y will happen. We also  promise that when you override this method, we will call it in this  particular sequence with regard to these other ones and the state will  be in this and that invariant. Every time you say virtual in an API, you are creating a call back  hook. As an OS or API framework designer, you've got to be real  careful about that. You don't want users overriding and hooking at any  arbitrary point in an API, because you cannot necessarily make those  promises. And people may not fully understand the promises they are  making when they make something virtual.The interview has more discussion about how developers think about class inheritance design, and how that led to their decision.Now to the following question:I'm not able to understand why in the world I'm going to add a method  in my DerivedClass with same name and same signature as BaseClass and  define a new behaviour but at the run-time polymorphism, the BaseClass  method will be invoked! (which is not overriding but logically it  should be).This would be when a derived class wants to declare that it does not abide by the contract of the base class, but has a method with the same name. (For anyone who doesn't know the difference between new and override in C#, see this MSDN page).A very practical scenario is this:You created an API, which has a class called Vehicle.I started using your API and derived Vehicle.Your Vehicle class did not have any method PerformEngineCheck().In my Car class, I add a method PerformEngineCheck(). You released a new version of your API and added a PerformEngineCheck().I cannot rename my method because my clients are dependent on my API, and it would break them.So when I recompile against your new API, C# warns me of this issue, e.g.If the base PerformEngineCheck() was not virtual:app2.cs(15,17): warning CS0108: 'Car.PerformEngineCheck()' hides inherited member 'Vehicle.PerformEngineCheck()'.Use the new keyword if hiding was intended.And if the base PerformEngineCheck() was virtual:app2.cs(15,17): warning CS0114: 'Car.PerformEngineCheck()' hides inherited member 'Vehicle.PerformEngineCheck()'.To make the current member override that implementation, add the override keyword. Otherwise add the new keyword.Now, I must explicitly make a decision whether my class is actually extending the base class' contract, or if it is a different contract but happens to be the same name.By making it new, I do not break my clients if the functionality of the base method was different from the derived method. Any code that referenced Vehicle will not see Car.PerformEngineCheck() called, but code that had a reference to Car will continue to see the same functionality that I had offered in PerformEngineCheck().A similar example is when another method in the base class might be calling PerformEngineCheck() (esp. in the newer version), how does one prevent it from calling the PerformEngineCheck() of the derived class? In Java, that decision would rest with the base class, but it does not know anything about the derived class. In C#, that decision rests both on the base class (via the virtual keyword), and on the derived class (via the new and override keywords).Of course, the errors that the compiler throws also provide a useful tool for the programmers to not unexpectedly make errors (i.e. either override or provide new functionality without realizing so.)Like Anders said, real world forces us into such issues which, if we were to start from scratch, we would never want to get into.EDIT: Added an example of where new would have to be used for ensuring interface compatibility.EDIT: While going through the comments, I also came across a write-up by Eric Lippert (one of the original members of C# design committee) on other example scenarios (mentioned by Brian).PART 2: Based on updated questionBut in case of C# if SpaceShip does not override the Vehicle class'  accelerate and use new then the logic of my code will be broken. Isn't  that a disadvantage?Who decides whether SpaceShip is actually overriding the Vehicle.accelerate() or if it's different? It has to be the SpaceShip developer. So if SpaceShip developer decides that they are not keeping the contract of the base class, then your call to Vehicle.accelerate() should not go to SpaceShip.accelerate(), or should it? That is when they will mark it as new. However, if they decide that it does indeed keep the contract, then they will in fact mark it override. In either case, your code will behave correctly by calling the correct method based on the contract. How can your code decide whether SpaceShip.accelerate() is actually overriding Vehicle.accelerate() or if it is a name collision? (See my example above).However, in the case of implicit inheritance, even if SpaceShip.accelerate() did not keep the contract of Vehicle.accelerate(), the method call would still go to SpaceShip.accelerate().