Q:

Trying to capture two lines before a found regex

I'm trying to figure out how to capture a regex and the two lines previous to it. 
Example:
Santa Claus
North Pole, North Pole
H0H 0H0

The regex I have is for the Postal Code [a-z]{1}\d{1}[a-z]{1}\s\d{1}[a-z]{1}\d{1}
I want to be able to capture that result and the previous two lines as well using on regex expression.
Does anyone have any ideas?
Thank you in advance.

A:

You could use the following:
(.*\n.*\n[a-z]\d[a-z]\s\d[a-z]\d)

Example Here

.*\n.*\n will match all characters on the previous two lines.
[a-z]\d[a-z]\s\d[a-z]\d - I removed {1} after each character class (since only one will be matched by default, this is redundant).

You may also need to add the case-insensitive i flag since [a-z] will only match lowercase characters. Otherwise that should be replaced with [A-Za-z] to catch the capital letters in the postal codes.

