1. The problem statement, all variables and given/known data A projectile is launched with an inital velocity of 30 m/s so that it covers a horizontal range of 45m. Determine the maximum height reached by the projectile. (There are two answers) I know the answers are 2.96m and 43.0m. but I only know how to find the first. :( 2. Relevant equations To be honest I have been working on this problem for a good 30 minutes. I found the 2.96m pretty easily, but its the 43m that has me stumped. I really have no idea what equations I could use to find the second maximum height of 43m. 3. The attempt at a solution The only thing that I can see to solve the second part of the problem is that the projectile was thrown horizontally at 30 m/s from a building, landing 45m away. However when I put that theory to paper I came up with the height only being roughly 11.025m tall. By this: 45m=30m/s times t I found that t would equal 1.5s, after which i plugged that into the equation y=1/2gt^2 ending with y equaling 11.025m. But that is not right. I tihnk the trick to this problem is in the wording of the problem but I just can't see it. It would be greatly appreciated if I could have some help, this is for an AP physics summer assignment. I'm close to dropping this class because of how angry this is getting me. I would be grateful for any advice.